Solutions Revisited Kinetic-Molecular View of the Solution Process Solubilities of Solids Effect of Temperature and Pressure on Solubility Molality and Mole Fraction Raoult’s Law Colligative Properties Colloids 13 - 1 Physical states of solutions Solutions can be made that exist in any of the three states. Solid solutions dental fillings, 14K gold, sterling silver Liquid solutions saline, vodka, vinegar, sugar water Gaseous solutions the atmosphere, anesthesia gases 13 - 2 Ideal solutions A solution that forms without a change in energy. • The volume occupied by the solution is equal to the sum of the volumes of the components. • The driving force for forming an ideal solution is increased entropy. + Solvent Solute Solution 13 - 3 Nonideal solutions When a solute is added to a solvent, the temperature of the resulting solution may go up or down. • There are changes in both entropy and enthalpy. • Volumes are not additive. + Solvent or Solute 13 - 4 Predicting Solubilites “Like dissolves like.” Materials with similar polarity are soluble in each other. Dissimilar ones are not. Miscible Liquids that are soluble in each other in all proportions such as ethanol and water. Immiscible Liquids that are not soluble in each other such as hexane and water. 13 - 5 Solution of solids When an ionic solid is placed in water, the outer ions are exposed to the polar water molecules. Water will pull the ions from the solid and surround them - solvate them. Solvation of ions is an exothermic process which helps overcome the lattice energy that holds the crystal together. 13 - 6 Solution of solids 13 - 7 Solution of solids While covalent compounds do not dissociate, they are solvated in solution. 13 - 8 Saturated Solutions At saturation, the solute is in dynamic equilibrium. The concentration is constant. Solute species are constantly in motion, moving in and out of solution. 13 - 9 Solubilities of solids Ionic substances are not soluble in nonpolar solvents like hexane. • A large amount of energy is need to separate the ions. • A nonpolar solvent can’t solvate ions so there is no solvation energy to offset the lattice energy. Predicting the solubility of ionic solids in water is difficult because a number of competing factors are involved. 13 - 10 Solubilities of solids Solids that exist as covalent networks are very insoluble - glass and graphite. Metals are also insoluble. The force that holds them together is too strong. Metals can only be ‘dissolved’ by chemical reaction which converts them to soluble compounds. Zn(s) + 2HCl(aq) ZnCl2(aq) + H2(g) 2Na(s) + 2H2O(l) 2NaOH(aq) + H2(g) 13 - 11 Crystalline hydrates Many compounds will crystallize from solution with a definite proportion of water. This water of hydration is an integral portion of the crystal. Energy is required to remove it. Example. CuSO . 5H O 4 2 Compounds with small, highly positive ions such as Cu2+ and Mg2+ commonly form hydrates. Larger, less positive ions like K+ and Na+ do not form hydrates. 13 - 12 Temperature and solubility Solubility (g/100ml water) 300 SO2 KCl glycine NaBr KNO3 sucrose 200 100 0 0 20 40 60 80 Temperature (oC) 100 13 - 13 Pressure and solubility of gases Increasing the pressure of a gas above a liquid increases the concentration of the gas. This shifts the equilibrium, driving more gas into the liquid. 13 - 14 Pressure and solubility of gases cg = kpgas This law is accurate to within 1-3% for slightly soluble gases and pressures up to one atmosphere. Solubility (g/100g water) Henry’s Law At constant temperature, the solubility of a gas is directly proportional to the pressure of the gas above the solution. 0.010 O2 0.005 N2 He 0.000 0 1 2 Pressure (atm) 13 - 15 Some new concentration units Our discussion of the physical properties of solutions requires the introduction of some new concentration units. Molality The number of moles of solute dissolved in one kilogram of solvent Moles of solute molality, m = Mass of solvent in kilograms Unlike molarity, this unit does not change with temperature. 13 - 16 Some new concentration units Mole fraction The moles of solute, expressed as a fraction of the total number of moles in the solution. cA = nA nA + n B + nC + . . . . Because the units in the numerator and denominator are the same, mole fraction is a unitless quantity. The sum of all components must equal one. 13 - 17 Mole fractions and partial pressure For gases, we can relate the partial pressure of a gas in a mixture to the mole fraction as: pA = cA Ptotal Example. What is the partial pressure of each gas in a mixture of 2.43 mol N2 and 3.07 mol of O2 if the total pressure is 26.9 atm? c N2 = nN2 nN2 + nO2 = 2.43 mol 2.43 mol + 3.07 mol = 0.442 cO2 = nO2 nN2 + nO2 = 3.07 mol 2.43 mol + 3.07 mol = 0.558 13 - 18 Mole fractions and partial pressure pN2 = cN2 Ptotal = 0.442 (26.9 atm) = 11.9 atm pO2 = cO2 Ptotal = 0.558 (26.9 atm) = 15.0 atm 13 - 19 Raoult’s law This law shows the vapor pressure relationship for a volatile component in solution and in its pure form. PA = cA PoA where PA cA PoA = vapor pressure of A in solution = mole fraction of A = vapor pressure of pure A This relationship simply shows that as the amount of A in a solution is reduced, its vapor pressure will also go down. The material must be volatile. 13 - 20 Distillation The concentration dependent changes in vapor pressure can be used to separate mixtures of volatile solvents. Distillation This method relies on the the fact that the mole fraction of the component with the higher vapor pressure is higher in the vapor above a liquid than in the liquid. 13 - 21 Distillation We can determine boiling point of a mixture by plotting of cA vs YA and cB vs YB. BPB vapor composition T, oC BPA 100%A 0%B liquid composition 0%A 100%B 13 - 22 Basic fractional distillation equipment Components • Still pot with heat source • Column • Still head • Receiver The vapor is initially produced in the pot. The separation occurs in the column. 13 - 23 Distillation Equipment Reflux condenser Still head Column Valve Receiver Still pot 13 - 24 The column This is the heart of the distillation process. The vapor will condense in a series of zones called plates. Each plate is an equilibrium between the gas and liquid phases. 13 - 25 Colligative properties “Bulk” properties that change when you add a solute to make a solution. • Based on how much you add but not what the solute is. • Effect of electrolytes is based on number of ions produced. Colligative properties • vapor pressure lowering • freezing point depression • boiling point elevation • osmotic pressure 13 - 26 Vapor pressure lowering The introduction of a nonvolatile solute will reduce the vapor pressure of the solvent in the resulting solution. • The vapor pressure of a nonvolatile component is essentially zero. • It does not contribute to the vapor pressure of the solution. • However, the solution’s vapor pressure is dependent on the solute mole fraction. 13 - 27 Vapor pressure lowering Water will end up in the ‘salt’ solution because it’s vapor pressure is lower than the pure water. 13 - 28 Boiling point elevation When you add a nonvolatile solute to a solvent, the boiling point goes up. This is because the vapor pressure has been lowered. Dbp = Kbp x molality The boiling point will continue to be elevated as you add more solute until you reach saturation. Examples Cooking pasta in salt water Antifreeze 13 - 29 Boiling point elevation Example Determine the boiling point for a 0.222 m aqueous solution of sucrose. Kbp = 0.512 oC m-1 for water. Dbp = 0.512 oC m-1 (0.222 m) = 0.114 oC BP = 100.00 oC + 0.114 oC = 100.11 oC 13 - 30 Freezing point depression When you add a solute to a solvent, the freezing point goes down. Dfp = Kfp x molality The more you add, the lower it gets. This will only work until you reach saturation. Examples “Salting” roads in winter Making ice cream 13 - 31 Freezing point depression Example Determine the freezing point for a 0.222 m aqueous solution of sucrose. Kbp = -1.86 oC m-1 for water. Dbp = -1.86 oC m-1 (0.222 m) = -0.413 oC FP = 0.00 oC - 0.413 oC = -0.41 oC 13 - 32 Example constants Kbp Solvent oC/m Water 100.0 +0.512 0.0 -1.86 Benzene 80.1 +2.53 5.5 -5.12 Camphor 207.4 +5.61 178.8 -39.7 78.3 +1.22 -117.3 -1.99 Ethanol Normal fp, oC Kfp Normal bp, oC oC/m 13 - 33 Ionic vs. covalent substances Ionic substances have a greater effect per mole than covalent. • 1 mol/kg of water for glucose = 1 molal • 1 mol/kg of water for NaCl = 2 molal ions • 1 mol/kg of water for CaCl2 = 3 molal ions Effects are based on the number of particles! 13 - 34 Osmosis The movement of a solvent through a semipermeable membrane from a dilute solution to a more concentrated one. Semipermeable membranes • only allow small molecules to go through • cell walls are semipermeable membranes 13 - 35 Osmosis 13 - 36 Semipermeable membrane ClNa+ ClNa+ ClNa+ 13 - 37 Osmotic pressure The pressure required to stop osmosis. osmotic pressure = MRT M = molar concentration T = temperature in Kelvin R = gas law constant Since molarity is moles/liter, this equation is just a modified form of the gas law equation. nRT P= V 13 - 38 Osmotic pressure 13 - 39 Osmotic Pressure Three conditions can exist for cells. • Concentration is the same on both sides. isotonic • Concentration is greater on the inside. hypertonic cell hypotonic solution • Concentration is greater on the outside. hypotonic cell hypertonic solution 13 - 40 Cell in isotonic solution A red blood cell and plasma have the same osmotic pressure. 13 - 41 Cells in hypertonic solution If the level of salt in the plasma is too high, the cell collapses. Crenation - water is drawn out of the cell. 13 - 42 Cells in hypotonic solution If the level of salt in the plasma is too low, the cell swells and ruptures. Hemolysis - water is drawn into the cell. 13 - 43 Dialysis The process where solvent and other small molecules can pass through a membrane. Similar to osmosis but the ‘holes’ in the membrane are larger. As a result, even hydrated ions can pass through. The method relies on: diffusion osmosis ultrafiltration 13 - 44 Dialysis By passing large amounts of a pure solvent past the membrane, we can flush out all but the largest components. pure water in water, ions and small molecule out 13 - 45 Colloids Homogeneous mixtures of two or more substances which are not solutions. The substances are present as larger particles than found in solution. Dispersing medium - The substance in a colloid found in the greater extent. Dispersed phase - The substance found in the lesser extent. 13 - 46 Colloids In colloidal suspensions, the particles are much larger than the solutes in a solution. • For solutions, ions and molecules have a size of about 10-7 cm. • In colloids, the particles are larger, with sizes from 10-7 to 10-5 cm. • The colloidal particles are still too small to settle out of solution due to gravity. 13 - 47 Tyndal effect Unlike solutions, colloidal suspensions exhibit light scattering. 1. purple gold sol 2. copper sulfate solution 3. iron(III) hydroxide colloid 1 2 3 13 - 48 Tyndal effect 13 - 49 Types of colloids Dispersing medium Dispersed phase Name Example Gas Gas Liquid Solid Aerosol Aerosol Fog Smoke Liquid Liquid Liquid Gas Liquid Solid Foam Emulsion Sol Whipped cream Milk, mayo Paint, ink Solid Solid Solid Gas Liquid Solid Solid foam Emulsion Marshmallow Butter Pearls, opals 13 - 50 Micelles One important class of colloid is the micelle. Molecules must have a polar and nonpolar end to organize into this type of structure. Examples lipoproteins soaps and detergents Polar head Nonpolar tail 13 - 51 How soap works Soaps and detergents Work by forming Micelles with oil. -OOC -OOC COO COO -OOC -OOC - COO - COO Nonpolar tails dissolve in oil. - Polar ‘heads’ are attracted to the water. 13 - 52 Biological micelle example cholesterol protein phospholipid Lipids bound to other molecules. Combination results in a micelle structure. 13 - 53