South Tuen Mun Government Secondary School
Biology Quiz 6
(A) Choose the best answer. (10 marks)
Directions : Questions 1 – 3 refer to the diagram below.
1. Which of the followings best describes the purpose of the set-up?
A. To show that the root of the plant is the major site of transpiration.
B. To find out the rate of transpiration in leaf shoot.
C. To show that there is water loss from the green leaves.
D. To show that no water is lost from the pot.
2. In order to achieve the purpose of the experiment, a control set-up must be used. The control set-up is
A. the same as the diagram, but the pot is not wrapped by the plastic bag.
B. the same as the diagram, but the green leaves are cut, leaving the stem behind.
C. the same as the diagram, but the pot and the green leaves are removed.
D. the same as the diagram, but the pot is removed.
3. Which of the following test can be used to test the liquid drop in the diagram? What is the result?
A.
B.
C.
D.
Test
Dry cobalt chloride paper
Dry copper chloride paper
Dry cobalt chloride paper
Dry copper chloride paper
Result
turns from blue to pink
turns from blue to pink
turns from pink to blue
turns from pink to blue
Directions : Question 4 – 6 refer to the diagram below.
4. Which of the followings is an important precaution of this experiment? What is the reason?
Precaution
A. The shoot is cut under water.
Reason
To prevent the entry of air bubble into the xylem.
B. The shoot is cut under water.
C. Oil must be added in the reservoir.
D. Oil must be added in the reservoir.
To allow the entry of water into the xylem.
To prevent the dissolving of oxygen into the water.
To move the air bubble back to the end of the tube.
5. The following table shows the result of the experiment in 15 minutes.
Decrease in weight
0.009 g.
Movement of air bubble
10 cm
What is the rate of water loss in the set up?
A. 0.006 g per minute.
C. 0.036 g per hour
6. The rate of water loss in the set up is the highest
A. on a windy, sunny, wet day.
C. on a windy, sunny, dry day.
B. 40 cm per hour
D. 0.67 cm per minute
B. on a non-windy, sunny, wet day.
D. on a windy, cloudy, wet day.
Directions : Questions 7 – 10 refer to the graph below which shows the rate of water transpired and the rate of
water absorbed on a normal day.
7. What do area X and area Y represent?
A.
B.
C.
D.
Area X
Net loss of water when rate of water transpiration
is faster than the rate of water absorption.
Net loss of water when rate of water transpiration
is faster than the rate of water absorption.
Net loss of water when rate of water transpiration
is slower than the rate of water absorption.
Net gain of water when rate of water transpiration
is slower than the rate of water absorption.
Area Y
Net gain of water when rate of water transpiration
is slower than the rate of water absorption.
Net loss of water when rate of water absorption is
slower than the rate of water transpiration.
Net loss of water when rate of water transpiration is
faster than the rate of water absorption.
Net gain of water when rate of water absorption is
faster than the rate of water transpiration.
8. If area Y is larger than area X in a period of 24 hours, which of the following will likely occur to a young
stem?
A. The thin-walled cells will become flaccid and the stem wilts.
B. The thin-walled cells will become turgid and the stem stands upright.
C. The thin-walled cells will become flaccid and the stem stands upright.
D. The thin-walled cells will become turgid and the stem wilts.
9. At what time of the day, does the young stem likely wilt?
A. Time P
B. Time Q
C. Time R
D. Time S
10. The rate of transpiration is the highest at 12:00 because
(i)
the temperature is usually very high at 12:00.
(ii) the light intensity is usually very high at 12:00.
(iii) the wind speed is usually very high at 12:00.
A. (i) and (ii) only
B. (ii) and (iii) only
C. (i) and (iii) only
D. (i), (ii) and (iii)
(B) Answer the following questions. (30 marks)
1. The diagram below shows a cross-section of a young herbaceous root. The arrows show the direction of
movements of substance A and substance D. Water is transported by tissue X and substance D is transported
by tissue Y.
(a) Name tissue X and tissue Y.
(b) Name substance A and substance D.
(2 marks)
(2 marks)
(c) Describe how substance A enters the root hair cell and how substance A moves from root hair cell to
tissue X.
(4 marks)
(d) What is the function of substance D to the root?
(1 mark)
(e) How does substance A move up tissue X and reach the green leaf?
(3 marks)
2. The following diagram shows a cross-section of a stem.
(a) Name A and B.
(b) How does B provide support to the plant?
(2 marks)
(2 marks)
(c) How does cell type C provide support to the plant?
(1 mark)
(d) From the diagram,
(i)
state and explain which cell type is more important for the support of the plant.
(2 marks)
(ii)
based on your answer in (i), describe and explain what happens to the stem on a windy, hot,
sunny and dry day.
(4 marks)
3. The following diagram shows the study of support in young stem and a woody stem. The two stems are put
in a concentrated salt solution.
(a) Which stem will not bend after 1 hour? Explain why the stem does not bend.
(b) Explain why the other stem bends after 1 hour.
(4 marks)
(3 marks)
South Tuen Mun Government Secondary School
Biology Quiz 6
Marking Scheme
(A) Choose the best answer. (10 marks)
1. C
6. C
2. B
7. A
3. A
8. B
4. A
9. B
5. C
10. A
(B) Answer the following questions. (30 marks)
1. (a) X – xylem (1)
(b) A – water (1)
Y – phloem (1)
D – sucrose / organic food (1)
(c) A / water moves into the root hair cell by osmosis (1). The water potential of the root hair cell
increases (1). The water potential is higher than the neighbouring cells / a water potential gradient is
produced between root hair cell and xylem / tissue Y (1). Water moves from one cell to another cell by
osmosis (1).
(d) D is broken down to release energy by respiration (1).
(e) Substance A / water moves up the xylem by transpiration pull (1). When water is lost from the leaf
surface (1), water molecules will pull one by one by a cohesive force (1).
2. (a) A – phloem (1)
B – xylem (1)
(b) B are thick-walled cells / have secondary thickening made up of lignin (1), lignin is rigid to provide
support (1).
(c) C provide support by the turgidity of the cell (1)
(d) (i) cell type C (1) because the stem has more cell type C than other cell types (1).
(ii) The stem wilts (1) because on a windy, hot, sunny and dry day, the rate of transpiration is higher /
more water is lost than water is absorbed (1), the thin walled cells are flaccid / lose turgidity (1).
Thus they are not strong enough to support the body weight of the stem (1).
3. (a) woody stem (1) because the stem contains a lot of xylem (1) which are thick-walled cells, the xylem
contains secondary thickening that is made of lignin (1), lignin is rigid to provide support / xylem does
not require the turgidity of cell to provide support (1).
(b) Concentrated salt solution has a lower water potential than the stem cells (1). There is a net movement
of water out of the stem cells by osmosis (1). The herbaceous stem depends on turgidity for support /
when the thin-walled cells become flaccid / lose turgidity, they cannot support the weight of the
stem (1).