```6
2
5
x
r
x
2
x y
5
3
0 4
x y z
Objective: To simplify square roots and
Standard 2.0
605 = 5i11i11  11 5
Example 1
5
121
11
11
Example 2 140= 2 i2 i5i7 2 35
14
2
10
7 2
5
Example 1 72x3 y 4 z 5
2
36
6 6
2 3 2
3
= 2 i2 i2 i3i3ix ix ix iy iy iy iy iz iz iz iz iz
= 2 i3ix iy iy iz iz 2 ix iz
2 2
 6 x y z 2 xz
Put absolute value bars around odd exponents
so that you don’t get negative answers.
1)
2)
3)
. 147
.128c6
.300a 4
1) 7√3
2) 8|c3|√2
3) 10a2√3
 You
6 i 10 = 6 i10 = 2 i3i2 i5 2 15
56
56

 8 = 2 i2 i2  2 2
7
7
1)
2)
2 14 i 21
324
3
1) 14 6
2)
6 3
 You
cannot have a radical in the denominator
 You can also split it up into two radicals
34
34

=
25
25
7
2
7
=
12
2 i17
34

5
5i5
2
7 i2
14
=

2
2
2 i2
3
21
7 i3
7

i =

6
2 i2 i3 2 3 3 2 3i3
7
1)
56
45
2)
9
18
3)
8 2
2 8
1)
2 70
15
2)
2
2
3)
2
 Page
724 #21-39 ODD
 Find
the missing side of the right triangle:
1.
a = 8, b = 15, c = ?
2.
b = 12, c = 13, a = ?
3.
b = 7, c = 10, a = ?
 Find
the missing side of the right triangle:
5 13
s
15
 How
do we know?
1.
9, 12, 15
2.
1, 2, 3
3.
2, 4, 5
4.
16, 30, 34
 On
a blank piece of paper, make a large
bingo board, 5x5
 Free space in the middle
```