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Physics 1C

Lecture 24A

Spectrum of EM Waves

There are distinct forms of EM waves at different frequencies (and wavelengths).

Recall that the wave speed is given by: v wave

= c = l f .

Wavelengths for visible light range between

400nm (violet) and 700nm (red).

There is no sharp division between one kind of EM wave and the next.

For example, you can have an X-ray and a Gamma

Ray with the exact same wavelength.

EM Spectrum

Note the overlap between types of waves (such as UV and X-rays).

All EM waves have the same speed in a vacuum, what distinguishes the types are their frequencies or wavelengths.

Note that the visible section is a quite small portion of the spectrum.

EM Spectrum

Wavelengths of light can range from very long (radio,

~100km) to very short

(gamma, ~1fm).

Frequencies have an equally long range of possible values: (gamma,

~10 22 Hz) to (radio, ~10Hz).

Visible light ranges from

Red (700nm, 4x10 14 Hz) to

Violet (400nm, 7x10 14 Hz)

EM Spectrum

Radio waves have a long wavelength (~100m) and thus are good for use as a communication tool (TV,

AM, FM).

Microwaves are smaller

(~1cm) and interfere easily with common things

( μwave oven grates).

Infrared waves are produced by hot objects.

EM Spectrum

Visible light (~500nm) is detected by the human eye. We are most sensitive to yellow-green (560nm).

UV light (~100nm) that comes from the Sun is mostly absorbed by the

Earth’s ozone layer.

EM Spectrum

X-rays (~0.1nm) are associated with fast electrons hitting off of a metal target (medical applications).

Gamma rays (~1fm) are emitted by radioactive nuclei. They can cause serious damage to living tissue as they penetrate deeply into most matter.

Spherical Waves

A spherical wave propagates radially outward from the source (for instance, your cell phone).

The energy propagates equally in all directions.

The intensity is:

The average power is the same through any spherical surface centered on the source.

Intensity will decrease as r increases.

Cell Phone Intensity

Example

A cell phone emits 0.60Watts of 1.9GHz radio waves.

What are the amplitudes of the electric and magnetic fields at a distance of 10cm?

Answer

Assume the cell phone is a point source of electromagnetic waves (or r = 0).

Cell Phone Intensity

Answer

The intensity of the radio waves at 10cm is:

We want the maximum values

(amplitudes) for the electric and magnetic fields.

Cell Phone Intensity

Answer

For magnetic field we can turn to:

Concept Question

The amplitude of the oscillating electric field at your cell phone is 8

μ

V/m when you are 10km from the broadcast antenna. What is the electric field amplitude when you are 20km from the antenna?

A) 8

μ

V/m.

B) 4

μ

V/m.

C) 2

μ

V/m.

D) 1

μ

V/m

Doppler Effect for Light

Since light is an EM wave, if the source or the observer moves with respect to each other the frequency of the wave will be Doppler shifted.

But since the speed of light is so large it takes a large relative speed, u , between the observer and the source for there to be any noticeable effect on the observed frequency, f o

.

For light the Doppler equation becomes: where f s is the frequency emitted by the source and c is the speed of light.

Doppler Effect for Light

As with the previous Doppler equation, you take the top sign (positive) if the observer and the source are moving toward each other.

You take the bottom sign (negative) if the observer and the source are moving away from each other.

Note that this equation is valid only when the relative speed, u , is much smaller than c .

Astronomers use the Doppler Effect for light to see if distant objects are moving toward or away from us.

How do we know that the

Universe is expanding ?

Chemical Elements have characteristic frequencies. (We’ll discuss this more later in the course)

• We assume that chemical elements are the same, and thus have the same characteristic frequencies everywhere in the universe.

We observe the frequencies from distant stars to be “redshifted”, i.e. at frequencies lower than expected.

• f o

< f s means distant stars are moving away from us.

Polarization of Light

Light from the sun is produced by the vibrations of multitude of atoms located there.

Each atom produces a wave with its own orientation of the electric field.

All directions of the electric field vector are equally possible and are in a plane perpendicular to the direction of propagation.

This type of wave is known as an unpolarized wave.

Polarization of Light

A wave is said to be linearly polarized if the resultant electric field vibrates in the same direction at all times at a particular point.

It is possible to polarize an unpolarized beam.

The most common technique for polarizing light is called polarization by selective absorption .

Polarization of Light

In this technique, you use a material that transmits waves whose electric field vectors in that plane are parallel to a certain direction ( transmission axis ).

This material also absorbs waves whose electric field vectors are perpendicular to that direction.

This device is known as a polarizer .

The material is known as a

Polaroid (1932).

Polarization of Light

When you place a second polarizing sheet (called the analyzer ) behind the polarizer, the intensity of the polarized beam that is transmitted will vary as:

I  I o cos 2  where I o is the intensity of the polarized wave incident on the analyzer.

The angle  is the angle between the transmission axes of the two polarizing sheets.

This is Malus’ Law .

Polarization of Light

The intensity of the transmitted beam is the highest when the transmission axes are parallel.

The intensity is zero when the transmission axes are perpendicular to each other.

This would cause complete absorption.

In the middle, the axes are at 45º and less intensity occurs.

The Nature of Light

An interesting question developed as to the nature of light: if light is indeed a wave then why can it travel from the Sun to

Earth when there is no medium present?

The answer: Light is a particle (photon), particles do not require a medium.

But if light is a particle, then how can it bend around corners?

The answer: Light is a wave , waves that propagate outward can bend around an obstacle.

The Nature of Light

But, if light is a wave how does that explain the photoelectric effect?

The answer: Light is a particle, only particles with high energy can eject the electrons.

But if light is a particle, then how does this explain the “standing wave” pattern I see with interference from double slits?

The answer: Light is a wave, waves will create bright/dark spots depending on path length difference.

The Nature of Light

But how can light be both a particle and a wave?

We say that light can have both wavelike properties and particle-like properties.

This is called wave-particle duality .

In some experiments light acts as a wave and in others it acts as a particle.

Experimenters will find whatever they are testing for.

Nature prevents testing both qualities at the same time.

The Nature of Light

We can identify light as being “particles” called photons .

Each photon has a particular energy which is quantified by its frequency.

E  hf h is called Planck’s constant and is: h  6.63

 10  34 J  s light interacts like a particle with other particles but its

The Ray Approximation

From now on we will have to treat light as having both properties (wave and particle).

The ray approximation is used in geometrical optics to approximately represent beams of light.

We draw imaginary lines (known as light rays ) along the direction of propagation of a single wave.

We can also represent this wave with wave fronts .

A wave front is a surface where the wave has the same phase and amplitude.

The Ray Approximation

Light rays travel in straight lines in a given medium.

Light rays can cross. They do not interact with each other.

Two rays can cross without either being affected in any way.

A light ray travels forever unless it interacts with matter.

It can interact with matter by either: reflection , refraction , scattering or absorption.

Light ray can also bend around sharp edges ( diffraction ) depending on the wavelength.

Ray Approximation: Barrier

A wave meets a barrier with l

<< d

( d is the diameter of the opening).

The ray approximation assumes that the individual waves emerging from the opening continue to move in a straight line.

The wave meets a barrier with an opening size on the order of the wavelength: l

~ d .

The waves undergo diffraction and spread out from the opening in all directions .

Ray Approximation: Barrier

The wave meets a barrier with an opening size much smaller than the wavelength: l

>> d .

In this case, the opening can be approximated as a point source .

Ray Model of Light

An object is a source of light rays.

Rays originate from every point on the object, and each point sends rays in all directions.

If the object is far away, the rays will appear parallel to the observer.

We make no distinction between self-luminous objects and reflective objects.

5) The eye sees by focusing a diverging bundle of rays.

The Nature of Light

The incident light ray will move in a straight line path as long as the medium does not change.

But, when it encounters a boundary with a second medium, (at least) part of this incident ray is reflected back into the first medium.

If the boundary is a smooth surface, the reflection is known as specular reflection .

This means all the reflected rays will be parallel to one another.

The Nature of Light

If the boundary is a rough surface, the reflection is known as diffuse reflection .

This means that the reflected rays will travel in a variety of directions.

Diffuse reflection is how you can see most everyday objects.

Although diffuse reflection is more common, it is harder to mathematically model than specular reflection.

Law of Reflection

We define a normal (perpendicular line to the surface) at the point where the incident ray hits strikes the surface.

The incident angle, θ

1

, is the angle that the incident ray makes with respect to the normal.

The reflected angle, θ ’

1

, is the angle that the reflected ray makes with respect to the normal.

The angle of incidence is equal to the angle of reflection.

For Next Time (FNT)

Continue Chapter 24 homework.

Start reading chapter 25.

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