Kinetics and Mechanism in Inorganic Chemistry Review Tutorial Questions Question 1 The following equations represent a generalised scheme for a reaction proceeding through an associative mechanism. k1 ML5 XY ML5 X + Y k1 k2 ML5 Y + X ML5 XY k2 (a) One such reaction was studied experimentally and it was found that the reverse reaction (k-2) is completely negligible. Modify the equations to show this special case. (b) Prove for the special case in (a) that the generalised rate law is d [ML5 Y] k1k2 [ML5 X][Y] dt k1 k2 (c) Write down the experimental rate law for the reaction in (a); use the symbol kIIobs for the experimentally determined rate constant. (d) Suppose the reaction is studied with [ML5X] = 5 × 10-6 M, and in successive experiments [Y] is varied between 0.100 M and 0.0100 M. Why is it true to say that under these conditions the experimental rate law becomes I kobs II kobs [Y] (e) What are the units of the two rate constants in (d)? (f) Sketch a graph to show how kIIobs can be determined from the experimental data. What is the intercept of the graph? (g) Relate kIIobs to the microscopic rate constants in (b). (h) Suppose the reaction is studied up to very high concentrations of Y (say, up to [Y] = 5 M). Will you expect to see saturation kinetics? (Assume at these concentrations the rate is still well below the diffusion limit.). What would you conclude if saturation kinetics were observed? Question 2 The table below gives rate constants for the anation of [Ni(H2O)6]2+. K0 is the equilibrium constant for formation of the outer sphere (or encounter) complex between the entering ligand, Y, and the metal ion, whilst k0 is the rate constant for substitution of H2O in the inner coordination sphere of the metal with Y from the outer coordination sphere. The values are for T = 25 oC. (a) Explain why K0 for CH3PO42- is significantly larger than for CH3COO–, and why K0 for all neutral species, Y, are identical. (b) The values of K0 is the table are estimated using an electrostatic model. Various such models are available – you are familiar with the Fouss-Eigen equation. Use that equation to determine values of K0 for CH3PO42-, for an anionic ligand (such as F-), for a neutral ligand (such as NH3), and for a cationic ligand such as NH2(CH2)2NMe3+. Compare your values with those given in the table. Assume the distance between the metal ion and the incoming ligand is 5.5 Å, that the reactions are in aqueous solution and that T = 25.0 oC. (c) Show that k0K0 corresponds to the experimentally determined second order rate constant, kIIobs provided [Y] is small. (d) Having a value for k0K0 and being able to estimate K0, one can then determine values of k0 (last column). Calculate these values using your values for K0 from the Fouss-Eigen equation. (e) Using both the values for k0 given in the table, and your values, what mechanistic conclusion can you come to about the anation of [Ni(H2O)6]2+? Is this conclusion dependent on the way K0 is estimated? 2 Question 3 Consider the following complexes: (i) [Fe(OH2)6]3+ and [Os(OH2)6]3+ (ii) [Co(OH2)6]3+ and [Co(OH2)6]2+ (iii) [Zn(OH2)6]2+ and [Cu(OH2)6]2+ (iv) [V(OH2)6]2+ and [Ni(OH2)6]2+ In each case indicate which of the two complexes will undergo water exchange faster in mildly acidic solution. Explain your choice in each case. Question 4 When ∆-tris(phen)iron(II) is placed in solution, it slowly racemizes, with a rate constant kr = 6.7 × 10-4 s-1. The rate constant for dissociation of the phen ligand is kd = 0.7 × 10-4 s-1. Postulate a mechanism for the racemization reaction that is consistent with the experimental data. N N phen Question 5 The reaction kan [Cu(tet-b)(X)]+ + H 2 O [Cu(tet-b)(H 2 O)]2+ + X- kaq shows the anation (kan) and aquation (kaq) of a five-coordinate Cu(II) square pyramidal complex. Available data for the reaction are listed below. a) What can be deduced about the mechanism of the reaction? b) Predict the sign of V‡ for the anation and the aquation reactions. 3 Would electrostriction effects have to be taken into account? Explain fully. Question 6 The anation reaction [Co(NH3)5(H2O)]2+ + Cl– → [Co(NH3)5Cl]+ + H2O is thought to proceed by an Id mechanism. (a) Write down the sequence of elementary steps that are involved in the reaction. (b) Outline how you would go about proving that the reaction did indeed proceed through an Id mechanism. (c) Explain whether the analogous reaction between Cl– and [Co(NH3)5(H2O)]3+ would be faster or slower. 4 Question 7 Calculate k12 for the reaction between [Fe(CN)4]4- and [IrCl6]2- from the following data (25 oC). Take the collision frequency to be 1011 s-1. k11 /M-1 s-1 k22 /M-1 s-1 E /V 7.4 × 102 2.3 × 105 0.24 Question 8 The following activation parameters have been measured (30 oC in MeOH) for the reaction k2 trans-[PtL2Cl2] + py [PtL2Clpy]+ + Cl– L ∆H‡ /kJ mol-1 ∆S‡ /J K-1 mol-1 ∆V‡ /cm3 mol-1 pyridine 49.3 -94 -8.8 PEt3 53.9 -100 -13.6 (a) Explain briefly how the parameters are determined experimentally. (b) What mechanistic information can be obtained from the values? (c) Calculate the rate constant at 25.0 oC when L = pyridine Question 9 Explain why [Cr(H2O)6]2+ + [Co(NH3)5(OH)]2+ → [Cr(H2O)5(OH)]2+ + [Co(NH3)5(H2O)]2+ is considerably faster than the reaction [Cr(H2O)6]2+ + [Co(NH3)5(H2O)]3+ → [Cr(H2O)5(OH)]2+ + [Co(NH3)5(H2O)]2+ 5 Question 10 Although the mechanism of the reaction at a square planar metal centre usually proceeds by an associative mechanism, a few instances are known where the reaction proceeds by parallel pathways, one associative and the other dissociative. The proposed mechanism for one such reaction is shown below. R Ph Ph Pt T SMe2 Ph Ph SMe2 SMe2 k3 , L k2 , L B Ph SMe2 Ph + SMe2 Pt Pt fast P Ph Ph Pt L L SMe2 SMe2 R is the reactant, L an entering ligand, T a three-coordinate intermediate, B a fivecoordinate intermediate and P is the product. (a) Show that kobs (a) k1k3 L k2 L k1 Me2S k3 L Consider the first term in the expression for kobs. What happens to the rate of the dissociative pathway (i) (ii) (b) when an excess of the leaving group SeM2, is added to the solution? as [L] becomes very large? Would you expect the reaction to proceed with retention of stereochemistry? Explain. Question 11 The rate constant for electron transfer between an electron donor D and an electon acceptor A is given by kET 2 e r 3 h 4 RT o 2 H DA 1/ 2 6 eG / RT which can be written in abbreviated form as kET N E eG / RT where νN = constant e-βr and κE = constant/ . (a) How does the rate of electron transfer between A and D depend on r, the distance between them predicted by the equation? (b) Explain what λ is; give one way how in the design of a complex between A and D for fast electron transfer one might go about minimising λ. (c) We showed during the course that the Gibbs energy of activation, ΔG‡ is related to the standard Gibbs energy of the reaction by the equation G o G 1 4 2 Prove that G (d) 1 2G o 4 Now use this result to discuss how kET depends about the potential difference between A and D. Question 12 The basic rule for non-complementary reactions in which the change in oxidation state of the oxidising and reducing agents are different is that the mechanism will consist of the smallest possible number of one-electron transfer steps because multiple, simultaneous, electron transfer is forbidden. For the reaction CrVI + 3FeII CrIII + 3FeIII the experimentally observed rate law is k [Cr VI ][FeII ]2 d [Cr III ] a III dt kb [Fe ] + kc [FeII ] It has been proposed that the reaction proceeds by the following mechanism 7 k1 Cr V + FeIII Cr VI + FeII k1 k2 Cr V + FeII Cr IV + FeIII k3 Cr IV + FeII Cr III + FeIII (a) On the basis of this mechanism, write down an expression for the rate of formation of the product, CrIII. (b) What is a steady state approximation? (c) Apply a steady state approximation to [CrV] and [CrIV] and show that [Cr IV ] k k1[Cr VI ][FeII ] [Cr IV ] 2 III II k3 k1[Fe ] k2 [Fe ] k2 [Cr V ] k3 (d) Hence, derive the rate law based on this proposed mechanism, and correlate the microscopic and macroscopic rate constants. (e) At the beginning of the reaction, [FeIII] << [FeII]. Simplify the rate law for conditions when this applies. What is the rate-determining step under these conditions? Question 13 The rate of the V2+(aq)|V3+(aq) electron self-exchange may be expressed by the rate law Rate = k[V2+(aq)][V3+(aq)] where k a b [H ] and a and b are constants. Propose a mechanism that would explain this observation and express the constants a and b in terms of the microscopic rate and equilibrium constants of your mechanism. 8