9-2: Genetic Crosses Help to predict the genetic makeup + appearance of offspring Genotype & Phenotype Genotype – genetic makeup of an organism – Consists of alleles inherited from parents – Ex. PP or Pp = purple flower; pp = white flower Phenotype – the appearance of an organism as a result of its genotype – Ex. PP or Pp = purple flower; pp = white flower More words to know… Homozygous – both alleles in a pair are alike – Also known as a PUREBRED – Homozygous dominant = PP – Homozygous recessive = pp Heterozygous – alleles are different – Also known as a HYBRID – Heterozygous = Pp Probability The likelihood that a specific event will occur – May be expressed as a decimal, percentage, fraction, or ratio – Equation: # times an event is expected to happen # opportunities for it to happen Probability (cont) Examples: – Mendel observed that yellow seed color in F2 appeared 6,022 times and green seed color appeared 2,001 times Total number of seeds = 8,023 – Probability of dominant trait appearing 6,022/8,023 = .75, 75%, ¾, or 3:1 – Probability of recessive trait appearing 2,001/8,023 = .25, 25%, ¼, or 1:3 Probability (cont) What does probability tell us about the offspring of 2 heterozygous individuals? – There are 3 out of 4 chances the offspring will have the dominant trait – There is 1 out of 4 chances the offspring will have the recessive trait *The results of probability are more likely to occur if you have more trials* Probability (cont) Ex. Flipping a coin What is the probability a coin will land on heads? – 50% What is the probability a coin will land on tails? – 50% Monohybrid Crosses A cross between individuals involving one pair of contrasting traits is called a monohybrid cross – There are 4 possible outcomes (22) Results are created with the use of Punnett Square – A diagram that helps biologist predict the probability that certain traits will be inherited by offspring Example 1: Homozygous (Dominant) x Homozygous (recessive) P – purple flower; p – white flower Cross = PP x pp p p P Pp Pp Pp Pp Genotypes = 4 Pp Phenotypes = 4 purple flowers P Example 2a: Homozygous (Dominant) x Heterozygous B – black coat; b – brown coat Cross = BB x Bb BB Bb BB Bb Genotypes = 2 BB, 2Bb Phenotypes = 4 black coat Example 2b: Homozygous (recessive) x Heterozygous B – black coat; b – brown coat Cross = bb x Bb B b b Bb bb b Bb bb Genotypes = 2 bb, 2 Bb Phenotypes = 2 brown coat, 2 black coat Example 3: Heterozygous x Heterozygous B – black coat; b – brown coat Cross = Bb x Bb B B b BB Bb Bb bb Genotypes = 1 BB, 2Bb, 1bb Phenotypes = 3 black, 1 brown b Gentoypic vs. Phenotypic Ratio Genotypic ratio for the last cross –1BB : 2Bb : 1bb Phenotypic ratio for the last cross –3 black :1 brown Example #4: Testcross A testcross is used to find an unknown genotype – Can help determine genotype of any individual whose phenotype is dominant – Cross individual w/ homozygous recessive – Examples: Complete vs. Incomplete Dominance Complete dominance – When one allele is completely dominant over the other Ex. Bb Incomplete dominance – No dominant or recessive allele; a heterozygous individual has an intermediate phenotype Ex. Bb Example #5: Incomplete Dominance Japanese 4 o’clock flowers (snapdragons) – R = red – r = white Cross: RR x rr Rr Rr Rr Rr Genotypes: 4 Rr Phenotypes: 4 pink flowers Cross 2 heterozygous flowers Cross: Rr x Rr RR Rr Rr rr What is the probable genotypic ratio? –1 RR : 2 Rr : 1 rr What is the probable phenotypic ratio? –1 Red : 2 Pink : 1 white CODOMINANCE When both alleles are dominant and influence the phenotype of the individual – Ex. Blood type B B A AB AB A AB AB Dihybrid Crosses A dihybrid cross involves crossing 2 contrasting traits – There are 16 possible outcomes (24) – Punnett square: Example #1: Homozygous Dominant x Homozygous Recessive R = round seeds r = wrinkled seeds Y = yellow seed color y = green seed color Cross = RRYY x rryy How do we determine the alleles given off by each parent? – The “FOIL” method!!! FOIL (First-Outer-Inner-Last) Parent 1 Alleles RRYY : RY,RY,RY,RY FOIL (First-Outer-Inner-Last) Parent 2 Alleles: rryy ry,ry,ry,ry ry ry ry ry RrYy RrYy RrYy RrYy RrYy RrYy RrYy RrYy RY RrYy RrYy RrYy RrYy RY RrYy RrYy RrYy RrYy RY RY Genotypes: 16 RrYy Phenotypes: 16 round , yellow Heterozygous x Heterozygous Cross: RrYy x RrYy Alleles from each parent: RY, Ry, rY, ry – Parent 2 = RY, Ry, rY, ry – Parent 1 = RrYy x RrYy RY Ry rY ry RRYY RRYy RrYY RrYy RRYy RRyy RrYy Rryy rY RrYY RrYy rrYY rrYy ry RrYy Rryy rrYy rryy RY Ry Results of the cross Genotypes – – 1 RRYY, 2RRYy, 1 RRyy, 2 RrYY, 4 RrYy, 2 Rryy, 1 rrYY, 2 rrYy, 1 rryy Phenoytpes – – 9 round, yellow; 3 round, green; 3 wrinkled, yellow; 1 wrinkled, green Multiple Alleles + Polygenic Traits Multiple Alleles – 3 or more alleles – Blood types A, B, O Polygenic – 2 or more genes – Height – Weight – Eye color* – Intelligence – Skin color