Conductivity, Ionic Mobilities, Transport Number Conducting media Insulators: there is a small amount of charge carrying particle Metals: electrons are the charge carrying particles. Electrolyte solutions: ions are the charge carrying particles. Semiconductors: band structure determines the number of charge carriers. l A R Resistance: - specific resistivity l – length of wire A – cross sectional area of wire G Conductance: Conductivity: Molar conductivity: 1 R 1 Ω-1 = S (Siemens) unit: m-1 Ω-1 = S m-1 Λm unit: if c is given in mol m-3, c than S m2 mol-1 Λm is concentration and temperature dependent, Λm = f(c,T),. In general, increasing the number of charge carriers increases the conductivity. Number of ions present in a solution of unit volume (concentration) depends on the concentration in a complicated way. → weak electrolytes The Coulomb interactions prevents the molar conductivity vs. concentration function to show ideal behaviour. → strong electrolytes. Conductivity 2008 1 Figure 1. The variation of the molar conductivity m with the concentration of the electrolyte. Measuring conductance: conductivity cell Noble metal electrodes → electrolysis alternating current → polarization Strong electrolytes Kohlrausch’s law: Λm Λm0 k c1/ 2 1. describes the concentration dependence of molar conductivity . When a straight line is fit to the points of m vs. c1/2 function for a strong electrolyte the intercept 0 gives Λm ,which is the limiting molar conductivity the molar conductivity in the limit of zero concentration. Constant k depends principally on the stoichiometry of salt, rather than specific identity. In the condition: c → 0, Λm Λm0 , the distance of ions in the solution is so large, that there is no interaction between them. Conductivity 2008 2 Figure 2. The Λm vs. c1/ 2 function. The circles represent experimenal points, while the solid lines are theoretical lines calculated with the Debye-HückelOnsager theory ( Λm Λm0 P Q Λm0 c1/ 2 ). Independent migration of ions Λm 2. λ+ and λ- are the limiting molar conductivity of cations and anions respectively, and are the numbers of cations and anions per formula for NaCl, CuSO4 1, 2 for BaCl2. Each ion is assumed to make its own contribution to molar conductivity, irrespective the nature of other ion with which it is associated. Table. Limiting ionic conductivities of sodium and potassium salts in water at 298 K, λ / mS m2 mol-1 Electrolyte Electrolyte Difference Λm0 Λm0 KCl 149.79 NaCl 126.39 23.4 KI 150.31 NaI 126.88 23.4 ½ K2SO4 153.48 ½ Na2SO4 130.1 23.4 Conductivity 2008 3 The difference between the Λm0 values of sodium and potassium salts is irrespective of the anions, as it can be seen from Table 1 Weak electrolytes A part of the amount of dissolved substance appears in the solution as ions, according to the ionization equilibrium. van’t Hoff’s experimental findings for osmotic pressure, π measurements in weak electrolytes: m0 R T π , i m0 R T 3. where m0 is the concentration in mol/kg determined from mass measurement. The effective concentration, i m0 is usually greater than m0, while i>1. The number of ionic and non-ionic particles present in a solution is given by i m0 m0 1 m0 The molecule dissociates ν ions, and α is the degree of ionization (1 > α > 0). Example: weak acid. CH3COOH ↔ H+ + CH3COOAcetic acid dissociates into two ionic species, therefore ν = 2, and i m0 2 m0 1 m0 m0 1 van’t Hoff found α to be proportional the ratio of molar conductivities, Λm Λm0 4. When m0 → 0, then α = 1, therefore Λm0 Λm . In dilute solution of weak electrolytes the ionization is complete. Eq. 4 is used to determine equilibrium constant for ionization processes. Data can be calculated from conductivity measurements. For general case, a weak acid dissociates Conductivity 2008 4 HAc ↔ H+ + AcThe thermodinamic equilibrium constant: a aH Ka Ac aHAc For dilute solutions (c < 10-4 molal) concentrations can be used instead of activities. The equilibrium concentrations for a weak acid dissociation, [H+] = [Ac-] = α∙c, and [HAc] = (1 – α)∙c. Ka a Ac a H aHAc c c 2 c c 1 1 5. Equation 5. is a quadratic equation in α, c 2 Ka Ka 0 Transforming Eq. 5. 1 c 1 1 c 2 Ka , and divided by α Ka Using Eq. 4 we get, one of the forms of Ostwald’s dilution law Λm0 1 c 0 m Λm m Ka or in a more applicable form 1 1 0 c 0 2m Λm m m K a Conductivity 2008 6. 5 Plotting the data for Eq. 6. in a linearized form Figure 3. Graph used to determine 0m from the intercept, and Ka from the slope. Intercept = Slope = 1 0m 1 0m 2 Ka Ionic Mobilities, Transport (transference) Number Electric force field directs migrating ions parallel to the force field lines and accelerates them toward the electrodes. A counter force prevents their speed to exceed a limit. This is the friction force resisting the relative motion of fluid layers. The condition for mechanical equilibrium of transporting ion, F friction F field 1. In a short time after the electric field has been switched on, the ions, e.g. the cations migrate with a constant speed, s toward the negative electrode. F friction s 6 r Conductivity 2008 6 F field zeE ze l A potential difference Δφ at a distance l produces E electric field which make spherical ions with radius, r move against friction, that is caused mainly by solvent molecules. When net force is zero (see Eq. 1.) the migration speed, s, at a migrating ion travels can be given as s zeE 6r As η, the viscosity of liquid or the radius of migrating ion increases the speed lowers. The hydrodynamic radius should be taken into account. For alkali metal ions (Li – Cs) the hydrodynamic radius of Li+ is the greatest, though its radius without hydration shell is the smallest. The surface charge density of Li+ is the greatest in the first column of periodic system. Migration speed can be referred to unit field: u s ze E 6r 2. the quantity u is called ionic mobility. The ion mobility is independent of the magnitude of electric field. Table 1. Ionic mobilities in water at 298 K, u / 10-8 m2 s-1 V-1 H+ Na+ OHCl- 36.23 5.19 Mobility as a function of conductivity λ = f(u) Definitions Electroneutrality principle, example: H2SO4 formula charge number charge ion concentration Conductivity 2008 ν+ = 2 z+ = 1 z+e c∙ν+ ν- = 1 z- = 2 z -e c∙ν7 20.64 7,91 Electroneutrality: z+ ν+ = z- ν- An experimental cell is set in which a strong electrolyte of concentration c is filled. The noble electrode metal pair is polarized at a potential Δφ which maintains an electric field, E (V/cm). Figure 4. In the calculation of the current, all the cations within a distance s+·Δt (i.e. those in volume A·s+·Δt) will pass through the area A. Likewise anions… The ion flux: J ion N A t 3. The number of ions, N pass through area, A at a time Δt producing ion flux. Each of the positive or negative ion concentration is chosen the same flux can be observed (electroneutrality). Ion concentration: c∙ν+ Number density, N V c∙ν- , in general: c∙ν can also be given in terms of ion concentration. If nion = ν·n, than (introducing NA the Avogadro number) Conductivity 2008 8 N NA N n N A ion N A c V NAV V N N A c V N N A c V 4. Volume can be given by speed s V s t A 5. From Eqs. 3. 4. and 5. stA cN A s cN A At J ion Number of ions number of charges conversion: J ch arg e J ion ze J ch arg e s cN A ze s c zF Introducing: J ch arg e u s uE , and E (NA e = F, the Faraday constant) l c zF l Current can be given as: I J ch arg e A I u c zF A l 6. Current can also be given from Ohm’s law: I G A R l 7. Comparing Eq. 6. and 7. we get Conductivity 2008 9 u c zF Defining individual molar conductivity: u zF c 8. Eq. 8. tells us the relation between a theoretical quantity, mobility of an ion and an experimentally determined quantity, molar conductivity. In the limit of zero concentration Λm0 F z u z u 9. Eq. 9. simplifies for electrolytes with z+ = z-, i.e. z : z electrolytes (KCl with z = 1, CuSO4 with z =2). Λm0 zF u u Transport number, t It is the fraction of the current carried by each ion that is present in solution t Ii I 10. i 1 The sum of transport numbers in a solution should give one, t t 1 where t and t are the sum of the transport number for cations and anions respectively. When a solution contains c1 concentration of NaCl and c2 concentration of KNO3 the transport number of Na+ can be given as t Na uNa Na z Na c1 FA FA Conductivity 2008 l uNa Na z Na c1 uCl Cl zCl c1 uK K z K c2 uNO NO z NO c2 l 3 10 3 3 We used Eq. 6. for substituting the current caused by different ions. This long equation is simplified by the following facts: νNa = 1, zNa = 1, νK = 1, zK = 1, νCl = 1, zCl = 1, νNO3 = 1, zNO3 = 1 t Na uNa c1 c1 uNa uCl c2 uK uNO 3 11. When we have a single z : z electrolyte with mobilities u+ and u-, the transport number of anion is t u u u This equation can also be given in molar conductivity representation t Conductivity 2008 11