Supplemental Problems

Supplemental Problems A Glencoe Program Hands-On Learning: Laboratory Manual, SE/TE Forensics Laboratory Manual, SE/TE CBL Laboratory Manual, SE/TE Small-Scale Laboratory Manual, SE/TE ChemLab and MiniLab Worksheets Review/Reinforcement: Study Guide for Content Mastery, SE/TE Solving Problems: A Chemistry Handbook Reviewing Chemistry Guided Reading Audio Program Applications and Enrichment: Challenge Problems Supplemental Problems Teacher Resources: Lesson Plans Block Scheduling Lesson Plans Spanish Resources Section Focus Transparencies and Masters Math Skills Transparencies and Masters Teaching Transparencies and Masters Solutions Manual Technology: Chemistry Interactive CD-ROM Vocabulary PuzzleMaker Software, Windows/MacIntosh Glencoe Science Web site: science.glencoe.com Assessment: Chapter Assessment MindJogger Videoquizzes (VHS/DVD) Computer Test Bank, Windows/MacIntosh Copyright © 2002 by The McGraw-Hill Companies, Inc. All rights reserved. Permission is granted to reproduce the material contained herein on the condition that such material be reproduced only for classroom use; be provided to students, teachers, and families without charge; and be used solely in conjunction with the Chemistry: Matter and Change program. Any other reproduction, for use or sale, is prohibited without prior written permission of the publisher. Send all inquiries to: Glencoe/McGraw-Hill 8787 Orion Place Columbus, OH 43240-4027 ISBN 0-07-824535-4 Printed in the United States of America. 1 2 3 4 5 6 7 8 9 10 045 09 08 07 06 05 04 03 02 01 SUPPLEMENTAL PROBLEMS Contents To the Teacher . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . iv Chapter 2 Data Analysis . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 Chapter 3 Matter—Properties and Changes . . . . . . . . . . . . . . . . . . . . . 3 Chapter 4 The Structure of the Atom . . . . . . . . . . . . . . . . . . . . . . . . . 5 Chapter 5 Electrons in Atoms . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 7 Chapter 6 The Periodic Table and Periodic Law . . . . . . . . . . . . . . . . . 9 Chapter 10 Chemical Reactions . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 11 Chapter 11 The Mole . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 13 Chapter 12 Stoichiometry . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 15 Chapter 13 States of Matter . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 17 Chapter 14 Gases . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 19 Chapter 15 Solutions . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 21 Chapter 16 Energy and Chemical Change . . . . . . . . . . . . . . . . . . . . . . 23 Chapter 17 Reaction Rates . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 25 Chapter 18 Chemical Equilibrium . . . . . . . . . . . . . . . . . . . . . . . . . . . . 27 Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. Chapter 19 Acids and Bases . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 29 Chapter 20 Redox Reactions . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 31 Chapter 21 Electrochemistry . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 33 Chapter 22 Hydrocarbons . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 35 Chapter 24 The Chemistry of Life . . . . . . . . . . . . . . . . . . . . . . . . . . . 37 Chapter 25 Nuclear Chemistry . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 39 Answer Key . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 42 Supplemental Problems Chemistry: Matter and Change iii To the Teacher Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. This Supplemental Problems book provides additional problems to supplement those in the student edition of Chemistry: Matter and Change. These problems are provided for each of the chapters for which additional mathematical problems would be beneficial. Most chapters contain 10–25 supplemental problems. You might use them as assessments or assign them for homework. Complete solutions can be found at the back of the Supplemental Problems book. iv Chemistry: Matter and Change Supplemental Problems 2 CHAPTER SUPPLEMENTAL PROBLEMS Data Analysis 1. A sample of aluminum is placed in a 25-mL graduated cylinder containing 10.0 mL of water. The level of water rises to 18.0 mL. Aluminum has a density of 2.7 g/mL. Calculate the mass of the sample. 2. Saturn is about 1 429 000 km from the Sun. How many meters is Saturn from the Sun? Write your answer in scientific notation. 3. Use the graph to answer the questions. 4. Look at the graph below. Then answer the questions. The Composition of Earth’s Crust Magnesium 2% Sodium Potassium 2% 2% Calcium 4% Iron 6% Aluminum 8% Titanium 1% Other elements 1% Oxygen 46% Silicon 28% Radii of Planets 75 000 a. What kind of graph is this? b. According to the graph, which element is 55 000 0 Earth’s crust is made up of titanium? Of calcium? Pluto Earth Mars 5000 Venus 15 000 Mercury 25 000 c. According to the graph, what percent of Neptune 35 000 Uranus 45 000 Saturn most abundant in Earth’s crust? Jupiter Radius (in km) Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 65 000 Planet a. What kind of graph is this? 5. You place a 28.95-g piece of gold in a 10-mL graduated cylinder. The level of the water rises 1.50 mL. What is the density of gold? You know that silver has a density of 10.5 g/cm3. What mass of silver will raise the level of the water in the graduated cylinder 1.50 mL? b. What are the variables? c. According to the graph, which has a larger radius, Neptune or Uranus? 6. Convert 55 miles per hour to kilometers per hour. How many kilometers/second is 55 miles per hour? (1 mile 1.6 km) d. According to the graph, what is the radius of Saturn? e. Convert the radius of Saturn to meters. Write your answer in scientific notation. 7. Convert the following data to scientific notation. a. 166 000 000 000 000 m2 b. 8847 m c. 484 liters Supplemental Problems Chemistry: Matter and Change • Chapter 2 1 CHAPTER 2 SUPPLEMENTAL PROBLEMS 8. Convert the following as indicated. a. Aluminum boils at 2467°C. What is aluminum’s boiling point in kelvins? b. Bromine melts at 7.2°C. What is bromine’s melting point in kelvins? c. Chlorine melts at 172 K. What is chlorine’s melting point in °C? 12. Mac measured the density of silver three times and obtained the following results: Trial 1: 10.6 g/cm3; Trial 2: 10.8 g/cm3; Trial 3: 9.6 g/cm3. Silver has a density of 10.5 g/cm3 a. Calculate Mac’s percent error for each trial. b. Which trial had the greatest percent error? d. What is 273 K in °C? 13. You calculate that your semester average in 9. American cars use about 600 000 000 gallons of oil per year. How many liters of oil do American cars use per year? Report your answer in scientific notation. (1 L 0.908 quart; 1 gallon 4 quarts) history is 97.5. When you get your report card, your average is 96. What was the percent error of your calculation? 14. Determine the number of significant figures in each measurement. a. 0.000 301 5 m Solve the following problems. Express your answers in proper scientific notation. b. 0.121 012 L c. 1.056 mL d. 12.90 s b. 3.7 106 8.0 105 e. 5000 dogs c. 1.85 1016 9.25 1016 f. 5.78910 103 g d. 2.8 1022 82 1021 e. 3.09 1020 9.1 1019 15. Round the number 31.257 592 to the requested number of significant figures. f. 17 103 3 104 1.3 104 a. 7 significant figures b. 5 significant figures g. 4.80 1015 13 11. a. (4.0 105) (3.0 1013 c. 3 significant figures 103) b. (5.0 1012) (8.05 103) 16. Complete the following calculations. Round off c. (8.9 105) (3.0 103) the answers to the correct number of significant figures. d. (1.6 1012) (8.01 103) a. 2.30 m 3.65 m 0.55 m e. (9.0 105) (3.0 103) b. 103.8 m 31 s f. (2.4 103) (8.0 103) c. 26.0 cm 2.1 cm g. (6.1 105) (3.01 102) 2 Chemistry: Matter and Change • Chapter 2 Supplemental Problems Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 10. a. 5.3 1012 3.0 1011 CHAPTER 3 SUPPLEMENTAL PROBLEMS Matter—Properties and Changes 1. An 18-g sample of element A combines completely with a 4-g sample of element B to form the compound AB. What is the mass of the compound formed? 7. During a chemical reaction, 4.032 g of hydrogen combined with oxygen to form 36.032 g of water. How many grams of oxygen reacted? 8. Nitrogen and oxygen combine to form different 2. A substance breaks down into three component elements when it is heated. The mass of each component element is listed in the table below. What was the mass of the substance before it was heated? Component Mass (g) A 39.10 B 54.94 C 64.00 compounds, as shown below. Compound Chemical Formula Mass N/1 g O Nitric oxide NO 1.76 g Nitrogen dioxide NO2 0.88 g Nitrous oxide NO4 0.44 g What is the ratio of the masses of nitrogen in each of the following? NO2/NO4 Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 3. Silver iodide powder has been used as an anti- septic and as an agent to seed clouds for rain. Silver iodide is 45.9% silver by mass. If you separate a 50-g sample of silver iodide into its elements, silver and iodine, how much silver would you have? 4. If 5 g of element A combines with 16 g of element B to form compound AB, how many grams of B are needed to form compound AB2? How many grams of B are needed to form AB3? 5. During a chemical reaction, 2.445 g of carbon reacts with 3.257 g of oxygen to form carbon monoxide gas. How many grams of carbon monoxide are formed in this reaction? NO/NO4 NO/NO2 9. Carbon and oxygen combine to form carbon monoxide (CO) and carbon dioxide (CO2). The masses of oxygen that combine with 12 g of carbon to form these two compounds are 16 g and 32 g, respectively. What is the ratio of the masses of oxygen in CO2/CO? 10. Phosphorus and chlorine combine to form two different compounds. In one compound, 3.88 g of phosphorus combines with 13.28 g of chlorine. In the other compound, 1.32 g of phosphorus combines with 7.56 g of chlorine. Do these data support the law of multiple proportions? Show your work. 6. Ibuprofen has the chemical formula C13H18O2. It is 75.69% carbon, 8.80% hydrogen, and 15.51% oxygen. How many mg of carbon does a 200-mg tablet of ibuprofen contain? Supplemental Problems Chemistry: Matter and Change • Chapter 3 3 CHAPTER 3 SUPPLEMENTAL PROBLEMS 11. Fluorine and xenon combine to form two different compounds. In one compound, 0.853 g of fluorine combines with 1.472 g of xenon. In the other compound, 0.624 g of fluorine combines with 2.16 g of xenon. Do these data support the law of multiple proportions? Show your work. 12. Ferric chloride is 34.4% iron and 65.6% chlorine by mass. A chemist analyzes three compounds that contain iron and chlorine. Her results are summarized in the data table below. Which of these compounds is likely to be ferric chloride? Explain your answer. Compound Mass of the Sample (g) Mass of Fe (g) Mass of Cl (g) 25 9.3 15.7 II 25 8.6 16.4 III 27 9.3 17.7 NaHCO3. A 168.02-g sample of baking soda contains 45.98 g of sodium, 2.02 g of hydrogen, 24.02 g of carbon, and 96 g of oxygen. What is the mass percentage of each element in baking soda? 14. The chemical formula for chalk is CaCO3. A100-g sample of chalk contains 40 g of calcium, 12 g of carbon, and 48 g of oxygen. What is the mass percentage of each element in chalk? What would be the mass of calcium in 200 g of chalk? 15. A 17-g sample of ammonia, NH3, contains 3 g of hydrogen. What percentage of ammonia is hydrogen? How many grams of nitrogen does the sample contain? Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. I 13. The chemical formula for baking soda is 4 Chemistry: Matter and Change • Chapter 3 Supplemental Problems CHAPTER 4 SUPPLEMENTAL PROBLEMS The Structure of the Atom 1. Use the periodic table to complete the 6. How many more neutrons does thorium-230 following table. Element have than protons? How many electrons does thorium-230 have? Atomic Number Protons Electrons 7. Show that the mass number and the number of a. Li b. c. 87 93 d. Hg 80 e. 81 f. 75 g. B protons are conserved in the following nuclear 230 4 equation: 234 92U 0 90 Th 2He. 8. Give the mass number of each isotope. a. Be with 5 neutrons b. Ga with 39 neutrons c. Si with 16 neutrons 2. Give the number of protons, electrons, and d. Ti with 26 neutrons neutrons in each of the following atoms. Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. a. 108 47Au 9. Give the atomic number of each isotope. b. 40 20Ca a. magnesium-25 c. 23 11Na b. bromine-79 c. antimony-121 3. Name each isotope, and write it in symbolic notation. a. atomic number 26; mass number 56 b. atomic number 29; mass number 64 c. atomic number 17; mass number 37 4. How many protons, electrons, and neutrons are 10. Neon has two isotopes: neon-10 and neon-12. a. Which isotope has the greater mass? b. Which has more neutrons? c. Which has more protons? d. Which has more electrons? in each of the following isotopes? a. uranium-235 b. hydrogen-3 c. silicon-29 5. How many neutrons does europium-151 have? What is the isotope’s mass number? Supplemental Problems 11. Use the table below to calculate the atomic mass of element X. Then use the periodic table to identify the element. Show all your work. Isotope Mass (amu) Percent Abundance 16X 15.995 99.762 17X 16.999 0.038 18X 17.999 0.20 Chemistry: Matter and Change • Chapter 4 5 CHAPTER 4 SUPPLEMENTAL PROBLEMS 12. Magnesium has three isotopes. Magnesium-24 15. An element has three naturally occurring iso- has a percent abundance of 78.99%. Magnesium-26 has a percent abundance of 11.01%. What is the percent abundance of magnesium-25? Assume that there are no other magnesium isotopes. topes. Information about each isotope is summarized below. 13. Calculate the atomic mass of iridium. Iridium has two isotopes. Iridium-191 has a mass of 191.0 amu and a percent abundance of 37.58%. Iridium-191 has a mass of 193.0 amu and a percent abundance of 62.42%. Show all your work. Isotope Mass (amu) Percent Abundance Isotope 1 23.985 78.10 Isotope 2 24.946 10.13 Isotope 3 25.983 11.17 a. Find the atomic mass of this element. Show all your work. b. Identify the element, using the periodic table. 14. An element has three naturally occurring c. Write each isotope in symbolic notation. isotopes. Isotope 1 has a mass of 19.992 amu. Isotope 3 has a mass of 21.991 amu. The pie graph shows the relative abundance of each isotope. Isotope 2 0.27% Isotope 3 9.22% mine the ages of objects that were once living, such as wood, bones, and fossils. While alive, living things take in all the isotopes of carbon, including carbon-14. Carbon-14 undergoes radioactive decay continuously. After an organism dies, the carbon-14 in its body continues to decay. However, its body no longer takes in new carbon-14. Thus, by measuring how much carbon-14 a once-living object contains and comparing it with the amount of carbon-14 in a currently living thing, you can determine the age of the object. a. In terms of subatomic structure, how does Isotope 1 90.51% carbon-14 differ from carbon-12 and carbon-13? b. How is carbon-14 like carbon-12 and carbon-13? c. Carbon-14 emits a beta particle as it decays. What atom does carbon-14 decay to? a. Calculate the atomic mass of the element. d. Write an equation to represent the decay of carbon-14. b. Identify the element, using the periodic table. 6 Chemistry: Matter and Change • Chapter 4 Supplemental Problems Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 16. The isotope carbon-14 can be used to deter- Isotope 2 has a mass of 20.994 amu. CHAPTER 5 SUPPLEMENTAL PROBLEMS Electrons in Atoms 1. Orange light has a frequency of 4.8 1014 s1. 6. List the sequence in which the following orbitals fill up: 1s, 2s, 3s, 4s, 5s, 6s, 7s, 2p, 3p, 4p, 5p, 6p, 7p, 3d, 4d, 5d, 6d, 4f, 5f. What is the energy of one quantum of orange light? 7. Which element has the ground-state electron 2. Which is greater, the energy of one photon configuration [Kr]5s24d105p4? of orange light or the energy of one quantum of radiation having a wavelength of 3.36 109m? 8. Which element has the ground-state electron configuration [Ar]4s23d10? 3. Use the relationships E h and c v to write E in terms of h, c, and . 9. Write electron-dot structures for the following atoms. 4. A radio station emits radiation at a wavelength a. [Ne]3s23p3 of 2.90 m. What is the station’s frequency in megahertz? b. [Ar]4s23d3 c. potassium 5. Record the frequency of your favorite radio Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. station. What is the wavelength of the radiation emitted from the station? 10. Complete the following table. Orbitals Element Symbol 1s 2s 2px 2py 2pz 1s22s22p3 a. Nitrogen b. Electron Configuration F )( )( )( )( ) c. Carbon d. Supplemental Problems 1s22s1 Chemistry: Matter and Change • Chapter 5 7 CHAPTER 5 SUPPLEMENTAL PROBLEMS Increasing Energy 11. Complete the orbital diagram for arsenic. 7p 6d 5f 7s 6p 5d 4f 6s 5p 4d 5s 4p 3d 4s 3p 7p 6d 5f 7s 6p 5d 4f 6s 5p 4d 5s 4p 3d 4s 3p 3s 3s 2p 2s 2p 2s 1s 1s questions. 13. What is the ground-state electron configuration of each of the following atoms? Use noble-gas notation. a. selenium b. krypton 2e 8e 8e 2e c. chlorine 14. What is the highest energy level (n) that is occupied in the following elements? a. He a. How many valence electrons does an atom of this element have? b. Ca c. Sn b. What is the atom’s electron-dot structure? c. If enough energy was added to remove an electron, from which energy level would the electron be removed? Explain your answer. 15. Write the electron configuration for each element described below and identify the element. a. an element that contains 8 electrons b. an element that contains 14 electrons 8 Chemistry: Matter and Change • Chapter 5 Supplemental Problems Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 12. Use the figure below to answer the following CHAPTER 6 SUPPLEMENTAL PROBLEMS The Periodic Table and Periodic Law For questions 1–5, do not use the periodic table. For questions 6–9, do not use Figure 6-12, 6-15, or 6-20. 1. Write the electron configurations for the elements in periods 2–4 of group 2A. 6. Rank the following atoms in order of decreasing radii. 2. Determine the group, period, and block of a. Al, Na, P, S the elements with the following electron configurations. b. Al, Ga, In a. [He]2s22p4 c. As, Ge, Ga b. [Xe]6s1 d. Br, Ca, Cl, K c. [Ar]4s23d104p2 7. Rank the following ions in order of decreasing radii. 3. Categorize each of the elements in problem 2 as a representative element or a transition element. a. Br, Cl, F b. Be2, Ca2, Mg2 c. Ca2, Ga3, K 4. Write the electron configuration of the element Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. fitting each of the following descriptions. Use noble-gas notations. a. Group 8A element in the third period b. Group 4A element in the fourth period c. Halogen in the second period d. Group 1A element in the fourth period 5. What are the noble-gas notations of all the elements with the following valence electron configurations? 8. Rank the following particles in order of decreasing radii. a. I, I b. K, K c. Al, Al3 9. Rank the following atoms in order of decreasing electronegativity. a. Na, Li, K a. s2 b. K, Sc, Ca b. s2p1 c. As, Sn, S Supplemental Problems Chemistry: Matter and Change • Chapter 6 9 CHAPTER 10 SUPPLEMENTAL PROBLEMS Chemical Reactions Balance the following chemical equations. 1. SnS2(s) O2(g) 0 SnO2(s) SO2(g) 2. C2H6(g) O2(g) 0 CO2(g) H2O(g) 3. Al(s) HCl(aq) 0 AlCl3(aq) H2(g) 4. CoCO3(s) 0 CoO(s) CO2(g) Write a balanced equation for each of the following reactions, substituting symbols and formulas for names. Include the state of each reactant and product. Then identify the reaction type for each. If more than one reaction type applies, list all that apply. 10. When chlorine gas is passed through a potassium bromide solution, bromine forms in a potassium chloride solution. 11. Magnesium burns in air to form magnesium oxide. Predict the products in each of the following reactions. If no reaction occurs, write NR. You may use Figure 10-10 for the relative activities of common metals and halogens. 12. Rb(s) CaCl2(aq) 13. Pt(s) MnBr2(aq) 14. F2(g) NaI(aq) Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 5. When aluminum nitrate and sodium hydroxide solutions are mixed, solid aluminum hydroxide forms. The other product is sodium nitrate. 6. When magnesium is heated in the presence of nitrogen gas, solid magnesium nitride forms. 7. When solid copper(II) oxide and hydrogen react, metallic copper and water form. 8. Most industrial production of metallic sodium is accomplished by passing an electric current through molten sodium chloride. Chlorine gas also is produced. 15. Zn(s) AgNO3(aq) Write a complete ionic equation and a net ionic equation for each of the following doubledisplacement reactions. 16. Ba(NO3)2(aq) H2SO4(aq) 0 BaSO4(s) 2HNO3(aq) 17. FeCl3(aq) (NH4)3PO4(aq) 0 FePO4(s) 3NH4Cl(aq) 18. KCl(aq) AgC2H3O2(aq) 0 AgCl(s) KC2H3O2(aq) 9. Liquid pentane (C5H12) burns, producing water vapor and carbon dioxide. Supplemental Problems Chemistry: Matter and Change • Chapter 10 11 CHAPTER 11 SUPPLEMENTAL PROBLEMS The Mole 1. Identify and calculate the number of representative particles in each of the following quantities. a. 2.15 moles of gold b. 0.151 mole of nitrogen oxide 6. Which quantity has the greatest mass? a. 4.16 1023 atoms of radium b. 1.50 1020 atoms of cadmium c. 1.33 1024 atoms of argon c. 11.5 moles of potassium bromide 7. Calculate the number of moles in each of the 2. Calculate the number of moles of the substance that contains the following number of representative particles. a. 8.92 1023 atoms of barium b. 5.50 1025 molecules of carbon monoxide following quantities. a. atoms of each element in 3.35 moles of aspirin (C9H8O4) b. positive and negative ions in 1.75 moles of calcium fluoride (CaF2) c. 2.66 1022 formula units of potassium iodide 8. Determine the molar mass of each of the following compounds. 3. Determine the mass in grams of each of the following quantities. Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. a. 1.24 moles of beryllium b. 3.35 moles of calcium c. 0.155 mole of sulfur a. formic acid (CH2O2) b. ammonium dichromate ((NH4)2Cr2O7) 9. What is the mass in grams of each of the following quantities? a. 2.53 moles of lead(II) nitrate (Pb(NO3)2) 4. Calculate the number of moles in each of the b. 4.62 moles of magnesium bromide (MgBr2) following quantities. a. 6.35 g lithium 10. Calculate the number of moles in each of the b. 346 g zinc following samples. c. 115 g nickel a. 3.75 g calcium carbide (CaC2) b. 245 g aluminum nitrite (Al(NO2)3) 5. How many atoms are in the following samples? a. 1.24 g cobalt 11. Determine the percent composition of each of the following compounds. b. 0.575 g cesium a. manganese oxide (MnO) c. 65.6 g silicon b. propanol (C3H8O) c. calcium phosphate (Ca3(PO4)2) Supplemental Problems Chemistry: Matter and Change • Chapter 11 13 CHAPTER 11 12. Determine the empirical formula for a 100.00-g sample of a compound having the following percent composition. a. 94.07% sulfur and 5.93% hydrogen b. 80.68% mercury, 12.87% oxygen, and 6.45% sulfur 13. A 48.30-g sample of an aluminum-iodine compound contains 3.20 g of aluminum. What is the empirical formula for the compound? SUPPLEMENTAL PROBLEMS 15. Caffeine is a compound found in some natural coffees and teas and in some colas. a. Determine the empirical formula for caffeine, using the following composition of a 100.00-g sample. 49.47 grams of carbon, 28.85 grams of nitrogen, 16.48 grams of oxygen, and 5.20 grams of hydrogen b. If the molar mass of caffeine is 194.19 g/mol, calculate its molecular formula. 14. A 50.00-g sample of hydrated manganese(II) Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. chloride yields 31.75 g of the anhydrous compound after heating. Determine the chemical formula and name of the hydrate. 14 Chemistry: Matter and Change • Chapter 11 Supplemental Problems CHAPTER 12 SUPPLEMENTAL PROBLEMS Stoichiometry 1. Silicon nitride is used in the manufacturing of high-temperature thermal insulation for heat engines and turbines. It is produced by the following reaction. 3Si(s) 2N2(g) 0 Si3N4(s) a. Interpret the equation in terms of particles, moles, and masses. b. Show that mass is conserved in the reaction. 2. The heat from a welder’s torch is produced by the burning of acetylene gas. The reaction is represented by the following balanced chemical equation. 2C2H2(g) 5O2(g) 0 4CO2(g) 2H2O(g) Calculate the mole ratios from the balanced equation. 4. To prevent corrosion and make paints adhere better, some aluminum products are treated with chromium(III) phosphate before finishing. Chromium(III) phosphate (CrPO4) is commercially produced by treating chromium metal with orthophosphoric acid (H3PO4). a. Balance the following equation for the reaction. Cr(s) H3PO4(aq) 0 H2(g) CrPO4(s) b. How many moles of chromium metal are needed to produce 855 g of chromium(III) phosphate? c. The reaction of 206 g chromium will release how many moles of hydrogen gas? 5. Sand (silicon dioxide) and coke (carbon) are Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 3. Limestone (CaCO3) is treated with hydrochloric acid and water to manufacture calcium chloride hexahydrate. This compound is used to melt ice and snow on pavements and roads. The following balanced chemical equation represents the reaction. CaCO3(s) 2HCl(aq) 5H2O(l) 0 CaCl26H2O(s) CO2(g) a. How many moles of calcium chloride hexahydrate will be produced from 4.00 mol calcium carbonate? b. How many moles of hydrogen chloride will be needed to produce 1.25 mol of the hydrate? combined to form silicon carbide (SiC), a compound used in high-strength ceramic materials. a. Balance the following equation for the reaction. SiO2(s) SiC(s) C(s) 0 CO(g) b. What mass of silicon carbide will be produced from the reaction of 352 g silicon dioxide? c. If 1.00 g of carbon is reacted, what mass of carbon monoxide is released? c. If 8.33 mol water is available for the reaction, how many moles of carbon dioxide will be released? Supplemental Problems Chemistry: Matter and Change • Chapter 12 15 12 CHAPTER SUPPLEMENTAL PROBLEMS 6. Two compounds of nitrogen, nitrogen tetroxide 7. One step in the industrial refining of nickel is (N2O4) and hydrazine (N2H4), are used as rocket fuels. When the two compounds are mixed, they ignite spontaneously and produce nitrogen gas and water. the decomposition of nickel carbonyl (Ni(CO)4) into nickel and carbon monoxide. In a laboratory reaction, 25.0 g nickel carbonyl yielded 5.34 g nickel. a. Balance the following equation for the a. Balance the following equation for the reaction. reaction. N2O4(l) N2(g) N2H4(l) 0 H2O(g) b. If 8.00 g nitrogen tetroxide and 4.00 g hydrazine are mixed, determine the following quantities. Ni(CO)4(g) 0 Ni(s) CO(g) b. Determine the theoretical yield of nickel. c. Determine the percent yield. 1. limiting reactant 2. mass of product (N2) Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 3. mass of excess reactant 16 Chemistry: Matter and Change • Chapter 12 Supplemental Problems CHAPTER 13 SUPPLEMENTAL PROBLEMS States of Matter 1. Calculate the ratio of effusion rates of oxygen (O2) to hydrogen (H2). 2. Methane (CH4) effuses at a rate of 2.45 mol/s. 6. What is the pressure of a mixture of nitrogen (N2) and oxygen (O2) if the partial pressure of N2 is 594 mm Hg and the partial pressure of O2 is 165 mm Hg? What will be the effusion rate of argon (Ar) under the same conditions? 7. A sample of air is collected at 101.1 kPa. If the 3. The effusion rate of hydrogen sulfide (H2S) partial pressure of water vapor in the sample is 2.8 kPa, what is the partial pressure of the dry air? is 1.50 mol/s. Another gas under similar conditions effuses at a rate of 1.25 mol/s. What is the molar mass of the second gas? 4. The pressure of a gas in a manometer is 12.9 mm Hg. Express this value in each of the following units. a. torr b. atmosphere 8. Suppose that 5-mL containers of helium (He), neon (Ne), and argon (Ar) are at pressures of 1 atm, 2 atm, and 3 atm, respectively. The He and Ne are then added to the container of Ar. a. What is the partial pressure of He in the container after the three gases are mixed? b. What is the total pressure in the container after the three gases are mixed? Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. c. kilopascal 5. The vapor pressure of water is 2.3 kPa at 23°C. What is the vapor pressure of water at this temperature expressed in atmospheres? Supplemental Problems Chemistry: Matter and Change • Chapter 13 17 CHAPTER 14 SUPPLEMENTAL PROBLEMS Gases 1. In one city, a balloon with a volume of 6.0 L is filled with air at 101 kPa pressure. The balloon in then taken to a second city at a much higher altitude. At this second city, atmospheric pressure is only 91 kPa. If the temperature is the same in both places, what will be the new volume of the balloon? 2. A certain mass of gas in a 2.25-L container has a pressure of 164 kPa. What will the new pressure be if the volume of the container is reduced to 1.50 L and the temperature stays constant? 7. A 50.0-mL sample of gas is cooled from 119°C to 80.0°C. If the pressure remains constant, what is the final volume of the gas? 8. A 10.0-L cylinder of gas is stored at room temperature (20.0°C) and a pressure of 1800 psi. If the gas is transferred to a 6.0-L cylinder, at what Celsius temperature would it have to be stored in order for the pressure to remain at 1800 psi? 9. If the gas pressure in an aerosol can is 148.5 kPa at 23°C, what is the pressure inside the can if it is heated to 298°C? 3. If 5.80 dm3 of gas is collected at a pressure of 92.0 kPa, what volume will the same gas occupy at 101.3 kPa if the temperature stays constant? Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 4. If the volume of an air pump used to inflate a football decreases from 480 mL to 375 mL, and the original pressure was 93.5 kPa, what is the new air pressure in the pump if the temperature stays constant? 5. Maintaining constant pressure, the volume of a gas is increased from 18.0 dm3 to 32.0 dm3 by heating it. If the original temperature was 18.0°C, what is the new temperature in degrees Celsius? 10. A tank for compressed gas has a maximum safe pressure limit of 850 kPa. The pressure gauge reads 425 kPa when the temperature is 28°C. What is the highest temperature in degrees Celsius the tank can withstand safely? 11. In a steel container, it was found that the pressure of the gas inside was 160 kPa when the container had been heated to 98°C. What had been the pressure of the gas when the temperature had been 50°C the previous day? 12. A steel cylinder is filled with a gas at a temperature of 25.0°C and a pressure of 225.0 kPa. What will the pressure be if the temperature is raised to 47°C? 6. A natural gas tank is constructed so that the pressure remains constant. On a hot day when the temperature was 33°C, the volume of gas in the tank was determined to be 3000.0 L. What would the volume be on a warm day when the temperature is 11°C? Supplemental Problems 13. A balloon is filled with gas at a pressure of 102.3 kPa and a temperature of 45.5°C. Its volume under these conditions is 12.5 L. The balloon is then taken into a decompression chamber where the volume is measured as 2.50 L. If the temperature is 36.0°C, what is the pressure in the chamber? Chemistry: Matter and Change • Chapter 14 19 CHAPTER 14 14. A weather balloon contains 14.0 L of helium at a pressure of 95.5 kPa and a temperature of 12.0°C. If this had been stored in a 1.50-L cylinder at 21.0°C, what must the pressure in the cylinder have been? SUPPLEMENTAL PROBLEMS 21. How many grams of gas are present in a sample that has a molar mass of 44 g/mol and occupies a 1.8-L container at 108 kPa and 26.7°C? 22. What is the molar mass of a gas if 142 g of the 15. How many moles of a gas will occupy 2.50 L at STP? gas occupies a volume of 45.1 L at 28.4°C and 94.6 kPa? 16. Calculate the volume that 3.60 g H2 gas will 23. Determine the volume of hydrogen gas needed 17. What volume is occupied by 0.580 mol of gas 24. Calculate the volume of chlorine gas at STP occupy at STP. at 98.4 kPa and 11°C? 18. When a sample of a gas was placed in a sealed container with a volume of 3.35 L and heated to 105°C, the gas vaporized and the resulting pressure inside the container was 170.0 kPa. How many moles of the gas was present? to make 8 L of water vapor. that is required to completely react with 3.50 g of silver, using the following equation: 2Ag(s) + Cl2(g) 0 2AgCl(s). 25. Use the reaction shown to calculate the mass of iron that must be used to obtain 0.500 L of hydrogen at STP. 3Fe(s) 4H2O(l) 0 Fe3O4(s) 4H2(g) 19. An engineer wishes to design a container that Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. will hold 14.0 mol of gas at a pressure no greater than 550 kPa and a temperature of 48°C. What is the minimum volume the container can have? 20. What is the molar mass of a sample of gas that has a density of 2.85g/L at 101 kPa pressure and 29°C? 20 Chemistry: Matter and Change • Chapter 14 Supplemental Problems CHAPTER 15 SUPPLEMENTAL PROBLEMS Solutions 1. The solubility of a gas is 0.34 g/L at STP. What is its solubility at a pressure of 0.80 atm and the same temperature? 2. At 25°C and 1.0 atm, 0.25 g of a gas dissolves in 1.00 L of water. What mass of the gas dissolves in 1.00 L of water at 25°C and 3.0 atm? 8. What is the molarity of a solution that contains 20.45 g of sodium chloride (NaCl) dissolved in 700.0 mL of solution? 9. Calculate the molarity of 0.205 L of a solution that contains 156.5 g of sucrose (C12H22O11). 10. A 0.600-L sample of a 2.50M solution of potas- 3. 1.56 g of a gas dissolves in 2.00 L of water at a pressure of 1.75 atm. At what pressure will 2.00 g of the gas dissolve in 2.00 L of water if the temperature remains constant? 4. What is the percent by mass of 92.3 g of potassium fluoride (KF) dissolved in 1000.0 g of water? 5. A 500.0 g-sample of aqueous hydrogen perox- Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. ide (H2O2) contains 31.50% H2O2 by mass. a. Find the mass of hydrogen peroxide in the solution. sium iodide (KI) contains what mass of KI? 11. What mass of ammonium chloride (NH4Cl) would you use to prepare 85.0 mL of a 1.20M solution NH4Cl? 12. How would you correctly prepare 125 mL of a 0.30M solution of copper(II) sulfate (CuSO4) from a 2.00M solution of CuSO4? 13. A 22.0-mL sample of 12M H2SO4 is diluted to a volume of 1200.0 mL. What is the molarity of the diluted solution? b. Find the mass of water in the solution. 14. A mass of 134 g of manganese dibromide 6. If 24.0 mL of methanol (CH3OH) is dissolved in 48.0 mL of water, determine the percent by volume of methanol in the solution. (MnBr2) is dissolved in 225 g of water. What is the molality of the solution? 15. Calculate the molality of a solution that con- 7. An aqueous solution of methanol is 45.0% methanol by volume. a. Find the volume of methanol in a 250.0-mL sample of the solution. b. Find the volume of water in this sample of tains 106 g naphthalene (C10H8) dissolved in 3.15 mol carbon tetrachloride (CCl4). 16. A solution is made by dissolving 425 g of nitric acid (HNO3) in 535 g of water. Find the mole fraction of nitric acid in the solution. the solution. Supplemental Problems Chemistry: Matter and Change • Chapter 15 21 CHAPTER 16 SUPPLEMENTAL PROBLEMS Energy and Chemical Change 1. Calculate the amount of heat released in the complete combustion of 8.17 g of Al to form Al2O3(s) at 25°C and 1 atm. Hf° for Al2O3(s) 1680 kJ/mol. 4Al(s) 3O2(g) 0 2Al2O3(s) 6. For the reaction H2(g) S(s) 0 H2S(g), H 20.2 kJ and S 43.1 J/K. When will the reaction be spontaneous? 7. The following reaction is nonspontaneous at 25°C. 2. From the following data at 25°C, H2(g) Cl2(g) 0 2HCl(g) H 185 kJ 2H2(g) O2(g) 0 2H2O(g) H 483.7 kJ calculate H at 25°C for the reaction below. 1 Cu2O(s) 0 2Cu(s) O2 (g) 2 Hf° 168.6 kJ If S 75.8 J/K, what is the lowest temperature at which the reaction will be spontaneous? 4HCl(g) O2(g) 0 2Cl2(g) 2H2O(g) 8. Calculate H° at 25°C for the reaction below. 3. Determine S for the reaction SO3(g) H2O(l) 0 H2SO4(l), 2ZnS(s) 3O2(g) 0 2ZnO(s) 2SO2(g) 206.0 given the following entropies. Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. Compound Entropy (J/molK) 0 350.5 Hf°(kJ/mol) 296.8 9. How much heat is evolved in the formation of SO3(g) 256.8 H2O(l) 70.0 35.0 g of Fe2O3(s) at 25°C and 1.00 atm pressure by the following reaction? 156.9 4Fe(s) 3O2(g) 0 2Fe2O3(s) H2SO4(l) Hf° (kJ/mol) 0 824.2 0 4. Calculate the molar entropy of vaporization for liquid hydrogen iodide at its boiling point, 34.55°C. HI(l) 7 HI(g) Hvap 19.76 kJ/mol 10. Calculate the standard heat of vaporization, Hvap, for tin(IV) chloride, SnCl4. Hf° 511.3 kJ/mol for SnCl4(l) and 471.5 kJ/mol for SnCl4(g). 5. Ozone (O3) in the atmosphere may react with nitric oxide (NO). O3(g) NO(g) 0 NO2(g) O2(g) From the following data, calculate the G° in kJ for the reaction at 25°C and determine whether the reaction is spontaneous. 11. Given the following data at 298 K, calculate S for the given reaction. S (J/molK) 2Ag2O(s) 0 4Ag(s) O2(g) 121.3 42.6 205.2 H° 199 kJ S° 4.1 J/K Supplemental Problems Chemistry: Matter and Change • Chapter 16 23 CHAPTER 16 SUPPLEMENTAL PROBLEMS 12. Calculate the G° at 298 K for the following reaction. Fe2O3(s) 13CO(g) 0 2Fe(CO)5(g) 3CO2(g) 824.2 110.5 733.8 H° (kJ/mol) 393.5 87.4 197.6 445.2 S° (J/molK) 213.6 17. How many degrees of temperature rise will occur when a 25.0-g block of aluminum absorbs 10.0 kJ of heat? The specific heat of aluminum is 0.897 J/g°C. 18. Find the standard enthalpy of formation for ethylene, C2H4(g), given the following data. C2H4(g) 3O2(g) 0 2CO2(g) 2H2O(l) 13. Estimate the temperature at which G 0 for H° 1411 kJ the following reaction. C(s) O2(g) 0 CO2(g) NH3(g) HCl(g) 0 NH4Cl(s) H° 393.5 kJ H2(g) 1 O2(g) 0 H2O(l) 2 H° 285.8 kJ H 176 kJ, S 284.5 J/K 14. Consider the reaction below at 25°C for which S 16.1 J/K. 19. Glycine is important for biological energy. The CH4(g) N2(g) 163.8 kJ 0 HCN(g) NH3(g) combustion of glycine is given by the following equation. 4C2H5O2N(s) 9O2(g) 0 8CO2(g) 10H2O(l) 2N2(g) H 3857 kJ 15. Estimate the temperature above which the following reaction is not spontaneous. PbS(s) 2HCl(g) 0 PbCl2(s) H2S(g) 100.4 92.31 359.4 Hf° (kJ/mol) 20.60 98.70 95.30 314.1 G° (kJ/mol) 33.60 16. Copper metal has a specific heat of 0.385 J/g°C and a melting point of 1083°C. Calculate the amount of heat required to raise the temperature of 22.8 g of copper from 20.0°C to 875°C. 24 Chemistry: Matter and Change • Chapter 16 Given that Hf° CO2(g) 393.5 kJ/mol and Hf° H2O(l) 285.8 kJ/mol, calculate the enthalpy of formation per mole of glycine. 20. At body temperature, 2404 J is required to evaporate 1 g of water. After vigorous exercise, a person feels chilly because the body is giving up heat to evaporate the perspiration. A typical person perspires 25 mL of water after 20 minutes of exercise. How much body heat is used to evaporate this water? Supplemental Problems Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. At what temperature will this reaction be spontaneous? CHAPTER 17 SUPPLEMENTAL PROBLEMS Reaction Rates 1. For the reaction BrO3 5Br 6H 0 ] [BrO3 3Br2 3H2O, the value of t 1.5 102 mol/(Ls) at a particular time. [Br] What is the value of at the same t instant? 2. The reaction, A 2B 0 Products, was found to have the rate law, Rate k[A][B]2. While holding the concentration of A constant, the concentration of B was increased from x to 3x. Predict by what factor the rate of the reaction will increase. 3. For the hypothetical reaction A B 0 Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. Products, the following initial rates of reaction have been measured for the given reactant concentrations. Test [A] (M) [B] (M) Rate (mol/(Lⴢhr)) 1 0.010 0.020 0.020 2 0.015 0.020 0.030 3 0.010 0.010 0.005 What is the rate law expression for this reaction? 4. For the chemical reaction H2O2 2H 2I 0 I2 2H2O, the rate law expression is Rate k[H2O2][I]. The following mechanism has been suggested. H2O2 I 0 HOI OH OH H 0 H2O HOI H I 0 I2 H2O 5. Consider the following rate data for the reaction below at a particular temperature. 2A 3B 0 Products Experiment Initial Initial [A] (M) [B] (M) Initial Rate of Loss of A (mol/(Lⴢs)) 1 0.10 0.30 1.00 105 2 0.10 0.60 2.00 105 3 0.20 0.90 1.20 104 What is the rate equation for this reaction? 6. Consider a chemical reaction involving compounds A and B that is found to be first order in A and second order in B. What will the reaction rate be for experiment 2? Experiment Rate (mol/(Lⴢs)) Initial [A] (M) Initial [B] (M) 1 0.10 1.0 0.2 2 ? 2.0 0.6 7. The data below were determined for the following reaction. S2O82 3I 0 2SO42 I3 Experiment [S2O82ⴚ] (M) Iⴚ (M) Initial Rate (mol/(Lⴢs)) 1 0.10 0.40 1.4 105 2 0.20 0.40 2.8 105 3 0.20 0.20 1.4 105 What is the rate equation for this reaction? Identify all intermediates included in this reaction. Supplemental Problems Chemistry: Matter and Change • Chapter 17 25 17 SUPPLEMENTAL PROBLEMS ship is found to be Rate What is the overall reaction order for this reaction? k[A][B]2. 9. For the rate law expression Rate k[A][B]2, what happens to the rate if the concentration of B is increased by a factor of 2? 10. Calculate the specific rate constant for the reaction A B 0 C, when the rate expression is Rate k[A]2[B]. Experiment Initial Initial [A] (M) [B] (M) Initial Rate of Formation of C (mol/(Lⴢs)) 1 0.10 0.10 2.0 104 2 0.20 0.10 8.0 104 3 0.20 0.20 1.6 103 11. The following figure shows the energy diagram of some reactants changing into products. Explain what the numbers in the diagram represent. 12. The following figure shows the potential energy diagram for a reaction. Explain what this diagram tells you about the reaction. b a c XY d ZR Reaction progress 13. Explain how the following mechanism can be used to determine the rate expression for a chemical reaction A 2B 0 AB2. Step 1 B B 0 B2 slow Step 2 B2 A 0 AB B fast Step 3 B AB 0 AB2 fast 14. What is the rate law expression for the following mechanism? Energy (kJ) 40 kJ 100 kJ Step 1 AB C2 0 AC2 B slow Step 2 B AB 0 AB2 fast Step 3 AC2 AB2 0 A2C2 B2 fast Step 4 A2C2 B2 0 A2C B2C fast Reaction progress 26 Chemistry: Matter and Change • Chapter 17 Supplemental Problems Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 8. For the reaction A B 0 C, the rate relation- Potential energy CHAPTER CHAPTER 18 SUPPLEMENTAL PROBLEMS Chemical Equilibrium 1. Write equilibrium expressions for the following reactions. a. NH4HS(g) 3 NH3(g) H2S(g) b. 4HCl(g) O2(g) 3 2Cl2(g) 2H2O(g) decreasing the volume of the reaction vessel would yield more product at equilibrium. Give the reason for your choice. a. N2O4(g) 3 2NO2(g) c. PCl5(g) 3 PCl3(g) Cl2(g) b. 2SO3(g) 3 2SO2(g) O2(g) d. CuSO43H2O(s) 2H2O(g) 3 c. CH4(g) 2O2(g) 3 CO2(g) 2H2O(g) CuSO45H2O(s) 2. At 793 K, the equilibrium constant for the reaction NCl3(g) Cl2(g) 3 NCl5(g) is 39.3. a. Do products or reactants dominate in this equilibrium? b. If the equilibrium constant for this reaction were less than 1, would the reactants or products be dominant? 3. At 773 K, the reaction 2NO(g) O2(g) 3 Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 5. For each reaction, state whether increasing or 2NO2(g) produces the following concentrations: [NO] 3.49 104M; [O2] 0.80M; [NO2] 0.25M. a. What is the equilibrium constant expression for the reaction? b. What is the equilibrium constant for the reaction? d. 2CO(g) O2(g) 3 2CO2(g) 6. What effect would an increase in temperature have on these reactions at equilibrium? Why? a. Heat H2(g) I2(g) 3 2HI(g) b. CH4(g) 2O2(g) 3 CO(g) 2H2O heat c. N2(g) 3H2(g) 3 2NH3(g) heat d. Heat CH4(g) 3 C(s) 2H2(g) 7. Phosphorous pentachloride decomposes to phosphorous trichloride according to this equation: PCl5(g) 3 PCl3(g) Cl2(g). At equilibrium, [PCl5] 1.00M and [Cl2] 3.16 102M. a. Write the expression for determining the concentration of PCl3. b. What is the equilibrium concentration of 4. If you wished to maximize the products of the following reactions, which concentrations would you lower or raise? a. H2(g) Br2(g) 3 2HBr(g) b. CO2(g) H2(g) 3 CO(g) H2O(g) c. SO2(g) NO2(g) 3 SO3(g) NO(g) d. C(s) CO2(g) 3 2CO(g) Supplemental Problems PCl3? Use: Keq 1.00 103. 8. The solubility product constant (Ksp ) of Ag2SO4 is 1.2 105. a. How would you estimate the molar solubility of SO42 without actually calculating it? b. What is the calculated molar solubility of SO42? Chemistry: Matter and Change • Chapter 18 27 CHAPTER 19 SUPPLEMENTAL PROBLEMS Acids and Bases Write balanced chemical equations for each of the following reactions that involve acids and bases. 13. What is its pH? 14. What is its pOH? 1. aluminum and hydrochloric acid 2. nitric acid and sodium carbonate A solution has a pH of 5.79. 15. What is its pOH? 3. potassium hydroxide and sulfuric acid 16. What is its [H]? Write the steps in the complete ionization of the following polyprotic acids. 17. What is its [OH]? 18. What is the pH of a 0.50M solution of HCl, a 4. H2CO3 strong acid? 5. H3BO3 19. What is the pH of a 1.5 103M solution of NaOH, a strong base? Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. A solution has a [H] of 1.0 105M. 6. What is its [OH]? 20. What is the molarity of a KOH solution if 25.0 mL of it is neutralized by 31.7 mL of a 0.100M nitric acid solution? 7. What is its pH? 21. During a titration, 0.200M HCl is added to a 8. What is its pOH? A solution has a [OH] of 3.6 107M. 9. What is its [H]? NaOH solution of unknown concentration. What is the concentration of the NaOH solution if 20.0 mL of it is neutralized by 30.7 mL of the standard solution? 22. A 25.0-mL sample of H2SO4 is neutralized by 27.4 mL of 1.00M KOH. What is the concentration of the acid? 10. What is its pH? 11. What is its pOH? 23. A 50.0-mL sample of 0.0100M Ca(OH)2 is neutralized by 45.6 mL of HBr. What is the molarity of the acid? A solution has a [H] of 5.6 106M. 12. What is its [OH]? Supplemental Problems Chemistry: Matter and Change • Chapter 19 29 CHAPTER 20 SUPPLEMENTAL PROBLEMS Redox Reactions Determine the oxidation number of the boldface element in these ions. 1. HgCl4 2. NO2 3. MnO2 4. metallic Au 5. Na2SiF6 6. Zn(NO3)2 7. Mg3P2 15. Cr2O72(aq) SO32(aq) 0 Cr3(aq) SO42(aq) in an acidic solution Write half-reactions for each of the following redox reactions. Identify each half-reaction as being either oxidation or reduction. 16. SnS2(s) O2(g) 0 SnO2(s) SO2(g) 17. Mg(s) N2(g) 0 Mg3N2(s) 18. Al(s) Cl2(g) 0 AlCl3(s) 19. NH3(aq) PbO(s) 0 N2(g) Pb(s) H2O(l) 20. Cu2S(s) O2(g) 0 Cu2(aq) SO42(aq) (Hint: Two different elements are oxidized.) Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 8. Na3PO4 9. H2O2 10. ClO3 Use your answers for questions 16–20 to help you balance the following equations, using halfreactions for the redox part of the equation. Show your work. 21. SnS2(s) O2(g) 0 SnO2(s) SO2(g) Balance the following equations, using the oxidation number method for the redox part of the equation. Show your work. 22. Mg(s) N2(g) 0 Mg3N2(s) 11. Cu2O(s) H2(g) 0 Cu(s) H2O(l) 23. Al(s) Cl2(g) 0 AlCl3(s) 12. Cl2(g) KBr(aq) 0 Br2(l) KCl(aq) 24. NH3(aq) PbO(s) 0 N2(g) Pb(s) H2O(l) 13. CaSi2(s) SbCl3(s) 0 25. Cu2S(s) O2(g) 0 Cu2(aq) SO42(aq) in Sb(s) Si(s) CaCl2(s) an acidic solution (Hint: Look at the ratio of the two oxidized elements in the equation.) 14. KI(aq) HNO3(aq) 0 I2(s) KNO3(aq) NO(g) H2O(l) Supplemental Problems Chemistry: Matter and Change • Chapter 20 31 21 CHAPTER SUPPLEMENTAL PROBLEMS Electrochemistry Use data from Table 21-1 as needed in the following problems. Assume that all half-cells are under standard conditions. 1. For each of these pairs of half-reactions, write a balanced equation for the overall cell reaction and calculate the standard cell potential, E 0cell. a. Cs(aq) e 0 Cs(s) Cu(aq) e 0 Cu(s) g. H3PO4(aq) 2H(aq) 2e 0 H3PO3(aq) H2O(l) SeO42(aq) 4H(aq) 2e 0 H2SeO3(aq) H2O(l) Cell reaction: E 0cell h. MnO4(aq) 8H(aq) 5e 0 Mn2(aq) 4H2O(l) Cell reaction: 2CO2(g) 2H(aq) 2e 0 H2C2O4(aq) E 0cell Cell reaction: b. Hg2(aq) 2e 0 Hg(l) E 0cell Mn2(aq) 2e 0 Mn(s) 2. Calculate the standard cell potential, E 0cell, for a Cell reaction: E 0cell c. Fe3(aq) 3e 0 Fe(s) Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. Cr3(aq) 3e 0 Cr(s) Cell reaction: d. Br2(g) 2e 0 2Br(aq) e a. PdPd2 E 0cell b. Hf Hf 4 E 0cell Au(aq) cell composed of a SnSn2 half-cell and each of these half-cells. 0 Au(s) Cell reaction: E 0cell e. Be2(aq) 2e 0 Be(s) Tl3(aq) 3e 0 Tl(s) E 0cell c. Cl2Cl E 0cell d. PbPb2 E 0cell 3. Which of the following cells will produce the Cell reaction: highest voltage? E 0cell Mn Mn2 Zn2 Zn f. NO3(aq) 4H(aq) 3e 0 NO(g) 2H2O(l) In3(aq) 3e 0 In(s) Zn Zn2 Ni2 Ni Ni Ni2 Cu2 Cu Cell reaction: E 0cell Supplemental Problems Chemistry: Matter and Change • Chapter 21 33 CHAPTER 21 4. For each of these overall cell reactions, write the oxidation and reduction half-reactions, calculate the standard cell potential, E 0cell, and determine if the reaction is spontaneous or not. a. Fe3(aq) Co2(aq) 0 Fe2(aq) Co3(aq) Oxidation half-reaction: Reduction half-reaction: E 0cell SUPPLEMENTAL PROBLEMS 5. Suppose a battery-powered device requires a minimum voltage of 9.0 V to run. How many lead–acid cells would be needed to run the device? (Remember that a standard automobile battery contains six lead–acid cells connected in one package.) The overall reaction of a lead–acid cell is Pb(s) PbO2(s) 4H(aq) 2SO42(aq) 0 2PbSO4(s) 2H2O(l) Spontaneous? b. Fe3(aq) Cu(aq) 0 6. What is the minimum voltage that must be Oxidation half-reaction: applied to a Down’s cell to cause the electrolysis of molten sodium chloride? The net cell reaction is Reduction half-reaction: 2Na(l) 2Cl(l) 0 2Na(l) Cl2(g) Fe2(aq) Cu2(aq) E 0cell c. 2Rh(s) 0 3Ni(s) 2Rh3(aq) 3Ni2(aq) Oxidation half-reaction: Reduction half-reaction: E 0cell Spontaneous? d. 2Na(aq) 2Hg(l) 2I(aq) 0 2Na(s) Hg2I2(s) 7. One way to determine the metallic composition of an alloy is to use electroplating. Suppose an electrolytic cell is set up with solution of nickel ions obtained from a 6.753-g sample of a nickel alloy. The cell also contains a platinum electrode that has a mass of 10.533 g. Electric current is used to reduce the nickel ions to nickel metal, which is deposited on the platinum electrode. After being plated with nickel, the platinum electrode has a mass of 15.042 g. What is the percentage of nickel in the alloy? Oxidation half-reaction: Reduction half-reaction: E 0cell Spontaneous? e. O2(g) 2H2SO3(aq) 0 2SO42(aq) 4H(aq) Oxidation half-reaction: Reduction half-reaction: E 0cell Spontaneous? 34 Chemistry: Matter and Change • Chapter 21 Supplemental Problems Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. Spontaneous? 22 CHAPTER SUPPLEMENTAL PROBLEMS Hydrocarbons 1. Use the IUPAC rules to name the following alkanes. branched-chain alkane. a. CH3CH2CH2CH2CH3 b. CH3 CH3 c. CH3 CH2CH3 CH3CH2CHCHCHCH2CH3 CH2CH3 d. CH3 CH3CH2 5. Chemists can analyze the composition of hydrocarbons by reacting them with copper oxide. The reaction converts carbon into carbon dioxide and hydrogen into water. Suppose 29 g of a hydrocarbon reacts to produce 88 g of CO2 and 45 g of H2O. CH3CHCHCH3 a. What are the masses of carbon and hydrogen in the hydrocarbon? b. What is the empirical formula of the hydrocarbon? c. If the hydrocarbon’s molecular mass is CH2CH3 CH3 CH3 CH2CH3 Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 4. Calculate the molecular mass of a 22-carbon 2. Draw the structure of each of the following 58 amu, what is its molecular formula? 6. Carbon has an electronegativity of 2.5. Hydrogen has an electronegativity of 2.2. Use these values to decide whether each of the following bonds is polar or nonpolar. alkanes. a. C-C a. 4-propyloctane b. C-H b. 3,4-diethylhexane c. H-H c. 2,2,4,4-tetramethylhexane d. 1-ethyl-3-methyl-2-propylcyclopentane 3. Calculate the number of hydrogen atoms in each of the following alkanes. a. heptane b. cyclooctane Supplemental Problems 7. The combustion of a saturated hydrocarbon releases 657 kJ per mole of –CH2– groups and 779 kJ per mole of –CH3 groups in the hydrocarbon. How much energy is released by the combustion of 1.00 L of liquid tetradecane (molecular formula C14H30), a major component of kerosene? The density of tetradecane is 0.764 g/mL. Chemistry: Matter and Change • Chapter 22 35 CHAPTER 22 SUPPLEMENTAL PROBLEMS 8. Use the IUPAC rules to name the following 10. Calculate the number of hydrogen atoms in hydrocarbons. each of the following unsaturated hydrocarbons. a. CH3CH2CHCHCH3 a. 2-pentene b. b. 1-hexyne CHCH2 CH3CH2CH2CHCH2CH2CH2CH3 c. 11. Write a balanced equation for the reaction in CH3 CH3CHCH2CH2CCH which calcium carbide, CaC2, reacts with water to form ethyne and calcium hydroxide. d. CH 3 CH2CH3 9. Draw the structure of each of the following hydrocarbons. a. 7-methyl-2,5-nonadiene b. 4-ethyl-2-heptyne c. 1,2-diethylcyclohexene Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. d. 1-ethyl-2-methyl-5-propylbenzene 36 Chemistry: Matter and Change • Chapter 22 Supplemental Problems 24 CHAPTER SUPPLEMENTAL PROBLEMS The Chemistry of Life 1. Calculate the molecular masses of the following biological molecules. a. Lysine, NH2(CH2)4CHNH2COOH b. Fructose, CH2OHCO(CHOH)3CH2OH c. Oleic acid, CH3(CH2)7CHCH(CH2)7COOH eride are hydrolyzed by a strong base, such as NaOH. It takes 3 moles of NaOH to saponify each mole of triglyceride. How many moles of triglyceride can be saponified by 120 g of NaOH? 6. A young adult male produces about 2.4 105 2. Write a balanced equation for the condensation reaction in which cysteine and glycine combine to form a dipeptide. Assume the carboxyl group of cysteine reacts. SH mol per day of the steroid sex hormone testosterone. The molecular mass of testosterone is 288. How many grams of testosterone per day does a young adult male produce? 7. Synthesizing fats is an efficient way for organ- C C H O isms to store energy. The catabolism of 1 g of fat yields about 38 kJ of energy, whereas the catabolism of 1 g of protein or carbohydrate yields about 17 kJ of energy. glycine a. How much carbohydrate would be needed H CH2 H2N 5. In saponification, the ester bonds of a triglyc- C C H O OH cysteine H2N OH Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. to store the same amount of energy as 10 g of fat? 3. In a peptide or protein that contains n amino acids, the number of possible amino acid sequences is An, where A is the number of different amino acids. a. How many amino acid sequences are possible for a polypeptide that contains 10 amino acids? b. How many different dipeptides can be made from the amino acids leucine (Leu) and valine (Val)? What are those dipeptides? 4. Write a balanced equation for the condensation reaction in which lauric acid, palmitic acid, and stearic acid combine with glycerol to form a triglyceride. CH3(CH2)10COOH lauric acid CH3(CH2)14COOH palmitic acid b. A cup (133 g) of ice cream contains about 32 g of carbohydrate, 4.8 g of protein, and 14 g of fat. How much energy is released when a cup of ice cream is fully catabolized? c. A person expends about 840 kJ per hour while walking at a moderate pace. How long would a person have to walk to expend all of the energy contained in a cup of ice cream? 8. A scientist analyzes a sample of DNA and finds that 21% of the nucleotide bases are A and 29% of the bases are C. What percentage of the bases are T and what percentage are G in the sample? CH3(CH2)16COOH stearic acid Supplemental Problems Chemistry: Matter and Change • Chapter 24 37 CHAPTER 24 9. It takes three consecutive nucleotides in a DNA molecule to code for one amino acid in a protein. If a single strand of DNA contains 747 nucleotides, how many amino acids would be in the protein that it codes for? 10. The DNA in a bacterial cell contains about 4.2 106 complementary base pairs. Each base pair has an average length of 3.4 1010 m. How long is the DNA in a bacterial cell? Assume that the DNA is stretched out straight rather than coiled. 11. One mole of ATP stores approximately 30.5 kJ of energy. This energy is released when ATP is hydrolyzed. a. Approximately 38 moles of ATP is produced for each mole of glucose that is catabolized in cellular respiration. How much energy is stored in ATP when 5.0 moles of glucose is catabolized in cellular respiration? SUPPLEMENTAL PROBLEMS 13. An average-sized woman produces about 1900 g of carbon dioxide per day. a. How many moles of glucose must be oxidized during cellular respiration to produce that much carbon dioxide? b. How much energy would be stored in ATP when that much glucose is oxidized? 14. Suppose the catabolism of a given amount of glucose produces 95 moles of ATP during cellular respiration. How many moles of ATP could be produced by the same amount of glucose during fermentation? 15. How many grams of glucose are needed to produce 102 g of ethanol during alcoholic fermentation? 16. Write a balanced equation for lactic acid fermentation. The formula for lactic acid is CH3CH(OH)COOH. b. Assume that 40% of this energy can be used Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. to drive anabolic reactions when ATP is hydrolyzed. The rest will be lost as heat. How much energy will be lost as heat if all of the ATP produced in part a is hydrolyzed? 12. A scientist performed an experiment to monitor photosynthesis by a plant. In the experiment, the plant produced 61 g of glucose. a. How many moles of glucose did the plant produce? b. How many moles of O2 did the plant produce? c. How many moles of CO2 were needed to produce that much glucose? d. What mass of water was needed to produce that much glucose? 38 Chemistry: Matter and Change • Chapter 24 Supplemental Problems CHAPTER 25 SUPPLEMENTAL PROBLEMS Nuclear Chemistry Write a complete nuclear equation for each of the following. 1. The decay of 53Fe 26 by beta emission. 2. The decay of 230 90 Th by alpha emission. 3. The decay of 37 18Ar by electron capture. 4. The decay of 38 19K by positron emission. 5. The decay of 93Tc 43 by gamma emission. Provide the missing term in each of the following equations. Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 6. 115B 42He 0 147N 1 45 7. 45 20Ca 1p 0 21Sc 8. 157N 0 188O 11p Answer the following questions about half-life. 13. The half-life of 115 51Sb is 32 minutes. How much of a 16.0-g sample of this isotope will remain at the end of 3.0 hours? 6 14. The half-life of 182 72Hf is 9.0 10 years. How much of a 1.0-g sample of this isotope will remain at the end of 40.0 million years? 15. The isotope strontium-90 is produced during the testing of nuclear weapons. If 100.0 mg of strontium-90 was released in the atmosphere in 1960, how much of the radioisotope remains 85 years later? The half life of strontium-90 is 29 years. 16. The radioisotope technetium-99 is often used as a radiotracer to detect disorders of the body. It has a half-life of 6.01 hours. If a patient received a 25.0-mg dose of this isotope during a medical procedure, how much would remain 48.0 hours after the dose was given? 1 99 1 9. 233 92U 0n 0 42Mo 30n 10. 4 0 206 82Pb 2He 11. 142 58Ce 1 0 142 59Pr 0n 4 1 12. 102 44Ru 2He 0 0n Supplemental Problems Chemistry: Matter and Change • Chapter 25 39 Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. SUPPLEMENTAL PROBLEMS Answer Key ANSWER KEY b. What are the variables shown? Chapter 2 1. A sample of aluminum is placed in a 25-mL graduated cylinder containing 10.0 mL of water. The level of water rises to 18.0 mL. Aluminum has a density of 2.7 g/mL. Calculate the mass of the sample. planet name and planet radius c. According to the graph, which has a larger radius, Neptune or Uranus? Uranus 22 g Solution: Volume 18.0 mL 10.0 mL 8.0 mL d. According to the graph, what is the radius of Saturn? mass volume density 8.0 mL 2.7 g/mL 22 g 60 000 km 2. Saturn is about 1 429 000 km from the Sun. How many meters is Saturn from the Sun? Write your answer in scientific notation. 1.429 109 m Solution: 1 429 000 1000 m/1 km 1 429 000 000 m 1.429 109 m e. Convert the radius of Saturn to meters. Write your answer in scientific notation. 6 107 m Solution: 60 000 km 1000 m/1 km 60 000 000 m 6 107 m 4. Look at the graph below. Then answer the 3. Look at the graph below. Then answer the questions. The Composition of Earth’s Crust Radii of Planets Magnesium 2% Sodium Potassium 2% 2% Calcium 4% 75 000 0 Planet Titanium 1% Other elements 1% Oxygen 46% Aluminum 8% Pluto Earth Mars 5000 Venus 15 000 Mercury 25 000 Iron 6% Neptune 35 000 Uranus 45 000 Saturn 55 000 Jupiter Radius (in km) 65 000 Silicon 28% a. What kind of graph is this? circle graph a. What kind of graph is this? bar graph b. According to the graph, which element is most abundant in Earth’s crust? oxygen 42 Chemistry: Matter and Change Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. questions. ANSWER KEY c. According to the graph, what percent of Earth’s crust is made up of titanium? Of calcium? 1% titanium; 4% calcium 8. Convert the following as indicated. a. Aluminum boils at 2467°C. What is aluminum’s boiling point in SI units? The SI unit of temperature is kelvin. Temperature in degrees Celsius (°C) 273 temperature in kelvins (K) 5. You place a 28.95-g piece of gold in a 10-mL graduated cylinder. The level of the water rises 1.50 mL. What is the density of gold? You know that silver has a density of 10.5 g/cm3. What mass of silver will raise the level of the water in the graduated cylinder 1.50 mL? 19.3 g/mL; 15.8 g Solution: mass density 28.95 g/1.50 mL 19.3 g/mL volume b. Bromine melts at 7.2°C. What is bromine’s melting point in kelvins? Temperature in degrees Celsius (°C) 273 temperature in kelvins (K) 7.2°C 273 266 K c. Chlorine melts at 172 K. What is chlorine’s mass volume density 1.50 mL 10.5 g/mL melting point in °C? 15.75 g 15.8 g Temperature in kelvins (K) 273 temperature in degrees Celsius (°C) 6. Convert 55 miles per hour to kilometers per hour. How many kilometers/second is 55 miles per hour? (Use: 1 mile 1.6 km) Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 2467°C 273 2740 K 88 km/h; 0.024 km/s Solution: (55 mi/h) (1.6 km /1 mi) 88 km/h 172 K 273 100.98°C d. What is 273 K in °C? Temperature in kelvins (K) 273 temperature in degrees Celsius (°C) 273 273 0°C (88 km/h) (1 h/60 min) (1 min/60 s) 0.024 km/s or 2.4 102 km/s 9. American cars use about 600 000 000 gallons 7. Convert the following data to scientific notation. a. 166 000 000 000 000 m2 1.66 1014 m2 b. 8847 m of oil per year. How many liters of oil do American cars use per year? Report your answer in scientific notation. (1 liter 0.908 quart; 1 gallon 4 quarts) 3 109 L Solution: (600 000 000 gallons) (4 quarts/1 gallon) (1 L/0.908 quart) 2 643 171 806 L 3 109 L 8.847 103 m c. 484 liters Solve the following problems. Express your answers in proper scientific notation. 4.84 102 liters 10. a. 5.3 1012 3.0 1011 5.6 1012 Supplemental Problems Answer Key Chemistry: Matter and Change 43 ANSWER KEY 2.9 106 c. 1.85 1016 9.25 1016 1.11 1017 d. 2.8 1022 82 1021 1.1 1023 e. 3.09 1020 9.1 1019 2.18 1020 f. 17 103 3 104 1.3 104 6 104 g. 4.80 1015 13 1013 4.67 1015 4.0 1016 c. (8.9 105) (3.0 103) 3.0 102 d. (1.6 1012) (8.01 103) 2.0 1014 e. (9.0 105) (3.0 103) 2.7 103 f. (2.4 103) (8.0 103) 3.0 105 g. (6.1 105) (3.01 102) 2.0 103 Solution: One way to solve each problem is shown below. Students may choose to solve the problems differently. Solution: One way to solve each problem is shown below. Students may choose to solve the problems differently. a. 5.3 1012 3.0 1011 5.3 1012 0.3 1012 5.6 1012 a. (4.0 105) (3.0 103) 12 108 1.2 109 b. 3.7 106 8.0 105 3.7 106 0.8 106 2.9 106 b. (5.0 1012) (8.05 103) 40.25 1015 4.0 1016 c. 1.85 1016 9.25 1016 11.1 1016 1.11 1017 c. (8.9 105) (3.0 103) 2.96 102 3.0 102 d. 2.8 1022 8.2 1021 2.8 1022 8.2 1022 11 1022 1.1 1023 d. (1.6 1012) (8.01 103) 0.2 1015 2.0 1014 e. 3.09 1020 9.1 1019 3.09 1020 0.91 1020 2.18 1020 e. (9.0 105) (3.0 103) 27 102 2.7 103 f. 17 103 3 104 1.3 104 1.7 104 3 104 1.3 104 6 104 f. (2.4 103) (8.0 103) 0.3 106 3.0 105 g. 4.80 1015 13 1013 4.80 1015 0.13 1015 4.67 1015 g. (6.1 105) (3.0 102) 2.03 103 2.0 103 11. a. (4.0 105) (3.0 103) 1.2 109 44 b. (5.0 1012) (8.05 103) Chemistry: Matter and Change 12. Mac measured the density of silver three times and obtained the following results: Trial 1: 10.6 g/cm3; Trial 2: 10.8 g/cm3; Trial 3: 9.6 g/cm3. Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. b. 3.7 106 8.0 105 ANSWER KEY Silver has a density of 10.5 g/cm3 a. Calculate Mac’s percent error for each trial. Trial 1: 0.95%; Trial 2: 2.86%; Trial 3: 8.6% b. Which trial had the greatest percent error? Trial 3 Solution: error a. percent error 100% accepted value Trial 1: percent error (10.6 g/cm3 10.5 g/cm3) 100% 0.952% 10.5 g/cm3 c. 1.056 mL 4 d. 12.90 s 4 e. 5000 dogs infinite, or unlimited f. 5.78910 103 g 6 Trial 2: percent error (10.8 g/cm3 10.5 g/cm3) 100% 2.86% 10.5 g/cm3 15. Round the number 31.257 592 to the requested Trial 3: percent error number of significant figures. 10.5 (9.6 100% 8.6% 10.5 g/cm3 a. 7 significant figures g/cm3 g/cm3) 31.257 59 Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 13. You calculate that your semester average in history is 97.5. When you get your report card, your average is 96. What was the percent error of your calculation? 1.6% Solution: b. 5 significant figures 31.258 c. 3 significant figures 31.3 error percent error 100% accepted value 97.5 96 percent error 100% 96 1.5625% 1.6% 14. Determine the number of significant figures in each measurement. a. 0.000 301 5 m 16. Complete the following calculations. Round off the answers to the correct number of significant figures. a. 2.30 m 3.65 m 0.55 m 4.62 m3 b. 103.8 m 31 s 4 3.3 m/s b. 0.121 012 L c. 26.0 cm 2.1 cm 6 55 cm2 Supplemental Problems Answer Key Chemistry: Matter and Change 45 ANSWER KEY Chapter 3 1. An 18-g sample of element A combines completely with a 4-g sample of element B to form the compound AB. What is the mass of the compound formed? There is 32 g of B in AB2. Compound AB3 contains three times as much element B as does compound AB. Therefore, 3 16 g 48 g. There is 48 g of B in AB3. 5. During a chemical reaction, 2.445 g of carbon Massreactants Massproducts reacts with 3.257 g of oxygen to form carbon monoxide gas. How many grams of carbon monoxide are formed in this reaction? MassA MassB MassAB MassAB 18 g 4 g 22 g Massreactants Massproducts elements when it is heated. The mass of each component element is listed in the table below. What was the mass of the substance before it was heated? Component Mass (g) A 39.10 B 54.94 C 64.00 Massreactants Massproducts 39.10 54.94 64.00 158.04 g 3. Silver iodide powder has been used as an anti- septic and as an agent to seed clouds for rain. Silver iodide is 45.9% silver by mass. If you separate a 50-g sample of silver iodide into its elements, silver and iodine, how much silver would you have? From the conservation of mass, the mass of silver recovered is equal to the mass of silver in the initial silver iodide sample. The amount of silver recovered would be 50.0 g 45.9% 50.0 0.459 22.95 g 23 g. 4. If 5 g of element A combines with 16 g of element B to form compound AB, how many grams of B are needed to form compound AB2? How many grams of B are needed to form AB3? Masscarbon Massoxygen Masscarbon monoxide 2.445 g 3.257 g 5.702 g 6. Ibuprofen has the chemical formula C13H18O2. It is 75.69% carbon, 8.80% hydrogen, and 15.51% oxygen. How many mg of carbon does a 200-mg tablet of ibuprofen contain? Mass percentage of an element (%) Mass of element 100% Mass of compound Masscarbon 100% Mass percentagecarbon Masscompound Masscarbon 75.69% carbon 100% 200 mg 200 mg 75.69% carbon Masscarbon 100% Masscarbon in the tablet 151.38 mg 7. During a chemical reaction, 4.032 g of hydrogen combined with oxygen to form 36.032 g of water. How many grams of oxygen reacted? Massreactants Massproducts Masshydrogen Massoxygen Masswater 4.032 g Massoxygen 36.032 g Massoxygen 36.032 g 4.032 g 32 g Compound AB2 contains twice as much element B as does compound AB. Therefore, 2 6 g 32 g. 46 Chemistry: Matter and Change Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 2. A substance breaks down into three component ANSWER KEY 8. Nitrogen and oxygen combine to form different compounds, as shown below. Mass ratiocompound I 0.292 1.67 Mass ratiocompound II 0.175 Compound Chemical Formula Mass N/1 g O Nitric oxide NO 1.76 g Nitrogen dioxide NO2 0.88 g Nitrous oxide NO4 0.44 g What is the ratio of the masses of nitrogen in each of the following? NO2/NO4 0.88 g 2 0.44 g NO/NO4 1.76 g 4 0.44 g These data are not consistent with the law of multiple proportions. The law of multiple proportions states that the different masses of Y that combine with a fixed mass of X can be expressed as a ratio of small whole numbers, and 1.67 is not a whole number. 11. Fluorine and xenon combine to form two different compounds. In one compound, 0.853 g of fluorine combines with 1.472 g of xenon. In the other compound, 0.624 g of fluorine combines with 2.16 g of xenon. Do these data support the law of multiple proportions? Show your work. NO/NO2 First, find the mass ratio for each compound. 1.76 g 2 0.88 g MassF 0.853 g 0.579 Compound I: 1.472 g MassXe 9. Carbon and oxygen combine to form carbon Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. Then, compare the two mass ratios. monoxide (CO) and carbon dioxide (CO2). The masses of oxygen that combine with 12 g of carbon to form these two compounds are 16 g and 32 g, respectively. What is the ratio of the masses of oxygen in CO2/CO? Mass ratiocarbon dioxide 32 g 2 16 g Mass ratiocarbon monoxide MassF 0.624 g 0.289 Compound II: 2.16 g MassXe Then, compare the two mass ratios. Mass ratiocompound I 0.579 2.00 Mass ratiocompound II 0.289 These data are consistent with the law of multiple proportions. The law of multiple proportions states that the different masses of Y that combine with a fixed mass of X can be expressed as a ratio of small whole numbers, and 2 is a whole number. 10. Phosphorus and chlorine combine to form two different compounds. In one compound, 3.88 g of phosphorus combines with 13.28 g of chlorine. In the other compound, 1.32 g of phosphorus combines with 7.56 g of chlorine. Do these data support the law of multiple proportions? Show your work. First, find the mass ratio for each compound. 12. Ferric chloride is 34.4% iron and 65.6% chlorine by mass. A chemist analyzes three compounds that contain iron and chlorine. Her results are summarized in the data table below. Which of these compounds is likely to be ferric chloride? Explain your answer. Compound Mass of the Sample (g) Mass of Fe (g) Mass of Cl (g) MassP 3.88 g 0.292 Compound I: 13.28 g MassCl I 25 9.3 15.7 II 25 8.6 16.4 MassP 1.32 g 0.175 Compound II: 7.56 g MassCl III 27 9.3 17.7 Supplemental Problems Answer Key Chemistry: Matter and Change 47 ANSWER KEY Massiron Mass percentageiron 100% Masscompound I 9.3 g 100% 25 g 37.2% Massiron 100% Mass percentageiron Masscompound II 8.6 g 100% 34.4% 25 g Mass percentageiron Massiron 100% Masscompound III 9.3 g 100% 34.4% 27 g Then, find the percent of chlorine by mass in each compound. Masschlorine 100% Mass percentagechlorine Masscompound I 2.02 g 100% 1.20% 168.02 g Masscarbon Mass percentagecarbon 100% Massbaking soda 24.02 g 100% 14.30% 168.02 g Massoxygen Mass percentageoxygen 100% Massbaking soda 96 g 100% 57.14% 168.02 g 14. The chemical formula for chalk is CaCO3. A100-g sample of chalk contains 40 g of calcium, 12 g of carbon, and 48 g of oxygen. What is the mass percentage of each element in chalk? What would be the mass of calcium in 200 g of chalk? 15.7 g 100% 62.8% 25 g Masscalcium Mass percentagecalcium 100% Masschalk Masschlorine Mass percentagechlorine 100% Masscompound II 40 g 100% 40% 100 g 16.4 g 100% 65.6% 25 g Masscarbon Mass percentagecarbon 100% Masschalk Masschlorine Mass percentagechlorine 100% Masscompound III 17.7 g 100% 65.6% 27 g Compounds II and III have the same composition as ferric chloride. 13. The chemical formula for baking soda is NaHCO3. A 168.02-g sample of baking soda contains 45.98 g of sodium, 2.02 g of hydrogen, 24.02 g of carbon, and 96 g of oxygen. What is the mass percentage of each element in baking soda? Masssodium Mass percentagesodium 100% Massbaking soda 45.98 g 100% 27.36% 168.02 g 48 Masshydrogen Mass percentagehydrogen 100% Massbaking soda Chemistry: Matter and Change 12 g 100% 12% 100 g Massoxygen Mass percentageoxygen 100% Masschalk 48 g 100% 48% 100 g Masscalcium Mass percentagecalcium 100% Masschalk (40%)(200 g) Masscalcium 80 g 100% 15. A 17-g sample of ammonia, NH3, contains 3 g of hydrogen. What percentage of ammonia is hydrogen? How many grams of nitrogen does the sample contain? Masshydrogen Mass percentagehydrogen 100% Massammonia Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. First, find the percent of iron by mass in each compound. ANSWER KEY c. 23 11Na 3g 100% 18% 17 g 11 protons, 11 electrons, 12 neutrons (23 11 12) Massreactants Massproducts Massnitrogen Masshydrogen Massammonia Massnitrogen Massammonia Masshydrogen 3. Name each isotope, and write it in symbolic 14 g 17 g 3 g notation. a. atomic number 26; mass number 56 Chapter 4 iron-56; 1. Use the periodic table to complete the 56Fe 26 b. atomic number 29; mass number 64 following table. Atomic number number of protons number of electrons copper-64; 64Cu 29 c. atomic number 17; mass number 37 Atomic Number Protons Electrons a. Li 3 3 3 b. Fr 87 87 87 c. Np 93 93 93 d. Hg 80 80 80 e. Tl 81 81 81 f. Re 75 75 75 g. B 5 5 5 Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. Element chlorine-37; 37Cl 17 4. How many protons, electrons, and neutrons are in each of the following isotopes? Atomic number number of protons number of electrons Number of neutrons mass number atomic number a. uranium-235 2. Give the number of protons, electrons, and neutrons in each of the following atoms. Atomic number number of protons number of electrons Number of neutrons mass number atomic number a. 108 47Au 47 protons, 47 electrons, 61 neutrons (108 47 61) 92 protons, 92 electrons, 143 neutrons (235 92 143) b. hydrogen-3 1 proton, 1 electron, 2 neutrons (3 1 2) c. silicon-29 14 protons, 14 electrons, 15 neutrons (29 14 15) b. 40 20Ca 20 protons, 20 electrons, 20 neutrons (40 20 20) Supplemental Problems Answer Key Chemistry: Matter and Change 49 ANSWER KEY 5. How many neutrons does europium-151 have? What is the isotope’s mass number? d. Ti with 26 neutrons 26 neutrons 22 protons 48 Number of neutrons mass number atomic number 151 63 88 neutrons 9. Give the atomic number of each isotope. The mass number is 151. From the periodic table, a. magnesium-25 6. How many more neutrons does thorium-230 have than protons? How many electrons does thorium-230 have? Number of neutrons = mass number – atomic number 12 b. bromine-79 35 230 90 140 neutrons Therefore, thorium-230 has 50 more neutrons than it does protons. Atomic number number of protons number of electrons Therefore, thorium-230 has 90 electrons. 7. Show that the mass number and the number of protons are conserved in the following nuclear 230 4 equation: 234 92U 0 90 Th 2He. Nuclear equation: 234U 92 0 230 Th 90 42He Mass number: 234 0 230 4 Atomic number: 92 0 90 2 c. antimony-121 51 10. Neon has two isotopes: neon-10 and neon-12. a. Which isotope has the greater mass? neon-12 b. Which has more neutrons? neon-12 c. Which has more protons? They have an equal number of protons. 8. Give the mass number of each isotope. Number of neutrons number of protons mass number d. Which has more electrons? They have an equal number of electrons. a. Be with 5 neutrons 5 neutrons 4 protons 9 b. Ga with 39 neutrons 39 neutrons 31 protons 70 c. Si with 16 neutrons 11. Use the table below to calculate the atomic mass of element X. Then use the periodic table to identify the element. Show all your work. Isotope Mass (amu) Percent Abundance 16X 15.995 99.762 17X 16.999 0.038 18X 17.999 0.20 16 neutrons 14 protons 30 50 Chemistry: Matter and Change Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. Difference between the number of protons and the number of neutrons 140 90 50 ANSWER KEY Mass contribution (mass)(percent abundance) 16X: (15.995 amu)(99.762%) 15.957 amu 17X: (16.999 amu)(0.038%) 0.0065 amu 18X: (17.999 amu)(0.20%) 0.036 amu The pie graph shows the relative abundance of each isotope. Isotope 2 0.27% Atomic mass of X 15.957 amu 0.0065 amu 0.036 amu 16.000 amu Isotope 3 9.22% The element is oxygen. 12. Magnesium has three isotopes. Magnesium-24 has a percent abundance of 78.99%. Magnesium-26 has a percent abundance of 11.01%. What is the percent abundance of magnesium-25? Assume that there are no other magnesium isotopes. Isotope 1 90.51% All the percentages should add up to 100%. Therefore: Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 100% (percent abundance of magnesium-24) (percent abundance of magnesium-25) (percent abundance of magnesium-26) a. Calculate the atomic mass of the element. Mass contribution (mass)(percent abundance) 100% 78.99% (percent abundance of magnesium-25) 11.01% Isotope 1: (19.992 amu)(90.51%) 18.10 amu Percent abundance of magnesium-25 100% (78.99% 11.01%) 10.00% Isotope 3: (21.991 amu)(9.22%) 2.03 amu Isotope 2: (20.994 amu)(0.27%) 0.057 amu Atomic mass 18.10 amu 0.057 amu 2.03 amu 20.19 amu 13. Calculate the atomic mass of iridium. Iridium has two isotopes. Iridium-191 has a mass of 191.0 amu and a percent abundance of 37.58%. Iridium-191 has a mass of 193.0 amu and a percent abundance of 62.42%. Show all your work. Mass contribution (mass)(percent abundance) Ir-191: (191.0 amu)(37.58%) 71.78 amu Ir-193: (193.0 amu)(62.42%) 120.5 amu Atomic mass of Ir 71.78 amu 120.5 amu 192.3 amu 14. An element has three naturally occurring b. Identify the element, using the periodic table. The element is neon. 15. An element has three naturally occurring isotopes. Information about each isotope is summarized below. Isotope Mass (amu) Percent Abundance Isotope 1 23.985 78.10 Isotope 2 24.946 10.13 Isotope 3 25.983 11.17 isotopes. Isotope 1 has a mass of 19.992 amu. Isotope 2 has a mass of 20.994 amu. Isotope 3 has a mass of 21.991 amu. Supplemental Problems Answer Key Chemistry: Matter and Change 51 ANSWER KEY a. Find the atomic mass of this element. Show c. Carbon-14 emits a beta particle as it decays. all your work. What atom does carbon-14 decay to? Mass contribution (mass)(percent abundance) If carbon-14 emits a beta particle, then it must become nitrogen-14 (1 x 6; thus, x 7, which is the atomic number of nitrogen). Isotope 1: (23.985 amu)(78.70%) 18.88 amu Isotope 2: (24.946 amu)(10.13%) 2.531 amu Isotope 3: (25.983 amu)(11.17%) 2.902 amu Atomic mass of element 18.88 amu 2.527 amu 2.902 amu 24.31 amu b. Identify the element, using the periodic d. Write an equation to represent the decay of carbon-14. The equation that shows this change is 14C 0 14N 0. 1 6 7 table. c. Write each isotope in symbolic notation. 24Mg, 25Mg, 26Mg 12 12 12 16. The isotope carbon-14 can be used to determine the ages of objects that were once living, such as wood, bones, and fossils. While alive, living things take in all the isotopes of carbon, including carbon-14. Carbon-14 undergoes radioactive decay continuously. After an organism dies, the carbon-14 in its body continues to decay. However, its body no longer takes in new carbon-14. Thus, by measuring how much carbon-14 a once-living object contains and comparing it with the amount of carbon-14 in a currently living thing, you can determine the age of the object. a. In terms of subatomic structure, how does 1. Orange light has a frequency of 4.8 1014 s1. What is the energy of one quantum of orange light? Ephoton h (6.626 1034 Js)(4.8 1014 s1) 3.18048 1019 J 3.2 1019 J 2. Which is greater, the energy of one photon of orange light or the energy of one quantum of radiation having a wavelength of 3.36 109m? Calculate the frequency: c , c therefore, (3.00 108 m/s)/(3.36 109 m) 8.93 1016 s1 Calculate the energy of one quantum: Ephoton h carbon-14 differ from carbon-12 and carbon-13? Ephoton (6.626 1034 Js)(8.93 1016 s1) 5.92 1017 J Carbon-14 has 8 neutrons, carbon-12 has 6 neutrons, and carbon-13 has 7 neutrons. Carbon-14 has a larger atomic mass than the other two isotopes have. From problem 1, orange light has an energy of 3.2 1019 J. Therefore, a quantum of radiation with a wavelength of 3.36 109 m has more energy than orange light does. b. How is carbon-14 like carbon-12 and carbon-13? All three isotopes have 6 protons and 6 electrons. They all show the same physical and chemical properties of the element carbon. 52 Chapter 5 Chemistry: Matter and Change 3. Use the relationships E h and c to write E in terms of h, c, and . c From c , . hc E h Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. The element is magnesium. ANSWER KEY 4. A radio station emits radiation at a wavelength 7. Which element has the ground-state electron configuration [Kr]5s24d105p4? of 2.90 m. What is the station’s frequency in megahertz? tellurium c c , therefore, 3.00 108 m/s 1.034 108 s1 2.90 m 8. Which element has the ground-state electron configuration [Ar]4s23d10? 1.034 108 s1 103.4 106 s1 103.4 megahertz zinc You can tune in at 103.4 FM. 9. Write electron-dot structures for the following atoms. 5. Record the frequency of your favorite radio sta- a. [Ne]3s23p3 tion. What is the wavelength of the radiation emitted from the station? •• •P• • Answers will vary. Students should use c , where c 3.00 108 m/s, to calculate the wavelength of their favorite radio station. b. [Ar]4s23d3 •V• 6. List the sequence in which the following c. potassium Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. orbitals fill up: 1s, 2s, 3s, 4s, 5s, 6s, 7s, 2p, 3p, 4p, 5p, 6p, 7p, 3d, 4d, 5d, 6d, 4f, 5f. K• The correct order is as follows: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p 10. Complete the following table. Orbitals Element Electron Configuration Symbol 1s 2s 2px 2py 2pz a. Nitrogen N )( )( ) ) ) 1s22s22p3 b. Fluorine F )( )( )( )( ) 1s22s22p5 c. Carbon C )( )( ) ) d. Lithium Li )( ) Supplemental Problems Answer Key 1s22s22p2 1s22s1 Chemistry: Matter and Change 53 ANSWER KEY 7p 6d 5f 7s 6p 5d 4f 6s 5p 4d 5s 7s 4p 5s 4s 3p 3s 2p 2s 1s 3d 7p 6d 5f 6p 5d 4f 6s 5p )( 4s () 3s )( 2s ) ) ) 4p 4d )( )( )( )( )( 3d () () () 3p )( )()( 2p )( 1s 12. Use the figure below to answer the following questions. fourth energy level. Electrons in the highest energy level are the least attracted to the nucleus because they are the most distant. 13. What is the ground-state electron configuration 2e 8e 8e 2e of each of the following atoms? Use noble-gas notation. a. selenium [Ar]4s23d104p4 b. krypton a. How many valence electrons does an atom [Kr] or [Ar]4s23d104p6 of this element have? 2 c. chlorine [Ne]3s23p5 b. What is the atom’s electron-dot structure? • Ca• 14. What is the highest energy level (n) that is c. If enough energy was added to remove an electron, from which energy level would the electron be removed? Explain your answer. occupied in the following elements? a. He n1 The first electron to leave the atom would be one in the highest energy level, which is the 54 Chemistry: Matter and Change Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. Increasing Energy 11. Complete the orbital diagram for arsenic. ANSWER KEY b. Ca n4 c. Sn 3. Categorize each of the elements in problem 2 as a representative element or a transition element. All of the elements are representative elements. n5 4. Write the electron configuration of the element 15. Write the electron configuration for each element described below and identify the element. a. an element that contains 8 electrons fitting each of the following descriptions. Use noble-gas notations. a. Group 8A element in the third period [Ne]3s23p6 1s22s22p4 b. Group 4A element in the fourth period b. an element that contains 14 electrons [Ar]4s23d104p2 1s22s22p63s23p2 The element is silicon. c. Halogen in the second period [He]2s22p5 Chapter 6 Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. For questions 1–5, do not use the periodic table. d. Group 1A element in the fourth period [Ar]4s1 1. Write the electron configurations for the elements in periods 2–4 of group 2A. period 2, group 2A: 1s22s2 period 3, group 2A: 1s22s22p63s2 period 4, group 2A: 1s22s22p63s23p64s2 5. What are the noble-gas notations of all the elements with the following valence electron configurations? a. s2 1s2, [He]2s2, [Ne]3s2, [Ar]4s2, [Kr]5s2, [Xe]6s2, [Rn]7s2 2. Determine the group, period, and block of the elements with the following electron configurations. a. [He]2s22p4 b. s2p1 [He]2s22p1, [Ne]3s23p1, [Ar]4s23d104p1, [Kr]5s24d105p1, [Xe]6s24f145d106p1 group 6A, period 2, p-block b. [Xe]6s1 group 1A, period 6, s-block For questions 6–9, do not use Figure 6-12, 6-15, or 6-20. 6. Rank the following atoms in order of decreasing radii. c. [Ar]4s23d104p2 group 4A, period 4, p-block Supplemental Problems Answer Key a. Al, Na, P, S Na, Al, P, S Chemistry: Matter and Change 55 ANSWER KEY b. Al, Ga, In b. K, Sc, Ca In, Ga, Al Sc, Ca, K c. As, Ge, Ga c. As, Sn, S Ga, Ge, As S, As, Sn d. Br, Ca, Cl, K K, Ca, Br, Cl Chapter 10 7. Rank the following ions in order of decreasing radii. a. Br, Cl, F Balance the following chemical equations. 1. SnS2(s) O2(g) 0 SnO2(s) SO2(g) SnS2(s) 3O2(g) 0 SnO2(s) 2SO2(g) Br, Cl, F 2. C2H6(g) O2(g) 0 CO2(g) H2O(g) Ca2, Ca2, Mg2, Mg2 2C2H6(g) 7O2(g) 0 4CO2(g) 6H2O(g) Be2 c. Ca2, Ga3, K K, Ca2, Ga3 8. Rank the following particles in order of decreasing radii. 3. Al(s) HCl(aq) 0 AlCl3(aq) H2(g) 2Al(s) 6HCl(aq) 0 2AlCl3(aq) 3H2(g) 4. CoCO3(s) 0 CoO(s) CO2(g) CoCO3(s) 0 CoO(s) CO2(g) a. I, I I, I b. K, K K, K c. Al, Al3 Al, Al3 9. Rank the following atoms in order of decreasing electronegativity. Write a balanced equation for each of the following reactions, substituting symbols and formulas for names. Include the state of each reactant and product. Then identify the reaction type for each. If more than one reaction type applies, list all that apply. 5. When aluminum nitrate and sodium hydroxide solutions are mixed, solid aluminum hydroxide forms. The other product is sodium nitrate. Al(NO3)3(aq) 3NaOH(aq) 0 Al(OH)3(s) 3NaNO3(aq) double-replacement a. Na, Li, K Li, Na, K 56 Chemistry: Matter and Change Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. b. Be2, ANSWER KEY 6. When magnesium is heated in the presence of nitrogen gas, solid magnesium nitride forms. 4Mg(s) 3N2(g) 0 2Mg2N3(s) synthesis 7. When solid copper(II) oxide and hydrogen Predict the products in each of the following reactions. If no reaction occurs, write NR. You may use Figure 10-10 for the relative activities of common metals and halogens. 12. Rb(s) CaCl2(aq) RbCl(aq) Ca(s) react, metallic copper and water form. CuO(s) H2(g) 0 Cu(s) H2O(l) single-replacement 8. Most industrial production of metallic sodium is accomplished by passing an electric current through molten sodium chloride. Chlorine gas also is produced. 2NaCl(l) 0 2Na(s) Cl2(g) decomposition 9. Liquid pentane (C5H12) burns, producing water vapor and carbon dioxide. Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. C5H12(l) 8O2(g) 0 6H2O(g) 5CO2(g) combustion 10. When chlorine gas is passed through a potassium bromide solution, bromine forms in a potassium chloride solution. Cl2(g) 2KBr(aq) 0 Br2(l) 2KCl(aq) single-replacement 11. Magnesium burns in air to form magnesium oxide. 2Mg(s) O2(g) 0 2MgO(s) synthesis, combustion 13. Pt(s) MnBr2(aq) NR 14. F2(g) NaI(aq) NaF(aq) I2(s) 15. Zn(s) AgNO3(aq) Ag(s) Zn(NO3)2(aq) Write a complete ionic equation and a net ionic equation for each of the following doubledisplacement reactions. 16. Ba(NO3)2(aq) H2SO4(aq) 0 BaSO4(s) 2HNO3(aq) Ba2(aq) 2NO3(aq) 2H(aq) SO42(aq) 0 BaSO4(s) 2H(aq) 2NO3(aq) Ba2(aq) SO42(aq) 0 BaSO4(s) 17. FeCl3(aq) (NH4)3PO4(aq) 0 FePO4(s) 3NH4Cl(aq) Fe3(aq) 3Cl(aq) 3NH4(aq) PO43(aq) 0 FePO4(s) 3NH4(aq) 3Cl(aq) Fe3(aq) PO43(aq) 0 FePO4(s) 18. KCl(aq) AgC2H3O2(aq) 0 AgCl(s) KC2H3O2(aq) K(aq) Cl(aq) Ag(aq) C2H3O2(aq) 0 AgCl(s) K(aq) C2H3O2(aq) Cl(aq) Ag(aq) 0 AgCl(s) Supplemental Problems Answer Key Chemistry: Matter and Change 57 ANSWER KEY c. 2.66 1022 formula units of potassium Chapter 11 1. Identify and calculate the number of representa- iodide tive particles in each of the following quantities. 2.66 1022 formula units KI a. 2.15 moles of gold 1 mol KI 6.02 1023 formula units KI 2.15 mol Au 6.02 1023 atoms Au 1 mol Au 0.0442 mol KI 1.29 1024 atoms Au 3. Determine the mass in grams of each of the b. 0.151 mole of nitrogen oxide following quantities. a. 1.24 moles of beryllium 6.02 1023 molecules NO 0.151 mol NO 1 mol NO 9.09 1022 molecules NO 1.24 mol Be 9.01 g Be 1 mol Be 11.2 g Be c. 11.5 moles of potassium bromide b. 3.35 moles of calcium 6.92 1024 formula units KBr 2. Calculate the number of moles of the substance 3.35 mol Ca 134 g Ca c. 0.155 mole of sulfur that contains the following number of representative particles. 0.155 mol S a. 8.92 1023 atoms of barium 4.97 g S 8.92 1023 atoms Ba 40.08 g Ca 1 mol Ca 32.07 g S 1 mol S 1 mol Ba 6.02 1023 atoms Ba 1.48 mol Ba 4. Calculate the number of moles in each of the following quantities. b. 5.50 1025 molecules of carbon monoxide a. 6.35 g lithium 1 mol Li 6.94 g Li 5.50 1025 molecules CO 6.35 g Li 1 mol CO 6.02 1023 molecules CO 0.915 mol Li 91.4 mol CO b. 346 g zinc 346 g Zn 1 mol Zn 65.39 g Zn 5.29 mol Zn 58 Chemistry: Matter and Change Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 6.02 1023 formula units KBr 11.5 mol KBr 1 mol KBr ANSWER KEY b. 1.50 1020 atoms of cadmium c. 115 g nickel 115 g Ni 1 mol Ni 58.69 g Ni 1.50 1020 atoms Cd 1.96 mol Ni 1 mol Cd 6.02 1023 atoms Cd 112.41 g Cd 1 mol Cd 0.0280 g Cd 5. How many atoms are in the following samples? a. 1.24 g cobalt 1 mol Co 1.24 g Co 58.93 g Co 6.02 1023 atoms Co 1 mol Co c. 1.33 1024 atoms of argon 1.33 1024 atoms Ar 1 mol Ar 6.02 1023 atoms Ar 39.95 g Ar 1 mol Ar 88.3 g Ar 1.27 1022 atoms Co The quantity 4.16 1023 atoms of radium has the greatest mass. b. 0.575 g cesium 0.575 g Ce 1 mol Ce 132.91 g Ce 6.02 1023 atoms Ce 1 mol Ce following quantities. a. atoms of each element in 3.35 moles of Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 2.60 1021 atoms Ce aspirin (C9H8O4) c. 65.6 g silicon 65.6 g Si 7. Calculate the number of moles in each of the 1 mol Si 28.09 g Si 6.02 1023 atoms Si 1 mol Si 1.41 1024 atoms Si 3.35 mol C9H8O4 9 mol C 30.2 mol C 1 mol C9H8O4 3.35 mol C9H8O4 8 mol H 26.8 mol H 1 mol C9H8O4 3.35 mol C9H8O4 4 mol O 13.4 mol O 1 mol C9H8O4 b. positive and negative ions in 1.75 moles of calcium fluoride (CaF2) 1.75 mol CaF2 1 mol Ca2 1.75 mol Ca2 1 mol CaF2 1.75 mol CaF2 2 mol F 3.50 mol F 1 mol CaF2 6. Which quantity has the greatest mass? a. 4.16 1023 atoms of radium 4.16 1023 atoms Ra 1 mol Ra 6.02 1023 atoms Ra 226 g Ra 1 mol Ra 156 g Ra Supplemental Problems Answer Key Chemistry: Matter and Change 59 ANSWER KEY 8. Determine the molar mass of each of the 9. What is the mass in grams of each of the following compounds. following quantities? a. formic acid (CH2O2) a. 2.53 moles of lead(II) nitrate (Pb(NO3)2) 12.01 g C 1 mol C 1 mol C 1 mol CH2O2 12.01 g C 1 mol CH2O2 1.01 g H 2 mol H 1 mol H 1 mol CH2O2 2.02 g H 1 mol CH2O2 16.00 g O 2 mol O 1 mol O 1 mol CH2O2 32.00 g O (12.01 g 2.02 g 32.00 g ) 46.03 g The molar mass of formic acid is 46.03 g/mol. b. ammonium dichromate ((NH4)2Cr2O7) 1 mol (NH4)2Cr2O7 2 mol N 1 mol (NH4)2Cr2O7 14.01 g N 28.02 g N 1 mol N 1 mol (NH4)2Cr2O7 207.2 g Pb 207.2 g Pb 1 mol Pb 2 mol N 1 mol Pb(NO3)2 1 mol Pb(NO3)2 14.01 g N 28.02 g N 1 mol N 6 mol O 1 mol Pb(NO3)2 1 mol Pb(NO3)2 16.00 g O 96.00 g O 1 mol O (207.2 g 28.02 g 96.00 g) 331.2 g The molar mass of lead(II) nitrate is 331.2 g/mol. 2.53 mol Pb(NO3)2 838 g 331.2 g Pb(NO3)2 1 mol Pb(NO3)2 The mass of 2.53 moles of lead(II) nitrate is 838 g. b. 4.62 moles of magnesium bromide (MgBr2) 2 mol Cr 1 mol (NH4)2Cr2O7 52.00 g Cr 104.0 g Cr 1 mol N 1 mol (NH4)2Cr2O7 1 mol Pb 1 mol Pb(NO3)2 8 mol H 1 mol (NH4)2Cr2O7 1.01 g H 8.08 g H 1 mol H 1 mol (NH4)2Cr2O7 1 mol Pb(NO3)2 7 mol O 1 mol (NH4)2Cr2O7 16.00 g O 112.0 g O 1 mol O 1 mol MgBr2 1 mol Mg 1 mol MgBr2 24.31 g Mg 24.31 g Mg 1 mol Mg 1 mol MgBr2 2 mol Br 1 mol MgBr2 79.90 g Br 159.80 g Br 1 mol Br (24.31 g 159.80 g) 184.11 g (28.02 g 8.08 g 104.00 g 112.0 g) 252.1 g The molar mass of magnesium bromide is 184.11 g/mol. The molar mass of ammonium dichromate is 252.1 g/mol. 4.62 mol MgBr2 851 g 184.11 g MgBr2 1 mol MgBr2 The mass of 4.62 moles of magnesium bromide is 851 g. 60 Chemistry: Matter and Change Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 1 mol CH2O2 ANSWER KEY 10. Calculate the number of moles in each of the following samples. the following compounds. a. 3.75 g calcium carbide (CaC2) a. manganese oxide (MnO) 1 mol CaC2 24.02 g C 1 mol CaC2 40.08 g Ca 2 mol C 12.01 g C 1 mol C 1 mol CaC2 1 mol MnO 1 mol Ca 40.08 g Ca 1 mol Ca 1 mol CaC2 1 mol MnO 1 mol Mn 54.94 g Mn 1 mol Mn 1 mol MnO 54.94 g Mn 1 mol O 16.00 g O 1 mol O 1 mol MnO 16.00 g O (24.02 g 40.08 g) 64.10 g (54.94 g 16.00 g) 70.94 g The molar mass of calcium carbide is 64.10 g/mol. The molar mass of manganese oxide is 70.94 g/mol. 54.94 g Mn mass percent Mn 100 70.94 g MnO 77.45% Mn 16.00 g O mass percent O 100 70.94 g MnO 22.55% O 1 mol CaC2 64.10 g CaC2 0.0585 mol CaC2 3.75 g CaC2 b. 245 g aluminum nitrite (Al(NO2)3) 1 mol Al(NO2)3 26.98 g Al 26.98 g Al 1 mol Al 1 mol Al 1 mol Al(NO2)3 b. propanol (C3H8O) 14.01 g N 3 mol N 1 mol N 1 mol Al(NO2)3 1 mol C3H8O 16.00 g O 6 mol O 1 mol Al(NO2)3 1 mol O 1 mol Al(NO2)3 96.00 g O 1 mol C3H8O 1 mol Al(NO2)3 42.03 g N Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 11. Determine the percent composition of each of (26.98 g 42.03 g 96.00 g) 165.01 g The molar mass of aluminum nitrite is 165.01 g/mol. 1 mol Al(NO2)3 165.01 g Al(NO2)3 1.48 mol Al(NO2)3 245 g Al(NO2)3 36.03 g C 8.08 g H 1 mol C3H8O 16.00 g O 12.01 g C 3 mol C 1 mol C 1 mol C3H8O 1.01 g H 8 mol H 1 mol H 1 mol C3H8O 16.00 g O 1 mol O 1 mol O 1 mol C3H8O (36.03 g 8.08 g 16.00 g) 60.11 g The molar mass of propanol is 60.11 g/mol. mass percent C 59.94% C mass percent H 13.44% H mass percent O 26.62% O Supplemental Problems Answer Key 36.03 g C 100 60.11 g C3H8O 8.08 g H 100 60.11 g C3H8O 16.00 g O 100 60.11 g C3H8O Chemistry: Matter and Change 61 ANSWER KEY c. calcium phosphate (Ca3(PO4)2) 1 mol Ca3(PO4)2 3 mol Ca 1 mol Ca3(PO4)2 40.08 g Ca 120.24 g Ca 1 mol Ca 2 mol P 1 mol Ca3(PO4)2 1 mol Ca3(PO4)2 30.97 g P 61.94 g P 1 mol P 8 mol O 1 mol Ca3(PO4)2 1 mol Ca3(PO4)2 16.00 g O 128.00 g O 1 mol O (120.24 g 61.94 g 128.00 g) 310.18 g The molar mass of calcium phosphate is 310.18 g/mol. 120.24 g Ca mass percent Ca 100 310.18 g Ca3(PO4)2 38.76% Ca 61.94 g P mass percent P 100 310.18 g Ca3(PO4)2 19.97% P 128.00 g O mass percent O 100 310.18 g Ca3(PO4)2 41.27% O b. 80.68% mercury, 12.87% oxygen, and 6.45% sulfur Mass of Hg 80.68 g Hg Mass of O 12.87 g O Mass of S 6.45 g S 80.68 g Hg 12.87 g O 6.45 g S 1 mol Hg 0.4022 mol Hg 200.59 g Hg 1 mol O 0.8044 mol O 16.00 g O 1 mol S 0.2011 mol S 32.07 g S 0.4022 mol Hg 2.000 mol Hg 2 mol Hg 0.2011 mol S 1.000 mol S 1 mol S 0.8044 mol O 4.000 mol O 4 mol O 0.2011 mol S 1.000 mol S 1 mol S 0.2011 mol S 1.000 mol S 1 mol S 0.2011 mol S 1.000 mol S 1 mol S 2 mol Hg : 4 mol O : 1 mol S The empirical formula is Hg2SO4. 13. A 48.30-g sample of an aluminum-iodine com- 12. Determine the empirical formula for a 100.00-g sample of a compound having the following percent composition. 48.30 g compound 3.20 g Al 45.10 g I 3.20 g Al 1 mol Al 0.1186 mol Al 26.98 g Al 45.10 g I 1 mol I 0.3554 mol I 126.90 g I a. 94.07% sulfur and 5.93% hydrogen In a 100.00-g sample: mass of S 94.07 g mass of H 5.93 g 94.07 g S 1 mol S 2.93 mol S 32.07 g S 5.93 g H 1 mol H 5.87 mol H 1.01 g H 5.87 mol H 2.00 mol H 2 mol H 2.93 mol S 1.00 mol S 1 mol S 0.3554 mol I 2.997 mol I 3 mol I 0.1186 mol Al 1.000 mol Al 1 mol Al 0.1186 mol Al 1.000 mol Al 1 mol Al 0.1186 mol Al 1.000 mol Al 1 mol Al 3 mol I : 1 mol Al The empirical formula is AlI3. 2.93 mol S 1.00 mol S 1 mol S 2.93 mol S 1.00 mol S 1 mol S 2 mol H : 1 mol S The empirical formula is H2S. 62 Chemistry: Matter and Change Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. pound contains 3.20 g of aluminum. What is the empirical formula for the compound? ANSWER KEY 14. A 50.00-g sample of hydrated manganese(II) chloride yields 31.75 g of the anhydrous compound after heating. Determine the chemical formula and name the hydrate. 50.00 g hydrate 31.75 g anhydrous compound 18.25 g water 1 mol MnCl2 54.94 g Mn 1 mol MnCl2 70.90 g Cl 54.94 g Mn 1 mol Mn 1 mol Mn 1 mol MnCl2 35.45 g Cl 2 mol Cl 1 mol Cl 1 mol MnCl2 (54.94 g 70.90 g) 125.84 g The molar mass of manganese(II) chloride is 125.84 g/mol. 1 mol MnCl2 31.75 g MnCl2 125.84 g MnCl2 0.2523 mol MnCl2 Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 18.25 g H2O 1 mol H2O 18.02 g H2O 49.47 g C 1 mol C 4.119 mol C 12.01 g C 28.85 g N 1 mol N 2.059 mol N 14.01 g N 16.48 g O 1 mol O 1.030 mol O 16.00 g O 5.20 g H 1 mol H 5.15 mol H 1.01 g H 4.119 mol C 3.999 mol C 4 mol C 1.030 mol O 1.000 mol O 1 mol O 2.059 mol N 1.999 mol N 2 mol N 1.030 mol O 1.000 mol O 1 mol O 5.15 mol H 5.00 mol H 5 mol H 1.030 mol O 1.00 mol O 1 mol O 1.030 mol O 1.000 mol O 1 mol O 1.030 mol O 1.000 mol O 1 mol O 4 mol C : 2 mol N : 5 mol H : 1 mol O The empirical formula of caffeine is C4H5N2O. b. If the molar mass of caffeine is 1.013 mol H2O 194.19 g/mol, calculate its molecular formula. 1.013 mol H2O 4.015 mol H2O 0.2523 mol MnCl2 1.000 mol MnCl2 4 mol C 12.01 g C 48.04 g C 1 mol C 2 mol N 14.01 g N 28.02 g N 1 mol N 5 mol H 1.01 g H 5.05 g H 1 mol H 1 mol O 16.00 g O 16.00 g O 1 mol O 4 mol H2O 1 mol Mn Cl2 The ratio of water to manganese dichloride is 4 : 1. The chemical formula of the hydrate is MnCl24H2O and its name is manganese(II) chloride tetrahydrate. (48.04 g 28.02 g 5.05 g 16.00 g) 97.11 g 15. Caffeine is a compound found in some natural coffees and teas and in some colas. a. Determine the empirical formula for caffeine, using the following composition of a 100.00-g sample. 49.47 grams of carbon, 28.85 grams of nitrogen, 16.48 grams of oxygen, and 5.20 grams of hydrogen Supplemental Problems Answer Key The molar mass of the empirical formula is 97.11 g/mol. molar mass of compound n molar mass of empirical formula 194.19 g/mol 2.00 97.11 g/mol The molecular formula for caffeine is (C4H5N2O)2, which is C8H10N4O2 Chemistry: Matter and Change 63 ANSWER KEY Chapter 12 1. Silicon nitride is used in the manufacturing of high-temperature thermal insulation for heat engines and turbines. It is produced by the following reaction. 3Si(s) 2N2(g) 0 Si3N4(s) a. Interpret the equation in terms of particles, 2 mol C2H2 5 mol O2 4 mol CO2 5 mol O2 2 mol H2O 5 mol O2 2 mol C2H2 4 mol CO2 5 mol O2 4 mol CO2 2 mol H2O 4 mol CO2 2 mol C2H2 2 mol H2O 5 mol O2 2 mol H2O 4 mol CO2 2 mol H2O moles, and masses. 3. Limestone (CaCO3) is treated with hydrochlo- 3 silicon atoms 2 nitrogen molecules 0 1 formula unit silicon nitride Moles: 3 mol Si 2 mol N2 0 1 mol Si3N4 Masses: 28.09 g Si 3 mol Si 84.27 g Si 1 mol si 2 mol N2 28.02 g N2 56.04 g N2 1 mol N2 1 mol Si3N4 140.11 g Si3N4 140.31 g Si3N4 1 mol Si3N4 84.27 g Si 56.04 g N2 0 140.31 g Si3N4 b. Show that mass is conserved in the reaction. Mass of reactants: 84.27 g 56.04 g 140.31 g Mass of product: 140.31 g Because the mass of the product is equal to the total mass of the reactants, mass is conserved in the reaction. ric acid and water to manufacture calcium chloride hexahydrate. This compound is used to melt ice and snow on pavements and roads. The following balanced chemical equation represents the reaction. CaCO3(s) 2HCl(aq) 5H2O(l) 0 CaCl26H2O(s) CO2(g) a. How many moles of calcium chloride hexahydrate will be produced from 4.00 mol calcium carbonate? 4.00 mol CaCO3 1 mol CaCl26H2O 1 mol CaCO3 4.00 mol CaCl26H2O b. How many moles of hydrogen chloride will be needed to produce 1.25 mol of the hydrate? 1.25 mol CaCl26H2O 2 mol HCl 1 mol CaCl26H2O 2.50 mol HCl 2. The heat from a welder’s torch is produced by the burning of acetylene gas. The reaction is represented by the following balanced chemical equation. 2C2H2(g) 5O2(g) 0 4CO2(g) 2H2O(g) Calculate the mole ratios from the balanced equation. 5 mol O2 2 mol C2H2 64 4 mol CO2 2 mol C2H2 Chemistry: Matter and Change c. If 8.33 mol water is available for the reaction, how many moles of carbon dioxide will be released? 8.33 mol H2O 1 mol CO2 5 mol H2O 1.67 mol CO2 2 mol H2O 2 mol C2H2 Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. Particles: ANSWER KEY 4. To prevent corrosion and make paints adhere b. What mass of silicon carbide will be better, some aluminum products are treated with chromium(III) phosphate before finishing. Chromium(III) phosphate (CrPO4) is commercially produced by treating chromium metal with orthophosphoric acid (H3PO4). produced from the reaction of 352 g silicon dioxide? a. Balance the following equation for the 5.86 mol SiO2 352 g SiO2 1 mol SiO2 5.86 mol SiO2 60.09 g SiO2 reaction. 2 Cr(s) 2 H3PO4(aq) 0 3 H2(g) 2 CrPO4(s) b. How many moles of chromium metal are needed to produce 855 g of chromium(III) phosphate? 855 g CrPO4 1 mol CrPO4 146.97 g CrPO4 5.82 mol CrPO4 5.82 mol CrPO4 5.86 mol SiC 1 mol SiC 5.86 mol SiC 1 mol SiO2 40.10 g SiC 235 g SiC 1 mol SiC c. If 1.00 g of carbon is reacted, what mass of carbon monoxide is released? 1.00 g C 1 mol C 0.0833 mol C 12.01 g C 0.0833 mol C 2 mol CO 0.0555 mol CO 3 mol C 0.0555 mol CO 2 mol Cr 2 mol CrPO4 28.01 g CO 1.55 g CO 1 mol CO 5.82 mol Cr 6. Two compounds of nitrogen, nitrogen tetroxide c. The reaction of 206 g chromium will Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. release how many moles of hydrogen gas? 206 g Cr 1 mol Cr 3.96 mol Cr 52.00 g Cr 3 mol H2 3.96 mol Cr 5.94 mol H2 2 mol Cr 5. Sand (silicon dioxide) and coke (carbon) are combined to form silicon carbide (SiC), a compound used in high-strength ceramic materials. a. Balance the following equation for the SiO2(s) 1 SiC(s) a. Balance the following equation for the reaction. 1 N2O4(l) 3 N2(g) 2 4 N2H4(l) 0 H2O(g) b. If 8.00 g nitrogen tetroxide and 4.00 g hydrazine are mixed, determine the following quantities. 1. limiting reactant reaction. 1 (N2O4) and hydrazine (N2H4), are used as rocket fuels. When the two compounds are mixed, they ignite spontaneously and produce nitrogen gas and water. 3 2 Supplemental Problems Answer Key C(s) 0 CO(g) balanced equation mole ratio 2 mol N2H4 2 1 mol N2O4 Chemistry: Matter and Change 65 ANSWER KEY 8.00 g N2O4 1 mol N2O4 92.02 g N2O4 b. Determine the theoretical yield of nickel. 0.0869 mol N2O4 4.00 g N2H4 25.0 g Ni(CO)4 1 mol N2H4 32.06 g N2H4 0.146 mol Ni(CO)4 0.125 mol N2H4 0.146 mol Ni(CO)4 actual mole ratio 0.125 mol N2H4 1.44 0.0869 mol N2O4 Because the actual mole ratio is less than the balanced equation mole ratio, the limiting reactant is hydrazine. 58.69 g Ni 8.57 g Ni 1 mol Ni c. Determine the percent yield. 2. mass of product (N2) 0.188 mol N2 1 mol Ni 1 mol Ni(CO)4 0.146 mol Ni 0.146 mol Ni 0.125 mol N2H4 1 mol Ni(CO)4 170.73 g Ni(CO)4 percent yield 3 mol N2 0.188 mol N2 2 mol N2H4 actual yield 100 theoretical yield 5.34 g Ni 100 62.3% 8.57 g Ni 28.02 g N2 5.27 g N2 1 mol N2 3. mass of excess reactant Chapter 13 1. Calculate the ratio of effusion rates of oxygen 0.0625 mol N2O4 0.0625 mol N2O4 (O2) to hydrogen (H2). RateO2 92.02 g N2O4 1 mol N2O4 5.75 g N2O4 RateH2 molar massH2 molar massO2 2.02 g/mol 32.00 g/mol 1.42 0.251 5.657 8.00 g N2O4 5.75 g N2O4 2.25 g N2O4 2. Methane (CH4) effuses at a rate of 2.45 mol/s. 7. One step in the industrial refining of nickel is What will be the effusion rate of argon (Ar) under the same conditions? the decomposition of nickel carbonyl (Ni(CO)4) into nickel and carbon monoxide. In a laboratory reaction, 25.0 g nickel carbonyl yielded 5.34 g nickel. RateAr RateCH4 a. Balance the following equation for the RateAr RateCH4 molar massCH4 molar massAr reaction. 1 Ni(CO)4(g) 0 1 Ni(s) 4 2.45 mol/s CO(g) 2.45 mol/s molar massCH4 molar massAr 16.05 g/mol 39.95 g/mol 4.006 6.321 1.55 mol/s 66 Chemistry: Matter and Change Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 1 mol N2O4 0.125 mol N2H4 2 mol N2H4 ANSWER KEY 3. The effusion rate of hydrogen sulfide (H2S) is 1.50 mol/s. Another gas under similar conditions effuses at a rate of 1.25 mol/s. What is the molar mass of the second gas? RateH2S Rateunknown (RateH2S)2 (Rateunknown)2 2 2 594 mm Hg 165 mm Hg molar massH2S (N2) and oxygen (O2) if the partial pressure of N2 is 594 mm Hg and the partial pressure of O2 is 165 mm Hg? Ptotal PN PO molar massunknown 6. What is the pressure of a mixture of nitrogen 759 mm Hg molar massunknown molar massH2S molar massunknown molar massH2S 34.09 g/mol (1.50 mol/s)2 (1.25 mol/s)2 34.09 g/mol 2.25 1.56 (RateH2S)2 (Rateunknown)2 49.2 g/mol 7. A sample of air is collected at 101.1 kPa. If the partial pressure of water vapor in the sample is 2.8 kPa, what is the partial pressure of the dry air? Ptotal Pdry air Pwater vapor Pdry air Ptotal Pwater vapor 101.1 kPa 2.8 kPa 98.3 kPa 4. The pressure of a gas in a manometer is 12.9 mm Hg. Express this value in each of the following units. Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. a. torr 12.9 mm Hg 1 torr 12.9 torr 1 mm Hg 1 atm 1.70 102 atm 760 mm Hg a. What is the partial pressure of He in the container after the three gases are mixed? b. What is the total pressure in the container after the three gases are mixed? Ptotal PHe PNe PAr c. kilopascal 12.9 mm Hg neon (Ne), and argon (Ar) are at pressures of 1 atm, 2 atm, and 3 atm, respectively. The He and Ne are then added to the container of Ar. 1 atm b. atmosphere 12.9 mm Hg 8. Suppose that 5-mL containers of helium (He), 1 atm 2 atm 3 atm 1 kPa 1.72 kPa 7.501 mm Hg 6 atm 5. The vapor pressure of water is 2.3 kPa at 23°C. What is the vapor pressure of water at this temperature expressed in atmospheres? 2.3 kPa 1 atm 2.3 102 atm 101.3 kPa Supplemental Problems Answer Key Chemistry: Matter and Change 67 ANSWER KEY 1. In one city, a balloon with a volume of 6.0 L is filled with air at 101 kPa pressure. The balloon in then taken to a second city at a much higher altitude. At this second city, atmospheric pressure is only 91 kPa. If the temperature is the same in both places, what will be the new volume of the balloon? P1V1 (101 kPa)(6.0 L) P1V1 P2V2; V2 ; V2 91 kPa P2 6.7 L 2. A certain mass of gas in a 2.25-L container has a pressure of 164 kPa. What will the new pressure be if the volume of the container is reduced to 1.50 L and the temperature stays constant? P1V1 (164 kPa)(2.25 L) P1V1 P2V2; P2 ; P2 1.50 L V2 246 kPa 3. If 5.80 dm3 of gas is collected at a pressure of 92.0 kPa, what volume will the same gas occupy at 101.3 kPa if the temperature stays constant? P1V1 P1V1 P2V2; V2 ; V2 P2 (92.0 kPa)(5.80 dm3) 5.27 dm3 101.3 kPa 4. If the volume of an air pump used to inflate a football decreases from 480 mL to 375 mL, and the original pressure was 93.5 kPa, what is the new air pressure in the pump if the temperature stays constant? 5. Maintaining constant pressure, the volume of a gas is increased from 18.0 dm3 to 32.0 dm3 by heating it. If the original temperature was 18.0°C, what is the new temperature in degrees Celsius? V1 V2 V2T1 (32.0 dm3)(291 K) ; T2 ; T2 T1 T2 V1 18.0 dm3 517 K 244°C 6. A natural gas tank is constructed so that the pressure remains constant. On a hot day when the temperature was 33°C, the volume of gas in the tank was determined to be 3000.0 L. What would the volume be on a warm day when the temperature is 11°C? V1 V2 V1T2 (3000.0 L)(284 K) ; V2 ; V2 306 K T1 T2 T1 2780 L 7. A 50.0-mL sample of gas is cooled from 119°C to 80.0°C. If the pressure remains constant, what is the final volume of the gas? V1 V2 V1T2 (50.0 mL)(353 K) ; V2 ; V2 392 K T1 T2 T1 45.0 mL 8. A 10.0-L cylinder of gas is stored at room temperature (20.0°C) and a pressure of 1800 psi. If the gas is transferred to a 6.0-L cylinder, at what Celsius temperature would it have to be stored in order for the pressure to remain at 1800 psi? V1 V2 V2T1 (6.0 L)(293 K) ; T2 ; T2 10.0 L T1 T2 V1 176 K 97°C P1V1 (93.5 kPa)(480 mL) P1V1 P2V2; P2 ; P2 375 mL V2 120 kPa 68 Chemistry: Matter and Change Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. Chapter 14 ANSWER KEY 9. If the gas pressure in an aerosol can is 148.5 kPa at 23°C, what is the pressure inside the can if it is heated to 298°C? P1 P2 P1T2 (148.5 kPa)(571 K) ;P ; P2 296 K T1 T2 2 T1 286 kPa 10. A tank for compressed gas has a maximum safe pressure limit of 850 kPa. The pressure gauge reads 425 kPa when the temperature is 28°C. What is the highest temperature in degrees Celsius the tank can withstand safely? P1 P2 T1P2 (301 K)(850 kPa) ; T2 ; T2 425 kPa T1 T2 P1 602 K 330°C 11. In a steel container, it was found that the pres- Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. sure of the gas inside was 160 kPa when the container had been heated to 98°C. What had been the pressure of the gas when the temperature had been 50°C the previous day? P1 P2 P2T1 (160 kPa)(323 K) ;P ; P1 371 K T1 T2 1 T2 140 kPa 13. A balloon is filled with gas at a pressure of 102.3 kPa and a temperature of 45.5°C. Its volume under these conditions is 12.5 L. The balloon is then taken into a decompression chamber where the volume is measured as 2.50 L. If the temperature is 36.0°C, what is the pressure in the chamber? P1V1 P2V2 P1V1T2 ; P2 ; P2 T1 T2 T1V2 (102.3 kPa)(12.5 L)(309 K) 496 kPa (318.5 K)(2.50 L) 14. A weather balloon contains 14.0 L of helium at a pressure of 95.5 kPa and a temperature of 12.0°C. If this had been stored in a 1.50-L cylinder at 21.0°C, what must the pressure in the cylinder have been? P1V1 P2V2 P2V2T1 ; P1 ; P1 T1 T2 V1T2 (95.5 kPa)(14.0 L)(294 K) 919 kPa (1.50 L)(285 K) 15. How many moles of a gas will occupy 2.50 L at STP? V(1 mol) (2.50 L)(1 mol) n ; n 0.112 mol 22.4 L 22.4 L 12. A steel cylinder is filled with a gas at a temperature of 25.0°C and a pressure of 225.0 kPa. What will the pressure be if the temperature is raised to 47°C? P1 P2 P1T2 (225.0 kPa)(320.0 K) ;P ; P2 298 K T1 T2 2 T1 242 kPa 16. Calculate the volume that 3.60 g H2 gas will occupy at STP. 3.60 g m n 1.78 mol; M 2.02 g/mol 22.4 L V 1.78 mol 39.9 L 1 mol 17. What volume is occupied by 0.580 mol of gas at 98.4 kPa and 11°C? nRT PV nRT; V ; P V (0.580 mol)(8.31 LkPa/molK)(284 K) 98.4 kPa 13.9 L Supplemental Problems Answer Key Chemistry: Matter and Change 69 ANSWER KEY 18. When a sample of a gas was placed in a sealed container with a volume of 3.35 L and heated to 105°C, the gas vaporized and the resulting pressure inside the container was 170.0 kPa. How many moles of the gas was present? PV PV nRT; n ; RT n (170.0 kPa)(3.35 L) (8.31 LkPa/molK)(378 K) 22. What is the molar mass of a gas if 142 g of the gas occupies a volume of 45.1 L at 28.4°C and 94.6 kPa? mRT mRT PV ; M ; M PV M (142 g)(8.31 LkPa/molK)(301.4 K) (94.6 kPa45.1 L) 83.4 g/mol 0.181 mol 23. Determine the volume of hydrogen gas needed to make 8 L of water vapor. 19. An engineer wishes to design a container that nRT PV nRT; V ; P V (14.0 mol)(8.31 LkPa/molK)(321 K) 550 kPa 67.9 L 20. What is the molar mass of a sample of gas that 2H2(g) O2(g) 0 2H2O(g); 2 volumes H2 8 L H2 (8 L H2O) 2 volumes H2O 24. Calculate the volume of chlorine gas at STP that is required to completely react with 3.50 g of silver, using the following equation: 2Ag(s) + Cl2(g) 0 2AgCl(s). 1 mol Ag 3.50 g Ag 107 g Ag 1mol Cl2 22.4 L Cl2 2 mol Ag 1 mol Cl 2 0.366 L Cl2 has a density of 2.85g/L at 101 kPa pressure and 29°C? 25. Use the reaction shown to calculate the mass of DRT M ; P M (2.85 g/L)(8.31 LkPa/molK)(302 K) 101 kPa 70.8 g/mol iron that must be used to obtain 0.500 L of hydrogen at STP. 3Fe(s) 4H2O(l) 0 Fe3O4(s) 4H2(g) 1 mol H2 (0.500 L H2) 22.4 L H2 55.8 g Fe 4 mol H 1 mol Fe 3 mol Fe 2 0.934 g Fe 21. How many grams of gas are present in a sample that has a molar mass of 44 g/mol and occupies a 1.8-L container at 108 kPa and 26.7°C? (44 g/mol)(108 kPa)(1.8 L) MPV m ; m RT (8.31 LkPa/molK)(299.7 K) 3.4 g 70 Chemistry: Matter and Change Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. will hold 14.0 mol of gas at a pressure no greater than 550 kPa and a temperature of 48°C. What is the minimum volume the container can have? ANSWER KEY 4. What is the percent by mass of 92.3 g of Chapter 15 1. The solubility of a gas is 0.34 g/L at STP. What is its solubility at a pressure of 0.80 atm and the same temperature? S1 P1 S2 potassium fluoride (KF) dissolved in 1000.0 g of water? mass of solution mass of solute mass of solvent mass of solution 1000.0 g 92.3 g 1092.3 g P2 P2 0.80 atm 0.34 g/L 0.27 g/L S2 S1 1.0 atm P1 S2 0.27 g/L Percent by mass mass of solute 100% mass of solution 1092.3 g (100%) 92.3 g Percent by mass 8.45% 2. At 25°C and 1.0 atm, 0.25 g of a gas dissolves in 1.00 L of water. What mass of the gas dissolves in 1.00 L of water at 25°C and 3.0 atm? S1 P1 S solution. P2 P2 P1 0.25 g/L atm 0.75 g/L 3.0 1.0 atm Percent by mass m V Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. m 0.75 g 3. 1.56 g of a gas dissolves in 2.00 L of water at a pressure of 1.75 atm. At what pressure will 2.00 g of the gas dissolve in 2.00 L of water if the temperature remains constant? P1 (500.0 g) 31.50% 100% mass of solute 157.5 g (H2O2) b. Find the mass of water in the solution. mass of solution mass of solute mass of solvent S2 P2 S2 mass of solute 100% mass of solution Mass of solute percent by mass mass of solution 100% m SV (0.75 g/L)(1.00 L) S1 ide (H2O2) contains 31.50% H2O2 by mass. a. Find the mass of hydrogen peroxide in the S2 S2 S1 5. A 500.0 g-sample of aqueous hydrogen perox- m2/V 2.00 g (1.75 atm) P2 P1 P1 1.56 g S1 m1/V P2 2.24 atm Supplemental Problems Answer Key mass of solvent mass of solution mass of solute 500.0 g 157.5 g mass of solvent 342.5 g (H2O) Chemistry: Matter and Change 71 ANSWER KEY in 48.0 mL of water, determine the percent by volume of methanol in the solution. 8. What is the molarity of a solution that contains 20.45 g of sodium chloride (NaCl) dissolved in 700.0 mL of solution? volume of solution volume of solute volume of solvent (20.45 g NaCl) volume of solution 24.0 mL 48.0 mL 72.0 mL (700.0 mL) Percent by volume volume of solute 100% volume of solution mL (100%) 24.0 72.0 mL Percent by volume 33.3% 7. An aqueous solution of methanol is 45.0% methanol by volume. 1 mol NaCl 0.3499 mol NaCl 58.44 g NaCl 10001 LmL 0.7000 L moles of solute liters of solution 0.3499 mol NaCl 0.4999 mol NaCl/L 0.7000 L Molarity Molarity 0.5000M NaCl 9. Calculate the molarity of 0.205 L of a solution that contains 156.5 g of sucrose (C12H22O11). a. Find the volume of methanol in a 250.0-mL 1 mol C12H22O11 12H22O11 342.34 g C sample of the solution. (156.5 g C12H22O11) Percent by volume 0.4571 mol C12H22O11 volume of solute 100% volume of solution Molarity Volume of solute percent by volume volume of solution 100% (250.0 mL) 45.0% 100% volume of solute 113 mL (methanol) b. Find the volume of water in this sample of the solution. volume of solution volume of solute volume of solvent volume of solvent volume of solution volume of solute 250.0 mL 113 mL moles of solute liters of solution 0.4571 mol C12H22O11 2.23 mol C12H22O11/L 0.205 L Molarity 2.23M C12H22O11 10. A 0.600-L sample of a 2.50M solution of potassium iodide (KI) contains what mass of KI? Molarity moles of solute liters of solution moles of solute molarity liters of solution (2.50 mol Kl/L)(0.600 L) moles of solute 1.50 mol Kl (1.50 mol Kl) 1 mol Kl 249 g Kl 1.66 g Kl volume of solvent 137 mL (water) 72 Chemistry: Matter and Change Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 6. If 24.0 mL of methanol (CH3OH) is dissolved ANSWER KEY 11. What mass of ammonium chloride (NH4Cl) would you use to prepare 85.0 mL of a 1.20M solution NH4Cl? (85.0 mL) 10001 LmL 0.0850 L moles of solute 0.102 mol NH4Cl 1 mol NH Cl 53.50 g NH4Cl 4 0.30M solution of copper(II) sulfate (CuSO4) from a 2.00M solution of CuSO4? M1V1 M2V2 M 0.30M V1 V2 2 (125 mL) 19 mL 2.00M M1 Dilute 19 mL 2.00M CuSO4 solution to 125 mL with water. (225 g) Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 2 1000 g 0.225 kg 1 kg moles of solute kilograms of solvent 0.624 mol MnBr2 0.225 kg Molality 15. Calculate the molality of a solution that contains 106 g naphthalene (C10H8) dissolved in 3.15 mol carbon tetrachloride (CCl4). (106 g C10H8) 13. A 22.0-mL sample of 12M H2SO4 is diluted to a volume of 1200.0 mL. What is the molarity of the diluted solution? 128.18 g C 1 mol C10H8 0.827 mol C10H8 10H8 (3.15 mol CCl4) (485 g) 153.81 g CCl4 485 g CCl4 1 mol CCl4 1000 g 0.485 kg 1 kg moles of solute kilograms of solvent 0.827 mol C10H8 10.485 kg Molality Molality 1.71m C10H8 M1V1 M2V2 M2 M1 1 mol MnBr2 Molality 2.77m MnBr2 12. How would you correctly prepare 125 mL of a 214.74 g MnBr 0.624 mol MnBr2 moles of solute molarity liters of solution (1.20 mol NH4Cl/L)(0.0850 L) 5.46 g NH4Cl (MnBr2) is dissolved in 225 g of water. What is the molality of the solution? (134 g MnBr2) moles of solute Molarity liters of solution (0.102 mol NH4Cl) 14. A mass of 134 g of manganese dibromide V1 22.0 mL (12M) 1200.0 mL V2 0.22M H2SO4 16. A solution is made by dissolving 425 g of nitric acid (HNO3) in 535 g of water. Find the mole fraction of nitric acid in the solution. (425 g HNO3) (535 g H2O) XHNO3 63.02 g HNO 6.74 mol HNO 1 mol HNO3 3 3 18.02 g H O 29.7 mol H O 1 mol H2O 2 nHNO3 nHNO3 nH2O 2 6.74 mol 6.74 mol 29.7 mol 6.74 mol 36.4 mol XHNO3 0.185 Supplemental Problems Answer Key Chemistry: Matter and Change 73 ANSWER KEY 4. Calculate the molar entropy of vaporization for Chapter 16 1. Calculate the amount of heat released in the complete combustion of 8.17 g of Al to form Al2O3(s) at 25°C and 1 atm. Hf° for Al2O3(s) 1680 kJ/mol. 4Al(s) 3O2(g) 0 2Al2O3(s) In the reaction, 2 mol Al2O3 is produced. The enthalpy of formation is 1680 kJ/mol. Therefore, the total energy of this reaction is 3360 kJ. For the combustion of 8.17 g of Al, 8.17 g Al 1 mol Al/27.0 g Al (3360 kJ/4 mol) 254 kJ. liquid hydrogen iodide at its boiling point, 34.55°C. HI(l) 7 HI(g) Hvap 19.76 kJ/mol At the boiling point, liquid and gaseous HI exists in equilibrium. Therefore, G 0. Hvap 19.76 kJ/mol T 273 K Tc 273 K (34.55°C) 238 K G H TS TS H S 1000 J H 19.76 kJ/mol 1 kJ T 238 K 83.0 J/molK 2. From the following data at 25°C, H 185 kJ 2H2(g) O2(g) 0 2H2O(g) H 483.7 kJ 5. Ozone (O3) in the atmosphere may react with nitric oxide (NO). calculate H at 25°C for the reaction below. O3(g) NO(g) 0 NO2(g) O2(g) 4HCl(g) O2(g) 0 2Cl2(g) 2H2O(g) From the following data, calculate the G° in kJ for the reaction at 25°C and determine whether the reaction is spontaneous. The final reaction is related to the two reference reactions. According to Hess’s law, the final reaction can be obtained by reversing the first reaction and multiplying it by 2, then adding the resulting equation to the second equation. This produces the enthalpy for the final reaction. The result is 2 (185 kJ) 1 (483.7 kJ) 114 kJ. H° 199 kJ S° 4.1 J/K G H TS G 199 kJ [298 K (4.1 J/K) 1 kJ/1000 J] G 198 kJ The reaction is spontaneous. 3. Determine S for the reaction SO3(g) H2O(l) 0 H2SO4(l), given the following entropies. Compound Entropy (J/molK) SO3(g) 256.8 H2O(l) 70.0 H2SO4(l) 156.9 The entropy for the reaction is the entropy of the product minus the entropies of the reactants. S (1 mol H2SO4 156.9 J/molK) (1 mol SO3 256.2 J/molK) (1 mol H2O 70.0 J/molK) 169.3 J/molK 74 Chemistry: Matter and Change 6. For the reaction H2(g) S(s) 0 H2S(g), H 20.2 kJ and S 43.1 J/K. When will the reaction be spontaneous? Spontaneity is determined from the free energy. When the free energy is negative, the reaction will be spontaneous. G H TS The enthalpy is negative and the entropy is positive. G () () Because the free energy can only be negative, the reaction will be spontaneous at all temperatures. Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. H2(g) Cl2(g) 0 2HCl(g) ANSWER KEY 7. The following reaction is nonspontaneous at 10. Calculate the standard heat of vaporization, Hvap, for tin(IV) chloride, SnCl4. 25°C. 1 Cu2O(s) 0 2Cu(s) O2 (g) 2 Hf° 168.6 kJ If S 75.8 J/K, what is the lowest temperature at which the reaction will be spontaneous? A reaction is spontaneous when the free energy is negative. When the enthalpy is positive and the entropy is positive, the reaction will be spontaneous at high temperatures. To determine the lowest temperature of spontaneity, determine the temperature of equilibrium. At any temperature higher than that, the reaction will be spontaneous. H TS 168.6 kJ 1000 J H T 2.22 103K 75.8 J/K 1 kJ S Hf° 511.3 kJ/mol for SnCl4(l) and 471.5 kJ/mol for SnCl4(g). At the boiling point, SnCl4(l) 3 SnCl4(g). Hvap Hf°products Hf°reactants Hvap [1 mol (471.5 kJ/mol)] [1 mol (511.3 kJ/mol)] Hvap 39.8 kJ 11. Given the following data at 298 K, calculate S for the given reaction. S (J/molK) 2Ag2O(s) 0 4Ag(s) O2(g) 121.3 42.6 205.2 Sreaction Sproducts Sreactants 8. Calculate H° at 25°C for the reaction below. 2ZnS(s) 3O2(g) 0 2ZnO(s) 2SO2(g) 206.0 0 350.5 Hf°(kJ/mol) 296.8 Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. H°reaction Hf°products Hf°reactants H [2 mol (350.5 kJ/mol) 2 mol (296.8 kJ/mol)] [2 mol (206.0 kJ/mol) 3 mol (0 kJ/mol)] H 882.6 kJ 4Fe(s) 3O2(g) 0 2Fe2O3(s) Hf° (kJ/mol) 0 0 824.2 205.2 J/mol K] [2 mol 121.3 J/mol K] Sreaction 133.0 J/K 12. Calculate the G° at 298 K for the following reaction. Fe2O3(s) 13CO(g) 0 2Fe(CO)5(g) 3CO2(g) 824.2 110.5 733.8 H° (kJ/mol) 393.5 87.4 197.6 445.2 S° (J/molK) 213.6 9. How much heat is evolved in the formation of 35.0 g of Fe2O3(s) at 25°C and 1.00 atm pressure by the following reaction? Sreaction [4 mol 42.6 J/mol K 1 mol G°reaction H°reaction TS°reaction H°reaction H°products H°reactants S°reaction S°products S°reactants H°reaction [2 mol (733.8 kJ/mol) 3 mol The formation of one mole of iron(III) oxide releases 824.2 kJ. (393.5 kJ/mol)] [1 mol (824.2 kJ/mol) 35.0 g Fe2O3 1 mol Fe2O3/159.7 g Fe2O3 (824.2 kJ/1 mol Fe2O3) 181 kJ S°reaction [2 mol (445.2 J/molK) 3 mol 13 mol (110.5 kJ/mol)] 387.4 kJ (213.6 J/molK)] [1 mol (87.4 J/molK) 13 mol (197.6 J/molK)] 1125 J/K Greaction 387.4 kJ (298 K (1125 J/K) 1 kJ/1000 J) Greaction 52.2 kJ 13. Estimate the temperature at which G 0 for Supplemental Problems Answer Key Chemistry: Matter and Change 75 ANSWER KEY the following reaction. Greaction Gproducts Greactants NH3(g) HCl(g) 0 NH4Cl(s) Greaction [1 mol (314.1 kJ/mol) 1 mol (33.60 kJ/mol)] [1 mol (98.70 kJ/mol) 2 mol (95.30 kJ/mol)] 58.4 kJ H 176 kJ, S 284.5 J/K At equilibrium, G 0. H TS T H/S T 176 kJ/(284.5 J/K 1kJ/1000 J) 619 K or 346°C 14. Consider the reaction below at 25°C for which S 16.1 J/K. H°reaction [1 mol (359.4 kJ/mol) 1 mol (20.60 kJ/mol)] [1 mol (100.4 kJ/mol) 2 mol (92.31 kJ/mol] 94.98 kJ S (H G)/T S (94.98 kJ (58.4 kJ))/298 K 0.123 kJ/K 1000 J 0.123 kJ/K 123 J/K 1 kJ Equilibrium occurs when the free energy is zero. CH4(g) N2(g) 163.8 kJ 0 HCN(g) NH3(g) T H/S At what temperature will this reaction be spontaneous? G 0 at equilibrium. G negative value for spontaneous reaction. Find the temperature of equilibrium. The reaction is spontaneous at any temperature higher than equilibrium temperature. G H TS Hreaction Hproducts Hreactants at G 0, H TS. T 163.8 kJ/(16.1 J/K 1 kJ/1000 J) 1.02 104 K 9.90 103°C Spontaneity occurs at any temperature higher than 9.90 103°C. 15. Estimate the temperature above which the T 94.98 kJ/(123 J/K 1 kJ/1000 J) 772 K 449°C The reaction is not spontaneous above this temperature. 16. Copper metal has a specific heat of 0.385 J/g°C and a melting point of 1083°C. Calculate the amount of heat required to raise the temperature of 22.8 g of copper from 20.0°C to 875°C. q c m T q 0.385 J/g°C 22.8 g (875°C 20.0°C) 1 kJ 7.51 kJ 1000 J following reaction is not spontaneous. PbS(s) 2HCl(g) 0 PbCl2(s) H2S(g) 100.4 92.31 359.4 Hf° (kJ/mol) 20.60 98.70 95.30 314.1 G° (kJ/mol) 33.60 To determine the temperature of spontaneity, the enthalpy and entropy values must be known. Get the entropy values from the free energy and the enthalpy at the standard state (T 298 K). 76 Chemistry: Matter and Change 17. How many degrees of temperature rise will occur when a 25.0-g block of aluminum absorbs 10.0 kJ of heat? The specific heat of aluminum is 0.897 J/g°C. q c m T q T cm (Tfinal Tinitial) 10 000 J/(25.0 g 0.897 J/g°C) 446°C Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. G H TS ANSWER KEY 18. Find the standard enthalpy of formation for ethylene, C2H4(g), given the following data. C2H4(g) 3O2(g) 0 2CO2(g) 2H2O(l) H° 1411 kJ C(s) O2(g) 0 CO2(g) H° 393.5 kJ H2(g) 1 O2(g) 0 H2O(l) 2 H° 285.8 kJ Use Hess’s law and rearrange the equations to get the equation for the formation of ethylene from elemental carbon and hydrogen. Multiply by the appropriate coefficients. 2CO2(g) 2H2O(l) 0 C2H4(g) 3O2(g) H° 1411 kJ H° 787.0 kJ 2H2(g) O2(g) 0 2H2O(l) H° 571.6 kJ Then add the enthalpies to get the enthalpy of formation for Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. evaporate 1 g of water. After vigorous exercise, a person feels chilly because the body is giving up heat to evaporate the perspiration. A typical person perspires 25 mL of water after 20 minutes of exercise. How much body heat is used to evaporate this water? Convert the 25 mL of water to grams of water. 25 mL 1 g/1 mL 25 g 1kJ 25 g 2404 J/g 60 kJ 1000 J Chapter 17 1. For the reaction BrO3 5Br 6H 0 [BrO3] 3Br2 3H2O, the value of t 2C(s) 2O2(g) 0 2CO2(g) 2C(s) 2H2(g) 0 C2H4(g) 20. At body temperature, 2404 J is required to 1.5 102 mol/(Ls) at a particular time. [Br] What is the value of at the same t instant? H 52.4 kJ 19. Glycine is important for biological energy. The combustion of glycine is given by the following equation. 4C2H5O2N(s) 9O2(g) 0 8CO2(g) 10H2O(l) 2N2(g) H 3857 kJ Given that Hf° CO2(g) 393.5 kJ/mol and Hf° H2O(l) 285.8 kJ/mol, calculate the enthalpy of formation per mole of glycine. H°reaction H°products H°reactants 3857 kJ [8 mol (393.5 kJ/mol) 10 mol (285.8 kJ/mol) 2 mol 0 kJ/mol] [4 mol (H glycine) 9 mol 0 kJ/mol] H glycine (3857 kJ 3148 kJ 2858 kJ)/ 4 mol 537.3 kJ/mol [BrO3] 1.5 102 mol/(Ls) t [Br ] (1/5) t [Br] (1.5 102 mol/(Ls)) 5 t [Br] 7.5 102 mol/(Ls) t 2. The reaction, A 2B 0 Products, was found to have the rate law, Rate k[A][B]2. While holding the concentration of A constant, the concentration of B was increased from x to 3x. Predict by what factor the rate of the reaction will increase. Let x [B] and y [A] initially. Initial rate k[A][B]2 k(y)(x)2 [A] does not change but [B] triples. Increased rate k(y)(3x)2 k(y)(x)2(3)2 9 (initial rate) The rate of reaction will increase by a factor of 9. Supplemental Problems Answer Key Chemistry: Matter and Change 77 ANSWER KEY Products, the following initial rates of reaction have been measured for the given reactant concentrations. 5. Consider the following rate data for the reaction below at a particular temperature. 2A 3B 0 Products Initial Rate of Loss of A (mol/(Lⴢs)) Test [A] (M) [B] (M) Rate (mol/(Lⴢhr)) 1 0.010 0.020 0.020 Experiment 2 0.015 0.020 0.030 1 0.10 0.30 1.00 105 3 0.010 0.010 0.005 2 0.10 0.60 2.00 105 3 0.20 0.90 1.20 104 Initial Initial [A] (M) [B] (M) What is the rate law expression for this reaction? What is the rate equation for this reaction? Set up the rate equation for all three tests. Rate 1 k[0.10]m[0.30]n Rate 1 k[0.010]m[0.020]n Rate 2 k[0.10]m[0.60]n k[0.10]m[0.30]n(2)n (2)n(Rate 1) Rate 2 k[0.015]m[0.020]n k(1.5)m[0.010]m[0.020]n (1.5)m(Rate 1) Rate 3 k[0.010]m[0.010]n k[0.010]m(0.5)n[0.020]n (0.5)n(Rate 1) Rate 3 k[0.20]m[0.90]n k[0.10]m(2)m[0.30]n(3)n (2)m(3)n(Rate 1) 0.030 (1.5)m 0.020 (Rate 2) (2.00 105 mol/(Ls)) 2 (2)n (Rate 1) (1.00 105 mol/(Ls)) n=1 (Rate 3) (1.20 104 mol/(Ls)) 12 (2)m(3)n (Rate 1) (1.00 105 mol/(Ls)) 1.5 (1.5)m m1 (2)m 4 (Rate 2) (1.5)m (Rate 1) (Rate 3) (0.5)n (Rate 1) (2)m(3)1 12 m2 Rate k[A]2[B]1 0.005 (0.5)n 0.020 0.25 (0.5)n n2 Substitute m and n to get Rate k[A]1[B]2. 4. For the chemical reaction H2O2 2H 2I 0 I2 2H2O, the rate law expression is Rate k[H2O2][I]. The following mechanism has been suggested. H2O2 I 0 HOI OH OH H 0 H2O HOI H I 0 I2 H2O Identify all intermediates included in this reaction. 6. Consider a chemical reaction involving compounds A and B that is found to be first order in A and second order in B. What will the reaction rate be for experiment 2? Experiment Rate (mol/(Lⴢs)) Initial [A] (M) Initial [B] (M) 1 0.10 1.0 0.2 2 ? 2.0 0.6 Rate 1 0.10 mol/(Ls) k[1.0]1[0.2]2 k(1.0)(0.04) k 2.5 L mol1 s1 Rate 2 2.5 L mol1 s1[2.0]1[0.6]2 1.8 mol/(Ls) The intermediates are OH and HOI. 78 Chemistry: Matter and Change Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 3. For the hypothetical reaction A B 0 ANSWER KEY 7. The data below were determined for the tion A B 0 C, when the rate expression is Rate k[A]2[B]. following reaction. 2 S2O8 Experiment 3I 2 0 2SO4 [S2O82ⴚ] I3 (M) Iⴚ (M) 10. Calculate the specific rate constant for the reac- Initial Rate (mol/(Lⴢs)) 1 0.10 0.40 1.4 105 2 0.20 0.40 2.8 105 3 0.20 0.20 1.4 105 What is the rate equation for this reaction? Rate 1 k[0.10]m[0.40]n Experiment Initial Initial [A] (M) [B] (M) Initial Rate of Formation of C (mol/(Lⴢs)) 1 0.10 0.10 2.0 104 2 0.20 0.10 8.0 104 3 0.20 0.20 1.6 103 2.0 104 mol/(Ls) k[0.10]2[0.10] k 0.20 L2 mol2 s1 2.0 101 L2 mol2 s1 Rate 2 k[0.20]m[0.40]n k[0.10]m(2)m[0.40]n (2)m(Rate 1) 11. The following figure shows the energy diagram Rate 3 k[0.20]m[0.20]n k[0.10]m(2)m[0.40]n(0.5)n (2)m(0.5)n(Rate 1) (Rate 2) (2.8 105 mol/(L s)) (2)m 2 (Rate 1) (1.4 105 mol/(L s)) of some reactants changing into products. Explain what the numbers in the diagram represent. m1 Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. (1.4 105 mol/(L s)) 1 (1.4 105) Energy (kJ) 40 kJ (Rate 3) (2)m(0.5)n 2(0.5)n (Rate 1) 100 kJ (0.5)n 0.5 n1 Rate k[S2O82][I] 8. For the reaction A B 0 C, the rate relation- ship is found to be Rate k[A][B]2. What is the overall reaction order for this reaction? Reaction progress The reaction has an activation energy of 40 kJ and an overall energy change of reaction of 100 kJ. This reaction will be exothermic with a loss of 100 kJ energy. The reaction is first order in A and second order in B. (1 2 3) This is a third-order reaction. 9. For the rate law expression Rate k[A][B]2, what happens to the rate if the concentration of B is increased by a factor of 2? The rate will increase by a factor of 4. (2)2 4 Supplemental Problems Answer Key Chemistry: Matter and Change 79 ANSWER KEY 12. The following figure shows the potential energy diagram for a reaction. Explain what this diagram tells you about the reaction. b. 4HCl(g) O2(g) 3 2Cl2(g) 2H2O(g) d ZR [Cl2]2[H2O]2 Keq [HCl]4[O2] Reaction progress The reaction can be expressed as X Y 0 Z R. The forward reaction has an activation energy of a. The reverse reaction has an activation energy of c d. Intermediate b is formed during the rate-determining step. The reaction releases energy d. The reaction is exothermic. 13. Explain how the following mechanism can be used to determine the rate expression for a chemical reaction A 2B 0 AB2. Step 1 B B 0 B2 slow Step 2 B2 A 0 AB B fast Step 3 B AB 0 AB2 fast The slow step is the rate-determining step and is responsible for the rate. Two units of B are involved, so the reaction will be second order in B. The rate expression is then Rate k[B]2. The overall reaction order for this reaction is second order. c. PCl5(g) 3 PCl3(g) Cl2(g) [Cl2][PCl3] Keq [PCl5] d. CuSO43H2O(s) 2H2O(g) 3 CuSO45H2O(s) 1 Keq [H2O]2 2. At 793 K, the equilibrium constant for the reaction NCl3(g) Cl2(g) 3 NCl5(g) is 39.3. a. Do products or reactants dominate in this equilibrium? Products dominate in this equilibrium. b. If the equilibrium constant for this reaction were less than 1, would the reactants or products be dominant? 14. What is the rate law expression for the following mechanism? Step 1 AB C2 0 AC2 B slow Step 2 B AB 0 AB2 fast Step 3 AC2 AB2 0 A2C2 B2 fast Step 4 A2C2 B2 0 A2C B2C fast Use the slow step, which is rate determining. Rate k[AB][C2] 80 Chemistry: Matter and Change When the equilibrium constant is less than 1, the reactants are dominant. 3. At 773 K, the reaction 2NO(g) O2(g) 3 2NO2(g) produces the following concentrations: [NO] 3.49 104M; [O2] 0.80M; [NO2] 0.25M. Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. Potential energy reactions. [NH3][H2S] Keq [NH4HS] c XY 1. Write equilibrium expressions for the following a. NH4HS(g) 3 NH3(g) H2S(g) b a Chapter 18 ANSWER KEY a. What is the equilibrium constant expression for the reaction? Keq [NO2]2 [NO]2[O2] b. What is the equilibrium constant for the b. 2SO3(g) 3 2SO2(g) O2(g) Increase the volume to increase SO2 and O2 production. This decreases the pressure and so favors the reaction in which more moles are formed. reaction? Keq 6.4 105 Solution: Substituting the equilibrium values into the expression and solving gives the Keq. [0.25]2 Keq 6.4 105 [3.49 104]2[0.80] 4. If you wished to maximize the products of the following reactions, which concentrations would you lower or raise? c. CH4(g) 2O2(g) 3 CO2(g) 2H2O(g) Because the same number of moles are on both sides of the reaction, increasing or decreasing the volume of the reaction vessel has no effect on the product yield. d. 2CO(g) O2(g) 3 2CO2(g) Decrease the volume to increase CO2 production. This forces the equilibrium to the side with the fewer number of moles. There are fewer moles of products than of reactants. a. H2(g) Br2(g) 3 2HBr(g) Add H2 or Br2, or remove HBr as it is formed. Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. b. CO2(g) H2(g) 3 CO(g) H2O(g) Add CO2 or H2, or remove CO or H2O as they are formed. c. SO2(g) NO2(g) 3 SO3(g) NO(g) Add SO2 or NO2, or remove SO3 or NO as they are formed. d. C(s) CO2(g) 3 2CO(g) Raise the concentration of CO2(g), or lower the concentration of CO(g). 5. For each reaction, state whether increasing or decreasing the volume of the reaction vessel would yield more product at equilibrium. Give the reason for your choice. a. N2O4(g) 3 2NO2(g) Increase the volume to increase NO2 production. This decreases the pressure and so favors the reaction in which more moles are formed. Supplemental Problems Answer Key 6. What effect would an increase in temperature have on these reactions at equilibrium? Why? a. Heat H2(g) I2(g) 3 2HI(g) Temperature increase favors the forward reaction. The reaction that moves to the right consumes heat and so would relieve this stress. b. CH4(g) 2O2(g) 3 CO(g) 2H2O heat Temperature increase favors the reverse reaction. The reaction that moves to the left consumes heat and so would relieve this stress. c. N2(g) 3H2(g) 3 2NH3(g) heat Temperature increase favors the reverse reaction. The reaction that moves to the left consumes heat and so would relieve this stress. d. Heat CH4(g) 3 C(s) 2H2(g) Temperature increase favors the forward reaction. The reaction that moves to the right consumes heat and so would relieve this stress. Chemistry: Matter and Change 81 ANSWER KEY 7. Phosphorous pentachloride decomposes to b. What is the calculated molar solubility phosphorous trichloride according to this equation: PCl5(g) 3 PCl3(g) Cl2(g). At equilibrium, [PCl5] 1.00M and [Cl2] 3.16 102M. of SO42? a. Write the expression for determining the There are two Ag ions for every SO42 ion. Let s equal [SO42]; [Ag] 2s. concentration of PCl3. [PCl5] [PCl3] Keq [Cl2] Solution: Answer: Solubility [SO42] 1.4 102 Solution: Substitute these terms into the Ksp expression and solve for s. (2s)2(s) 4s3 1.2 105 s3 3.0 106 [PCl3][Cl2] Keq ; solving for [PCl3] gives [PCl5] [PCl3] Keq [PCl5] [Cl2] Take the cube root of both sides. s 1.4 102 [SO42]. (This is in good agreement with the estimate.) b. What is the equilibrium concentration of Answer: [PCl3] 3.16 102M Solution: Substitute known concentrations and calculate [PCl3]. (1.00) [PCl3] (1.00 103) (3.16 102) 3.16 Chapter 19 Write balanced chemical equations for each of the following reactions that involve acids and bases. 1. aluminum and hydrochloric acid 2Al(s) 6HCl(aq) 0 2AlCl3(aq) 3H2(g) 102M 2. nitric acid and sodium carbonate 8. The solubility product constant (Ksp ) of Ag2SO4 is 1.2 105. 2HNO3(aq) Na2CO3(s) 0 2NaNO3(aq) H2O(l) CO2(g) a. How would you estimate the molar solubility of SO42 without actually calculating it? Answer: Write the solubility equilibrium equation and the solubility product expression for Ag2SO4. Ag2SO4(s) 3 2Ag(aq) SO42(aq) Ksp [Ag]2[SO42] 1.2 105 Ksp is about 105; the estimate would be the cube root or about 101 to 102. 82 Chemistry: Matter and Change 3. potassium hydroxide and sulfuric acid 2KOH(aq) H2SO4(aq) 0 K2SO4(aq) 2H2O(l) Write the steps in the complete ionization of the following polyprotic acids. 4. H2CO3 H2CO3(aq) H2O(l) 3 H3O(aq) HCO3(aq); HCO3(aq) H2O(l) 3 H3O(aq) CO32(aq) Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. PCl3? Use: Keq 1.00 103. ANSWER KEY 5. H3BO3 H3BO3(aq) H2O(l) 3 H3O(aq) H2BO3(aq); H2BO3(aq) H2O(l) 3 H3O(aq) HBO32(aq); HBO32(aq) H2O(l) 3 H3O(aq) BO33(aq) 14. What is its pOH? 14.0 5.25 8.75 A solution has a pH of 5.79. A solution has a [H] of 1.0 105M. 6. What is its [OH]? 1.0 1014 1.0 109M 1.0 105 7. What is its pH? log(1.0 105) 5 8. What is its pOH? 15. What is its pOH? 14.00 5.79 8.21 16. What is its [H]? antilog(5.79) 1.6 106M 17. What is its [OH]? 1.0 1014 6.3 109M 1.6 106 14 5 9 18. What is the pH of a 0.50M solution of HCl, a A solution has a [OH] of 3.6 107M. Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 9. What is its [H]? 1.0 1014 2.8 108M 3.6 107 strong acid? pH log 0.50 0.30 19. What is the pH of a 1.5 103M solution of NaOH, a strong base? 10. What is its pH? log(2.8 108) 7.56 11. What is its pOH? 14.00 7.56 6.44 A solution has a [H] of 5.6 106M. 12. What is its [OH]? 1.0 1014 1.8 109M 5.6 106 1.00 1014 [H] 6.7 1012M; pH 1.5 103 log (6.7 1012) 11.17 20. What is the molarity of a KOH solution if 25.0 mL of it is neutralized by 31.7 mL of a 0.100M nitric acid solution? KOH(aq) HNO3(aq) 0 KNO3(aq) H2O(l); 0.0317 L HNO3 0.100 mol HNO3/L HNO3 3.17 103 mol HNO3; mol HNO3 : mol KOH 1:1, so 3.17 103 mol HNO3 : 3.17 103 mol KOH; 3.17 103 mol KOH/0.0250 L KOH 0.127M 13. What is its pH? log(5.6 106) 5.25 Supplemental Problems Answer Key Chemistry: Matter and Change 83 ANSWER KEY NaOH solution of unknown concentration. What is the concentration of the NaOH solution if 20.0 mL of it is neutralized by 30.7 mL of the standard solution? NaOH(aq) HCl(aq) 0 NaCl(aq) H2O(l); 0.0307 L HCl 0.200 mol HCl/L HCl 6.14 103 mol HCl; mol HCl : mol NaOH 1:1, so 6.14 103 mol HCl : 6.14 103 mol NaOH; 6.14 103 mol NaOH/0.0200 L NaOH 0.307M 22. A 25.0-mL sample of H2SO4 is neutralized by 27.4 mL of 1.00M KOH. What is the concentration of the acid? 2KOH(aq) H2SO4(aq) 0 K2SO4 (aq) 2H2O(l); 0.0274 L KOH 1.00 mol KOH/L KOH 0.0274 mol KOH; mol KOH : mol H2SO4 2:1, so 0.0274 mol KOH : 0.0137 mol H2SO4; 0.0137 mol H2SO4/0.0250 L H2SO4 0.548M 23. A 50.0-mL sample of 0.0100M Ca(OH)2 is neutralized by 45.6 mL of HBr. What is the molarity of the acid? Ca(OH)2(aq) 2HBr(aq) 0 CaBr2(aq) 2H2O(l); 0.0500 L Ca(OH)2 0.0100 mol Ca(OH)2/L Ca(OH)2 5.00 104 mol Ca(OH)2; mol Ca(OH)2 : mol HBr 1:2, so 5.00 104 mol Ca(OH)2 : 1.00 103 mol HBr; 1.00 103 mol HBr/0.0456 L HBr 0.0219M 3. MnO2 4 4. metallic Au 0 5. Na2SiF6 4 6. Zn(NO3)2 5 7. Mg3P2 3 8. Na3PO4 5 9. H2O2 1 10. ClO3 5 Chapter 20 Determine the oxidation number of the boldface element in these ions. 1. HgCl4 3 2. NO2 4 Balance the following equations, using the oxidation number method for the redox part of the equation. Show your work. 11. Cu2O(s) H2(g) 0 Cu(s) H2O(l) 2(1) 2 Cu2O(s) H2(g) 0 2Cu(s) H2O(l) 2(1) 2 Cu2O(s) H2(g) 0 2Cu(s) H2O(l) 84 Chemistry: Matter and Change Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 21. During a titration, 0.200M HCl is added to a ANSWER KEY 12. Cl2(g) KBr(aq) 0 Br2(l) KCl(aq) 1 Cl2(g) KBr(aq) 0 Br2(l) KCl(aq) Write half-reactions for each of the following redox reactions. Identify each half-reaction as being either oxidation or reduction. 16. SnS2(s) O2(g) 0 SnO2(s) SO2(g) S2 0 S4 6e, oxidation; O2 4e 0 2O2, reduction 1 Cl2(g) 2KBr(aq) 0 Br2(l) 2KCl(aq) 17. Mg(s) N2(g) 0 Mg3N2(s) 13. CaSi2(s) SbCl3(s) 0 Sb(s) Si(s) CaCl2(s) 3(1) 3 CaSi2(s) SbCl3(s) 0 Sb(s) Si(s) CaCl2(s) 3 3CaSi2(s) 2SbCl3(s) 0 2Sb(s) 6Si(s) 3CaCl2(s) 14. KI(aq) HNO3(aq) 0 I2(s) KNO3(aq) NO(g) H2O(l) Mg 0 Mg2 2e, oxidation; N2 6e 0 2N3, reduction 18. Al(s) Cl2(g) 0 AlCl3(s) Al 0 Al3 3e, oxidation; Cl2 2e 0 2Cl, reduction 19. NH3(aq) PbO(s) 0 N2(g) Pb(s) H2O(l) 2N3 0 N2 6e, oxidation; Pb2 2e 0 2Pb, reduction Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 3(1) 3 KI(aq) HNO3(aq) 0 I2(s) KNO3(aq) NO(g) H2O(l) 3 6KI(aq) 8HNO3(aq) 0 3I2(s) 6KNO3(aq) 2NO(g) 4H2O(l) 15. Cr2O72(aq) SO32(aq) 0 Cr3(aq) SO42(aq) in an acidic solution 2(3) 6 20. Cu2S(s) O2(g) 0 Cu2(aq) SO42(aq) (Hint: Two different elements are oxidized.) S2 0 S4 6e, Cu 0 Cu2 1e, oxidation; O2 4e 0 2O2, reduction Use your answers for questions 16–20 to help you balance the following equations, using halfreactions for the redox part of the equation. Show your work. 21. SnS2(s) O2(g) 0 SnO2(s) SO2(g) Cr2O72(aq) SO32(aq) 0 Cr3(aq) SO42(aq) 3(2) 6 Cr2O72(aq) 3SO32(aq) 8H(aq) 0 2Cr3(aq) 3SO42(aq) 4H2O(l) Supplemental Problems Answer Key 2(S2 S4 6e); 3(O2 4e 0 2O2) 2S2 0 2S4 12e 3O2 12e 0 6O2 SnS2(s) 3O2(g) 0 SnO2(s) 2SO2(g) Chemistry: Matter and Change 85 ANSWER KEY 22. Mg(s) N2(g) 0 Mg3N2(s) 3(Mg 0 Mg2 2e); N2 6e 0 2N3 3Mg 0 3Mg2 6e N2 6e 0 2N3 Chapter 21 Use data from Table 21-1 as needed in the following problems. Assume that all half-cells are under standard conditions. 1. For each of these pairs of half-reactions, write 3Mg(s) N2(g) 0 Mg3N2(s) a balanced equation for the overall cell reaction and calculate the standard cell potential, E 0cell. 23. Al(s) Cl2(g) 0 AlCl3(s) a. Cs(aq) e 0 Cs(s) 2(Al 0 Al3 3e); 3(Cl2 2e 0 2Cl) 2Al 0 2Al3 6e 3Cl2 6e 0 6Cl) Cu(aq) e 0 Cu(s) Cell reaction: Cu(aq) Cs(s) 0 Cu(s) Cs(aq) 2Al(s) 3Cl2(g) 2AlCl3(s) 24. NH3(aq) PbO(s) 0 N2(g) Pb(s) H2O(l) E 0cell 0.521 V (3.026 V) 3.547 V 2N3 0 N2 6e; 3(Pb2 2e 0 2Pb) b. Hg2(aq) 2e 0 Hg(l) 2N3 0 N2 6e 6e 0 6Pb Mn2(aq) 2e 0 Mn(s) 2NH3(aq) 3PbO(s) 0 N2(g) 3Pb(s) 3H2O(l) 25. Cu2S(s) O2(g) 0 Cu2(aq) SO42(aq) in an acidic solution (Hint: Look at the ratio of the two oxidized elements in the equation.) Cu and S2 are both oxidized. According to the equation, two Cu ions are oxidized for every one S2 ion oxidized, for a total loss of 10e for the oxidation part: S2 0 S6 8e 2Cu 0 2Cu2 2e Cell reaction: Hg2(aq) Mn(s) 0 Hg(l) Mn2(aq) E 0cell 0.851 V (1.185 V) 2.036 V c. Fe3(aq) 3e 0 Fe(s) Cr3(aq) 3e 0 Cr(s) Cell reaction: reduction: O2 4e 0 2O2 Fe3(aq) Cr(s) 0 Fe(s) Cr3(aq) Because 20 is the least common multiple of 10 and 4, multiply the oxidation equations by 2 and the reduction equation by 5. E 0cell 0.037 V (0.744 V) 0.707 V 2S2 0 2S6 16e 4Cu 0 4Cu2 4e 5O2 20e 0 10O2 2Cu2S(s) 5O2(g) 4Cu2(aq) 4H(aq) 2SO42(aq) d. Br2(g) 2e 0 2Br(aq) 0 2H2O(l) Au(aq) e 0 Au(s) Cell reaction: 2Au(aq) 2Br(aq) 0 2Au(s) Br2(g) 86 Chemistry: Matter and Change Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 3Pb2 ANSWER KEY h. MnO4(aq) 8H(aq) 5e 0 E 0cell 1.692 V (1.06 V) 0.632 V; round to 0.63 V Mn2(aq) 4H2O(l) 2CO2(g) 2H(aq) 2e 0 H2C2O4(aq) Cell reaction: e. Be2(aq) 2e 0 Be(s) 2MnO4(aq) 6H(aq) 5H2C2O4(aq) 0 2Mn2(aq) 8H2O(l) 10CO2(g) Tl3(aq) 3e 0 Tl(s) Cell reaction: 2Tl3(aq) 3Be(s) 0 2Tl(s) 3Be2(aq) E 0cell E 0cell 1.507 V (0.49 V) 1.997 V; round to 2.00 V 0.741 V (1.847 V) 2.558 V f. NO3(aq) 4H(aq) 3e 0 NO(g) 2H2O(l) In3(aq) 3e 0 In(s) cell composed of a SnSn2 half-cell and each of these half-cells. a. PdPd2 Cell reaction: E 0cell NO3(aq) 4H(aq) In(s) 0 NO(g) 2H2O(l) In3(aq) 0.951 V (0.1375 V) 1.0885 V; round to 1.089 V E 0cell Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 2. Calculate the standard cell potential, E 0cell, for a b. Hf Hf 4 0.957 V (0.3382 V) 1.2952 V; round to 1.295 V g. H3PO4(aq) 2H(aq) 2e 0 H3PO3(aq) H2O(l) 4H(aq) SeO4 H2SeO3(aq) H2O(l) 2(aq) 2e 0.1375 V (1.55 V) 1.4125 V; round to 1.41 V c. Cl2Cl 0 Cell reaction: SeO42(aq) 2H(aq) H3PO3(aq) 0 H2SeO3(aq) H3PO4(aq) E 0cell E 0cell E 0cell 1.35827 V (0.1375 V) 1.49577 V; round to 1.4958 V d. PbPb2 E 0cell 0.1262 V (0.1375 V) 0.0113 V 1.151 V (0.276 V) 1.427 V Supplemental Problems Answer Key Chemistry: Matter and Change 87 ANSWER KEY 3. Which of the following cells will produce the highest voltage? 0 E cell Mn Mn2 Zn2 Zn 0.771 V (0.153 V) 0.618 V Zn Zn2 Ni2 Ni Spontaneous? Ni Ni2 Cu2 Cu yes E 0cell (Mn-Zn) 0.7618 V (1.185 V) 0.4232 V; round to 0.423 V c. 3Ni2(aq) 2Rh(s) 0 3Ni(s) 2Rh3(aq) E 0cell (Zn-Ni) 0.257 V (0.7618 V) 0.5048 V; round to 0.505 V Oxidation half-reaction: E 0cell (Ni-Cu) 0.3419 V (0.257 V) 0.5989 V; round to 0.599 V Rh(s) 0 Rh3(aq) 3e The NiNi2 Cu2 Cu half-cell will produce the highest voltage. Reduction half-reaction: Ni2(aq) 2e 0 Ni(s) the oxidation and reduction half-reactions, calculate the standard cell potential, E 0cell, and determine if the reaction is spontaneous or not. a. Fe3(aq) Co2(aq) 0 Fe2(aq) Co3(aq) Oxidation half-reaction: Co2(aq) 0 Co3(aq) e Reduction half-reaction: Fe3(aq) e 0 Fe2(aq) E 0cell 0.771 V (1.92 V) 1.149 V; round to 1.15 V Spontaneous? no b. Fe3(aq) Cu(aq) 0 Fe2(aq) Cu2(aq) E 0cell 0.257 V (0.758 V) 1.015 V Spontaneous? no d. 2Na(aq) 2Hg(l) 2I(aq) 0 2Na(s) Hg2I2(s) Oxidation half-reaction: 2Hg(l) 2I(aq) 0 Hg2I2(s) 2e Reduction half-reaction: Na(aq) e 0 Na(s) E 0cell 2.71 V (0.0405 V) 2.6695 V; round to 2.67 V Spontaneous? no Oxidation half-reaction: Cu(aq) 0 Cu2(aq) e Reduction half-reaction: Fe3(aq) e 0 Fe2(aq) 88 Chemistry: Matter and Change Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 4. For each of these overall cell reactions, write ANSWER KEY e. O2(g) 2H2SO3(aq) 0 2(aq) 2SO4 4H(aq) Oxidation half-reaction: H2SO3(aq) H2O(l) 0 SO42(aq) 4H(aq) 2e Reduction half-reaction: O2(g) 4H(aq) 4e 0 2H2O(l) E 0cell 1.229 V (0.172 V) 1.057 V 7. One way to determine the metallic composition of an alloy is to use electroplating. Suppose an electrolytic cell is set up with solution of nickel ions obtained from a 6.753-g sample of a nickel alloy. The cell also contains a platinum electrode that has a mass of 10.533 g. Electric current is used to reduce the nickel ions to nickel metal, which is deposited on the platinum electrode. After being plated with nickel, the platinum electrode has a mass of 15.042 g. What is the percentage of nickel in the alloy? (15.042 g 10.533 g) 100% 66.77% 6.753 g Spontaneous? Chapter 22 yes 1. Use the IUPAC rules to name the following alkanes. 5. Suppose a battery-powered device requires a Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. minimum voltage of 9.0 V to run. How many lead–acid cells would be needed to run the device? (Remember that a standard automobile battery contains six lead–acid cells connected in one package.) The overall reaction of a lead–acid cell is a. CH3CH2CH2CH2CH3 pentane b. CH3CHCHCH3 CH3 Pb(s) PbO2(s) 4H(aq) 2SO42(aq) 0 2PbSO4(s) 2H2O(l) E 0cell CH3 2,3-dimethylbutane 1.6913 V (0.3588 V) 2.0501 V 9.0 V/2.0501 V 4.4 c. At least 5 lead–acid cells would be needed to run the device. CH3 CH2CH3 CH3CH2CHCHCHCH2CH3 CH2CH3 6. What is the minimum voltage that must be applied to a Down’s cell to cause the electrolysis of molten sodium chloride? The net cell reaction is 2Na(l) 2Cl(l) 0 2Na(l) Cl2(g) 1.35827 V (2.71 V) 4.06827 V; round to 4.07 V E 0cell The minimum voltage to cause electrolysis is 4.07 V. 3,4-diethyl-5-methylheptane d. CH3 CH3CH2 CH2CH3 CH3 CH3 CH2CH3 1,3,5-triethyl-2,4,6-trimethylcyclohexane 2. Draw the structure of each of the following Supplemental Problems Answer Key Chemistry: Matter and Change 89 ANSWER KEY alkanes. 4. Calculate the molecular mass of a 22-carbon a. 4-propyloctane CH2CH2CH3 CH3CH2CH2CHCH2CH2CH2CH3 b. 3,4-diethylhexane CH2CH3 CH3CH2CHCHCH2CH3 branched-chain alkane. Branched-chain alkanes have the formula CnH2n2. If n 22, the number of hydrogen atoms (2 22) 2 46. 22 12.011 amu 264.24 amu 22 atoms C 46 1.008 amu 46 atoms H molecular mass 46.37 amu 310.61 amu CH2CH3 c. 2,2,4,4-tetramethylhexane CH3 CH3 CH3CCH2CCH2CH3 CH3 CH3 d. 1-ethyl-3-methyl-2-propylcyclopentane CH2CH3 CH2CH2CH3 CH3 5. Chemists can analyze the composition of hydrocarbons by reacting them with copper oxide. The reaction converts carbon into carbon dioxide and hydrogen into water. Suppose 29 g of a hydrocarbon reacts to produce 88 g of CO2 and 45 g of H2O. a. What are the masses of carbon and hydrogen in the hydrocarbon? All of the carbon in CO2 and all of the hydrogen in H2O come from the hydrocarbon. molecular mass CO2 (1 12.0 amu) (2 16.0 amu) 44.0 amu each of the following alkanes. a. heptane Straight-chain alkanes have the formula CnH2n2. In heptane, n 7, so the number of hydrogen atoms (2 7) 2 16. b. cyclooctane Cyclic alkanes with one ring have the same number of hydrogen atoms as straight-chain alkanes, less two hydrogen atoms lost when the ring is formed. In cyclooctane, n 8, so the number of hydrogen atoms (2 8) 2 2 16. mass C 88 g CO2 (12 g C/44 g CO2) 24 g molecular mass H2O (2 1.0 amu) (1 16.0 amu) 18.0 amu mass H 45 g H2O (2.0 g C/18 g H2O) 5.0 g b. What is the empirical formula of the hydrocarbon? 24 g C (1 mole C/12 g C) 2 moles C 5 g H (1 mole H/1 g H) 5 moles H The empirical formula is C2H5. c. If the hydrocarbon’s molecular mass is 58 amu, what is its molecular formula? The empirical formula (C2H5) corresponds to a molecular mass of (2 12 amu) (5 1 amu) 58 amu 29 amu. Since 2, the molecular 29 amu formula must be twice the empirical formula, or C4H10. 90 Chemistry: Matter and Change Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 3. Calculate the number of hydrogen atoms in ANSWER KEY 6. Carbon has an electronegativity of 2.5. Hydrogen has an electronegativity of 2.2. Use these values to decide whether each of the following bonds is polar or nonpolar. 8. Use the IUPAC rules to name the following hydrocarbons. a. CH3CH2CHCHCH3 2-pentene a. C-C 2.5 2.5 0. Since the difference is less than 0.5, the bond is nonpolar. b. CHCH2 CH3CH2CH2CHCH2CH2CH2CH3 b. C-H 3-propyl-1-heptene 2.5 2.2 0.3. Since the difference is less than 0.5, the bond is nonpolar. c. CH3 CH3CHCH2CH2CCH c. H-H 2.2 2.2 0. Since the difference is less than 0.5, the bond is nonpolar. 5-methyl-1-hexyne d. CH 3 CH2CH3 Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 7. The combustion of a saturated hydrocarbon releases 657 kJ per mole of –CH2– groups and 779 kJ per mole of –CH3 groups in the hydrocarbon. How much energy is released by the combustion of 1.00 L of liquid tetradecane (molecular formula C14H30), a major component of kerosene? The density of tetradecane is 0.764 g/mL. 14 atoms C 30 atoms H 14 12.011 amu 168.15 amu 30 1.008 amu molecular mass 30.24 amu 198.39 amu 1.00 L (103 mL/1 L) (0.764 g/mL) (1 mole/198.39 g) 3.85 moles tetradecane Each molecule of tetradecane has 12 –CH2– groups and 2 –CH3 groups. 3.85 moles tetradecane (12 moles –CH2–/mole tetradecane) (657 kJ/mole –CH2–) 30 400 kJ 1-ethyl-4-methylbenzene 9. Draw the structure of each of the following hydrocarbons. a. 7-methyl-2,5-nonadiene CH3 CH3CHCHCH2CHCHCHCH2CH3 b. 4-ethyl-2-heptyne CH2CH3 CH3CCCHCH2CH2CH3 c. 1,2-diethylcyclohexene 3.85 moles tetradecane (2 moles –CH3/mole tetradecane) (779 kJ/mole –CH3) 6000 kJ CH2CH3 30 400 kJ 6000 kJ 36 400 kJ 3.64 104 J CH2CH3 d. 1-ethyl-2-methyl-5-propylbenzene CH2CH3 CH3 CH3CH2CH2 Supplemental Problems Answer Key Chemistry: Matter and Change 91 ANSWER KEY 10. Calculate the number of hydrogen atoms in 2. Write a balanced equation for the condensation each of the following unsaturated hydrocarbons. reaction in which cysteine and glycine combine to form a dipeptide. Assume the carboxyl group of cysteine reacts. a. 2-pentene Alkenes with one double bond have the formula CnH2n. In 2-pentene, n 5, so the number of hydrogen atoms 2 5 10. SH H CH2 H2N b. 1-hexyne Alkynes with one triple bond have the formula CnH2n2. In 1-hexyne, n 6, so the number of hydrogen atoms (2 6) 2 10. C C H O H2N OH cysteine C C H O OH glycine SH CH2 11. Write a balanced equation for the reaction in which calcium carbide, CaC2, reacts with water to form ethyne and calcium hydroxide. H2N H C C H O OH H2N C C H O OH SH CaC2 2H2O 0 C2H2 Ca(OH)2 CH2 H2N Chapter 24 C C H O H H N C C H O OH H2O ing biological molecules. a. Lysine, NH2(CH2)4CHNH2COOH 6 atoms C 6 12.0 u 72.0 u 14 atoms H 14 1.0 u 14.0 u acids, the number of possible amino acid sequences is An, where A is the number of different amino acids. 2 atoms O 2 16.0 u 32.0 u a. How many amino acid sequences are 2 atoms N 2 14.0 u 28.0 u molecular mass 146.0 u b. Fructose, CH2OHCO(CHOH)3CH2OH 6 atoms C 6 12.0 u 72.0 u 12 atoms H 12 1.0 u 12.0 u 6 atoms O 6 16.0 u 96.0 u molecular mass 180.0 u c. Oleic acid, CH3(CH2)7CHCH(CH2)7COOH 18 atoms C 18 12.0 u 216.0 u 34 atoms H 34 1.0 u 34.0 u 2 atoms O 2 16.0 u 32.0 u molecular mass 92 3. In a peptide or protein that contains n amino Chemistry: Matter and Change possible for a polypeptide that contains 10 amino acids? A 20, so the number of possible amino acid sequences 2010 1.024 1013. b. How many different dipeptides can be made from the amino acids leucine (Leu) and valine (Val)? What are those dipeptides? A 2, so the number of different dipeptides 22 4. The dipeptides are Leu-Leu, Leu-Val, Val-Leu, and Val-Val. 282.0 u Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. 1. Calculate the molecular masses of the follow- ANSWER KEY 4. Write a balanced equation for the condensation reaction in which lauric acid, palmitic acid, and stearic acid combine with glycerol to form a triglyceride. CH3(CH2)10COOH lauric acid CH3(CH2)14COOH palmitic acid 7. Synthesizing fats is an efficient way for organ- isms to store energy. The catabolism of 1 g of fat yields about 38 kJ of energy, whereas the catabolism of 1 g of protein or carbohydrate yields about 17 kJ of energy. a. How much carbohydrate would be needed to store the same amount of energy as 10 g of fat? CH3(CH2)16COOH stearic acid 38 kJ (10 g fat) g fat O CH2OH HO O C(CH2)10CH3 CH2 O O CHOH HO CH O HO C(CH2)14CH3 3H2O O O CH2OH 22 g carbohydrate C(CH2)10CH3 O C(CH2)14CH3 C(CH2)16CH3 CH2 O C(CH2)16CH3 5. In saponification, the ester bonds of a triglyc- Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. eride are hydrolyzed by a strong base, such as NaOH. It takes 3 moles of NaOH to saponify each mole of triglyceride. How many moles of triglyceride can be saponified by 120 g of NaOH? 1 mol NaOH (120 g NaOH) 40 g NaOH 1 mol triglyceride 1 mol triglyceride 3 mol NaOH 6. A young adult male produces about 2.4 105 mol per day of the steroid sex hormone testosterone. The molecular mass of testosterone is 288. How many grams of testosterone per day does a young adult male produce? (2.4 105 mol testosterone)(288 g testosterone) 1 mol testosterone 6.9 103 g testosterone Supplemental Problems Answer Key 1 g carbohydrate 17 kJ b. A cup (133 g) of ice cream contains about 32 g of carbohydrate, 4.8 g of protein, and 14 g of fat. How much energy is released when a cup of ice cream is fully catabolized? carbohydrate: 32 g 17 kJ/g 544 kJ protein: 4.8 g 17 kJ/g 82 kJ fat: 14 g 38 kJ/g 532 kJ total: 1158 kJ (about 1.2 106 J) c. A person expends about 840 kJ per hour while walking at a moderate pace. How long would a person have to walk to expend all of the energy contained in a cup of ice cream? 1158 kJ 1 h 1.4 h 840 kJ 8. A scientist analyzes a sample of DNA and finds that 21% of the nucleotide bases are A and 29% of the bases are C. What percentage of the bases are T and what percentage are G in the sample? The amount of T always equals the amount of A, and the amount of G always equals the amount of C. Therefore, 21% of the nucleotide bases are T and 29% of the bases are G. Chemistry: Matter and Change 93 ANSWER KEY 9. It takes three consecutive nucleotides in a DNA molecule to code for one amino acid in a protein. If a single strand of DNA contains 747 nucleotides, how many amino acids would be in the protein that it codes for? 12. A scientist performed an experiment to monitor photosynthesis by a plant. In the experiment, the plant produced 61 g of glucose. a. How many moles of glucose did the plant produce? (747 nucleotides)(1 amino acid) 3 nucleotides (61 g glucose)(1 mol glucose) 180 g glucose 249 amino acids 0.34 mol glucose b. How many moles of O2 did the plant 10. The DNA in a bacterial cell contains about 106 4.2 complementary base pairs. Each base pair has an average length of 3.4 1010 m. How long is the DNA in a bacterial cell? Assume that the DNA is stretched out straight rather than coiled. (4.2 106 base pairs)(3.4 1010 m) base pair produce? (0.34 mol glucose)(6 mol O2) 2.0 mol O2 1 mol glucose c. How many moles of CO2 were needed to produce that much glucose? (0.34 mol glucose)(6 mol CO2) 2.0 mol CO2 1 mol glucose 1.4 103 m d. What mass of water was needed to produce that much glucose? 11. One mole of ATP stores approximately 30.5 kJ 6 mol H2O (0.34 mol glu) 1 mol glu a. Approximately 38 moles of ATP is 36 g H2O produced for each mole of glucose that is catabolized in cellular respiration. How much energy is stored in ATP when 5.0 moles of glucose is catabolized in cellular respiration? 38 mol ATP (5.0 mol glucose) 1 mol glucose 1 mol ATP 30.5 kJ 5.8 106 J b. Assume that 40% of this energy can be used to drive anabolic reactions when ATP is hydrolyzed. The rest will be lost as heat. How much energy will be lost as heat if all of the ATP produced in part a is hydrolyzed? Total energy energy used to drive anabolic reactions energy lost as heat 18 g H2O 1 mol H O 2 13. An average-sized woman produces about 1900 g of carbon dioxide per day. a. How many moles of glucose must be oxidized during cellular respiration to produce that much carbon dioxide? 1 mol CO2 (1900 g CO2) 44 g CO2 1 mol glucose 6 mol CO 2 7.2 mol glucose b. How much energy would be stored in ATP when that much glucose is oxidized? 38 mol ATP (7.2 mol glucose) 1 mol glucose 1 mol ATP 30.5 kJ 8300 kJ (or 8.3 106 J) 100% 40% energy lost as heat energy lost as heat 100% 5.8 94 106 40% 60% J 60% 3.5 106 J Chemistry: Matter and Change Supplemental Problems Answer Key Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. of energy. This energy is released when ATP is hydrolyzed. ANSWER KEY 14. Suppose the catabolism of a given amount of glucose produces 95 moles of ATP during cellular respiration. How many moles of ATP could be produced by the same amount of glucose during fermentation? (95 mol ATPCR)(2 mol ATPF) 5.0 mol ATPF 38 mol ATPCR 15. How many grams of glucose are needed to produce 102 g of ethanol during alcoholic fermentation? 1 mol ethanol (102 g ethanol) 46 g ethanol 1 mol glucose 2 mol ethanol 180 g glucose 2.00 102 g glucose 1 mol glucose 5. The decay of 93 43Tc by gamma emission. 93Tc 43 0 00 Provide the missing term in each of the following equations. 6. 115B 42He 0 147N 1n 0 1 45 7. 45 20Ca 1p 0 21Sc 1n 0 4He 2 8. 157N mentation. The formula for lactic acid is CH3CH(OH)COOH. C6H12O6 0 2CH3CH(OH)COOH 0 188O 11p 1 99 1 9. 233 92U 0n 0 42Mo 30n 10. 210Po 84 132Sn 50 4 0 206 82Pb 2He 1p 1 11. 142 58Ce 16. Write a balanced equation for lactic acid fer- 93Tc 43 1 0 142 59Pr 0n 4 1 12. 102 44Ru 2He 0 0n 105Pd 46 Answer the following questions about half-life. 13. The half-life of 115 51Sb is 32 minutes. How much Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. of a 16.0-g sample of this isotope will remain at the end of 3.0 hours? Chapter 25 0.34 g Write a complete nuclear equation for each of the following. 1. The decay of 53 26Fe by beta emission. 53Fe 26 0 0 1 53Co 27 2. The decay of 230 90 Th by alpha emission. 230 Th 90 0 42He 115Sb 51 Solution: 3 hours 60 minutes 180 minutes 1 hour Amount remaining Initial amount (1/2)t/T 180 minutes Amount remaining 16.0 g (1/2) 32 minutes Amount remaining 16.0 g (1/2)5.6 Amount remaining 16.0 g 0.021 0.34 g 226Ra 88 3. The decay of 37 18Ar by electron capture. 37Ar 18 0 1e 0 37Cl 17 X ray photon 4. The decay of 38 19K by positron emission. 38K 19 0 01 38Ar 18 Supplemental Problems Answer Key Chemistry: Matter and Change 95 ANSWER KEY 6 14. The half-life of 182 72Hf is 9.0 10 years. How much of a 1.0-g sample of this isotope will remain at the end of 40.0 million years? 0.047 g 182Hf 72 Solution: 16. The radioisotope technetium-99 is often used as a radiotracer to detect disorders of the body. It has a half-life of 6.01 hours. If a patient received a 25.0-mg dose of this isotope during a medical procedure, how much would remain 48.0 hours after the dose was given? 40 million years 4.0 107 years 1.05 mg technetium-99 Amount remaining Initial amount (1/2)t/T Solution: Amount remaining 1.0 g 4.0 107 yr (1/2) 9.0 106 yr Amount remaining Initial amount (1/2)t/T 48.0 hours Amount remaining 1.0 g (1/2)4.4 Amount remaining 25.0 mg (1/2) 6.01 hours Amount remaining 1.0 g 0.047 0.047 g Amount remaining 25.0 mg (1/2)7.99 Amount remaining 25.0 mg 0.00419 15. The isotope strontium-90 is produced during Amount remaining 1.05 mg the testing of nuclear weapons. If 100.0 mg of strontium-90 was released in the atmosphere in 1960, how much of the radioisotope remains 85 years later? The half life of strontium-90 is 29 years. 13 mg strontium-90 Solution: Amount remaining Initial amount (1/2)t/T 85 years Copyright © Glencoe/McGraw-Hill, a division of the McGraw-Hill Companies, Inc. Amount remaining 100.0 mg (1/2) 29 years Amount remaining 100.0 mg (1/2)2.9 Amount remaining 100.0 mg 0.13 13 mg 96 Chemistry: Matter and Change Supplemental Problems Answer Key

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