Molar Concentration Notes

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Another Mole Concept: The Molar Concentration

Some Definitions you need to remember:

Solution:

Solvent:

Solute:

homogeneous mixture of two or more substances.

the component of a solution that exists in greater quantity. the component of the solution that exists in smaller quantity.

Concentration: amount of a substance present in a given volume of solution.

Concentrated: has relatively large amount of substance present in a given volume of

Dilute: solution. has relatively small amount of substance present in a given volume of solution.

Molar concentration or Molarity: number of moles of a particular substance in one liter of solution.

Unit for Molarity: “mole/L” or “M”

1.0 M is read as “ 1.0 MOLAR”

Symbol for concentration:

The Formula for concentration:

[ ] e.g. [NaCl] = 1.2 M

Molar Concentration (c) = moles (n) c = molar concentration

Volume (V) n = number of moles

V = volume, in litres

Examples:

1.

What is the molar concentration of 5.12 g of NaCl that is made into a 250.0 mL of solution?

- convert grams into moles moles of NaCl = 5.12 g x

[NaCl] = n =

1 mol =

58.5 g

0.0875 mol =

V 0.2500 L

0.0875 mol

0.350 M

2.

What mass of NaOH is contained in 2.0 L of 0.200 M NaOH?

- solve for number of moles n = c x V n = 0.200 mol/L x 3.50 L = 0.700 mol mass = 0.700 mol x 40.0 g /1mol = 28.0 g

3.

What is the molarity of pure suphuric acid, H

2

SO

4

, having a density of 1.839 g/mL?

Density =

[H

2

SO

4

] = amount (mass)

Volume

1.839 g

0.001 L x molarity=

1 mol =

98.1 g amount (as mole)

Volume

18.7 M

4.

What is the molarity of CaCl

2

in solution made by dissolving and diluting 15.00 g of CaCl

2

6H

2

O to 500.0 mL?

When CaCl hydrate.

2

6H

2

O dissolves, the moles of CaCl

2

produced is equal to the moles of the

Number of moles = 15.00 g x 1 mole/ 219.1 g =

[CaCl

2

] = [CaCl

2

6H

2

O] = ________ = 1.369M

0.500 L

5.

How would you make a 0.500 L solution of 0.20 M Potassium permanganate?

6.

How many molecules are there in the solution above (question 5)?

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