. . . . ..--~--— ---------- ~~~
D20
Use the DePriester chart to generate the temperature-composition
diagram for isobutane and propane at 1000 kPa.
T(Q
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-— --- . .
---
I=
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.
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,
o,~$o
0.?s0
e. $s I
V8
——
D4.
.- —.- ---- -. . .
If a 40 mole % ethanol, 60 mole % water mixture at 60° C and 1
atm is heated:
——————-
a. At what temperature does it first begin to boil? What is the
composition of the first bubble of vapor?
b. At what temperature would it stop boiling (assume no
material is removed)? What is the composition of the last
dropIet of liquid?
c. At 82° C, what fr=tion is liquid?
d. When 80% has been vaporized, what iS the temperature and
what are the liquid and vapor compositions?
t
! c)
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..*
*n
,.- *.
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,,, r,,,,
. . L,,
:.
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r
z-oq-2
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,
[
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....
~.~- . . . . . . . . . . . . . . -
D1l. A t 1 atm, the ethylene dibromide-propy lene dibromide system
has a constant relative volatility of a= = 1.30 (Perry et al.,
1963, p. 13-3). Use the aEP value to generate the y-x equilibrium
diagram.
I
Ye
-
Ye
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(2-2s]
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--------------
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9
2D11
Page 1
.
E2.
Uw +be O* W;ehf
b)
,
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______
--
Find the dew-point and bubble-point temperatures for a mixture
that is 20 mole ~o n-butane, 50 mole % n-pentane, and 30 mole
% n-hexane. Pressure is 1 atm.
a)
>
..__.~
~Sc ~$, (~m~~)
,
C&d&
!
u-
..
,.
,’
.:
Vo
0. s“
/,
..-. —
, . . . ,!
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II
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(
Problem 2E2
At2
Atl
At6
-1280557
-1524891
-1778901
butane
pentane
hexane
Apl
Ap2
7.94986
7.33129
6.96783
o
0
0
Ap3
-0.96455
-0.89143
-0.84634
o
0
0
p (psia) =
14.696
p (psia) =
14.696
Bubble Point Calculation
T (0 C)=
27.8
541.66
0
T ( R)=
0.2
0.5
0.3
butane
pentane
hexane
Ki*zi
K
zi
2.70
0.77
0.25
0.54
0.38
0.08
1.00
Dew Point Calculation
T (0 C)=
T (0 R)=
K
zi
butane
pentane
hexane
0.2
0.5
0.3
46.4
575.2
zi/Ki
4.42
1.39
0.50
0.05
0.36
0.59
1.00
Page 1
0
0
0
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.-.L—- -.., .-. . .
D9.
!
.-
.—--+ .,
A mixture of n-butane, n-pentane, and n-hexane is at 120° F and
20 psia. Liquid and vapor are in equilibrium. If the liquid is 0.10
mole fraction h-butane, find the compositions of Iiquid and vapor.
Note: Watch your units. This problem is not trial-and-error.
I
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Kcb =
. . . . .
. . . . . . . . . . . . . . ._, -, ,“-,, ,...
~....
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