Name
Period
Date
The Gas Laws – Ch. 10 (p.313-322)
1. The gas left in a used aerosol can is at a pressure of 1 atm at 27C. If this can is thrown
into a fire, what is the internal pressure of the gas when its temperature reaches 927C?
GIVEN
T1= 300K
P1= 101 KPA
T2= 1200K
P2= X
ANSWER:
GAS LAW
WORK
BOYLE
FORMULA
101 / 300 = X / 1200
X = 404
P1/T1=P2/T2
404 KPA OR 4 ATM
2. A sample of carbon dioxide occupies a volume of 3.50 L at 125 kPa. What pressure would
the gas exert if the volume were decreased to 2.00 L?
GIVEN
V1 = 3.50 L
P1 = 125 KPA
V2 = 2.00 L
P2 = X
ANSWER:
GAS LAW
WORK
CHARLES
FORMULA
(125) (3.50) = (2.00) (X)
X = 218.75 KPA
P1V1 = P2V2
218.75 KPA
3. A sample of propane occupies 250.0 L at 125 kPa and 38C. Find its volume at 100.0 kPa
and 95C.
GIVEN
GAS LAW
WORK
COMBINED
V1 = 250.0 L
P1 = 125 KPA
T1 = 311 K
V2 = x
P2 = 100.0 kPa
T2 = 368 K
FORMULA
(125) (250.0) / 311 = (100.0) (X) / 368
X = 369.77
P1V1/T1=P2V2/T2
ANSWER: 369.77 L
The Gas Laws – Ch. 6
CHEM
4. Oxygen gas is at a temperature of 40C when it occupies a volume of 2.3 L. To what
temperature in Celsius should it be raised to occupy a volume of 6.5 dm3?
GIVEN
T1 = 313 K
V1 = 2.3 L
T2 = X
V2 = 6.5 L
ANSWER:
GAS LAW
CHARLES
FORMULA
V1/T1 = V2/T2
WORK
2.3 / 313 = 6.5 / X
X = 884
884 – 273 = 611 C
611 C
5. Fluorine exerts a pressure of 900. torr. When the pressure is changed to 1.5 atm, its
volume is 250. mL. What was the original volume?
GIVEN
1 TORR = 133 PA
900 TORR = 120 KPA
P1 = 120 KPA
V1 = X
P2 = 151.5
V2 = 250 ML
ANSWER:
GAS LAW
WORK
BOYLE
FORMULA
(120) (X) = (151.5) (250)
X = 315.625 ML
P1V1 = P2V2
315.625 ML
6. The volume of a gas is 200.0 mL at 275 K and 92.1 kPa. Find its volume at STP.
GIVEN
GAS LAW
WORK
COMBINED
V1 = 200 ML
T1 = 275 K
P1 = 92.1 KPA
V2 = X
T2 = 293 K
P2 = 101 KPA
ANSWER:
FORMULA
(92.1) (200) / 275 = (101) (X) / 293
X = 194 ML
P1V1/T1=P2V2/T2
194 ML
7. A sample of N2 occupies a volume of 250 mL at 25C. What volume will it occupy at 95C?
GIVEN
V1 = 250 ML
T1 = 298 K
V2 = X
T2 = 368 K
ANSWER:
GAS LAW
WORK
CHARLES
FORMULA
250 / 298 = X / 368
X = 308 ML
V1/T1 = V2/T2
308 ML
The Gas Laws – Ch. 6
CHEM
The Gas Laws – Ch. 6
CHEM