CHEM 1515 Exam V John V. Gelder December 14, 1993 Name ________________________ TA's Name ________________________ Lab Section ________________________ INSTRUCTIONS: 1. This examination consists of a total of 15 different pages. The last umpteen pages include a whole heck of alot of important mathematical equations, constants and tables. All work should be done in this booklet. You may carefully remove the last 5 pages of the examination. 2. PRINT your name, your TA's name and your laboratory section now in the space at the top of this sheet. DO NOT SEPARATE THE PAGES. 3. Answer all questions that you can and whenever called for show your work clearly. Your method of solving problems should pattern the approach used in lecture. You do not have to show your work for the multiple choice or short answer questions. 4. No credit will be awarded if your work is not shown in problems 2 – 6. Please circle your final answer! 5. Point values are shown next to the problem number. 6. Budget your time for each of the questions. Some problems may have a low point value yet be very challenging. If you do not recognize the solution to a question quickly, skip it, and return to the question after completing the easier problems. 7. Look through the exam before beginning; plan your work; then begin. 8. R e l a x and do well. SCORES Page 2 Page 3 Page 4 Page 5 Page 6 TOTAL _____ (19) _____ (24) _____ (20) _____ (24) _____ (63) ______ (150) CHEM 1515 Exam V – F93 (9) Page 2 1. Write the chemical formula(s) of the product(s) and balance the following reactions. Identify the phase of each product as either (g)as, (l)iquid, (s)olid or (aq)ueous. Soluble ionic compounds should be written in the form of their component ions. a) HC9H7O4(aq) b) C3H8(g) c) Al(s) + NaOH(aq) → + O2(g) → + Fe2O3(s) → (10) 2. Balance the following oxidation-reduction reaction using the half-reaction method. a) H2O2(aq) + Cr(OH)3(s) → CrO42–(aq) basic solution identify the oxidizing agent ________ identify the reducing agent ________ CHEM 1515 Exam V – F93 Page 3 (24) 3. The rate constant for the second order decomposition of NOBr 2NOBr(g) → Br2(g) + 2NO(g) is 1.41 x 10–5 mm Hg–1·s–1 at 10 ˚C. A sample of NOBr at a pressure of 250 mm Hg is placed in a flask at this temperature and sealed. a) What will be the pressure of NOBr in the flask after 100 seconds? b) Assuming there is no NO or Br2 in the container initially, calculate the total pressure in the flask after 100 seconds? c) How much time has elapsed when the total pressure in the flask is 350 mm Hg? CHEM 1515 Exam V – F93 Page 4 (20)4a. Exactly 1 liter of a buffer solution contains 0.400 mol (CH 3)3N, trimethylamine, and 0.500 mol of (CH3)3NHCl. Calculate the pH of the buffer solution. b) Calculate the new pH if 0.0500 mol of hydrochloric acid, HCl, are added to the buffer solution in part a). CHEM 1515 Exam V – F93 Page 5 (14)5a. The mole fraction of ethylene glycol, C2H6O2, in a particular ethylene glycol–water solution is equal to 0.03125. Determine the mass of ethylene glycol in 3.785 L (1 gallon) of this solution if the density of the solution is 1.012 g·mL–1. b. ethylene glycol dissolves in water. Draw a Lewis structure for ethylene glycol which supports this experimental fact. (10)6a. Write the half-reactions and determine the products of the reaction when a piece of sodium metal is added to water at 25 ˚C. b) Is the reaction spontaneous or nonspontaneous? Briefly explain your answer. (Note: You may show a calculation to support your conclusion.) c) If a piece of sodium with a mass 1.00 g is added to 100 mL of water, estimate the pH of the resulting solution. CHEM 1515 Exam V – F93 Page 6 Multiple Choice: (63 points) Print the letter (A, B, C, D, E) which corresponds to the answer selected. 7. ________ 8. ________ 9. ________ 10. ________ 11. ________ 12. ________ 13. ________ 14. ________ 15. ________ 16. ________ 17. ________ 18. ________ 19. ________ 20. ________ 21. ________ 22. ________ 23. ________ 24. ________ 25. ________ 26. ________ 27. ________ ONLY THE ANSWERS IN THE AREA ABOVE WILL BE GRADED. Select the most correct answer for each question. Each question is worth 3 points. 7. ∆G˚ for the reaction BaO(s) + CO2(g) → BaCO3(s) is – at 25 ˚C. Which of the following statements is true? A) B) C) D) The reaction remains spontaneous at higher temperatures. The reaction becomes nonspontaneous at higher temperatures. The reaction is spontaneous at all temperatures. There is not enough information to answer this question. 8. The standard entropy of formation, ∆S˚f of H2O(l) is J A) 70 K J B) 406 K J C) –163 K J D) –266 K 9. A hydrochloric acid solution is 38.0% by mass and it is also 12.5 M. Calculate the density of the solution. A) B) C) D) 0.835 g·mL–1 1.04 g·mL–1 1.20 g·mL–1 1.31 g·mL–1 10. For the half-reaction 2H+(aq) (1.00 x 10–7 M) +2e– → H2(g) (1.00 atm) Ecell is A) +0.829 v B) –0.829 v C) +0.414 v D) –0.414 v CHEM 1515 Exam V – F93 Page 7 11. Which of the following compounds has the greater solubility in water? A) B) C) D) H3C–CH2–CH3 CCl4 CH2Cl2 CH3CH2OH 12. Which of the following solutions will have the lowest freezing point? A) B) C) D) 0.100 M CaCl2 0.100 M NaCl 0.100 M C6H12O6 0.100 M NH4NO3 13. Which of the following mathematical relationships would be used to determine the time required for 30% of a reactant to decompose in the first order reaction; A(g) → products 1.20 A) t = k 0.357 B) t = k 2.33 C) t = k·[A 0] 0.428 D) t = k·[A ] 0 14. In the following reaction aA(g) + bB(g) → cC(g) + dD(g) 1.00 mol of A is mixed with 2.00 mol of B in a 1.00 L container at a given temperature. After 10 minutes the concentration of all species were found to be; after 10 min [A] 0.875 M [B] 1.81 M [C] 0.0625 M [D] 0.250 M The balanced chemical equation must be; A) B) C) D) 2A(g) + 3B(g) → C(g) + 4D(g) A(g) + 2B(g) → C(g) + D(g) A(g) + 2B(g) → C(g) + 4D(g) 2A(g) + B(g) → C(g) + D(g) 15. Increasing the temperature in an endothermic reaction will A) B) C) D) E) increase both the rate of the reaction and the magnitude of the equilibrium constant. increase the rate of the reaction and decrease the magnitude of the equilibrium constant. decrease the rate of the reaction and increase the magnitude of the equilibrium constant. decrease both the rate of the reaction and the magnitude of the equilibrium constant. increase the rate and have no affect on the equilibrium constant. CHEM 1515 Exam V – F93 Page 8 16. Which of the following statements is true? A) The half-life of a second order reaction is independent of the initial concentration of the reactant. B) The decay of many radioactive elements follows second order kinetics. C) When a plot of [reactant] versus time is a straight line the rate constant can be determined from the yintercept. D) The units for the rate constant of a first and a second order reaction are different. 17. Which of the following statements is true? A) The activation energy is the minimum energy required for a reaction to occur. B) The number of collisions per second between molecules in the gas phase is independent of temperature. C) The activation energy can be determined knowing the difference in energy of the reactants and the products in a chemical reaction. D) The activation energy is generally smallest for exothermic reactions. 18. Which of the following statements is true? A) Bimolecular elementary reactions are less common compared to termolecular elementary reactions in most mechanisms. B) Intermediates in chemical reactions are short-lived species which initially appear as a product in a multistep reaction mechanism. C) The overall rate law for a chemical reaction must be identical to the rate law for the fastest elementary step in a multi-step mechanism. D) A catalyst never appears in the elementary step(s) of a mechanism because by definition it is not consumed in the reaction. 19. Which of the following reactions has the most positive value of ∆S˚? A) B) C) D) 2Mg(s) + CO2(g) → 2MgO(s) + C(s) NH3(g) + HCl(g) → NH4Cl(s) 6Li(s) + N2(g) → 2Li3N(s) CaSO4·2H2O(s) → CaSO4(s) + 2H2O(g) 20. A reaction rate for a particular reaction triples when the temperature is raised from 17 ˚C to 37 ˚C. The activation energy is, J A) 287 mol kJ B) 20 mol kJ C) 41 mol kJ D) 57 mol 21. A solution which is 0.0100 M piperidine (C5H10NH2) has a pH of 11.53. Calculate Kb for piperidine. A) B) C) D) 1.13 x 10–3 1.70 x 10–3 3.36 x 10–3 2.95 x 10–12 CHEM 1515 Exam V – F93 Page 9 22. The mechanism, Step 1) Step 2) NO2(g) + NO2(g) → NO3(g) + NO(g) NO3(g) + CO(g) → NO2(g) + CO2(g) (slow) (fast) has been proposed for the reaction NO2(g) + CO(g) → NO(g) + CO2(g) Based on this mechanism the expected rate law is, A) B) C) D) rate = k[NO2]1[CO]1 rate = k[NO2]2[CO]0 rate = k[NO3]1[CO]1 rate = k[NO2]2[CO]1 23. Which of the following solutions is acidic? A) B) C) D) 0.100 M HCN/0.100 M NaCN 0.100 M NH3/0.900 M NH4NO3 0.100 M C5H5N/0.100 M C5H5NHCl 0.100 M HBrO/0.900 M NaBrO (Ka for HCN = 4.9 x 10-10) (Kb for NH3 = 1.8 x 10-5) (Kb for C5H5N = 1.7 x 10-9) (Ka for HBrO = 2.0 x 10-9) 24. Which of the following salts, when dissolved in water, produces a acidic solution? A) B) C) D) (CH3)3NHCl NaIO3 Na2CO3 KCl 25. Which is the strongest acid? A) B) C) D) 0.100 M H2SO3 (Ka1 = 1.7 x 10-2 Ka2 = 6.4 x 10-8) 0.100 M HF (Ka = 7.2 x 10-4) 0.100 M H3PO4 (Ka1 = 7.5 x 10-3 Ka2 = 6.2 x 10-8 Ka3 = 4.2 x 10-13) 0.100 M H3BO3 (Ka = 5.8 x 10-10) 26. Which of the following titrations has the highest equivalence point pH? A) B) C) D) 100.0 mL of 0.500 M HCl and 0.400 M NaOH 40.0 mL of 0.400 M HBr and 0.300 M (CH3)2NH 35.0 mL of 0.900 M HF and 0.450 M NaOH 30.0 mL of 0.800 M HCN and 0.600 M NaOH 27. Rank the pure substances NF3, F2, NaF and HF in terms of increasing strength of attractive forces A) B) C) D) NaF < F2 < NF3 < HF NF3 < F2 < HF < NaF F2 < NF3 < HF < NaF HF < F2 < NaF < NF3 CHEM 1515 Exam V – F93 Page 10 Useful Information Equations Constants PV = nRT L·atm R = 0.0821 mol·K = 8.314 Psolution = χsolventP˚solvent density of H2O = 1.00 ∆T = ikm kf(H2O) = 1.86 ∆H˚rxn = ∑(∆Hf˚(products)) – ∑(∆Hf˚(reactants)) ˚C m J mole.K g cm3 ˚C kb(H2O) = 0.512 m ∆S˚rxn = ∑(S˚(products)) – ∑(S˚(reactants)) ∆G˚rxn = ∑(∆Gf˚(products)) – ∑(∆Gf˚(reactants)) ∆G˚ = ∆H˚ - T∆S˚ ∆G˚ = –RT ln K ∆G = ∆G˚ + RT ln Q J F = 96,500 volt · mol = 96,500 coulombs ∆G˚ = –nFE˚ 0.0257 ln Q n 0.059 Ecell = E˚ – n log Q E 1 k 1 ln k1 = Ra T - T 1 2 2 [A] ln [A] t = -kt o Ecell = E˚ – 0.0257 ln K n 0.059 E˚ = n log K E˚ = 1 1 [A]t [A]o = kt Kp = Kc(RT)∆n x1,2 = –b± b 2 – 4ac for ax2 + bx + c = 0 2a pH = –log[H+] pH + pOH = 14 Kw = 1.0 x 10–14 CHEM 1515 Exam V – F93 Periodic Table of the Elements IA 1 VIIIA 1 2 H He 1.008 3 2 Page 11 IIA IIIA IVA VA VIA VIIA 4.00 4 Li Be 6.94 9.01 11 12 3 Na Mg 22.99 24.30 19 20 4 5 6 7 5 6 7 8 9 10 B C N O F Ne 10.81 12.01 14.01 16.00 19.00 20.18 13 14 15 16 17 18 IIIB IVB VB VIB VIIB 21 22 K Ca Sc Ti 23 24 25 VIII 26 27 IB 28 29 Al Si P S Cl Ar 31 32 33 34 35 IIB 26.98 28.09 30.97 32.06 35.45 39.95 30 36 V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr 39.10 40.08 44.96 47.88 50.94 52.00 54.94 55.85 58.93 58.69 63.55 65.38 69.72 72.59 74.92 78.96 79.90 83.80 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe 85.47 87.62 88.91 91.22 92.91 95.94 (98) 101.1 102.9 106.4 107.9 112.4 114.8 118.7 121.8 127.6 126.9 131.3 55 56 57 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn 132.9 137.3 138.9 178.5 180.9 183.8 186.2 190.2 192.2 195.1 197.0 200.6 204.4 207.2 209.0 (209) (210) (222) 87 88 89 104 105 106 107 108 109 Fr Ra Ac Rf Db Sg Bh Hs Mt (223) 226.0 227.0 (261) (262) (263) (262) (265) (266) 58 Lanthanides 59 60 61 62 63 64 65 66 67 68 69 70 71 Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu 140.1 140.9 144.2 (145) 150.4 152.0 157.2 158.9 162.5 164.9 167.3 168.9 173.0 175.0 90 91 92 93 94 95 96 97 98 99 100 101 102 103 Actinides Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr 232.0 231.0 238.0 237.0 (244) (243) (247) (247) (251) (252) (257) (258) (259) (260) CHEM 1515 Exam V – F93 Page 12 E.1 DISSOCIATION CONSTANTS FOR ACIDS AT 25 ˚C Name Formula Ka1 HC2H3O2 Arsenic H3AsO4 1.8 x 10– 5 8.0 x 10– 3 5.6 x 10– 3 Arsenous Benzoic Boric Butyric acid Carbonic Cyanic Citric H3AsO3 HC7H5O2 H3BO3 HC4H7O2 H2CO3 HCNO H3C6H5O7 6.0 6.5 5.8 1.5 4.3 3.5 7.4 Formic Hydroazoic Hydrocyanic Hydrofluoric Hydrogen chromate ion Hydrogen peroxide Hydrogen selenate ion Hydrogen sulfate ion Hydrogen sulfide Hypobromous Hypochlorous Hypoiodus Iodic Lactic Malonic Oxalic HCHO2 HN3 HCN HF HCrO4– H2O2 HSeO4– HSO4– H2S HBrO HClO HIO HIO3 HC3H5O3 H2C3H2O4 H 2C 2O 4 1.8 1.9 4.9 7.2 3.0 2.4 2.2 1.2 5.7 2.0 3.0 2.0 1.7 1.4 1.5 5.9 Nitrous Phenol Phosphoric Paraperiodic Propanoic Pyrophosphoric Selenous Sulfuric Sulfurous Tartaric HNO2 HC6H5O H3PO4 H5IO6 HC3H5O2 H4P2O H2SeO3 H2SO4 H2SO3 H2C4H4O6 Acetic Ascorbic E.2 HC6H7O6 10–10 10– 5 10–10 10– 5 10– 7 10– 4 10– 4 x 10– 4 x 10– 5 x 10–10 x 10– 4 x 10– 7 x 10–12 x 10– 2 x 10– 2 x 10– 8 x 10– 9 x 10– 8 x 10–11 x 10– 1 x 10– 4 x 10– 3 x 10– 2 x 10– 4 x x x x x x x 4.5 1.3 x 10–10 7.5 x 10– 3 2.8 x 10– 2 1.4 x 10– 5 3.0 x 10– 2 2.3 x 10– 3 strong acid 1.7 x 10– 2 1.0 x 10–3 Ka2 Ka3 1.0 x 10– 7 3.0 x 10–12 5.6 x 10–11 1.7 x 10– 5 4.0 x 10– 7 1.3 x 10–13 2.0 x 10– 6 6.4 x 10– 5 6.2 x 10– 8 5.3 x 10– 9 4.4 5.3 1.2 6.4 4.6 x x x x x 4.2 x 10–13 10– 3 10– 9 10– 2 10– 8 10– 5 DISSOCIATION CONSTANTS FOR BASES AT 25˚C Name Ammonia Aniline Dimethylamine Ethylamine Hydrazine Formula NH3 C6H5NH2 (CH3)2NH C2H5NH2 H2NNH2 1.8 4.3 5.4 6.4 1.3 Kb x 10– 5 x 10–10 x 10– 4 x 10– 4 x 10– 6 Name Hydroxylamine Methylamine Pyridine Trimethylamine Formula HONH2 CH3NH2 C5H5N (CH3)3N Kb 1.1 x 10– 8 4.4 x 10– 4 1.7 x 10– 9 6.4 x 10– 5 CHEM 1515 Exam V – F93 E. 3 Page 13 SOLUBILITY-PRODUCT CONSTANTS FOR COMPOUNDS AT 25˚C Name Formula Barium carbonate Barium chromate Barium Fluoride Barium hydroxide Barium oxalate Barium phosphate Barium sulfate Cadmium carbonate Cadmium hydroxide Cadmium sulfide Calcium carbonate Calcium chromate Calcium fluoride Calcium hydroxide Calcium phosphate Calcium sulfate Cerium(III) fluoride Chromium(III) fluoride Chromium(III) hydroxide Cobalt(II) carbonate Cobalt(II) hydroxide Cobalt(III) hydroxide Copper(I) bromide Copper(I) chloride Copper(I) sulfide Copper(II) carbonate Copper(II) chromate Copper(II) hydroxide Copper(II) phosphate Copper(II) sulfide Gold(III) chloride Iron(II) carbonate Iron(II) hydroxide Iron(II) sulfide Iron(III) hydroxide Lanthanum fluoride Lanthanum iodate Lead carbonate Lead chloride Lead chromate Lead fluoride Lead hydroxide Lead sulfide Magnesium hydroxide Magnesium oxalate Manganese carbonate Mercury(I) sulfide Mercury(II) sulfide Silver sulfide Strontium fluoride BaCO3 BaCrO4 BaF2 Ba(OH)2 BaC2O4 Ba3(PO4)2 BaSO4 CdCO3 Cd(OH)2 CdS CaCO3 CaCrO4 CaF2 Ca(OH)2 Ca3(PO4)2 CaSO4 CeF3 CrF3 Cr(OH)3 CoCO3 Co(OH)2 Co(OH)3 CuBr CuCl Cu2S CuCO3 CuCrO4 Cu(OH)2 Cu3(PO4)2 CuS AuCl3 FeCO3 Fe(OH)2 FeS Fe(OH)3 LaF3 La(IO3)3 PbCO3 PbCl 2 PbCrO4 PbF 2 Pb(OH)2 PbS Mg(OH)2 MgC2O4 MnCO3 Hg2S HgS Ag2S SrF2 Ksp 5.1 x 10-9 1.2 x 10-10 1.0 x 10-6 5 x 10-3 1.6 x 10-7 3.4 x 10-23 1.1 x 10-10 5.2 x 10-12 2.5 x 10-14 8.0 x 10-27 2.8 x 10-9 7.1 x 10-4 3.9 x 10-11 5.5 x 10-6 2.0 x 10-29 9.1 x 10-6 8 x 10-16 6.6 x 10-11 6.3 x 10-31 1.4 x 10-13 1.6 x 10-15 1.6 x 10-44 5.3 x 10-9 1.2 x 10-6 2.5 x 10-48 1.4 x 10-10 3.6 x 10-6 2.2 x 10-20 1.3 x 10-37 6.3 x 10-36 3.2 x 10-25 3.2 x 10-11 8.0 x 10-16 6.3 x 10-18 4 x 10-38 7 x 10-17 6.1 x 10-12 7.4 x 10-14 1.6 x 10-5 2.8 x 10-13 2.7 x 10-8 1.2 x 10-15 8.0 x 10-28 1.8 x 10-11 8.6 x 10-5 1.8 x 10-11 1.0 x 10-47 4.0 x 10-53 6.3 x 10-50 2.5 x 10-9 CHEM 1515 Exam V – F93 Page 14 Table of Standard Reduction Potentials (25 ˚C) CHEM 1515 Exam V – F93 Page 15 A. Acidic Solution Eo(V) Li+ + e– → Li(s) K+ + e– → K(s) –3.045 –2.925 Ba2+ + 2e– → Ba(s) Sr2+ + 2e– → Sr(s) –2.906 Ca2+ + 2e– → Ca(s) Na+ + e– → Na(s) –2.866 Mg2+ + 2e– → Mg(s) H2(g) + 2e– → 2H– Al3+ + 3e– → Al(s) Mn2+ + 2e– → Mn(s) –2.363 Zn2+ + 2e– → Zn(s) Cr3+ + 3e– → Cr(s) –0.763 Fe2+ + 2e– → Fe(s) Cr3+ + e– → Cr2+ –0.440 Cd2+ + 2e– → Cd(s) PbSO4(s) + 2e– → Pb(s) + SO42– PbCl2(s) + 2e– → Pb(s) + 2Cl– Ni2+ + 2e– → Ni(s) Sn2+ + 2e– → Sn(s) Pb2+ + 2e– → Pb(s) 2H+ + 2e– → H2(g) S(s) + 2H+ + 2e– → H2S(aq) Sn4+ + 2e– → Sn2+ –2.888 –2.714 –2.25 –1.662 –1.185 –0.744 –0.408 –0.403 –0.359 –0.268 –0.250 MnO4– + 8H+ + 5e– → Mn2+ + 4H2O(l) 2HClO(aq) + 2H+ + 2e– → Cl2(g) + 2H2O(l) HClO2(aq) + 2H+ + 2e– → HClO(aq) + H2O(l) H2O2(aq) + 2H+ + 2e– → 2H2O(l) S2O 82– + 2e– → 2SO42– O3(g) + 2H+ + 2e– → O2(g) + H2O(l) F2(g) + 2e– → 2F– F2(g) + 2H+ + 2e– → 2HF(aq) ~1.2 1.21 1.229 0.83 1.23 1.29 1.33 1.360 1.455 1.498 1.51 1.63 1.645 1.776 2.00 2.07 2.87 3.06 –0.136 –0.126 0.000 0.142 0.15 Sb2O3(s) + 6H+ + 6e– → 2Sb(s) + 3H2O(l) Cu2+ + e– → Cu+ 0.152 SO42– + 4H+ + 2e– → H2SO3(aq) + H2O(l) AgCl(s) + e– → Ag(s) + Cl– 0.172 Cu2+ + 2e– → Cu(s) SO42– + 8H+ + 6e– → S(s) + 4H2O(l) H2SO3(aq) + 4H+ + 4e– → S(s) + 3H2O(l) I2(s) + 2e– → 2I– MnO4– + e– → MnO42– [PtCl6]2– + 2e– → [PtCl4]2– + 2Cl– O2(g) + 2H+ + 2e– → H2O2(aq) Fe3+ + e– → Fe2+ Pt2+ + 2e– → Pt(s) ClO3– + 3H+ + 2e– → HClO2(aq) + H2O(l) O2(g) + 4H+ + 4e– → 2H2O(l) O2(g) + 4H+(pH = 7) + 4e– → 2H2O(l) MnO2(s) + 4H+ + 2e– → Mn2+ + 2H2O(l) 2HNO2(aq) + 4H+ + 4e– → N2O(g) + 3H2O(l) Cr2O72– + 14H+ + 6e– → 2Cr3+ + 7H2O(l) Cl2(g) + 2e– → 2Cl– PbO2(s) + 4H+ + 2e– → Pb2+ + 2H2O(l) Au3+ + 3e– → Au(s) 0.153 0.222 0.337 0.357 0.450 0.536 0.564 0.68 0.682 0.771 Hg2+ + 2e– → Hg(l) 0.788 Ag+ + e– → Ag(s) 2NO3– + 4H+ + 2e– → N2O4(g) + 2H2O(l) 2Hg2+ + 2e– → Hg22+ NO3– + 4H+ + 3e– → NO(g) + 2H2O(l) Pd2+ + 2e– → Pd(s) Br2(l) + 2e– → 2Br– Br2(aq) + 2e– → 2Br– ClO4– + 2H+ + 2e– → ClO3– + H2O(l) 2IO3– + 12H+ + 10e– → I2(s) + 6H2O(l) 0.799 0.803 0.920 0.96 0.987 1.065 1.087 1.19 1.195 Eo(V) B. Alkaline Solution Mg(OH)2(s) + 2e– → Mg(s) + 2OH– Al(OH)3(s) + 3e– → Al(s) + 3OH– Zn(OH)2(s) + 2e– → Zn(s) + 2OH– Fe(OH)2(s) + 2e– → Fe(s) + 2OH– 2H2O(l) + 2e– → H2(g) + 2OH– 2H2O(l) + 2e– → H2(g) + 2OH–(pH = 7) Cd(OH)2(s) + 2e– → Cd(s) + 2OH– Ni(OH)2(s) + 2e– → Ni(s) + 2OH– Fe(OH)3(s) + e– → Fe(OH)2(s) + OH– 2S(s) + 2e– → S22Cu2O(s) + H2O(l) + 2e– → 2Cu(s) + 2OH– CrO42– + 4H2O(l) + 3e– → Cr(OH)3(s) + 5OH– MnO2(s) + 2H2O(l) + 2e– → Mn(OH)2(s) + 2OH– NO3– + H2O(l) + 2e– → NO2– + 2OH– HgO(s) + H2O(l) + 2e– → Hg(l) + 2OH– PbO2(s) + H2O(l) + 2e– → PbO(s) + 2OH– ClO3– + H2O(l) + 2e– → ClO2– + 2OH– ClO4– + H2O(l) + 2e– → ClO3– + 2OH– O2(g) + 2H2O(l) + 4e– → 4OH– NiO2(s) + 2H2O(l) + 2e– → Ni(OH)2(s) + 2OH– MnO4– + 2H2O(l) + 3e– → MnO2(s) + 4OH– BrO3– + 3H2O(l) + 6e– → Br– + 6OH– ClO– + H2O(l) + 2e– → Cl– + 2OH– O ( ) H O(l) 2 O ( ) 2OH –2.690 –2.30 –1.245 –0.877 –0.828 –0.43 –0.809 –0.72 –0.56 –0.447 –0.358 –0.13 –0.05 0.01 0.098 0.247 0.33 0.36 0.401 0.490 0.588 0.61 0.89 1 24 CHEM 1515 Exam V – F93 Page 16 CHEM 1515 Exam V – F93 Page 17 Thermodynamic Values (25 ˚C) o o Substance ∆H f and State kJ mol ∆G f kJ mol Carb o n C(s) (graphite) C(s) (diamond) CO(g) CO2(g) CH4(g) CH3OH(g) CH3OH(l) H2CO(g) HCOOH(g) HCN(g) C2H2(g) C2H4(g) CH3CHO(g) C2H5OH(l) C2H6(g) C3H6(g) C3H8(g) 0 2 -110.5 -393.5 ? -201 -239 -116 -363 135.1 227 52 -166 -278 -84.7 20.9 -104 0 3 -137 -394 -51 -163 -166 -110 -351 125 209 68 -129 -175 -32.9 62.7 -24 Bromine Br2(l) BrCl(g) 0 14.64 0 -0.96 ∆H f . J K mol and State kJ mol ∆G f kJ mol 6 2 198 214 186 240 127 219 249 202 201 219 250 161 229.5 266.9 270 Nitrogen N2(g) NCl3(g) NF3(g) NH3(g) NH3(aq) NH2CONH2(aq) NO(g) NO2(g) N2O(g) N2O4(g) N2O5(g) N2H3CH3(l) HNO3(aq) HNO3(l) NH4Cl(s) NH4ClO4(s) 0 230 -125 ? ? ? 90 32 82 10 -42 54 -207 -174 -314 -295 0 271 -83.6 -17 -27 ? 87 52 104 98 134 180 -111 -81 -201 -89 Silver Ag(s) Ag+(aq) Ag(S2O3)3-(aq) AgBr(s) AgCl(s) 0 105.6 -1285.7 -100.4 -127.1 0 77.1 --96.9 -109.8 42.6 72.7 -107.1 96.2 152. 240 0 -23 0 7 223 121 -167 -92 -131 -95 57 187 Fluorine F2(g) F-(aq) HF(g) 0 -333 -271 0 -279 -273 203 -14 174 Magnesium Mg(s) Mg(aq) MgO(s) Oxygen O2(g) O(g) 249 O3(g) 0 203 0 -230 -286 -242 0 115 0 -157 -237 -229 o Substance Chlorine Cl 2 (g) Cl2(aq) Cl-(aq) HCl(g) Hydrogen H2(g) H(g) 217 H+(aq) OH-(aq) H2O(l) H2O(g) o So 131 0 -11 70 189 0 -492 -601 0 -456 -569 33 -118 26.9 0 232 143 0 161 163 205 239 So . J K mol 192 -137 -139 193 111 174 211 240 220 304 178 166 146 156 95 186 Sulfur S(rhombic) SO2(g) SO3(g) H2S(g) 0 -296.8 -395.7 -20.17 0 -300.2 -371.1 -33.0 31.8 248.8 256.3 205.6 Titanium TiCl4(g) TiO2(s) -763 -945 -727 -890 355 50 Aluminum AlCl3(s) -526 -505 184 Barium BaCl2(aq) -872 Ba(OH)2·8H2O(s) -3342 -823 -2793 123 427 Iodine I2(s) HI(g) 0 25.94 0 1.30 116.7 206.3