Chapter 4 Alkyl halides (卤代烷): Nucleophilic substitution and elimination (亲核取代和消除) Text 1: chapter 6 Text 2: 第九章 Contents Classification and Nomenclature of Alkyl halides Physical properties of alkyl halides Preparation of Alkyl halides Reactions of alkyl halides • Nucleophilic Substitution Reactions • Elimination Reactions 4.1 Classification and Nomenclature of Alkyl halides • Halohydrocarbons (卤代烃) alkyl halides (卤代烷烃): vinyl halides (卤代烯烃): aryl halides (卤代芳烃): X C sp3 X C sp2 X sp2 Classification of alkyl halides Primary halides 伯卤代烷; 1° Secondary halides 仲卤代烷; 2° H R C Tertiary halides 叔卤代烷; 3° R H X R H C R X R R C X X a geminal dihalide 偕二卤代 C C C X X a vicinal dihalide 邻(连)二卤代 X Nomenclature of alkyl halides Common name: “alkyl halide” (某基卤) IUPAC name: “haloalkane” (卤代烷), -X is treated as a substituent fluoride----------fluorine -----------chloride---------chlorine ----------bromide---------bromine ----------iodide------------iodine ------------- fluorochlorobromoiodo- CH3CH2 F fluoroethane (氟乙烷) ethyl fluoride (乙基氟) Br Bromocyclohexane (溴代环己烷) cyclohexyl bromide 环己基溴 (CH3)3CCl 2-chloro-2-methylpropane t-butyl chloride (叔丁基氯) CH 3CH 2CHCH 3 Br 2-bromobutane (2-溴 丁烷) sec-butyl bromide (仲丁基溴) H Cl CH3 H Cl (1R,3R)-1-chloro-3-methylcyclopentane trans-1-chloro-3-methylcyclopentane (1R,3R)-1-甲基-3-氯环戊烷 trans- 1-甲基-3-氯环戊烷 CH2Cl2 CHCl 3 dichloromethane trichloromethane (二氯甲烷) chloroform (氯仿) methylene dichloride CF3CF2CF3 perfluoropropane 全氟丙烷 3-(chloromethyl)pentane 3-氯甲基戊烷 CCl4 perchloromethane tetrachloromethane carbon tetrachloride (四氯化碳) Common uses of alkyl halides reading material: text 1: 6-3 • solvents (溶剂): CHCl3, CH2Cl2, ClCH2CH2Cl • reagents (试剂): • anesthetics (麻醉剂): CF3CHClBr • refrigerants (致冷剂) : CF2Cl2 (Freon-12,氟里昂-12) CHClF2 (Freon-22) • pesticides (农药): DDT, • poly(vinyl chloride) (聚氯乙烯), Teflon(特氟隆,聚四 氟乙烯) 4.2 Physical properties of alkyl halides • Solubilities(溶解性): very poor in water; Miscible with each other and with other relatively nonpolar solvents.(彼此互溶, 与其它非极性溶剂互溶.) • Boiling point (bp, 沸点): monohalides (一卤代烷): 规律与烷烃相似. • Density (d, 密度): R-F, R-Cl, < 1; R-Br, R-I, > 1. 多卤代烷大于1. 随碳链增长, 同类型卤代烷密度降低. • 一卤代烷具有不愉快的气味, 有毒. • 在铜丝上燃烧时产生绿色火焰, 可用于鉴定卤素. 4.3 Preparation of alkyl halides (6-6) (Reading material: text 1 6-6, p 220-223) 1) Free-radical halogenation (自由基卤代) 6-6A + Cl2 CH3 H3C C H CH3 + Br2 Cl hv + hv HCl CH3 H3C C Br + HBr CH3 Allylic halogenation (烯丙位卤化) 6-6B H H H NBS, CCl4 H hv or initiator H N Br + HBr N H N Br O O O O O Br + Br2 O NBS N-bromosuccinimide N-溴代丁二酰亚胺 Allylic radical is resonance-stableilized. 烯丙 基自由基稳定. Important reactions !! 2) From alkenes (烯烃加成) CH3COOH CH3CH2CH2CH CH2 + HBr CH3CH2CH2CH CH3 Br 84% 3) From alcohol (醇的取代) CH3CH2CH2CH2OH + HBr H2SO4 CH3CH2CH2CH2Br + H2O 95% 4) From other halides (halogen exchange, 主要用于制备碘代烷) RCl (Br ) + NaI acetone RI + NaCl(Br) 4.4 Reactions of alkyl halides • Nucleophilic substitution (亲核取代反应) • Elimination (消除反应): dehydrohalogenation (脱卤化氢) • Formation of organometallic compounds (形成 有机金属化合物) C:Z homolysis ¾ùÁÑ C. + Z. Carbon radical or free radical C+ C: Z heterolysis + : Z carbocation; carbonium ion £¨ ̼正Àë×Ó£© ÒìÁÑ C: + carbanion £¨ ̼负Àë×Ó£© Z+ Reactive intermediates (反应活性中间 体) 1) Nucleophilic substitution reactions (亲核取代反应): Structure of alkyl halides _ + C X X = F , Cl, Br, I Carbon-halogen bond lengths Bond CH3F CH3Cl Bond Length (Å) 1.39 1.78 CH3Br CH3I 1.93 2.14 In a nucleophilic sibstitution, a nucleophile(Nuc:- or Nu ) replaces a leaving group (X-) from a carbon, using its lone pair of electrons to form a new bond to the carbon atom. C C H + Nu- C C X + X- H Nu Nu: Nucleophiles 亲核试剂 X: Cl, Br, I, reactivity: I>Br>Cl For examples: R X + OH R X + R'O Na+ R X + CN R X + I R OH + X R' + R O R CN + X R I + X NaX R X + H2O NH3 R X + RNH2 R2NH R X + P(C6H5)3 ROH + HX RNH2 + HX R2NH + HX R3N + HX + RNH3 X OH + R2NH2 X + R3NH X RNH2 OH - OH - R2NH R3N [ RP(C6H5)3]+X - 任何具有亲核性的试剂或中间体都可能与卤代烃反应,SH, carbanion, etc 2) Elimination reactions (消除反应): C C + B:- C C + B H + X- H X B: base, OH-, CH3O-, CH3CH2O- X: Cl, Br, I 1,2-elimination, β-elimination CH 3CH 2CHCH 3 Br CH3CH2ONa CH3CH2OH CH3CH CHCH 3 81% CH3CH2CH CH2 19% Positional Orientation of elimination 消去反应的取向 Saytzeff rule: (扎衣切夫规则) In elimination reactions, the most highly substituted alkene usually predominates. 在β-消去中,主要得到双键碳上取代基较多的烯烃,也称扎 衣切夫烯烃。 CH 3CHCH 3 Br CH3CH2ONa CH CHCH 3 3 CH3CH2OH OEt 21% + CH3CH CH2 79% Most Nu are also basic and can engage in either substitution or elimination, depending on the alkyl halide and the reaction conditions. 3) Formation of organometallic compounds (形成有机金属化合物) (T2: p234; T1 p 420 10-8, 9 ) R M + C M M: Li, Na; Mg; B, Al, Ga; Si, Ge, Sn, Pb; P, As, Sb; etc. R X + Mg ether(ÃÑ) R MgX organomagnethium compound “Grignard reagent” (格利雅试剂, 格氏试剂) 活性顺序: RI £¾RBr £¾RCl £¾RF Important reagents in organic synthesis !!! R X + 2 Li ether(ÃÑ) RLi + LiX organolithium compound 有机锂化合物 R X + 2 Na ether(ÃÑ) RNa + RX RNa + ether(ÃÑ) NaX R R + NaX Wurtz reaction (武慈反应) 2RLi + CuI R2CuLi ether(ÃÑ) + R'X R2CuLi + LiI R R' + RCu + LiX 4) Reduction of alkyl halides to alkanes (还原反应) Reductive agents (还原剂):LiAlH4, NaBH4 CH3(CH 2)8CH2Br reactivity: 1. LiAlH4 2. H2O CH3(CH 2)8CH3 RI > RBr > RCl primary > secondary > tertiary halides CH3(CH 2)6CH2X NaBH4 ¶þ¸Ê´¼¶þ¼×ÃÑ CH3(CH 2)6CH3 Testing of RX Physical methods: IR, 1H NMR, MS 在铜丝上燃烧时产生绿色火焰. Chemical methods: Reaction with AgNO3 / EtOH solution. R X + AgNO3 R ONO2 + AgX 4.5 Nucleophilic substitution reactions (text 1: p 225-247; text 2: p 237-246) Experimental facts: CH3Br H2O + NaOH ¦Í = K CH3Br CH3 CH3 C Br CH3 + NaOH ¦Í = K CH3 CH3OH + NaBr OH H2O CH3 C Br CH3 CH3 CH 3 C OH CH 3 + NaBr SN2:second-order nucleophilic substitution (双分子亲核取代反应) SN1:first-order nucleophilic substitution (单分子亲核取代反应) 20世纪30年代英国伦敦大学教授英果(C. Ingold) 1) SN2:Second-order nucleophilic substitution (双分子亲核取代反应) CH3Br + NaOH H2O ¦Í = K CH3Br Mechanism H HO CH3OH δ + H slow H nucleophile substrate (底物) – H C C H fast H product (产物) H δ– Br H transition state (过渡态, TS) H HO OH HO C Br + NaBr + Br Nu C C Nu C :L C :L : Nu Nu :L :L TS – HO E – H C δ H δ Br H Eact H HO exothermic reaction 放热反应 C Br H H H HO C H H reaction coordination The reaction-energy diagram (反应能线图) Characteristics of SN2 (1) second-order reaction (二级反应) ν= k[RX][Nu] (2) concerted reaction (协同进行,一步完成。) (3) having a transition state, no intermediate. (反应中经过一个过渡态,没中间体。) (4) stereochemistry: inversion of configuration (构型转化) Walden inversion (瓦尔登转化) C6H13 I* + CH 3 C H optically pure C6H13 I I* C + I CH 3 H racemization (外消旋化) inversion of configuration (构型转化) Walden inversion (瓦尔登转化) C6H13 HO C6H13 Br + HO CH 3 H H3C H (S) (R) H3 C HO + CH 3 Br H Cl (R) HO H Cl (R) 瓦尔登转变是指骨架构型转变,不是指R转为S, 或S转为R。 Nu, Substrate, Solvent, Temperature Factors affecting SN2 reactions A. The effect of nucleophile CH3O- + CH3I rapid CH3OCH3 + I- methoxide ion (¼×Ñõ»ùÀë×Ó£© CH3OH + CH3I methanol very slow + CH3OCH3 H • A base is always a stronger nucleophile than its conjugate acid. + IHO- > HOH CH3O- > CH3OH RO- > ROH RS- > RSH CH3COO- > CH3COOH • In a group of nucleophiles in which the nucleophilic atom is the same, nucleophilicities parallel basicities. (一般情况下, 含有相同亲核性原子的亲核试剂, 其碱性 越强, 亲核能力越强.) Order of basicity and nucleophilicity: RO- > HO- >> RCOO-> ROH > HOH But: basicity ≠ nucleophilicity H3 C CH3 CH2 O O H3 C CH3 basicity: nucleophilicity: > < Steric hindrance (空间位阻) Strong Nu : less electronegative, large valence shell, more polarizable, soft base, less steric hindrance (位阻小) strong R3P, HS-, I-, -CN, HO-, CH3O- , R2NH moderate Br-, Cl-, NH3, CH3OH, CH3SCH3, CH3COO- weak F-, H2O, CH3OH strong weak strong B. The effect of the structure of the substarate (底物结构的影响) R---X(L) Relative rates of reactions of alkyl halides in SN2 reactions Substituent Compound Methyl 1o 2o Neopentyl ÐÂÎì »ù 3o relative rate CH3X CH3CH2X (CH3)2CHX (CH3)3CCH2X (CH3)3CX General order of reactivity in SN2 reaction CH3- > 1° > 2°> 3 ° 30 1 0.02 0.00001 0 H Br H CH3 CH3 Br H H H Br H CH3 CH3 H3C Br CH3 R-: steric effects Leaving group effects A good leaving group must be electron withdrawing; stable after leaving; (usually weak base) polarizable, to stablize the TS I-, Br-, Cl-, O O S HOH, ROH, NR3, etc. O O R O S O O R Br- + CH3 CH3 OH × Br CH3 + OH + H CH3 + OHO H H BrBr CH3 + H2O poor leaving group F HO RO NH2 NHR CN C. Solvent effects on SN2 reactions Protic solvent (质子性溶剂) H2O, ROH, HCOOH, NH3, etc. Aprotic solvent (非质子性溶剂) hexane, acetone(丙酮), acetonitrile(乙腈), etc. Polar solvent (极性溶剂): H2O, ROH, acetone(丙酮), acetonitrile(乙腈), etc. Apolar solvent (非极性溶剂): Hexane, carbon tetrachloride Polar Aprotic Solvents (极性非质子溶剂) O CH3CN acetonitrile 乙腈 O H O H3C acetone 丙酮 N CH3 CH3 N,N-Dimethylformamide (DMF) N,N-二甲基甲酰胺 CH3 H3C S CH3 Dimethyl sulfoxide (DMSO) 二甲亚砜 Generally, polar solvents are required in the nucleophilic substitution reaction. H H H X- O H O Relative Nucleophilicity H O H in protic solvents: I- > Br- > Cl- > F- H H O SH- > CN- > I- > OH- > N3- > Br- > CH3CO2- > Cl- > F- > H2O in aprotic solvents: I- < Br- < Cl- < FO CH2Cl KF, 18-crown-6 CH3CN O CH2F O + K + ClO O O 18-crown-6 F- Factors affecting SN2 reactions Nu Strong Nucleophiles are needed. R less steric hindrance Substrate L good leaving groups are required. Solvent Wide variety, polar aprotic Temperature Higher temperature can increase the rate. 2) CH3 SN1: First-order nucleophilic substitution (单分子亲核取代) CH3 C Br CH3 + NaOH (CH3)3C Br + CH3OH H2O boil ¦Í = K CH3 CH3 CH 3 C OH CH 3 + NaBr (CH3)3C OCH3+ HBr- CH3 C Br CH3 Mechanism of SN1 step 1 CH3 rate-limiting step CH3 C Br CH3 slow CH3 CH3 C CH3 + OH fast CH3 CH3 CH3 C + Br CH3 carbocation intermediate TS 1 step 2 CH3 CH3 C Br ¦Ä ¦Ä CH3 CH3 ¦Ä ¦Ä C OH CH3 TS 2 CH 3 CH 3 C OH CH 3 E TS 1 rate-limiting step TS 2 Eact2 Eact1 £¨CH 3£©3C Br OH £¨CH 3£©3CBr £¨CH 3£©3COH Br reaction coordination The reaction-energy diagram (反应能线图) The structure of carbocations CH3+ methyl cation (CH3)3C+ tert-butyl cation Vacant p orbital H Vacant p orbital H3C + H planar H + CH3 planar H3C sp2 S sp2 sp3 Stereochemistry R1 racemization (外消旋化) C R2 R3 Nu R1 Nu R1 C C R2 R3 R3 R2 Nu Factors affecting SN1 reactions Nu No effects, weak ones are OK. R Stability of carbocation, or Substituent effects L Good leaving groups are required. Similar as SN1. Substrate Solvent Good ionizing solvents needed, protic solvents Temperature Higher temperature can increase the rate. The relative stabilities of carbocations benzylic > allylic > R3C+ > R2CH+ > RCH2+ > CH3+ (most stable) (least stable) CH2 CH2 benzylic cation allylic cation How a methyl group helps stabilize the positive charge of a carbocation? H . C . H H H C +CH H sp2 sp3 +CH CH 2 3 3 H3C C H C H sp2 H3C H H C H3C H3C . +CH (CH ) 2 3 2 +CH (CH ) 2 3 3 CH 3 hyperconjugation 超共轭效应, σ-p electron-donating of alkyl group 烷基的给电子效 应 Rearrangement (重排) of carbocation CH3 H3C C CH CH3 H3C Br -BrSN1 CH3 H3C C CH CH3 H3C Nu- CH3 H3C C CH CH3 H3C Nu CH3 H3C C CH Ph H3C Br -BrSN1 stable CH3 H3C C CH Ph H3C Nu- CH3 H3C C CH Ph H3C Nu CH3 H3C C CH CH3 H3C stable Nu- Nu CH3 H3C C CH CH3 H3C CH3 H3C C CH Ph H3C Characteristics of SN1 (1) first-order reaction (一级反应) ν= k[RX] (2) multi-step reaction (多步反应) (3) having a carbocation intermediate. (反应经过碳正离子中间体。) (4)stereochemistry: racemization (外消旋化) (5) rearrangement (重排) Allylic halides 烯丙基卤 SN1 CH3CH CHCH2Br Br CH3CH CHCH2 CH3CH CH CH2 stable intermediate ¦Ä CH3CH CH OH- OH- ¦Ä CH2 CH3CH = CHCH2OH CH3CH OH Nu ¦Ä SN2 H H H C C C H H X ¦Ä stablized TS CH = CH2 SN2 kinetics Rate = k[R–X][Nu], second-order SN1 Rate = k[R–X], first-order Mechanism Bimolecular, Concerted, TS Stereochemistry Stereospecific (立体专一的) (inversion) Two Steps, intermediate, carbocation, rearrangements Loss of Stereochemistry (racemization) Substrate (R-) Sterics (methyl >1°> 2°, No 3°) Cation Stability (benzylic > allylic > 3° > 2°)(No 1° or methyl) Leaving Group Moderately Important (same trend as SN1) Very Important (– I > –Br > –Cl, H2O > -OH) Nucleophile Solvent Strong/Moderate Required strong: RS–, I–, R2N–, R2NH, RO–, HO–, CN– moderate: RSH, Br–, RCO2– wide variety, (especially polar aprotic) Not important Polar protic But: H Cl C H C NaOH-H2O OH CH3 OH CH3 C H + inversion 56.5% + Cl- CH3 retention 43.5% ?? 离子对机理 R X k1 k -1 + R X k2 k -2 k3 R X k R + -3 分子骨架 紧密离子对 溶剂分割离子对 碳正离子 构型转化 骨架构型转化 部分外消旋化 外消旋化 典型SN2 典型SN1 X 4.6 Elimination reactions (消除反应) C C H X + B:- C C + B H + X- alkene B: base, OH-, RO-, etc. X: Cl, Br, I, HOH, OTs, etc. 1,2-elimination, β-elimination Dehydrohalogenations (脱卤化氢) CH3 H3C C CH3 CH3CH2OH H3C H3C Br H + H-Br + H-Br H Rate = k[R–X], first-order CH3 H3C C Br CH3CH2ONa CH3 CH3CH2OH H3C H3C Rate = k[R–X][B], second-order H H Mechanisms of Elimination E1 reaction: Unimolecular Elimination First-order Elimination 单分子消除 E2 reaction: Bimolecular Elimination Second-order Elimination 双分子消除 1) The E1 mechanism rate-limiting step step 1 CH3 E1 compete with SN1 Rearrangement exist. CH3 C Br CH3 slow step 2 CH3 CH3 C Br ¦Ä ¦Ä CH 3 CH3 CH3 C CH3 + Br intermediate TS 1 CH3 H2C C H CH3CH2OH CH3 fast H3C H + H3C H CH3CH2OH2 fast step 3 CH3CH2OH + H+ 2) The E2 mechanism CH3CH2O H H2C slow CH3 C CH3CH2O H H2C CH3 CH3 C CH3 Br Br fast H H3C + CH3CH2OH + Br Transition state single-step, concerted H-C-C-X: anti-coplanar (反式共平面) anti elimination H H3C - B H C C X - B is far from X, stable TS Stereochemistry of elimination: Anti elimination(反式消除) for the E2 reaction. B H + H B H C C Br Br The orbitals are aligned. B is far away from L. Br H H X X X H Anti coplanar staggered conformation X H X H Syn coplanar eclipsed conformation X H Br H KOC(CH3)3 KOC(CH3)3 HOC(CH3)3 HOC(CH3)3 Br H H H (1) (2) cis-1,4- trans-1,4- k1 > k2 Br H H H NaOCH3 D D syn elimination problem 6-38 H H Br C C Ph Br H C Ph CH3 Ph CH3 NaOCH3 CH3 Ph H C Ph H trans Ph Ph NaOCH3 H cis diastereomers Ph CH3 cis-trans isomers Positional orientation of elimination (消除反应的定位方向) CH 3CH 2CHCH 3 Br CH3CH2ONa CH3CH2OH CH3CH CHCH 3 + CH3CH2CH CH2 81% Saytzeff product 19% Hoffman prduct Saytzeff rule: (Zaitsev, 扎衣切夫规则) In elimination reactions, the most highly substituted alkene usually predominates. 在β-消去中,当有两种β-H时,总是从含H最少的β-C上消去 H,即得到双键碳上取代基较多的烯烃—扎衣切夫烯烃。 why ? 原因:取代基多的烯烃能量更低。 The competition of SN2 with E2 a a H + Nu E2 C - Nu C b X b SN2 H C Nu C + X- H + X- (a) (b) CH3CH2ONa + CH3CH2Br CH3CH2OH 55oC CH3CH2OCH2CH3 + CH2=CH2 SN2 (90%) E2 (10%) CH3CH2ONa + CH3CHCH3 CH3CH2OH (CH3)CHOC2H5 + 55oC SN2 (21%) Br CH2=CHCH3 E2 (79%) CH3 (c) CH3CH2ONa + CH3CCH3 Br CH3CH2OH (CH ) COCH CH +CH =C(CH ) 3 3 2 3 2 3 2 o 25 C SN1 (9%) E2 (91%) minor major CH3 (d) CH3CH2ONa + CH3CCH3 Br CH3CH2OH 55oC CH2=C(CH3)2 E1+E2 (100%) + CH3CH2OH (e) (f) - CH3CH2CH2Br + CH3O CH3OH CH3CH2CH2OCH3 + CH3CH=CH2 o 50 C - CH3CH2CH2Br + (CH3)3CO SN2 major (CH3)3COH o 50 C E2 minor CH3CH2CH2OC(CH3)3 + CH3CH=CH2 SN2 minor E2 major Factors affecting the relative rates of E2 and SN2 reaction E2 SN2 Structure of substrate secondary and tertiary primary alkyl halide alkyl halide Basicity of nucleophile stronger sterically hindered base Stronger basic nucleophile Temperature high temperature low temperature E2 E1 Mechanism Concerted Two Steps (carbocation rearrangements.) Rate Equation Rate = kr[R–X][Base] Rate = kr[R–X] Stereochemistry Stereospecific (anti coplanar TS) Not Stereospecific Substrate Alkene Stability (3° > 2° > 1°) Cation Stability (benzylic > allylic > 3 ° > 2 ° Base Strong Base Required (RO–, R2N–) Not Important: Usually Weak(ROH, R2NH) Leaving Group Moderately Important (same trend as SN1) Very Important (same trend as SN1) Solvent Wide Range of Solvents Polar Protic Product Ratio Saytzeff Rule: The most highly substituted alkene usually predominates. Hofmann Product: Use of a sterically hindered base will result in formation of the least substituted alkene (Hofmann product). Predicting the Products: Substitution versus Elimination Start Bimolecular Reaction Is Nuc/Base bulky? no What kind of substrate? methyl or 1° SN2 yes Is Nuc/Base strong? yes 3° E2 SN2+E2 1° Unfavorable Reaction mostly E1* 2° no yes What kind of substrate? 2°, 3°, or stabilized 1° Unimolecular Reaction Is Nuc/Base bulky? no mostly SN1* * Under conditions that favor a unimolecular reaction (weak Nu/base and polar protic solvent), mixtures of SN1 and E1 are usually obtained. Essential problem-solving skills 1. Correctly name RX, and identify them as 1°, 2°, or 3°. 2. Predict the products of SN1, SN2, E1, and E2 reactions, including stereochemistry. 3. Draw the mechanisms and energy profiles of SN1, SN2, E1, and E2 reactions, 4. Predict and explain the rearrangement of cations in firstorder reactions. 5. Predict which substitutions and eliminations will be faster, based on differences in substrats, base/nucleophile, leaving group, or solvent. 6. Predict whether a reaction will be first-order or secondorder. 7. When possible, predict predominance of substitution or elimination. 8. Use the Saytzeff rule to predict major and minor elimination pfoducts. Assignments • text 1: 6-43, 44, 45, 46, 51, 53, 55, 56 • 6-59, 60, 61, 63, 66 • text 2(selected): p 254: 6, 7, 8, 10,11, 13, 14, 15