Data Analysis
Chapter 2
Section 2.1
Pgs. 25-30
Base Units of Measurement

Length


Volume


Base unit – Meter, m
Base unit – Liter, L
Mass

Base unit – Gram, g
Which is longer, a kilometer or a mile?
Prefixes
•
Milli – thousandath
–
•
Centi – hundred
–
•
Ex. Millenium
Ex. Century
Deci – ten
–
Ex. Decade
•
Kilo - thousand
•
Relative to the base unit
Length
Common Units of Length
Abbreviation
Meter Equivalent
Millimeter
mm
1000 mm = 1 m
Centimeter
cm
100 cm = 1 m
Decimeter
dm
10 dm = 1 m
Meter
m
1m
Kilometer
km
1 km = 1000 m
Base Unit
Volume
Common Units of Length
Abbreviation
Meter Equivalent
Milliliter
ml
1000 ml = 1 L
Centiliter
cl
100 cl = 1 L
Deciliter
dl
10 dl = 1 L
Liter
L
1L
Kiloliter
kl
1 kl = 1000 L
Base Unit
Mass
Common Units of Length
Abbreviation
Meter Equivalent
Milligram
mg
1000 mg = 1 g
Centigram
cg
100 cg = 1 g
Decigram
dg
10 dg = 1 g
Gram
g
1g
Kilogram
kg
1 kg = 1000 g
Base Unit
Density

Do you remember how to find density from physical
science class?

Density = mass/volume



D = m/V
Units for solids are typically:


Or
g/cm3
Units for liquids are typically:

g/mL
Refresher Problems



You have 16 grams of sucrose (a sugar) that fits in a
box that is exactly 10 cm3. What is the density of
sucrose?
16 g/10 cm3 = 1.6 g/cm3
1.59 is actually the density of sucrose which is
typically table sugar
Refresher Problems


You have 20 mL of maple syrup to smother all over your
pancakes. If maple syrup has a density of 1.3 g/mL how
much more mass will your fluffy pancakes have?
m = d x V = (1.3 g/mL)(20 mL) = 26 g
m
d
V
Temperature


The Kelvin (K) is actually the SI unit for
temperature
To convert Celsius (oC) into Kelvin the equation is:


C + 273 = K
To convert Kelvin into Celsius the equation is:

K – 273 = oC
Temperature Problems

Convert 115 oC into Kelvin


115 oC + 273 = 388 K
Convert 356 K into Celsius

356 K – 273 = 83 oC
Homework

Temperature/Density WS

Read pgs 25-30

Answer problem #'s 1, 2, 3, 5, 6, 9, 10, 11
Dimensional Analysis
•
153 mg = ______ g
Start by writing down what you are starting with
153 mg
Put the units you want canceled on the bottom and the
unit you are looking for on top:
153 mg x ________g__
mg
Dimensional Analysis
Cancel units
153 mg x ________g__
mg
Are the units left over what we were looking for?
Yes
153 mg x ________g__
mg
Dimensional Analysis
Insert the proper conversion factors
153 mg x ____1___g__
1000 mg
Do the math and solve:
0.153 g
Dimensional Analysis
26.7 mg = ______ kg
Start by writing down what you are starting with
26.7 mg
Put the units you want canceled on the bottom and the
unit you are looking for on top. If they are not within
1000 units of each other use the measurement that is
within 1000 units:
26.7 mg x ________g_
mg
Dimensional Analysis
Cancel units
26.7 mg x ________g_
mg
Are the units left over what we were looking for?
No
26.7 mg x _________g_
mg
Put the units you want canceled on the bottom and the
unit you are looking for on top.
26.7 mg x ________g_ x ________kg__
Dimensional Analysis
Cancel units
26.7 mg x ________g_ x _________kg__
mg
g
Are the units left over what we were looking for?
Yes
26.7 mg x ________g_ x _________kg__
mg
Insert the proper conversion factors
26.7 mg x ____1___g_ x ____1___kg__
g
Dimensional Analysis
Do the math and solve:
26.7 mg x ____1___g_ x ____1___kg__
1000
mg
(26.7 x 1 x 1 kg) / (1000 x 1000)
= 0.0000267 kg = 2.67 x 10-5 kg
1000 g
Dimensional Analysis
•
224 oz = _____ kg
224 oz x ________g_
oz
224 oz x ________g_ x _______kg_
oz
g
224 oz x ___28.4 _g_ x ____1__kg_
1
= 6.3616 kg = 6.36 kg
oz
1000 g
Dimensional Analysis
•
•
150 mm = _____ cm
Try on your own, I chose someone to do on
the board
Homework
•
•
Chemistry and CP Chemistry

Read pgs 34-35

Answer question #'s 17(not C), 18(not
D), 25, 28
Honors Chemistry

Read pgs 31-35

Answer question #'s 17(not C), 18(not
D), 22, 23, 24, 25, 28