Rational
Numbers
Linear
Equations
Functions/
Graphing
Solving Equations
Systems
100 pt
100 pt
100 pt
100 pt
200 pt
200 pt
200 pt
200 pt
300 pt
300 pt
300 pt
300 pt
400 pt
400 pt
400 pt
400 pt
Final
Which number is irrational?
A.  213
2
B.
3.12
C.
64
D.
9.31307...
D.
9.31307…
Which is the best
approximation of
A. 7
B. 7.41
C. 7.42
D. 8
55
?
C.
7.42
33 is between two
integers. What are
the squares of
those integers?
25 and 36
Suppose 17.12 is graphed on the
number line. What square root
would be graphed at that same
point on the number line (round
to the nearest whole number)?
293
Which equation is a linear
equation?
2
x
a. y = + 3
b. xy = 5
c. y = 2/3x
d. x = -9
d. x = -9
At what point will the
line 2x - 3y = 7 cross
the x-axis?
(3½ , 0)
Write the linear equation
in standard form:
2
1
 x y
3
2
4x - 6y = -3
Write an equation in slope
intercept form for a line
passing through (2, 0) and
(-1, 6).
y = -2x+4
Which ordered pair represents a
point that would lie on the
graph of y = 4x -10?
A. (4, -10)
B. (4, 6)
C. (-4, 6)
D. (-4, 10)
B. (4, 6)
2
-2x
If g(x) =
+ 4x + 9,
find g(-3).
-21
Write an
equation
of the line
in slope
intercept
form.
y = - 2x + 4
Graph on your whiteboard
3x – 4y = 8
A system of equations
produces two lines that
intersect. The solution of the
this system can be described
as….
One point
Solve the system using
substitution
1
x = 2 y+3
2x – y = 6
Infinitely many
solutions
Solve the equation
4
1

2  x  4  1  x  3  x
3
3

x=6
Solve the system using
elimination
3x + 4y = -25
2x - 3y = 6
(-3, -4)
FINAL JEOPARDY
CHEMISTRY Michael needs 10 milliliters of 34% HCl
(hydrochloric acid) solution for a chemistry experiment. There is a
bottle of 10% HCl solution and a bottle of 40% HCl solution in the
lab. How much of each solution should he use to obtain the required
amount of 34% HCl solution?
2 mL of the 10% HCl solution
8 mL of the 40% HCl solution
CHEMISTRY Michael needs 10 milliliters of 34% HCl (hydrochloric
acid) solution for a chemistry experiment. There is a bottle of 10%
HCl solution and a bottle of 40% HCl solution in the lab. How much of
each solution should he use to obtain the required amount of 34% HCl
solution? (Think back to chapter 2… this time we will use 2 equations
instead)
Given information
10 mL 34% HCL
x mL 10% HCL
y mL 40% HCL
Solve
y = 10 – x
0.10x + 0.40(10 – x) = 3.4
0.1x + 4 – 0.4x = 3.4
-0.3x = -6
x=2
System of Equations
x + y = 10
0.10x + 0.40y = 0.34(10)
y = 10 – x
y = 10 – 2
y=8
Answer: 2 mL of 10% HCl solution, 8 mL of 40% HCl solution