Reactions of Ethylene Answers
NOTE: Double bonds are shown here for clarity only.
1)
a)
Construct equations (name the products) for
chlorination of propene
CH2=CHCH3(g) + CL2(g) ->
b)
CH2Cl CHCl CH3(l) (1, 2-dichloropropane)
hydrobromination of 1 heptene
CH2=CHCH2CH2CH2CH2CH3(l) + HBr(g) -> CH3CHBr CH2CH2CH2CH2CH3(l)
(2-bromoheptane) (can also make 1-bromoheptane)
c)
hydration of 3-hexene
CH3CH2CH=CHCH2CH3 (l) + H2O (l) -> CH3CH3CHOH CH2CH2CH3(l)
(3-hexanol)
d)
oxidation of 2-butene
CH3CHCHCH3(g) + O2(g) + H2O(l)
[O]
CH3CHOH CHOH CH3 (l)
2,3-butanediol
e)
aqueous chlorination of propene
CH2CHCH3(g) + Cl2(aq)  CH2Cl CHOH CH3 (l)
1-chloro-2-propanol.
WHY DOESN’T THIS LOOK GOOD?
READ THE PRAC MANUAL 1.1
2)
Propose a method for the preparation of
(include an equation)
a)
b)
c)
d)
e)
2-chlorobutane (addition of HCl (g) to 1-butene or 2-butene)
2,3-dichlorobutane (addition of CL2(g) to 2 butene)
3-bromo-2-butanol (addition of Br2(aq) to 2 butene)
2-butanol (addition of water to 1-butene)
2,3-pentanediol (oxidation of 2-pentene)
Using what you have done already, and the answers to Q1 you should be able to
write the balanced equations now I have given you the reagents.