Bonding – General Concepts What is a Bond? • A force that holds atoms together. • We will look at it in terms of energy. – Bond energy - the energy required to break a bond. • Why are compounds formed? – Because it gives the system the lowest energy. Ionic Bonding • An atom with a low ionization energy reacts with an atom with high electron affinity. • The electron moves. • Opposite charges hold the atoms together. Electronegativity • The ability of an electron to attract shared electrons to itself. • Pauling method • Imaginary molecule HX • Expected H-X energy = H-H energy + X-X energy 2 • D = (H-X) actual - (H-X)expected Electronegativity D is known for almost every element • Gives us relative electronegativities of all elements. • Tends to increase left to right. • decreases as you go down a group. • Most Noble gases do not have values. • Difference in electronegativity between atoms tells us how polar. Electronegativity: The ability of an atom in a molecule to attract shared electrons to itself. Zero Covalent Intermediate Polar Covalent Large Ionic Covalent Character decreases Ionic Character increases Electronegativity Bond difference Type Ionic Bonds Electrons are transferred Electronegativity differences are generally greater than 1.7 The formation of ionic bonds is always exothermic! Determination of Ionic Character Electronegativity difference is not the final determination of ionic character Compounds are ionic if they conduct electricity in their molten state Coulomb’s Law Q1Q2 E (2.31 x 10 J nm) r Q1Q2 E r 19 • Q is the charge. • r is the distance between the centers. • If charges are opposite, E is negative – exothermic • Same charge, positive E, requires energy to bring them together. – endothermic Size of ions • Ion size increases down a group. • Cations are smaller than the atoms they came from. • Anions are larger. • across a row they get smaller, and then suddenly larger. • First half are cations. • Second half are anions. Periodic Trends • Across the period nuclear charge increases so they get smaller. • Energy level changes between anions and cations. Li+1 B+3 Be+2 C+4 N-3 O-2 F-1 Table of Ion Sizes Size of Isoelectronic ions • Iso - same • Iso electronic ions have the same # of electrons • Al+3 Mg+2 Na+1 Ne F-1 O-2 and N-3 • All have 10 electrons. • All have the configuration 1s22s22p6 Size of Isoelectronic ions • Positive ions have more protons so they are smaller. Al+3 Na+1 Mg+2 Ne F-1 O-2 N-3 Ionic Compounds • We mean the solid crystal. • Ions align themselves to maximize attractions between opposite charges, • and to minimize repulsion between like ions. • Can stabilize ions that would be unstable as a gas. • React to achieve noble gas configuration Li < Na < C < O < F Na < Li < C < O < F F < O < C < Li < Na Na < Li < F < O < C Na < Li < C < F < O 82% 12% 6% O C 0% i< Na <L i< C F< < O F< < Na <L Na O F< Na <L i< <C C < < Li O < < F F 0% < O < <C Na Li < 1. 2. 3. 4. 5. List the following atoms in order of increasing ionization energy: Li, Na, C, O, F. Sodium losing an electron is an ________ process and fluorine losing an electron is an _______ process. 40% 20% 20% 15% d ic n m in fo r or e ne ed e m he r ex ot at io rm ic th e ic, rm m ex ot he er m ic , en do do th e en ic, en do th rm er m ic , ex ot he rm rm ic ic 5% ex ot he endothermic, exothermic exothermic, endothermic endothermic, endothermic exothermic, exothermic more information needed en do th 1. 2. 3. 4. 5. Which of the following statements is true about the ionization energy of Mg+? 27% 18% bo ve ea o. .. d o. .. no ne of th an o lt eq ua lt be ill It w It w ill be eq ua lt o an d an d io th e o o lt eq ua eq ua be be ill ill It w 9% o. .. ... 9% It w 1. It will be equal to the ionization energy of Li. 2. It will be equal to and opposite in sign to the electron affinity of Mg. 3. It will be equal to and opposite in sign to the electron affinity of Mg+. 4. It will be equal to and opposite in sign to the electron affinity of Mg2+. 5. none of the above 36% 74% Choose the compound with the most ionic bond. 16% 5% 5% KC l LiF l Na C KF LiCl KF NaCl LiF KCl LiC 1. 2. 3. 4. 5. l 0% In which pair do both compounds exhibit predominantly ionic bonding? 100% Ca O d an Rb Cl an d Na F nd 0% H2 O O3 0% KI a BH 3a nd nd 5a 0% 3 HF 0% Na 2S O PCl5 and HF Na2SO3 and BH3 KI and O3 NaF and H2O RbCl and CaO PC l 1. 2. 3. 4. 5. Which of the following arrangements is in order of increasing size? . S2 – >K + >C l– . .. Ca 2+ > > Ca 2+ Ga 3+ > 0% >. .. 0% S2 – >C Ca 2+ Ga 3+ > Ga 3+ > S2 –> > K+ > l– >C l– >. .. .. >. l– Ca 2+ >C K+ > Ca 2+ S2 – Ga3+ > Ca2+ > K+ > Cl– > S2– S2– > Cl– > K+ > Ca2+ > Ga3+ Ga3+ > S2– > Ca2+ > Cl– > K+ Ga3+ > Ca2+ > S2– > Cl– > K+ Ga3+ > Ca2+ > S2– > K+ > Cl– 33% 0% Ga 3+ > 1. 2. 3. 4. 5. 67% Which of the following species would be expected to have the lowest ionization energy? 0% M g2 + 0% O2 - 0% 50% Na + 50% Ne FNe O2Mg2+ Na+ F- 1. 2. 3. 4. 5. Sodium Chloride Crystal Lattice Ionic compounds form solids at ordinary temperatures. Ionic compounds organize in a characteristic crystal lattice of alternating positive and negative ions. Forming Ionic Compounds • Lattice energy - the energy associated with making a solid ionic compound from its gaseous ions. • M+(g) + X-(g) MX(s) • This is the energy that “pays” for making ionic compounds. • Energy is a state function so we can get from reactants to products in a round about way. Calculating Lattice Energy • Lattice Energy = k(Q1Q2 / r) • k is a constant that depends on the structure of the crystal. • Q’s are charges. • r is internuclear distance. • Lattice energy is greater with more highly charged ions. • This bigger lattice energy “pays” for the extra ionization energy. • Also “pays” for unfavorable electron affinity. Estimate DHf for Sodium Chloride Na(s) + ½ Cl2(g) NaCl(s) Lattice Energy Ionization Energy for Na Electron Affinity for Cl -786 kJ/mol 495 kJ/mol -349 kJ/mol Bond energy of Cl2 239 kJ/mol Enthalpy of sublimation for Na 109 kJ/mol Na+(g) + Cl-(g) NaCl(s) Na(g) Na+(g) + e½ Cl2(g) Cl(g) Cl(g) + e- Cl-(g) Na(s) Na(g) Na(s) + ½ Cl2(g) NaCl(s) -786 kJ + 495 kJ + ½(239 kJ) - 349 kJ + 109 kJ -412 kJ/mol Lattice Energies of Alkali Metals Halides (kJ/mol) F- Cl- Br- I- Li+ 1036 853 807 757 Na+ 923 787 747 704 K+ 821 715 682 649 Rb+ 785 689 660 630 Cs+ 740 659 631 604 Lattice Energies of Salts of the OH- and O2- Ions (kJ/mol) OH- O2- Na+ 900 2481 Mg2+ 3006 3791 Al3+ 5627 15,916 What about covalent compounds? • The electrons in each atom are attracted to the nucleus of the other. • The electrons repel each other, • The nuclei repel each other. • They reach a distance with the lowest possible energy. • The distance between is the bond length. Covalent Bonds Polar-Covalent bonds Electrons are unequally shared Electronegativity difference between .3 and 1.7 Nonpolar-Covalent bonds Electrons are equally shared Electronegativity difference of 0 to 0.3 Covalent Bonding Forces Electron – electron repulsive forces Proton – proton repulsive forces Electron – proton attractive forces Bond Length Diagram The Octet Rule Combinations of elements tend to form so that each atom, by gaining, losing, or sharing electrons, has an octet of electrons in its highest occupied energy level. Diatomic Fluorine Formation of Water by the Octet Rule Comments About the Octet Rule 2nd row elements C, N, O, F observe the octet rule. 2nd row elements B and Be often have fewer than 8 electrons around themselves - they are very reactive. 3rd row and heavier elements CAN exceed the octet rule using empty valence d orbitals. When writing Lewis structures, satisfy octets first, then place electrons around elements having available d orbitals. Lewis Structures Shows how valence electrons are arranged among atoms in a molecule. Reflects central idea that stability of a compound relates to noble gas electron configuration. Completing a Lewis Structure -CH3Cl Make carbon the central atom Add up available valence electrons: Join peripheral atoms to the central atom with electron pairs. H .. .. Complete octets on H atoms other than hydrogen with remaining electrons C .. H Total = 14 .. Cl .. .. C = 4, H = (3)(1), Cl = 7 Multiple Covalent Bonds: Double bonds H H C H H C H C H H Ethene Two pairs of shared electrons C H Multiple Covalent Bonds: Triple bonds H C C H H C C H Ethyne Three pairs of shared electrons Resonance Resonance is invoked when more than one valid Lewis structure can be written for a particular molecule. H H Benzene, C6H6 H H H H H H H H H H The actual structure is an average of the resonance structures. The bond lengths in the ring are identical, and between those of single and double bonds. Resonance Bond Length and Bond Energy Resonance bonds are shorter and stronger than single bonds. H H H H H H H H H H H H Resonance bonds are longer and weaker than double bonds. Resonance in Ozone, O3 O O O O O O Neither structure is correct. Oxygen bond lengths are identical, and intermediate to single and double bonds Resonance in Polyatomic Ions Resonance in a carbonate ion: Resonance in an acetate ion: Localized Electron Model Lewis structures are an application of the “Localized Electron Model” L.E.M. says: Electron pairs can be thought of as “belonging” to pairs of atoms when bonding Resonance points out a weakness in the Localized Electron Model. Models Models are attempts to explain how nature operates on the microscopic level based on experiences in the macroscopic world. Models can be physical as with this DNA model Models can be mathematical Models can be theoretical or philosophical Fundamental Properties of Models A model does not equal reality. Models are oversimplifications, and are therefore often wrong. Models become more complicated as they age. We must understand the underlying assumptions in a model so that we don’t misuse it. VSEPR – Valence Shell Electron Pair Repulsion X+E Overall Structure Forms 2 3 4 Linear AX2 Trigonal Planar AX3, AX2E Tetrahedral AX4, AX3E, AX2E2 Trigonal bipyramidal AX5, AX4E, AX3E2, AX2E3 Octahedral AX6, AX5E, AX4E2 5 6 A = central atom X = atoms bonded to A E = nonbonding electron pairs on A VSEPR: Linear AX2 CO2 VSEPR: Trigonal Planar AX3 AX2E BF3 SnCl2 VSEPR: Tetrahedral AX4 CCl4 AX3E PCl3 AX2E2 Cl2O VSEPR: Trigonal Bi-pyramidal AX5 PCl5 AX4E SF4 AX3E2 ClF3 AX2E3 I 3- VSEPR: Octahedral AX6 SF6 AX5E BrF5 AX4E2 ICl4-