SOLUTIONS TO BRIEF EXERCISES BRIEF EXERCISE 12-1 $450,000 ÷ $50,000 = 9 years BRIEF EXERCISE 12-2 Present Value Net annual cash flows – $40,000 X 5.65 Capital investment Net present value $226,000 215,000 $ 11,000 The investment should be made because the net present value is positive. BRIEF EXERCISE 12-3 Cash 10% Discount Present Flows X Factor = Value Present value of net annual cash flows Present value of salvage value $25,000 X 65,000 X 3.79079 .62092 Capital investment Net present value = $ 94,770 = 40,360 135,130 136,000 $ (870) Since the net present value is negative, the project is unacceptable. BRIEF EXERCISE 12-4 Cash 9% Discount Present Flows X Factor = Value Present value of net annual cash flows Present value of salvage value $34,000 X 0X 5.53482 .50187 Capital investment Net present value = ($188,184) =( 0) ( 188,184) ( 200,000) ($ (11,816) The reduction in downtime would have to have a present value of at least $11,816 in order for the project to be acceptable. 12-6 Copyright © 2012 John Wiley & Sons, Inc. Weygandt, Managerial Accounting, 6/e, Solutions Manual (For Instructor Use Only) BRIEF EXERCISE 12-5 Project A Cash Flows Present value of net annual cash flows Present value of salvage value 9% Discount Present X Factor = Value $70,000 X 0 X 6.41766 .42241 Capital investment Net present value = $449,236 = 0 449,236 400,000 $ 49,236 Profitability index = $449,236/$400,000 = 1.12 Project B Cash Flows Present value of net annual cash flows Present value of salvage value 9% Discount Present X Factor = Value $50,000 X 0 X 6.41766 .42241 Capital investment Net present value = $320,883 = 0 320,883 280,000 $ 40,883 Profitability index = $320,883/$280,000 = 1.15 Project B has a lower net present value than Project A, but because of its lower capital investment, it has a higher profitability index. Based on its profitability index, Project B should be accepted. BRIEF EXERCISE 12-6 Original estimate Cash 10% Discount Present Flows X Factor = Value Present value of net annual cash flows Present value of salvage value $46,000 X 0 X 5.75902 .42410 Capital investment Net present value Copyright © 2012 John Wiley & Sons, Inc. Weygandt, Managerial Accounting, 6/e, Solutions Manual = $264,915 = 0 264,915 250,000 $ 14,915 (For Instructor Use Only) 12-7 BRIEF EXERCISE 12-6 (Continued) Revised estimate Cash 10% Discount Present Flows X Factor = Value Present value of net annual cash flows Present value of salvage value $39,000 X 0X 6.49506 .35049 Capital investment Net present value = ($253,307) =( 0) ( 253,307) ( 260,000) ($ (6,693) The original net present value was projected to be a positive $14,915; however, the revised estimate is a negative $6,693. The project is not a success. BRIEF EXERCISE 12-7 When net annual cash flows are expected to be equal, the internal rate of return can be approximated by dividing the capital investment by the net annual cash flows to determine the discount factor, and then locating this discount factor on the present value of an annuity table. $176,000/$33,740 = 5.21636 By tracing across on the 7-year row we see that the discount factor for 8% is 5.20637. Thus, the internal rate of return on this project is approximately 8%. BRIEF EXERCISE 12-8 When net annual cash flows are expected to be equal, the internal rate of return can be approximated by dividing the capital investment by the net annual cash flows to determine the discount factor, and then locating this discount factor on the present value of an annuity table. Since this exercise has a salvage value, not all cash flows are equal. In this case, the internal rate of return can be approximated by identifying the discount rate that will result in a net present value of zero. By experimenting with various rates, we determined that the net present value is approximately zero when a discount rate of approximately 9% is used. 12-8 Copyright © 2012 John Wiley & Sons, Inc. Weygandt, Managerial Accounting, 6/e, Solutions Manual (For Instructor Use Only) BRIEF EXERCISE 12-8 (Continued) Net annual cash flows = $400,000 – $150,000 = $250,000 Cash 9% Discount Flows X Factor = Present value of net annual cash flows Present value of salvage value $250,000 X 716,000 X 7.16073 .35554 Capital investment Net present value Present Value = $1,790,183 = 254,567 2,044,750 2,045,000 $ (250) The 9% internal rate of return exceeds the company’s 7% required rate of return; thus, the project should be accepted. BRIEF EXERCISE 12-9 The annual rate of return is calculated by dividing expected annual income by the average investment. The company’s expected annual income is: $130,000 – $70,000 = $60,000 Its average investment is: $470,000 + $10,000 = $240,000 2 Therefore, its annual rate of return is: $60,000/$240,000 = 25% Copyright © 2012 John Wiley & Sons, Inc. Weygandt, Managerial Accounting, 6/e, Solutions Manual (For Instructor Use Only) 12-9 SOLUTIONS FOR DO IT! REVIEW EXERCISES DO IT! 12-1 Estimated annual cash inflows....................................... Estimated annual cash outflows .................................... Net annual cash flow .......................................................... $80,000 40,000 $40,000 Cash payback period = $120,000/$40,000 = 3 years. DO IT! 12-2 Estimated annual cash inflows....................................... Estimated annual cash outflows .................................... Net annual cash flow .......................................................... Present value of net annual cash flows Capital investment Net present value a Table 4, Appendix A. $80,000 40,000 $40,000 Cash Flow 12% Discount Factor Present Value $40,000 3.03735 a $121,494 120,000 $ 1,494 Since the net present value is positive, the project should be accepted DO IT! 12-3 Estimated annual cash inflows....................................... Estimated annual cash outflows .................................... Net annual cash flow .......................................................... $80,000 40,000 $40,000 $120,000/$40,000 = 3.00. Using Table 4 of Appendix A and the factors that correspond with the four-period row, 3.00 is between the factors for 12% and 15%. Since the project has an internal rate that is more than 12%, the company’s required rate of return, the project should be accepted. 12-10 Copyright © 2012 John Wiley & Sons, Inc. Weygandt, Managerial Accounting, 6/e, Solutions Manual (For Instructor Use Only) DO IT! 12-4 Revenues ................................................................................ Less: Expenses (excluding depreciation) ........................ Depreciation ($120,000/4 years) ............................... Annual net income............................................................... $80,000 $40,000 30,000 70,000 $ 10,000 Average investment = ($120,000 + 0)/2 = $60,000. Annual rate of return = $10,000/$60,000 = 16.7%. Since the annual rate of return, 16.7%, is greater than Wallowa’s required rate of return, 12%, the proposed project is acceptable. Copyright © 2012 John Wiley & Sons, Inc. Weygandt, Managerial Accounting, 6/e, Solutions Manual (For Instructor Use Only) 12-11 SOLUTIONS TO EXERCISES EXERCISE 12-1 (a) The cash payback period is: $56,000 ÷ $7,500 = 7.5 years The net present value is: Present value of net annual cash flows Present value of salvage value Capital investment Net present value 8% Cash Discount Present Flows X Factor = Value $ 7,500 X 5.74664 = $43,100 27,000 X .54027 = 14,587 57,687 56,000 $ 1,687 (b) In order to meet the cash payback criteria, the project would have to have a cash payback period of less than 4 years (8 ÷ 2). It does not meet this criteria. The net present value is positive, however, suggesting the project should be accepted. The reason for the difference is that the project’s high estimated salvage value increases the present value of the project. The net present value is a better indicator of the project’s worth. EXERCISE 12-2 (a) Year 1 2 3 AA Net Annual Cash Flow $ 7,000 9,000 12,000 Cumulative Net Cash Flow $ 7,000 16,000 28,000 Cash payback period 2.50 years $22,000 – $16,000 = $6,000 $6,000 ÷ $12,000 = .50 12-12 Copyright © 2012 John Wiley & Sons, Inc. Weygandt, Managerial Accounting, 6/e, Solutions Manual (For Instructor Use Only) EXERCISE 12-2 (Continued) BB 22,000 ÷ 10,000 = 2.2 years Year 1 2 3 CC Net Annual Cash Flow $13,000 12,000 11,000 Cumulative Net Cash Flow $13,000 25,000 36,000 Cash payback period 1.75 years $22,000 – 13,000 = $9,000 $9,000 ÷ $12,000 = .75 The most desirable project is CC because it has the shortest payback period. The least desirable project is AA because it has the longest payback period. As indicated, only CC is acceptable because its cash payback is 1.75 years. (b) AA Year Discount Factor Cash Flow 1 .89286 $ 7,000 2 .79719 9,000 3 .71178 12,000 Total present value Investment Net present value Present Value BB Cash Present Flow Value $ 6,250 $10,000 7,175 10,000 10,000 8,541 21,966 (22,000 ) $ (34 ) CC Cash Flow $ 8,929 $13,000 7,972 12,000 11,000 7,118 24,019 (1) (22,000 ) $ 2,019 Present Value $11,607 9,566 7,830 29,003 (22,000 ) $ 7,003 (1) This total may also be obtained from Table 4: $10,000 X 2.40183 = $24,018. (The difference of $1 is due to rounding) Project CC is still the most desirable project. Also, on the basis of net present values, project BB is also acceptable. Project AA is not desirable. Copyright © 2012 John Wiley & Sons, Inc. Weygandt, Managerial Accounting, 6/e, Solutions Manual (For Instructor Use Only) 12-13 EXERCISE 12-3 Investment in new equipment ................ Disposal of old equipment ...................... Additional training required.................... Net initial investment required............... $2,450,000 (260,000) 85,000 $2,275,000 Calculation of net present value: Cash flows Maintenance Net cash flows from operations: Terminal salvage Present value of cash inflows Initial investment Net present value Year 1 2 3 4 5 6 7 Discount Factor, 9% 0.91743 0.84168 0.77218 0.70843 0.64993 0.59627 0.54703 5 0.64993 7 0.54703 Amount $ 390,000 400,000 411,000 426,000 434,000 435,000 436,000 (100,000) 350,000 Present Value $ 357,798 336,672 317,366 301,791 282,070 259,377 238,505 (64,993) 2,028,586 191,461 2,220,047 (2,275,000) $ (54,953) Based on the net present calculation alone, the sewing machine should not be purchased. However, the internal rate of return would be only slightly lower than the 9% minimum required, so the company may want to look at some of the non-quantitative factors involved. 12-14 Copyright © 2012 John Wiley & Sons, Inc. Weygandt, Managerial Accounting, 6/e, Solutions Manual (For Instructor Use Only) EXERCISE 12-4 Machine A Cash 9% Discount Present Flows X Factor = Value Present value of net annual cash flows Present value of salvage value $15,000 X 0 X 5.53482 .50187 = $83,022 = 0 83,022 75,500 $ 7,522 Capital investment Net present value Profitability index = $83,022/$75,500 = 1.10 Machine B Cash 9% Discount Flows X Factor = Present value of net annual cash flows Present value of salvage value $30,000 X 0 X 5.53482 .50187 Capital investment Net present value Present Value = ($166,045) = ( 0) ( 166,045) ( 180,000) ($ (13,955) Profitability index = $166,045/$180,000 = .92 Machine B has a negative net present value, and also a lower profitability index. Machine B should be rejected and Machine A should be purchased. EXERCISE 12-5 When net annual cash flows are expected to be equal, the internal rate of return can be approximated by dividing the capital investment by the net annual cash flows to determine the discount factor, and then locating this discount factor on the present value of an annuity table. $430,000/$101,000 = 4.25743 By tracing across on the 6-year row, we see that the discount factor for 11% is 4.23054. Thus, the internal rate of return on this project is approximately 11%. Since this is above the company’s required rate of return, the project should be accepted. Copyright © 2012 John Wiley & Sons, Inc. Weygandt, Managerial Accounting, 6/e, Solutions Manual (For Instructor Use Only) 12-15 EXERCISE 12-6 (a) Total net investment = $29,300 + $1,500 – $2,000 = $28,800 Annual net cash flow = $7,000 Payback period = $28,800 ÷ $7,000 = 4.1 years (b) Net present value approximates zero when discount rate is 12%. Item Net annual cash flows Capital investment Net present value (c) Amount $7,000 Years 1–6 Present Value $28,780 (28,800) $ (20) PV Factor 4.11141 Because the approximate internal rate of return of 12% exceeds the required rate of return of 10%, the investment should be accepted. EXERCISE 12-7 (a) Project 22A 23A 24A Capital Investment ÷ $240,000 $270,000 $280,000 ÷ ÷ ÷ Net Annual Cash Flows* ($16,700 + $40,000) ($20,600 + $30,000) ($17,500 + $40,000) Internal Rate of Return = Factor = = = 4.233 5.336 4.870 Closest Discount Factor Internal Rate of Return 4.23054 5.32825 4.86842 11% 12% 10% *(Annual income + Depreciation expense) (b) The acceptable projects are 22A and 23A because their rates of return are equal to or greater than the 11% required rate of return. 12-16 Copyright © 2012 John Wiley & Sons, Inc. Weygandt, Managerial Accounting, 6/e, Solutions Manual (For Instructor Use Only) EXERCISE 12-8 The annual rate of return is calculated by dividing expected annual income by the average investment. The company’s expected annual income is: $70,000 – $41,500 = $28,500 Its average investment is: $300,000 + $80,000 = $190,000 2 Therefore, its annual rate of return is: $28,500 ÷ $190,000 = 15% EXERCISE 12-9 (a) Cost of hoist: $35,000 + $3,300 + $700 = $39,000. Net annual cash flows: Number of extra mufflers 5 X 52 weeks Contribution margin per muffler ($72 – $36 – $12) Total net annual cash flows (a) X (b) Cash payback period = $39,000 ÷ $6,240 = 6.25 years. (a) 260 (b) X $24 $6,240 (b) Average investment: ($39,000 + $3,000) ÷ 2 = $21,000. Annual depreciation: ($39,000 – $3,000) ÷ 8 = $4,500. Annual net income: $6,240 – $4,500 = $1,740. Annual rate of return = $1,740 ÷ $21,000 = 8.3% (rounded). Copyright © 2012 John Wiley & Sons, Inc. Weygandt, Managerial Accounting, 6/e, Solutions Manual (For Instructor Use Only) 12-17 EXERCISE 12-10 (a) 1. 2. Cash payback period: $190,000 ÷ $50,000 = 3.8 years. Annual rate of return: $12,000 ÷ [($190,000 + $0) ÷ 2] = 12.63%. (b) Item Net annual cash flows Capital investment Net present value Amount Years PV Factor $ 50,000 1–5 3.60478 Present Value $180,239)) (190,000) $ (9,761))) EXERCISE 12-11 (a) Year 1 2 3 Net Annual Cash Flow $45,000 40,000 35,000 Cumulative Net Cash Flow $ 45,000 85,000 120,000 Cash payback period 2.57 years (2 + [($105,000 – $85,000) ÷ $35,000]) (b) Average annual net income = ($10,000 + $12,000 + $14,000 + $16,000 + $18,000) ÷ 5 = $14,000 Average investment = ($105,000 + $0) ÷ 2 = $52,500 Annual rate of return = $14,000 ÷ $52,500 = 26.67% (c) Net cash flows Year 1 2 3 4 5 Discount Factor, 12% 0.89286 0.79719 0.71178 0.63552 0.56743 Amount $45,000 40,000 35,000 30,000 25,000 Present value of cash in flows Initial investment 130,231 (105,000) Net present value 12-18 Copyright © 2012 John Wiley & Sons, Inc. Present Value $ 40,179 31,888 24,912 19,066 14,186 $ 25,231 Weygandt, Managerial Accounting, 6/e, Solutions Manual (For Instructor Use Only) SOLUTIONS TO PROBLEMS PROBLEM 12-1A (a) Project Kilo $150,000 ÷ ($14,000 + $30,000) = 3.41 years Year 1 2 3 4 5 Project Lima Cash Flow $51,000 ($18,000 + $33,000) $50,000 ($17,000 + $33,000) $49,000 ($16,000 + $33,000) $45,000 ($12,000 + $33,000) $42,000 ($ 9,000 + $33,000) Cumulative Cash Flow $ 51,000 $101,000 $150,000 $195,000 $237,000 Cash payback period 3.33 years $165,000 – $150,000 = $15,000 $15,000 ÷ $45,000 = .33 Year 1 2 3 4 5 Project Oscar Cash Flow $67,000 ($27,000 + $40,000) $63,000 ($23,000 + $40,000) $61,000 ($21,000 + $40,000) $53,000 ($13,000 + $40,000) $52,000 ($12,000 + $40,000) Cumulative Cash Flow $ 67,000 $130,000 $191,000 $244,000 $296,000 Cash payback period 3.17 years $200,000 – $191,000 = $9,000 $9,000 ÷ $53,000 = .17 Copyright © 2012 John Wiley & Sons, Inc. Weygandt, Managerial Accounting, 6/e, Solutions Manual (For Instructor Use Only) 12-19 PROBLEM 12-1A (Continued) (b) Project Kilo Item Net annual cash flows Capital investment Negative net present value Discount Factor .86957 .75614 .65752 .57175 .49718 Year 1 2 3 4 5 Total Capital investment Positive (negative) net present value Amount $44,000 Years 1–5 PV Factor 3.35216 Present Value $147,495 (150,000) $ (2,505) Project Lima Cash Flow PV $ 44,348 $ 51,000 37,807 50,000 32,218 49,000 25,729 45,000 20,882 42,000 $237,000 160,984 (165,000) Project Oscar Cash Flow PV $ 67,000 $ 58,261 63,000 47,637 40,109 61,000 30,303 53,000 25,853 52,000 202,163 $296,000 (200,000) $ $ (4,016) 2,163 (c) Project Kilo = $14,000 ÷ [($150,000 + $0) ÷ 2] = 18.67%. Project Lima = $14,400 ÷ [($165,000 + $0) ÷ 2] = 17.5%. Project Oscar = $19,200 ÷ [($200,000 + $0) ÷ 2] = 19.2%. (d) Project Kilo Lima Oscar Cash Payback 3 2 1 Net Present Value 2 3 1 Annual Rate of Return 2 3 1 The best project is Oscar. 12-20 Copyright © 2012 John Wiley & Sons, Inc. Weygandt, Managerial Accounting, 6/e, Solutions Manual (For Instructor Use Only) PROBLEM 12-2A (a) Sales Expenses Drivers’ salaries Out-of-pocket expenses Depreciation Total expenses Net income Cash inflow (1) Annual Net Income (2) Annual Cash Inflow *$108,000* $108,000 * 48,000* * 30,000* * 25,000* * 103,000* *$ 5,000* 48,000 30,000 0 78,000 $ 30,000 *5 vans X 10 trips X 6 students X 30 weeks X $12.00 = $108,000. (b) 1. Cash payback period = $75,000 ÷ $30,000* = 2.50 years. *$5,000 + $25,000 2. Annual rate of return = $5,000 ÷ ($75,000 + 0) = 13.33%. 2 (c) Present value of annual cash inflows ($30,000 X 2.28323*) = $68,497 Capital investment = (75,000) Net present value = $ (6,503) *3 years at 15%, PV of annuity of 1. (d) The computations show that the commuter service is not a wise investment for these reasons: (1) annual net income will only be $5,000, (2) the annual rate of return (13.33%) is less than the cost of capital (15%), (3) the cash payback period is 83% (2.5 ÷ 3) of the useful life of the vans, and (4) net present value is negative. Copyright © 2012 John Wiley & Sons, Inc. Weygandt, Managerial Accounting, 6/e, Solutions Manual (For Instructor Use Only) 12-21 PROBLEM 12-3A (a) (1) Option A Present value of net annual cash flows Present value of cost to rebuild Present value of salvage value Cash Flows a $40,000a ( (50,000) ( 0) X X X X 8% Discount Factor 5.20637 .73503 .58349 Capital investment Net present value = = = = Present Value ($208,255) ( (36,752) ( 0) ($171,503) ( (160,000) ($ 11,503) a Net annual cash flows = $70,000 – $30,000 = $40,000 (2) Profitability index = $171,503/$160,000 = 1.07 (3) The internal rate of return can be approximated by finding the discount rate that results in a net present value of approximately zero. This is accomplished with a 10% discount rate. Present value of net annual cash flows Present value of cost to rebuild Present value of salvage value Cash Flows a $40,000a ( (50,000) ( 0) X X X X 10% Discount Factor 4.86842 .68301 .51316 Present = Value = ($194,737) = ( (34,151) = ( 0) ($160,586) (160,000) ($ 586 8% Discount Factor 5.20637 .73503 .58349 Present = Value = $281,144 = 0 = 4,668 $285,812 (227,000) $ 58,812 Capital investment Net present value a Net annual cash flows = $70,000 – $30,000 = $40,000 (1) Option B Present value of net annual cash flows Present value of cost to rebuild Present value of salvage value Cash Flows b $54,000b 0 8,000 X X X X Capital investment Net present value b Net annual cash flows = $80,000 – $26,000 = $54,000 (2) Profitability index = $285,812/$227,000 = 1.26 12-22 Copyright © 2012 John Wiley & Sons, Inc. Weygandt, Managerial Accounting, 6/e, Solutions Manual (For Instructor Use Only) PROBLEM 12-3A (Continued) (3) Internal rate of return on Option B is 15%, as calculated below: Present value of net annual cash flows Present value of cost to rebuild Present value of salvage value Cash Flows b $54,000b 0 8,000 X X X X 15% Discount Factor 4.16042 .57175 .37594 Capital investment Net present value b Present = Value = $224,663 = 0 = 3,008 $227,671 (227,000) $ 671 Net annual cash flows = $80,000 – $26,000 = $54,000 (b) Option A has a lower net present value than Option B, and also a lower profitability index and internal rate of return. Therefore, Option B is the preferred project. Copyright © 2012 John Wiley & Sons, Inc. Weygandt, Managerial Accounting, 6/e, Solutions Manual (For Instructor Use Only) 12-23