HEAT TRANSFER EXPERIMENT Freshman Engineering Clinic II Prepared by Drs. Kauser Jahan and Robert P. Hesketh Spring 2009 Introduction to Heat Transfer: Natural and Forced Convection There are many examples of natural and forced convection: Forced Convection: Radiator fan in car blowing air by radiator. Fan cooling Pentium chip on personal computer. Natural Convection Heat loss from a road surface on a hot day: notice the density gradients in the air. (Remember seeing the density difference?) Heat loss from a computer monitor. Heat loss from a hot plate. What is the difference between the above two examples? In both cases energy is lost from a solid surface to a fluid that is moving. In Forced Convection the fluid is moving by some outside force such as a fan. In Natural convection the fluid motion is caused by a density difference between the hot fluid next to the hot surface and the cold fluid far from the surface. The hot, low density fluid flows upward causing the cold high density fluid to flow downward. To obtain simple expressions for the transfer of heat from a solid surface to a fluid engineers use the empirical relation: Rate of " Proportionality Area of Temperature (1) Heat Transfer Constant" the Surface Difference or Rate of Heat Transfer = UoA(Tsurface-Tair) (2) The proportionality constant, Uo, is commonly referred to as an overall heat transfer coefficient. This heat transfer coefficient is a function of the properties of the insulating material (thermal conductivity), physical properties of the fluids, and velocity of the fluids. All heat transfer coefficients have been obtained from carefully conducted experiments. The data from these experiments are correlated using an appropriate equation. The results of these experiments are first published in journal articles and then they are summarized in textbooks. Water Cooling Experiment: This experiment will demonstrate natural convection. In this experiment you will fill two cups with hot water. You will measure the temperature as a function of time using the data acquisition system. Your data will be analyzed to determine the overall heat transfer coefficient for each cup. In this experiment you will need to know the external surface area of your cups and lids. Below is an example of a derivation of the external surface area of your paper and Styrofoam cups using second semester calculus: Surface area of the side of the conical cup: External z L z L Surface Area 2r dz 2 equation of the slanted line dz of Side of z0 z0 Conical cup z d top z 0 2 2 z L 1. 2. z dtop dbottom d bottom 2 L 2 dbottom dbottom dz L 2 eq. of slanted line: r (3) (4) (5) External surface area d top dbottom (6) of the side of the L 2 conical cup Sample Preparation Top Outside Diameter 1.1. Record in your laboratory notebook a dimensioned drawing of each of your cups and mugs. Calculate the external surface area of the walls and top surface of your cups and mug. 1.2. Boil a pot of water using the electric kettle next Cup Vertical Height, L to your machine. Make sure that you will have enough water. 1.3. Weigh each empty cup and lid. 1.4. Fill the cups to the top with cold water and weigh the combined mass of water, cup and lid. Make sure that you do not leave an air gap between the liquid surface and the plastic top Bottom Outside Diameter of your cup. Calculate the mass of water in each cup. 1.5. Record the room temperature. 1.6. Carefully place the thermometer through the hole in the plastic lids. Since water evaporation will effect your results a lid is required. Make sure that the water level is as close to the top of the plastic lid as possible. 1.7. Locate the tip of the thermometer roughly half way in the cup. 1.8. Adjust ring stand arms and to achieve this requirement. Experimental Run 2.1. Using a team of 4 people, have one person pour water into each of the cups. Have the second person follow by placing lids on the cup. The third person will insert the 533562178 2 thermocouple into the cup. The fourth person will record the data (Time and Temperature). Data Analysis 3.1. On a single graph, plot the temperature as a function of time for each of the cups. Tliquid Troom vs t. Fit an exponential 3.2. Using the theory given below make a plot of T T initial room trendline through this data. Tliquid Troom vs t. Fit a best fit line and obtain equation. Use slope to 3.3. Plot ln T T initial room determine Uo, for each of your cups. Use the measured mass of water, heat capacity of water = 4,184 J/(kg ºC), and your calculated external surface area. 3. Energy Balance: Control Volume is the hot liquid within the cup or mug Accumulation Rate of energy additon to Rate of energy removal of energy in the from the control volume. the control volume. control volume d mC p Tliquid 0 J Rate of Heat Loss from Coffee U o Ao Tliquid Troom 1. dt s T t U o Ao dTliquid Tliquid Troom t 0 mC p dt Tin itia l U A Tliquid Troom exp o o T mC p initial Troom t (7) (8) (9) The appropriateness of the above equation can be checked by evaluating it at its limits. At the initial time the temperature of the liquid is the initial temperature. At the time of infinity the liquid temperature is equal to the room temperature. References: Bejan, A. (2004) Convection Heat Transfer, Publisher: Wiley, John & Sons, Incorporated. TEAM LABORATORY REPORT a) b) c) d) e) f) A letter of transmittal (should state what you did and what were your findings?) Include typed raw data in tabular form along with values of all variables Include calculations of surface area Include the two plots mentioned in 3.2 and 3.3. Show calculations indicating how you obtained the values of U0 for your cups. Interpret your results – Compare the values of Uo for each cup. Which one has the higher value? Why? 533562178 3 SAMPLE PLOTS mentioned in 3.2 and 3.3 1 0.9 0.8 0.7 Insulated Row an Cup 0.6 0.5 0.4 0.3 0.2 0.1 0 0 20 40 60 80 100 120 140 160 180 Tim e (Minutes) 0 -0.2 0 20 40 60 80 100 120 140 160 180 -0.4 Insulated Row an Cup -0.6 -0.8 ln -1 -1.2 y = -0.0117x R2 = 0.9968 -1.4 -1.6 -1.8 -2 Tim e (Minutes) Use slope of line to determine value of Uo U A Slope = o o mC p 533562178 4