Atmospheric chemistry Lecture 2. Chemical Kinetics 1. Thermal and Photolysis Reactions Two basic types of atmospheric reactions: i) thermal reactions in which the collision of molecules or the interval vibrations of molecules causes a reaction. These reactions are a) decomposition reactions b) combination reactions c) disproportion reactions ii) photochemical reactions in which the absorption of a photon provides energy for reaction. A number of processes can occur after photon absorption. a) collisonal deactivation reaction b) photodissociation reaction c) intramolecular rearrangement reactions: d) photoisomerization reactions e) direct reaction: the excited species directly react with another molecule 1 2. Thermal Reaction Rates 2.1. Bimolecular reactions Consider the following bimolecular reaction A+B→C+D The reaction rate is expressed as − d d [ A] = − [ B ] = k[ A][ B ] dt dt In this expression the concentrations are expressed as number densities so that the product [A][B] is proportional to the frequency of collisions. The temperature dependence for the reaction rate constant k, k = Ae − Ea / RT where A is the A-factor or the pre-exponential factor, Ea is the activation energy or the threshold energy for reaction, R is the gas constant, T is the gas temperature. 2 A is related to molecular cross-section × mean relative collision velocity × steric factor • The maximum possible value of the rate constant of a bimolecular reaction is achieved if every molecular collision between A and B results in reaction. This is called the gas-kinetic collision rate. • The corresponding value of the second order rate constant k at 298 k for molecules of interests in atmospheric chemistry is in the range of 10 –10 cm3 molecule s-1. • Most reactions have rate constants less than this. o (1) The activation energy Ea must be overcome for the reaction to proceed. o (2) Molecules that are geometrically complex may have to be aligned properly at the point of collision for reaction to take place and perfect alignment is not achieved in every collision. Examples of bimolecular reactions: O3 + NO → NO2 + O2, k = 2.0×10-12 exp(-1400/T) OH + HCHO → HO2 + CO + H2O, k = 8.8×10-12 exp(25/T) 3 2.2 Three-body reactions A + B + M → AB + M • A three-body reaction involves reaction of two species A and B to form one single product AB. • This reaction requires a third body M to stabilize the excited product AB* by collision. • The third body M is any inert molecule that can remove the excess energy from AB* and eventually dissipate it as heat. (N2, O2 in the atmosphere) Example 1: O + O + M → O2 + M The elementary steps of a third body reaction are: A + B → AB* (R3) AB* → A + B (R4) AB* + M →AB + M* (R5) M* → M + heat (R6) Example 2: OH + NO2 + M → HNO3 + M Example 3: O + O2 + M → O3 + M 4 The rate of a three-body reaction is defined as the formation rate of AB. d [ AB] = k 5 [ AB*][M ] dt (9.3) In the atmosphere, [M] is simply the number density of air. pseudo-steady-state approximation (PSSA) • When an intermediate (e.g., AB*) has a very short lifetime and reacts as soon as it is produced, the rate of generation of AB* is equal to the rate of disappearance. • PSSA is a fundamental way to deal with such reactive intermediates when deriving the overall rate of a chemical reaction mechanism. PSSA gives k3[A][B] = k4 [AB*] + k5[AB*][M] [ AB*] = k 3 [ A][ B ] k 4 + k5 [M ] d [ AB ] k 3 k 5 [ A][ B ][ M ] = dt k 4 + k5 [M ] 5 (9.5) (9.3) d [ AB ] k 3 k 5 [ A][ B ][ M ] = dt k 4 + k5 [M ] The formation rate of AB depends on the concentration of M, i.e., pressure-dependent. • Low-pressure limit case: R α [M] k5[M] << k4, Æ d [ AB ] k 3 k 5 = [ A][ B ][ M ] . dt k4 ko = k3k5/k4 is referred as the low-pressure limit rate constant. • High-pressure limit case: R independent of [M]. [M] is sufficiently large. Æ k5[M] >> k4, Æ d [ AB] = k 3 [ A][ B] . dt k3 is referred as the high-pressure limit rate constant k∞. General form of the rate of a three-body reaction d [ AB ] k o [ A][ B ][ M ] = k dt 1 + o [M ] k∞ 6 3. Photolysis reactions Sunlight drives the chemistry of the atmosphere. These reactions that involve the breaking of a chemical bond by an incident photon are called photolysis reactions. Table 1. Comparison of photon energies with chemical bond energies Name Typical wavelength (nm) Typical range of energies (kJ/mol) Visible Red 700 170 Orange 620 190 Yellow 580 210 Green 530 230 Blue 470 250 Violet 420 280 Near ultraviolet 400-200 300-600 Vacuum ultraviolet 200-50 600-2400 7 Figure 1. Some of the photolysis reactions that occur at various altitudes in the atmosphere. (Source: Atkins, Physical Chemistry, pp820.) 8 The primary step of a photolysis reaction is: X + hv → X* X*: an electronically excited state of molecule X. X* subsequently undergo either physical or chemical processes: Physcial processes: Fluorescence X* → X + hv Collisional deactivation X* + M → X + M Chemical processes: Dissociation X* → Y + Z Isomerization X* → X’ Direct reaction X* + Y → Z1 + Z2 Intramolecular rearrangement X* → Y X* → X+ + e Ionization The general form of photolysis reactions: X + hv → Y + Z (R11). The rate of reaction is: − d d d [ X ] = [Y ] = [ Z ] = k[ X ] , (9.11) dt dt dt k: photolysis rate constant for reaction R11, unit: s-1. 9 Determination of k: k = q xσ x I . (9.12) qx: quantum yield (molecules photon-1), varying from 0 to 1. σx: absorption cross-section in units of cm2 molecule-1. I: number of photos crossing a unit horizontal area per unit time from any direction (unit: photons cm-2 s-1). 3.1 Actinic flux The actinic flux at the earth’s surface is affected by the extent of light absorption and scattering in the atmosphere, the zenith angle, the extent of surface reflection, and the presence of clouds. 10 Estimation of the actinic flux: use a radiative transfer model. Figure 3. Calculated actinic flux 11 Table 2. Calculated Actinic flux as a function of wavelength and zenith angle 12 3.2. Calculation of photolysis rates The three parameters, qx, σx, and I, vary with wavelength. It is necessary to integrate over the wavelength spectrum to obtain the total rate of photolysis: k=∫ λi λ = 290 nm q x (λ )σ λ (λ ) I λ dλ . (9.13) λi: the longest wavelength at which the light absorption occurs. (The shortest wavelength for photochemistry in the troposphere is 290 nm). In practice, the sum of product q(λ) σ(λ) I(λ) over discrete wavelength intervals ∆λ is used. k= λi q (λ )σ (λ )I ' (λ ) ∑ λ = 290 nm σ (λ ) and q(λ ) : the values averaged over a wavelength interval ∆λ centered at λ, ( σ (λ ) : cm2 molecule-1) I'(λ): actinic flux in photons cm-2s-1 summed over the wavelength interval ∆λ centered at λ. 13 Experimental methods for σ (λ ) and k: σ (λ ) • The absorption cross sections are determined at various gas phase concentrations in 1 atm of ultra-pure air using a conventional UVvisible spectrophotometer. • An alternate, experimentally more convenient method, is to measure the absorption spectrum of the compound dissolved in an inert organic solvent. k • following the simultaneous rates of disappearance of the species of interest and of a reference organic in an irradiated NO-organic-air mixture. o limitation: the minimum value of k which can be accurately measured is about 1 x 10-5 s-1). This is a relatively rapid rate, thus while nitrite, α-dicarbonyls, and nitrosamine photolysis rates could be measured, that of simple aldehydes and ketones could not. • use experimentally determined absorption cross sections σ(λ), q(λ) available in the literature, in combination with actinic flux estimates I(λ), to calculate k. o Limitation: Many q(λ) values available in the literature were obtained at reduced pressures in absence of air, which subjects the calculated k to significant errors. 14 3.3 Important atmospheric species that undergo photolysis Species ozone Photochemical process O3 + hν Æ O1D + O2 λ < 320 nm O3 + hν Æ O3P + O2 λ ≥ 320 nm Nitrogen dioxide NO2 + hν Æ O3P + NO λ < 397.8 nm Nitrous acid HONO + hν Æ OH + NO λ < 400 nm Organic nitrite Nitric acid RONO + hν Æ RO + NO λ < 430 nm HNO3 + hν Æ OH + NO2 200nm <λ < 320nm RCH2NO2 + hν Æ RCH2O + NO2 200nm <λ < 330nm CH3C(O)OONO2 ÆCH3C(O)OO + NO2 200nm <λ < 300nm Organic nitrate Peroxyacetyl nitrate (PAN) comment Not siginifant in tropospheric chemistry A key step in ozone formation chemistry A major source for OH radicals Negligible compared to its thermal decomposition NO3 + hν Æ NO + O2, λ ≥ 580 nm Æ NO2 + O3P 470nm <λ < 580nm Nitrosyl chloride ClNO + hν Æ Cl + NO λ < 540 nm Important in marine urban environments A source for OH Hydrogen H2O2 + hν Æ 2 OH λ ≤ 360 nm radicals peroxide formaldehyde HCHO + hν Æ H + HCO λ < 370 nm Æ H2 + CO λ < 370 nm acetaldehyde CH3CHO + hν Æ CH3 + HCO λ < 330 nm Æ CH4 + CO λ < 300 nm acetone CH3COCH3 + hν Æ CH3 + CH3CO λ < 330 nm dicarbonyls Photolysis e.g. (CHO)2 + hν Æ 2 CO + H2 predominates over Æ HCHO + CO reaction with OH or λ < 470 nm O3 Nitrate radical 15 4. Radical-assisted reactions Radicals: chemical species with an unpaired electron in the valence shell. Examples: ●OH, HO2●, ●CH3, ●OCH3, Cl How about NO, O ? Radical Initiation, propagation, and termination Radical Initiation Noradical + hv Æ radical + radical Radical propagation Radical + nonradical Æ Radical + nonradical Radical termination Radical + radical Æ nonradical + nonradical Radical + radical + M Æ nonradical + M 16 Exercises: (1) The most important oxidizing species for tropospheric compounds is usually the hydroxyl (OH) radical. A standard way of determining the OH rate constant of a compound is to measure its decay in a reactor in the presence of OH relative to the decay of a second compound, the OH rate constant of which is known. Consider two compounds A and B, A being the one for which the OH rate constant is to be determined and B the reference compound for which its OH rate constant is known. Show that the concentrations of A and B in such a reactor obey the following relation: ln [ A]0 k A [ B ]0 ln = [ A]t k B [ B ]t where [A]0 and [B]0 are the initial concentrations, [A]t and [B]t are the concentrations at time t, and kA and kB are the OH rate constants. Thus, plotting ln [ A]0 [ B]0 versus ln [ A]t [ B ]t yields a straight line with slope kA/kB. Knowing kB allows one to calculate kA from the slope. (2) The low and high pressure limiting rate constants for the reaction of ClO with NO2 to form chlorine nitrate at 298 K are given by ko = 1.8 x 10-31 cm6 molecule-2 s-1 and k∞ = 1.5 x 10-11 cm3 molecule-1 s-1. The chemical reaction is ClO + NO2 + M ↔ ClONO2 + M (Forward reaction rate k1 and backward reaction rate k-1). The thermal decomposition reaction rate was measured to be k-1 = 10 -6.16 exp(-90.7 kJ mol-1/RT) in units of cm3 molecule-1 s-1. Calculate (a) the effective bimolecular rate constant k1 at 298 K and 1 atm, and (b) the rate constant k-1 for the thermal decomposition at 298 K and 1 atm. 17