Net Ionic Equations HW: Net Ionic equations worksheet Net Ionic Equations Most ionic compounds dissociate completely into cations and anions when they dissolve in water. Written for double and single replacement reactions Net Ionic Equations 1. Write the complete ionic equation (includes all dissolved ionic compounds as their free ions.) Cl2 (g) + 2NaBr (aq) → Br2 (l) + 2NaCl (aq) Complete Ionic Equations (step 1) Cl2 (g) + 2NaBr (aq) → Br2 (l) + 2NaCl (aq) Cl2 (g) + 2Na+(aq) + 2Br-(aq) → Br2(l) + 2Na+(aq) + 2Cl-(aq) Spectator ions (step 2) Spectator ion: not directly involved in a reaction. Appears on both sides of the equation. In the previous problem, 2Na+(aq) is the spectator ion. Net ionic equation (step 3) Indicates only the particles that actually take part in the reaction. Cl2(g) + 2Br-(aq) → Br2(l) + 2Cl-(aq) Make sure that the charges balance on both sides of the equation Net Ionic Equation (Example) Solutions of Lead(II) acetate and cupric sulfate are mixed. 1. Write the balanced equation Write the complete ionic equation Identify the spectator ions Write the net ionic equation 2. 3. 4. Balanced Equation Pb(C2H3O2)2(aq) + CuSO4(aq) → PbSO4(s) + Cu(C2H3O2)2(aq) Complete Ionic Equation Pb2+(aq) + 2C2H3O2-(aq) + Cu2+(aq) + SO42-(aq)→ PbSO4(s) + Cu2+(aq) + 2 C2H3O2-(aq) Note: PbSO4 does not dissolve in water! Identify Spectator Ions 2C2H3O2-(aq) Cu2+(aq) Appear on both sides of the equation Net Ionic equation Eliminate spectator ions Pb2+(aq) + SO42-(aq) → PbSO4(s) Note: zero net charge on reactant side; zero net charge on product side