Chapter 8: Electron Configurations and the Periodic Table Chem 6A, Section D Oct 25, 2011 Chem 6A Michael J. Sailor, UC San Diego 1 The Periodic Table of the Elements Chem 6A Michael J. Sailor, UC San Diego 2 Electron Configurations Aufbau ="Building up" As each proton is added to the nucleus, you add an electron to the hydrogen-like orbitals. Add to s, then d, then p orbitals of the same principle quantum number 3 Chem 6A Michael J. Sailor, UC San Diego Quantum numbers Quantum Number Called Describes n l Principle quantum number SIZE and ENERGY Angular momentum (Azimuthal) quantum number SHAPE ml Magnetic quantum number ORIENTATION ms Electron spin quantum number INTRINSIC ANGULAR MOMENTUM OF THE ELECTRON Chem 6A Michael J. Sailor, UC San Diego 4 The Periodic Table of the Elements 5 Chem 6A Michael J. Sailor, UC San Diego The Periodic Table of the Elements 1s 2s 3s 4s 5s 6s 7s 3d 4d 5d Chem 6A Michael J. Sailor, UC San Diego 2p 3p 4p 5p 6p 6 Electron Configurations How to fill up orbitals with electrons? • Electrons go in lowest energy orbital first, they spread over all the empty orbitals with the same spin, then they pair up. • Pauli Exclusion Principle: No more than 2 electrons per orbital, must be of opposite spin. • Hund's rule: When there is more than one orbital with the same energy, fill up empty orbitals first, keeping the spins the same. 7 Chem 6A Michael J. Sailor, UC San Diego The Building-up Principle (aufbau) Pauli exclusion principle: no more than 2 electrons in each orbital. Pairs of electrons in the same orbital must have opposite spins. Hund’s rule: When there is more than one orbital with the same energy (degenerate), fill up empty orbitals with one electron before pairing the electrons, keep the spins the same. from T. Moeller “Inorganic Chemistry” Wiley 1952 9 Similar figure in your textbook Chem 6A Michael J. Sailor, UC San Diego 8 Stern-Gerlach Experiment: Ag atoms Screen OVEN Containing Ag Magnet The atoms split into two paths in a magnetic field This experiment tells us that each individual electron has a magnetic moment; there must be a 4th quantum number: Electron spin, or ms Chem 6A Michael J. Sailor, UC San Diego 9 Electron Configurations Example Electron configurations: Potassium 1s22s22p63s23p64s1 shorthand: [Ar]4s1 Vanadium [Ar]4s23d3 Selenium [Ar]4s23d104p4 Note: (n+1)s orbitals always fill up before nd. 4f and 5d orbitals have similar energies, Lanthanides fill up 4f and 5d orbitals in somewhat random order. Don’t worry about lanthanides for now. Chem 6A Michael J. Sailor, UC San Diego 10 Electron Configurations Chem 6A Michael J. Sailor, UC San Diego 11 Electron Configurations-Exceptions Exceptions: everything fills up normally, with a few exceptions: Cr: [Ar]4s13d5 Why? half-filled shells are unusually stable. This one you can't predict, just memorize. Cu: [Ar]4s13d10 Why? fully-filled shells are stable. Memorize these Chem 6A Michael J. Sailor, UC San Diego 12 Ordering of s, p, d, and f orbitals Relative ENERGIES: s<p<d<f Fill ns, then np, then nd orbital. Example (V): Vanadium: 1s22s22p63s23p64s23d3 You always fill up (n+1)s before nd. Why? 13 Chem 6A Michael J. Sailor, UC San Diego Ordering of s, p, d, and f orbitals You always fill up (n+1)s before nd. Why? Main factors determining relative energy ordering for orbitals with the same value of n: – Nuclear charge – 3 s orbital Electron-electron repulsion (shielding) 3 px orbital 3 dxz orbital 17 www.rsc.org/chemsoc/visualelements/orbital/ Chem 6A Michael J. Sailor, UC San Diego 14 Ordering of s, p, d, and f orbitals ORBITAL SHAPE: Which orbital allows the electrons to get closer to the nucleus? Radial Probability Functions 1s Ψ2 (probabbility) The electron likes to get closer to the nucleus if it can, so it goes into the s orbital before the p orbital 2s has greater probability “Electron close to the nucleus than 2p Penetration” 2p 2s 0 1 2 3 r, Bohr radii 4 Chem 6A Michael J. Sailor, UC San Diego 5 6 15 Electron Penetration The lower the value of l, the greater the penetration. Relative ENERGIES: s < p < d < f Chem 6A Michael J. Sailor, UC San Diego 16 Chem 6A Michael J. Sailor, UC San Diego 17 Periodic Trends ATOMIC RADII Relative size of atoms IONIC RADII Relative size of ions IONIZATION ENERGY ELETRON AFFINITY Chem 6A Michael J. Sailor, UC San Diego 18 Periodic Trends: ATOMIC RADII Fig 8.8 TREND: • small on top, big on bottom • shrink going L to R, because nuclear charge is increasing w/o increasing n 22 19 Chem 6A Michael J. Sailor, UC San Diego Periodic Trends: ATOMIC RADII Fig 8.9 Chem 6A Michael J. Sailor, UC San Diego 20 Problem: Atomic Radius Rank the following set of main group elements in order of decreasing atomic size: Br, Rb, Kr, Ca, Sr Chem 6A Michael J. Sailor, UC San Diego 21 Solution: Atomic Radius Rank in order of decreasing atomic size: Br, Rb, Kr, Ca, Sr Elements with n = 4: Br, Kr, Ca Size increases going L->R, so big to small is Ca > Br > Kr Elements with n = 5: Rb, Sr Size increases going L->R, so big to small is Rb > Sr Chem 6A Michael J. Sailor, UC San Diego 22 Solution: Atomic Radius Rank in order of decreasing atomic size: Br, Rb, Kr, Ca, Sr Is Sr > Ca or is Ca > Sr? Sr > Ca, so the final ranking is Rb > Sr > Ca > Br > Kr 23 Chem 6A Michael J. Sailor, UC San Diego Periodic Trends: IONIC RADII Fig 8.20 Chem 6A Michael J. Sailor, UC San Diego 24 Periodic Trends: IONIC RADII Fig 8.21 Chem 6A Michael J. Sailor, UC San Diego 25 Periodic Trends: IONIZATION ENERGY and ELECTRON AFFINITY • IONIZATION ENERGY: A → A+ + e- • ELECTRON AFFINITY: A + e - → A- They are not the reverse of each other! Chem 6A Michael J. Sailor, UC San Diego 26 Periodic Trends: IONIZATION ENERGY Fig 8.10 27 Chem 6A Michael J. Sailor, UC San Diego Periodic Trends: IONIZATION ENERGY It is really hard to pull an electron from He Fig 8.11 It is really easy to pull an electron from Cs Chem 6A Michael J. Sailor, UC San Diego 28 Periodic Trends: ELECTRON AFFINITY Fig 8.13 Chem 6A Michael J. Sailor, UC San Diego 29 Periodic Trends: ELECTRON AFFINITY ELECTRON AFFINITY: Can be either exothermic or endothermic Chem 6A Michael J. Sailor, UC San Diego 30 Periodic Trends: SUMMARY Fig 8.14 31 Chem 6A Michael J. Sailor, UC San Diego Periodic Trends: IONIZATION ENERGY Fig 8.12 1st, 2nd, and 3rd ionization energies for Beryllium (Be) Why is 3rd IE so much larger than 1st or 2nd IE? Chem 6A Michael J. Sailor, UC San Diego 32 Problem: Predicting Common Oxidation States from Ionization Energy The ionization energies for lead are given below. Based on this information, predict the common oxidation states for this element. Chem 6A Michael J. Sailor, UC San Diego 33 Lead in the Washington, DC water supply March 12, 2004 Steve Curwood radio interview with Marc Edwards on “Living on Earth:” D.C. WATER WOES CURWOOD: “Last year, at the request of some Washington, D.C. residents, Marc Edwards, a civil engineer and corrosion specialist with Virginia Tech, began testing the quality of drinking water being piped into their homes. Soon, he says, he found concentrations of lead in that water that he describes as being literally off the charts. Some of the levels were so high that the water could be considered hazardous waste.” http://www.loe.org/ETS/organizations.php3?action=printContentItem&orgid=33&typeID=18&itemID=195#feature3 33 Chem 6A Michael J. Sailor, UC San Diego 34 Solution: Predicting Common Oxidation States from Ionization Energy 7000 IE, KJ/mol 6000 5000 Pb3+ → Pb4+ 4000 3000 2000 Pb+ → Pb2+ 1000 0 1 2 3 State 4 5 Pb2+, Pb4+ are the most common oxidation states for Pb. Chem 6A Michael J. Sailor, UC San Diego 35 Inert Pairs Sn2+, Tl+, Pb2+, Bi3+ are stable ions, even though they do not have a noble gas configuration: Pb: [Xe] 6s25d106p2 Pb2+: [Xe] 6s25d10 Pb4+: [Xe] 5d10 The s electrons are not as easily removed in these elements--a pair of s electrons is “inert” Common oxides of lead: PbO, PbO2 Chem 6A Michael J. Sailor, UC San Diego 36 Lead in the Washington, DC water supply March 12, 2004 Steve Curwood radio interview with Marc Edwards on “Living on Earth:” D.C. WATER WOES CURWOOD: “Last year, at the request of some Washington, D.C. residents, Marc Edwards, a civil engineer and corrosion specialist with Virginia Tech, began testing the quality of drinking water being piped into their homes. Soon, he says, he found concentrations of lead in that water that he describes as being literally off the charts. Some of the levels were so high that the water could be considered hazardous waste.” http://www.loe.org/ETS/organizations.php3?action=printContentItem&orgid=33&typeID=18&itemID=195#feature3 Chem 6A Michael J. Sailor, UC San Diego 37 Use of monochloramine in water purification April, 1999 Guidance Manual from EPA: “Use an alternative or supplemental disinfectant or oxidant such as chloramines or chlorine dioxide that will produce fewer DBPs (Disinfectant Byproducts).” “Monochloramine, and chlorine dioxide are typically used to maintain a disinfectant residual in the distribution system” Chem 6A Michael J. Sailor, UC San Diego 38 Use of monochloramine in water purification Chlorine: Cl2 + H2O → HOCl Monochloramine: + H+ + Cl- NH3 + HOCl → NH2Cl + H2O • Monochloramine kills bacteria too • Not as strong an oxidant as chlorine or hypochlorite • Produces fewer potentially toxic or carcinogenic byproducts Chem 6A Michael J. Sailor, UC San Diego 39 Presence of lead in simulated drinking water 2 months after switching to chloramine disinfectant water disinfected with chlorine Rebecca Renner, ENVIRONMENTAL SCIENCE & TECHNOLOGY JUNE 15, 2004 Chem 6A Michael J. Sailor, UC San Diego 40 Chemistry of lead oxides oxidation state: + 4 Hypochlorite reaction: Pb + 2HOCl → PbO2 + 2HCl Monochloramine reaction: oxidation state: + 2 Pb + NH2Cl + H2O → PbO + NH3 + HCl Solubility in water: PbO: 0.017 g/L at 20 °C Solubility of PbO2 << PbO Chem 6A Michael J. Sailor, UC San Diego 41 Acid-Base Behavior of Oxides Some metal oxides and most metalloid oxides are amphoteric (react with acid or base): acid: Al2O3 + 6H+ → 2Al3+ + 3H2O base: Al2O3 + 2OH- + 3H2O → 2Al(OH)4- Chem 6A Michael J. Sailor, UC San Diego 42 Acid-Base Behavior of Oxides Metal oxides produce basic solutions in water: MgO + H2O → Mg2+ + 2OH Because metals are ionic Nonmetal oxides produce acidic solutions: CO2 + H2O → HCO3- + H+ Because nonmetals are covalent Chem 6A Michael J. Sailor, UC San Diego 43 Acid-Base Behavior of Oxides Metal oxides produce basic solutions in water: PbO + H2O → Pb2+ + 2OH PbO2 + 2H2O → Pb4+ + 4OH Neither is very soluble in water, but PbO >> PbO2 Chem 6A Michael J. Sailor, UC San Diego 44 Chemistry of lead oxides “Changes in pH, drops in ORP, or both could destabilize these PbO2 films, and thus increase plumbosolvency…observations that have been made by some water systems of erratic lead release from lead service lines, and increases or decreases without clear correlations with pH, DIC, and temperature, may be caused at least in part by effects of ORP changes.” --Lytle, D.A. and Schock, M.R., U.S. Environmental Protection Agency, 2005 ORP = oxidation-reduction potential DIC = dissolved inorganic carbon Chem 6A Michael J. Sailor, UC San Diego 45 Periodic Trends Main Points: Quantum numbers summary Electron configurations for d-block elements: – First-in, first-out for transition metals: ns electrons removed before (n-1)d electrons – Magnetic properties of transition metal ions: paramagnetism, diamagnetism Chem 6A Michael J. Sailor, UC San Diego 46 Measurement of Magnetic Fig 8.19 Properties No unpaired electrons in compound Compound has unpaired electrons Chem 6A Michael J. Sailor, UC San Diego 47 Problem: Predicting Diamagnetism or Paramagnetism from Electron Configurations 2+ Possible electron configurations for the paramagnetic ion Fe are given below. Which is correct? (a) (b) (c) (d) (e) None of the above are correct Chem 6A Michael J. Sailor, UC San Diego 48 Solution: Predicting Diamagnetism or Paramagnetism from Electron Configurations Electron configuration for Fe: 4s23d6 Electron configuration for Fe2+: 3d6 Always remove (n+1)s electrons before nd electrons when you make ions. How to place electrons in the d orbital? Follow Hund’s rule: Chem 6A Michael J. Sailor, UC San Diego 49 Solution: Predicting Diamagnetism or Paramagnetism from Electron Configurations So (c) is the correct answer: Fe2+ How many unpaired electrons in Fe2+? 4 Chem 6A Michael J. Sailor, UC San Diego 50