The food is deemed sterilized when Cl. Botulinum spores are reduced by a factor of 10-12 π π0 = 10−12 (1) In order to calculate the time required to reach this level of sterilization, we must first determine the decimal reduction time, D, given by equation 2, where k represents the reaction velocity constant. (Geankoplis 2003) 2.303 π π·= (2) This represents the time required to reduce the original number of microbes by 1/10. As our sterilization requirement as already been determined to be 10^-12, we must multiply this value by 12 in order to determine our thermal process time, given by equation 3 (Geankoplis 2003). π‘ = 12 π· (3) As we are dealing with Cl. Botulinum, we can determine our thermal processing time from experimental data of thermal death rates given in literature. The decimal reduction time for Cl botulinum spores at 250oF is given as well as the experimental value z. Z represents the increase in temperature in oF that will increase the death rate by a factor of ten. D250 = 3 min Z = 18 oF These values can be used to find the decimal reduction time for any other temperature, given by equation 4 (Geankoplis 2003). π·π = π·250 π₯10 250−π π§ (4) Our processing temperature is 190oF. Plugging these values into Equation 4 will yield the decimal reduction time for 190 degrees. This value can then be used with equation 3 to yield the thermal death time of 7.756 x 10^4 seconds for 190 π·190 = π·250 π₯10 250−190 π§ o = 6.643π₯103 F. π‘ = 12π·190 = 7.756π₯104 We use the t value to find the processing time using equation 5 as thermal death time does not necessarily equal processing time. πΉπ = π‘ ∗ 10 (ππ πΉ−250) π§ (5 πΉπ =∗ 10 (190−250) π§ = 36 min Our minimum processing time to guarantee elimination of the Cl. Botulinum is therefore 36 minutes. We also need to calculate the heat transfer through the cooking chamber. To do so, we must use the specified parameters as well as the Choi Okos Equation to calculate the specific heat capacity of the salsa, given in equations 6-11 in J/kg*K. Parameters: π1 = 355.37 πΎ π2 = 366.48 πΎ πΏ= π2 + π1 = 360.925 2 π = 377.594 πΎ πΆπππ = 1.8459.103 + 1.8306πΏ − 4.6509.10−3 πΏ 2 = 1.901.103 π½ ππ πΎ πΆππ€ = 4.1289.103 − 9.0864.10−2 πΏ + 5.4732. 10−3 πΏ 2 = 4.809.103 π½ ππ πΎ πΆππ = 2.0082.103 + 1.2089πΏ − 1.3129.10−3 πΏ 2 = 2.273.103 π½ ππ πΎ πΆπππ‘ = 1.9842.103 + 1.4733πΏ − 4.8008.10−3 πΏ 2 = 1.891.103 π½ ππ πΎ πΆππππ = 1.5488.103 + 1.9625πΏ − 5.9399.10−3 πΏ 2 = 1.483.103 π½ ππ πΎ πΆππ£π = 0.0267πΆππ + 0.0059πΆπππ‘ + 0.1328πΆππππ + 0.0306πΆπππ + 0.8133πΆππ€ = 4.238.103 π½ ππ πΎ In addition to the heat capacity of the salsa, we must also calculate the thermal conductivity. The Choi-Okos equation can be used to calculate this value, given in equations 12-16. Equation 17 is the average of all the calculated thermal conductivities and represents the overall thermal conductivity for the system in W/m*K. πΎπππ = 1.7881 ∗ 10−1 + 1.1958 ∗ 10−3 ∗ πΏ − 2.7178 ∗ 10−6 ∗ πΏ 2 = 0.256 (12) πΎπππ‘ = 1.8071 ∗ 10−1 + 2.7604 ∗ 10−4 ∗ πΏ − 1.7749 ∗ 10−7 ∗ πΏ 2 = 0.058 (13) πΎππππ = 2.0141 ∗ 10−1 + 1.3874 ∗ 10−3 ∗ πΏ − 4.3312 ∗ 10−6 ∗ πΏ 2 = 0.138 (14) πΎπππ = 1.8331 ∗ 10−1 + 1.2497 ∗ 10−3 ∗ πΏ − 3.1683 ∗ 10−6 ∗ πΏ 2 = 0.222 (15) (πΎπ€ππ‘ = 0.57109 + 1.7625 ∗ 10−3 ∗ πΏ − 6.7306 ∗ 10−6 ∗ πΏ 2 = 0.256) (16) πΎππ£π = 0.0267 ∗ πΎπππ + 0.0059 ∗ πΎπππ‘ + 0.1328 ∗ πΎππππ + 0.0306 ∗ πΎπππ + 0.8133 ∗ πΎπ€ππ‘ = .301 π π∗πΎ (17) The Choi-Okos equation is once again used in calculating the densities of each component of the product, given in equations 18-22. Equation 23 represents the average density of the overall product. ππ = 1.399 ∗ 103 − 5.1840 ∗ 10−1 ∗ (πΏ − 273) (18) ππππ‘ = 9.2559 ∗ 102 − 4.1757 ∗ 10−1 ∗ (πΏ − 273) (19) ππ = 1.5991 ∗ 103 − 3.1046 ∗ 10−1 ∗ (πΏ − 273) (20) ππππ = 1.3115 ∗ 103 − 2.8063 ∗ 10−1 ∗ (πΏ − 273) (21) ππ€ππ‘ = 9.9718 ∗ 102 + 3.1439 ∗ 10−3 ∗ (πΏ − 273) − 3.7574 ∗ 10−3 ∗ (πΏ − 273) (22) πππ£π = 0.0267 ∗ ππ + 0.0059 ∗ ππππ‘ + 0.1328 ∗ ππ + 0.03066 ∗ ππππ + 0.8133 ∗ ππ€ππ‘ = 1.075 ∗ 103 (23) In order to calculate the processing time, we must also know the parameters of the jar itself, such as height, diameter, and heat capacity given below. H = 0.12065 m height of the glass jar d = 0.08255 m diameter of the glass jar h = 6000 W/m2K heat capacity These parameters can be used in conjunction with the Heisler charts to find total processing time. We can calculate total radius, x1, from the given parameters. π₯1 = π = 0.041 2 π₯=0 As we consider the center of the can to be a radius of 0, or x = 0, we can use Equations 24-27 and our values for the average density, thermal conductivity, and heat capacity of the salsa to to determine the n, m,α, and Y values used on the Heisler charts (Geankoplis 2003). π= π₯ =0 π₯1 π= πΎππ£π β∗π₯1 10−3 = 1.216 ∗ (25) πΌ= πΎππ£π πππ£π ∗πΆππ£π = 6.606.10 −8 (26) π−π2 π = π−π1 = 0.5 (27) After applying these values to the Heisler charts, we arrive at a value of 0.25 for X. We can then use equations 28 and 29 to calculate our processing time of 107.457 minutes. Equation 29 is the time given in minutes, Equation 28 in seconds. Calculated value X = 25 π‘πππ = π∗(π₯1)2 πΌ = 6.447 ∗ 103 π (28) π= π‘πππ 60 = 107.457 πππ (29) As our final processing time of 107.457 minutes is greater than our thermal processing time, the salsa will be adequately sterilized to prevent foodborne illness. Along with that, the high temperature will melt the rubber in the lid and seal the jar. The canning process will ensure a longer shelf life for our low acid food product.