Chapter 18–1 Chapter 18 Amines and Neurotransmitters Solutions to In-Chapter Problems 18.1 To determine whether an amine is 1o, 2o, or 3o, count the number of carbons bonded to the nitrogen atom as in Example 18.1. A 1o amine has one C–N bond, and so forth. 1o 2o 2o 1o 3o C6H5 a. H2N(CH2)3NH(CH2)4NH(CH2)3NH2 b. CH3CH2O C N CH3 O 18.2 Label the amine and hydroxyl group in scopolamine, a drug used to treat motion sickness, as 1o, 2o, or 3o as in Example 18.1. CH3 3° amine 1° hydroxyl group N O CH2OH O C CH O scopolamine 18.3 Methamphetamine is a 2° amine. Give the molecular shape around each atom by counting groups. CH3 a. 2° amine b. CH2CHNHCH3 (1) 3 groups trigonal planar (3) 3 atoms 1 lone pair trigonal (2) 4 groups pyramidal tetrahedral 18.4 Name each amine as in Example 18.2. 2 a. CH3CH2CHCH3 Answer: 2-butanamine CH3CH2CHCH3 NH2 NH2 butane (4 C's) 1 butanamine 1 b. CH3CH2CH2 NHCH3 propane 3 C's propanamine CH3CH2CH2 NHCH3 Answer: N-methyl-1-propanamine N-methyl © 2013 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Amines and Neurotransmitters 18–2 c. N(CH3)2 N(CH3)2 6 C's in the ring cyclohexanamine Answer: N,N-dimethylcyclohexanamine N,N-dimethyl d. (CH3CH2CH2CH2)2NH Answer: dibutylamine 2 butyl groups (4 C's) 18.5 Work backwards to draw the structure corresponding to each name. a. N-methylaniline c. 3,5-diethylaniline NHCH3 CH3CH2 5 N-methyl 1 NH2 3 CH2CH3 3,5-diethyl d. N,N-diethylaniline b. m-ethylaniline N CH2CH3 N,N-diethyl CH3CH2 NH2 CH2CH3 m-ethyl 18.6 Work backwards to draw the structure corresponding to each name. a. 3-hexanamine NH 2 e. N,N-dimethylethylamine CH3CH2CHCH2CH2CH3 CH3CH2NCH3 CH3 3 b. N-methylpentylamine !f. 2-aminocyclohexanone CH3CH2CH2CH2CH2 NHCH3 O2N 2 NH2 2-amino g. 1-propylcyclohexanamine CH2CH2CH3 NH2 1 p-nitro d. N-methylpiperidine 1-propyl NH2 h. N-propylaniline H N N N-methyl O 1 N-methyl c. p-nitroaniline N,N-dimethyl CH3 CH2CH2CH3 N-propyl © 2013 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Chapter 18–3 18.7 Determine the compound in each pair with a higher boiling point, using the rules in Example 18.3. O a. CH3 C or CH2CH3 (CH3)2CHCH2NH2 a 1o amine with N–H bonds intermolecular hydrogen bonding higher boiling point a ketone with only C–H bonds b. or (CH3)2CHCH2NH2 (CH3)2CHCH2OH a 1o amine with N–H bonds intermolecular hydrogen bonding c. a 1o alcohol with an O–H bond intermolecular hydrogen bonding stronger intermolecular forces higher boiling point or NH2 CH3 a 1o amine with N–H bonds intermolecular hydrogen bonding higher boiling point hydrocarbon 18.8 Caffeine is soluble in the organic solvent CH2Cl2 because caffeine is organic and “like dissolves like.” 18.9 Nicotine has two heterocycles: pyridine and pyrrolidine. pyridine pyrrolidine N N CH3 18.10 Draw both enantiomers of nicotine. chirality center H H N N N N CH3 CH3 N N CH3 enantiomers 18.11 Morphine contains a 3° amine. HO O N HO CH3 N is bonded to three groups: 3° amine. © 2013 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Amines and Neurotransmitters 18–4 18.12 Identify the functional groups in heroin. ester CH3 O C aromatic ring O ether O O C CH3 3o amine N CH3 O alkene ester 18.13 Quinine has 11 trigonal planar carbon atoms [part (a), labeled with *] and nine tetrahedral carbon atoms [part (b), all other C’s]. * * CH2=CH HO CH3O * * * * * N CH * * N quinine * * 18.14 Draw the products when the amines are treated with HCl as in Example 18.4. HCl a. CH3CH2NH2 HCl b. (CH3CH2)2NH + (CH3CH3NH3) + Cl– + (CH3CH2)2NH2 + HCl c. (CH3CH2)3N (CH3CH2)3NH + + Cl– Cl– 18.15 Draw the products of each reaction. a. CH3CH2CH2CH2 NH2 b. (CH3)2NH + (CH3CH2CH2CH2 HCl + NH3) + Cl– + + (CH3)2NH2 C6H5COOH + C6H5COO– + c. + N H + H2O OH– N H H © 2013 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Chapter 18–5 18.16 Draw the products of the reaction. HO + HO H2SO4 OH CHCH2NHCH3 HO OH + CHCH2NH2CH3 HO HSO4– 18.17 Name each ammonium salt as in Example 18.5. a. (CH3NH3) b. [(CH3CH2CH2)2NH2] Br– Cl– chloride derived from methylamine c. [(CH3)2NHCH2CH3] acetate derived from ethyldimethylamine bromide derived from dipropylamine methylammonium chloride CH3COO– dipropylammonium bromide ethyldimethylammonium acetate 18.18 Ammonium salts are water-soluble solids. A water-insoluble amine can be converted to a watersoluble ammonium salt by treatment with acid. a. (CH3CH2)3N b. [(CH3CH2)3NH] Br– 3° amine with 6 C's water insoluble ammonium salt water soluble c. CH3CH2NH2 H d. 1° amine with 2 C's water soluble N H Cl– ammonium salt water soluble 18.19 Draw the products of each reaction. a. [(CH3CH2)3NH] Br– b. (CH3CH2NH3) HSO4– NaOH NaOH H c. (CH3CH2)3N + H2O + NaBr N H Cl– NaOH NH + H2O + NaCl CH3CH2NH2 + H2O + NaHSO4 18.20 Draw the structure of each amine from which the ammonium salt is derived. O HO OH CCH2CH3 CHCH2 N CH3 C CH2 CH N CH3 H phenylephrine CH3 CH3 methadone 18.21 A quaternary ammonium salt like Bitrex has four R groups bonded to N, so there is no proton available that can be removed to form an amine. © 2013 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Amines and Neurotransmitters 18–6 18.22 The chirality center in each compound is labeled. HO * HO CH2CHNH2 * HO CH2CHNH2 COOH COOH tyrosine * = chirality center L-dopa HO HO OH HO CHCH2NH2 HO * norepinephrine CH2CHNH2 dopamine H achiral 18.23 COOH must be removed and OH must be added. The COOH group is removed, and the OH group is added. CH2CH2NH2 CH2CHNH2 HO COOH N H N H tryptophan serotonin 18.24 Serotonin, bufotenin, and psilocin have the same ring system with a two-carbon chain containing a N atom bonded to it. They all contain an OH group bonded to the six-membered ring. 1o 3o CH2CH2NH2 HO 3o OH CH2CH2N(CH3)2 CH2CH2N(CH3)2 HO 2o N H N H serotonin 2o N H bufotenin 2o psilocin 18.25 To convert phenylephrine to methamphetamine requires the addition of a methyl group and removal of two OH groups. 18.26 The atoms of 2-phenylethylamine are in bold in each compound. O CH3O a. CH3O CH3O (CH3CH2)2N CH2CH2NH2 mescaline C N CH3 b. LSD N H © 2013 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Chapter 18–7 18.27 Classify each alcohol and amine as 1°, 2°, or 3°. OH groups not labeled are phenols. 2° alcohol 2° alcohol OH OH HO 1° alcohol CHCH2NHC(CH3)3 HO 2° amine HOCH2 1° alcohol albuterol (Trade names: Ventolin, Proventil) HOCH2 CHCH2NH(CH2)6O(CH2)4 2° amine salmeterol (Trade name: Serevent) 18.28 Draw the complete structure for cimetidine. H H H H H H C N C S C C N C N C H C H H H H N H N C H C N H C H H Solutions to End-of-Chapter Problems 18.29 To determine whether an amine or amide is 1o, 2o, or 3o, count the number of carbons bonded to the nitrogen atom as in Example 18.1. 3° amine 2° amide 18.30 To determine whether an amine or amide is 1o, 2o, or 3o, count the number of carbons bonded to the nitrogen atom as in Example 18.1. 3° amide N 3° amine N O CH3 18.31 To determine whether an amine is 1o, 2o, or 3o, count the number of carbons bonded to the nitrogen atom as in Example 18.1. 2o a. CH3CHCH2CH2NHCH3 3o b. N CH3 CH3 © 2013 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Amines and Neurotransmitters 18–8 18.32 To determine whether an amine is 1o, 2o, or 3o, count the number of carbons bonded to the nitrogen atom as in Example 18.1. 1o 3o CH3 a. b. CH3CCH2NH2 N(CH3)2 CH3 18.33 Draw a structure to fit each description. CH2CH3 a. CH3CH2CH2CH2CH2NH2 b. CH3CH2CH2NCH2CH2CH3 c. N CH3 d. CH3CH2NCH2CH3 H 18.34 CH2CH3 2° amine C6H15N 1° amine C5H13N + quaternary ammonium ion C8H20N+ 3° amine C6H13N Draw a structure to fit each description. 1o alcohol 1o amine 2o alcohol 3o amine 1o amine CH3 a. HOCH2CH2CH2CH2NH2 b. CH3CHCH2NHCH3 OH 2o amine 18.35 c. HOCCH2NH2 d. CH3 N CH2CH2OH CH3 CH3 3o alcohol 1o alcohol Name each amine as in Example 18.2. methyl a. b. cyclohexane cyclohexanamine ethyl aniline N-ethyl-N-methylaniline © 2013 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Chapter 18–9 18.36 Name each amine as in Example 18.2. a. CH2CH2CH2CH2CH2 N,N-dimethylpentanamine N CH3 CH3 2 methyl groups Cl NH2 b. m-chloroaniline m-chloro 18.37 Name each amine as in Example 18.2. H a. CH3CH2 N CH2CH3 Answer: diethylamine 2 ethyl groups NH2 NH2 b. CH3CH2CHCH2CH2CH2CH2CH3 octane (8 C's) CH3CH2CHCH2CH2CH2CH2CH3 1 octanamine NHCH3 c. CH3CH2CH2CHCH2CH3 hexane (6 C's) 3 2 18.38 Answer: N-methyl-3-hexanamine 1 2 CH3CHCH2CH2CH2CH2CH3 NHCH2CH3 heptane (7 C's) N-methyl CH3CH2CH2CHCH2CH3 hexanamine CH3CHCH2CH2CH2CH2CH3 3 NHCH3 1 d. 2 Answer: 3-octanamine NHCH2CH3 Answer: N-ethyl-2-heptanamine N-ethyl heptanamine Name each amine as in Example 18.2. a. CH3(CH2)6NH2 heptanamine heptane (7 C's) b. NHCH2CH3 cyclopentane (5 C ring) Answer: 1-heptanamine Answer: N-ethylcyclopentanamine N-ethyl © 2013 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Amines and Neurotransmitters 18–10 c. Answer: N-ethylpyrrolidine N CH2CH3 pyrrolidine N-ethyl 1 CH3CHCH3 d. N CH2CH3 3 N CH2CH3 CH3 CH3 propanamine propane (3 C's) 18.39 2 CH3CHCH3 Answer: N-ethyl-N-methyl-2-propanamine N-ethyl N-methyl Work backwards to draw the structure corresponding to each name. a. 1-decanamine d. 3-aminobutanoic acid 3 CH3CH2CH2CH2CH2CH2CH2CH2CH2CH2NH2 CH3CHCH2COOH NH2 3-amino b. tricyclohexylamine 1 e. N,N-dipropyl-2-octanamine CH3CH2CH2CH2CH2CH2CHCH3 N(CH2CH2CH3)2 N N,N-dipropyl 3 cyclohexyl groups f. N-ethylhexylamine c. p-bromoaniline CH3CH2NHCH2CH2CH2CH2CH2CH3 NH2 p-bromo 18.40 N-ethyl Br Work backwards to draw the structure corresponding to each name. a. cyclobutylamine d. 3-amino-2-butanone NH2 3 O CH3CHCCH3 b. 4-nonanamine NH2 1 3-amino 4 CH3CH2CH2CHCH2CH2CH2CH2CH3 NH2 e. 3-methyl-1-butanamine 1 3 CH3CHCH2CH2NH2 CH3 c. N-pentylaniline f. N-ethyl-N-propylcyclopentylamine NHCH2CH2CH2CH2CH3 N CH2CH2CH3 N-pentyl N-ethyl CH2CH3 N-propyl © 2013 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Chapter 18–11 18.41 Draw the structures to illustrate the differences between N,N-dimethylaniline and 2,4diethylaninline 3° amine 1° amine NH2 N(CH3)2 CH3CH2 N,N-dimethylaniline 18.42 CH2CH3 2,4-diethylaniline Draw the structures to illustrate the differences between N-butylaniline and o-butylaniline. 2° amine 1° amine NH(CH2)3CH3 NH2 CH2CH2CH2CH3 N-butylaniline 18.43 o-butylaniline Work backwards from the name to draw each ammonium salt. a. dipropylammonium chloride + [(CH3CH2CH2)2NH2] Cl– b. butylammonium bromide c. ethyldimethylammonium hydroxide + + (CH3CH2CH2CH2NH3) Br– ethyl CH3CH2N(CH3)2 OH– H dimethyl 18.44 Work backwards from the name to draw each ammonium salt. a. cyclohexylammonium fluoride b. triethylammonium iodide c. ethylmethylammonium chloride H CH2CH3 + NH3 F– CH3CH2 ethyl NH+ I– H CH2CH3 18.45 + CH3CH2NCH3 –Cl methyl Draw and name the four amines of molecular formula C3H9N. CH3 N CH3 CH3CH2CH2NH2 CH3CH2NHCH3 trimethylamine CH3CHNH2 CH3 CH3 1-propanamine N-methylethanamine 2-propanamine © 2013 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Amines and Neurotransmitters 18–12 18.46 Draw and name the eight constitutional isomers of molecular formula C4H11N. Identify the chirality center present in one of the amines. chirality center NH2 * CH3CH2CHCH 3 CH3CH2CH2CH2NH2 CH3CHCH2NH2 1-butanamine CH3CCH3 CH3 NH2 CH3 2-aminobutane 2-methyl-1-propanamine CH3CH2NHCH2CH3 CH3CHNHCH3 CH3CH2NCH3 N-methyl-2-propanamine N,N-dimethylethanamine 2-amino-2-methylpropane CH3 CH3CH2CH2NHCH3 diethylamine N-methyl-1-propanamine CH3 18.47 Pyridine is capable of hydrogen bonding with water, so it is more water soluble than benzene. Pyridine has a higher boiling point than benzene because it contains polar C–N bonds, while benzene is a nonpolar hydrocarbon. 18.48 CH3CH2CH2NH2 is water soluble because it is capable of hydrogen bonding with water. CH3CH2CH2CH3 is not water soluble because it is a nonpolar hydrocarbon and cannot hydrogen bond to water. 18.49 Determine the compound in each pair with a higher boiling point, using the rules in Example 18.3. a. CH3CH2CH2NH2 or CH3(CH2)7NH2 3 C amine b. CH3(CH2)6OH 8 C amine higher boiling point or CH2N(CH3)2 or 3° amine no N–H bonds CH2CH2CH2NH2 1° amine N–H bonds higher boiling point CH3(CH2)6NH2 alcohol higher boiling point 18.50 c. amine Determine the compound in each pair with the higher boiling point using the rules in Example 18.3. a. (CH3CH2)2C O or ketone (CH3CH2)2CHNH2 amine higher boiling point Cl c. CH3CHCH2CHCH3 1° amine b. or hydrocarbon NH + NH2 NH3 Cl– or CH3CH2CH2CHCH3 ammonium salt higher boiling point amine higher boiling point © 2013 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Chapter 18–13 18.51 The hydrogen bond is drawn as a dashed line. CH2CH3 CH3CH2 H N CH2CH3 N H CH3CH2 18.52 The hydrogen bond is drawn as a dashed line. H CH3CH2 O N H H CH3CH2 18.53 Primary amines can hydrogen bond to each other, whereas 3o amines cannot. Therefore, 1o amines have higher boiling points than 3o amines of similar size. Since all amines contain nitrogen atoms, any amine can hydrogen bond to water. Therefore, 1o and 3o amines have similar solubility properties. 18.54 CH3(CH2)5NH3+Cl is more water soluble than CH3(CH2)5NH2 because the ammonium salt is an ionic solid and therefore soluble in water. CH3(CH2)5NH2 contains six carbons and is therefore not water soluble. 18.55 Draw the reaction of each amine with water by transferring a proton from H2O to the amine. a. CH3CH2NH2 + H2O (CH3CH2NH3) + OH– + b. (CH3CH2)2NH + H2O (CH3CH2)2NH2 c. (CH3CH2)3N + H2O 18.56 + (CH3CH2)3NH + + OH– + OH– Draw the ammonium salt that is formed when each amine is treated with HCl. + NH3 Cl – a. NH2 + HCl b. CH2NHCH3 + HCl + CH2NH2CH3 Cl – c. N(CH2CH3)2 + HCl + NH(CH2CH3)2 Cl – © 2013 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Amines and Neurotransmitters 18–14 18.57 Draw the products of each reaction. a. CH3CH2CH2N(CH3)2 + NH2 + H2SO4 + Cl– + NH3 b. CH CH CHCH CH 3 2 2 3 + CH3CH2CH2NH(CH3)2 HCl CH3CH2CHCH2CH3 + HSO4– + c. + Br– + HBr N N H H + N CH2CH3 d. CH3CH2 CH3CH2 + NaOH CH2CH3 18.58 CH2CH3 + H2O + Na+ CH2CH3 Draw the products of each acid–base reaction. a. + HCl b. CH3CH2CHCH2CH3 + H2SO4 CH3CH2CHCH2CH3 NHCH3 c. CH3NH2 + d. Cl– + + N H N 18.59 N + HSO4– NH2CH3 + + CH3NH3 CH3COOH + CH3(CH2)5NH3 + NaOH CH3(CH2)5NH2 + CH3COO– + H2O + Na+ Draw the products of each reaction. + a. HCl N H N CH2CH2CH3 H HO b. + HO HCl O O N HO H CH3 N HO Cl– CH2CH2CH3 Cl– H CH3 © 2013 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Chapter 18–15 18.60 Draw the products of each reaction. a. CH2CHNH2 + CH2CHNH3 HSO4– + H2SO4 CH3 CH3 HO b. 18.61 HO HO CH2CH2NH2 + H2SO4 + CH2CH2NH3 HSO4– HO The heterocycle in both coniine and morphine is piperidine (labeled in bold). HO O N H N CH2CH2CH3 coniine 18.62 CH3 HO morphine The pyrrolidine N is trigonal pyramidal because it is surrounded by four groups, three of which are bonds and one of which is a lone pair of electrons. The pyridine N has only three groups around it, two of which are bonds and one of which is a lone pair. The pyridine N doesn’t have enough groups around it to be trigonal pyramidal. N trigonal planar N CH3 trigonal pyramidal 18.63 Caffeine is a mild stimulant, imparting a feeling of alertness after consumption. It also increases heart rate, dilates airways, and stimulates the secretion of stomach acid. These effects are observed because caffeine increases glucose production, making an individual feel energetic. 18.64 Caffeine intake should be limited in pregnant and nursing mothers because excessive consumption increases the risk of miscarriage and caffeine can pass into breast milk, possibly affecting the health of a newborn baby. 18.65 An alkaloid solution is slightly basic since its amine pulls off a proton from water, forming OH– and an ammonium ion. 18.66 a. Morphine is found in poppies and is used as a pain reliever for people suffering from severe chronic pain. b. Quinine is found in the bark of the cinchona tree and is used to treat malaria. c. Atropine is found in the nightshade plant and is used to increase heart rate. © 2013 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Amines and Neurotransmitters 18–16 18.67 Dopamine affects brain processes that control movement, emotions, and pleasure. Normal dopamine levels give an individual a pleasurable, satisfied feeling. Increased levels result in an intense “high.” Drugs such as heroin, cocaine, and alcohol increase dopamine levels. When there is too little dopamine in the brain, an individual loses control of fine motor skills and Parkinson’s disease results. 18.68 Patients with Parkinson’s disease cannot be treated by giving them dopamine, even though the disease results from low dopamine levels, because dopamine does not cross the blood–brain barrier. 18.69 Serotonin plays an important role in mood, sleep, perception, and temperature regulation. We get sleepy after eating a turkey dinner on Thanksgiving because the unusually high level of tryptophan in turkey is converted to serotonin. A deficiency of serotonin causes depression. 18.70 Two examples of SSRIs are fluoxetine (Prozac) and sertraline (Zoloft). They combat depression by inhibiting the reuptake of serotonin by the presynaptic neuron. 18.71 Dopamine [part (a)] and norepinephrine [part (b)] are derived from tyrosine, serotonin [part (c)] is derived from tryptophan, and histamine [part (d)] is derived from histidine. 18.72 A neurotransmitter is a chemical messenger that transmits nerve impulses from one nerve cell (neuron) to another cell. A hormone is a compound produced by an endocrine gland, which then travels through the bloodstream to a target tissue or organ. 18.73 The atoms of 2-phenylethylamine are labeled in bold in the compounds below. CH3 a. CH2CH2CH2NH2 HN c. b. C CH2N(CH3)2 CH2 CH3 not a derivative of 2-phenylethylamine 18.74 The atoms of 2-phenylethylamine are labeled in bold in the compounds below. CH3 CH3 a. C C CH3 b. CH2NH c. CH2CH2 N CH3 NHCH3 not a derivative of 2-phenylethylamine 18.75 The atoms of 2-phenylethylamine are labeled in bold. CH3 CH2CNH2 CH3 © 2013 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Chapter 18–17 18.76 The atoms of 2-phenylethylamine are labeled in bold. OH HO CHCH2NHC(CH3)3 HOCH2 18.77 Chlorpheniramine is an example of an antihistamine. Antihistamines bind to the H1 histamine receptor, but they evoke a different response than histamine. An antihistamine like chlorpheniramine or diphenhydramine, for example, inhibits vasodilation, so it is used to treat the symptoms of the common cold and environmental allergies. 18.78 Cimetidine is an anti-ulcer drug. It binds to the H2 histamine, thus reducing acid secretions in the stomach. 18.79 Answer each question about benzphetamine. 3o amine a. and b. CH3 CH2CHNCH2 CH3 chirality center c. CH3 H H CH3 C C NCH2 H H CH3 CH3 C C CH3 H H CH2N enantiomers CH3 CH2CHNH2 d. CH2 1° amine constitutional isomer CH2CH2N e. CH3 CH3 CH2 3° amine constitutional isomer CH3 f. CH2CHNHCH2 + Cl– benzphetamine hydrochloride CH3 © 2013 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Amines and Neurotransmitters 18–18 + CH3COOH CH2CHNCH2 + CH3COO– CH2CHNHCH2 CH3 CH3 18.80 + CH3 CH3 g. Answer each question about phentermine. CH3 a. 1o amine CH2CNH2 CH3 trigonal planar tetrahedral CH3 b. trigonal pyramidal CH2CNH2 CH3 tetrahedral c. CH2CHCH2NH2 CH3 d. CH2CHNHCH3 CH3 CH3 + CH2CNH3 Br– e. CH3 f. CH2CNH2 CH3 O CH3 + HO C + – OC CH3 CH3 18.81 O + CH2CNH3 Answer the questions about Ritalin. aromatic ring a., b., and c. chirality center 2o amine HN CH COOCH3 e. H H N CH + Cl– COOCH3 ester d. 2-phenylethylamine in bold © 2013 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Chapter 18–19 18.82 Answer the questions about seldane. 2° alcohol a., b., c., d., and e. (CH3)3C 3° amine 3° alcohol OH OH CHCH2CH2CH2 N C aromatic ring chirality center quaternary carbon aromatic ring Cl– OH f. 18.83 (CH3)3C OH + CHCH2CH2CH2 N C Work backwards to draw the structure of the amine and carboxylic acid that are used to form Chlortrimeton, an ammonium salt. H Cl CHCH2CH2N(CH3)2 N H H Cl C C HOOC COOH CHCH2CH2N(CH3)2 N + H H C C HOOC chlorpheniramine maleate Chlortrimeton 18.84 Draw the structure of the dextromethorphan hydrobromide. CH3O Br– + NH CH3 18.85 A vasodilator dilates blood vessels and a bronchodilator dilates airways in the lungs. Histamine is a vasodilator and albuterol is a bronchodilator. 18.86 Antihistamines that cause drowsiness are able to cross the blood–brain barrier and bind to H1 receptors in the central nervous system. Antihistamines that do not cause drowsiness also bind to H1 receptors, but they are unable to cross the blood–brain barrier and bind to the H1 receptors in the central nervous system. © 2013 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. COO– Amines and Neurotransmitters 18–20 18.87 Albuterol will exist in the ionic form in the stomach (lower pH) and in the neutral form in the intestines. OH HO HOCH2 OH + CHCH2NH2CH(CH3)3 HO ionic form CHCH2NHC(CH3)3 HOCH2 neutral form albuterol 18.88 Eating a poppy seed bagel can produce a positive test in a drug screening because poppy seeds contain morphine. 18.89 Heroin has two esters, which can be made from the two OH groups in morphine. Add acetic acid (CH3COOH) and H2SO4 to make the two esters in heroin. CH3 HO Both OH groups are converted to esters. CH3COOH H2SO4 O O O CH3 CH3 C N CH3 O heroin morphine 18.90 O O N HO C The compound that might cause the odor that allows for heroin detection is acetic acid, the main ingredient in vinegar. CH3 C HO O O O O + 2 H2O O CH3 C N CH3 O 2 CH3 C + O OH acetic acid (vinegar) N HO CH3 heroin © 2013 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part.