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6 2 5 x r x 2 x y 5 3 0 4 x y z Objective: To simplify square roots and radical expressions. Standard 2.0 605 = 5i11i11 11 5 Example 1 5 121 11 11 Example 2 140= 2 i2 i5i7 2 35 14 2 10 7 2 5 Example 1 72x3 y 4 z 5 2 36 6 6 2 3 2 3 = 2 i2 i2 i3i3ix ix ix iy iy iy iy iz iz iz iz iz = 2 i3ix iy iy iz iz 2 ix iz 2 2 6 x y z 2 xz Put absolute value bars around odd exponents so that you don’t get negative answers. 1) 2) 3) . 147 .128c6 .300a 4 Answers: 1) 7√3 2) 8|c3|√2 3) 10a2√3 You can combine into one radical 6 i 10 = 6 i10 = 2 i3i2 i5 2 15 56 56 8 = 2 i2 i2 2 2 7 7 1) 2) 2 14 i 21 324 3 Answers: 1) 14 6 2) 6 3 You cannot have a radical in the denominator You can also split it up into two radicals 34 34 = 25 25 7 2 7 = 12 2 i17 34 5 5i5 2 7 i2 14 = 2 2 2 i2 3 21 7 i3 7 i = 6 2 i2 i3 2 3 3 2 3i3 7 1) 56 45 2) 9 18 3) 8 2 2 8 Answers: 1) 2 70 15 2) 2 2 3) 2 Page 724 #21-39 ODD Find the missing side of the right triangle: 1. a = 8, b = 15, c = ? 2. b = 12, c = 13, a = ? 3. b = 7, c = 10, a = ? Find the missing side of the right triangle: 5 13 s 15 How do we know? 1. 9, 12, 15 2. 1, 2, 3 3. 2, 4, 5 4. 16, 30, 34 On a blank piece of paper, make a large bingo board, 5x5 Free space in the middle