Physics 1310 Name:_______________________ Quiz 8c (10 points) 1. An astronomer on Earth observes Galaxy A moving to the left at 0.81c and Galaxy B moving to the right at 0.83c. A resident of Galaxy B observes a supernova explosion in Galaxy B that lasts 2 months. Galaxy A Earth Galaxy B From the point of view of an observer in Galaxy A, how long does this supernova explosion last? VB from A = (VB from Earth + VEarth from A ) / (1 + VB from Earth * VEarth from A / c2 ) = (0.81 c + 0.83 c )/ (1 + 0.81*0.83) = 0.98 c t = 2 months / sqrt(1-0.982) = 10 months 2. An electron is moving at 70.3% the speed of light. Calculate its relativistic kinetic energy. KE = E – rest energy = 511 KeV /sqrt(1-0.7032) - 511 KeV KE = 1011 KeV - 511 KeV = 500 KeV 3. The wavelength corresponding to the peak of a star’s spectrum equals 724.5 nm. What is the temperature of this star’s surface? T = 2898 m – K / 724.5 nm = 4000 K 4. A hydrogen atom is initially in its ground state (n = 1). What is the wavelength of the photon that must be absorbed to move this atom to its first excited state (n = 2)? Is this photon in the visible, UV, IR, or radio region of the spectrum? E1 = -13.6 eV E2 = -13.6 eV / 4 = -3.4 eV E = 10.2 eV Ephoton = 10.2 eV = 1240 eV nm / 10.2 eV = 122 nm, UV 5. An atom is initially in its ground state. It absorbs a photon with wavelength equal to 827 nm and moves to a metastable excited state. The atom then absorbs a second photon with wavelength equal to 496 nm to move to a higher energy excited state. The atom then emits a photon and falls to the ground state. What is the wavelength of the emitted photon? Is this photon in the visible, UV, IR, or radio region of the spectrum? E first absorbed photon= 1240 nm-eV / 827 nm = 1.50 eV E second absorbed photon= 1240 nm-eV / 496 nm =2.50 eV E emitted photon= 2.50 eV + 1.50 eV = 4.00 eV emitted photon= 1240 eV nm / 4.00 eV = 310 nm, UV