Name: ______________________________
Period: ______
Chemistry 1
Chapter 10 Review Sheet
Solve the following problems on your own paper.
1. Find the number of molecules of carbon dioxide in 4.56 moles of CO2.
4.56 mol CO2 6.02x1023 m.c. CO2
= 2.75 x 1024 m.c. CO2
1 mol CO2
2. Find the number of moles of lead in 647 grams of lead.
647 g Pb
1 mol Pb = 3.12 mol Pb
207.2 g Pb
3. Calculate the gfm of one mole of C15H34O4.
15C x 12.0 g = 180.0 g
34H x 1.0g = 34.0 g
4O x 16.0 g = 64.0 g
278.0 g total
4. Calculate the number of moles in 358 g of aluminum hydroxide (hint: criss-cross to create the formula of
aluminum hydroxide before you begin your dimensional analysis).
358 g Al(OH)3
1 mol Al(OH)3
= 4.59 mol Al(OH)3
78.0 g Al(OH)3
5. Calculate the mass of 6.42 x 105 molecules of C3H9O5.
6.42 x 105 mc C3H9O5
1 mol C3H9O5
125.0 g C3H9O5 = 1.33 x 10-16 g C3H9O5
6.02 x 1023 mc C3H9O5 1 mol C3H9O5
6. Volume of a gas is found at STP. What does this stand for and what are the values used for temperature and
pressure?
STP = standard temperature and pressure = 1°C and 1 atmosphere pressure
7. A compound is 63.3% xenon and 36.7% fluorine by mass. Calculate the empirical formula.
63.3 g Xe 1 mol Xe = 0.482 mol / 0.482 = 1
131.3 g Xe
36.7 g F
1 mol F = 1.93 mol /0.482 = 4
19.0 g F
Empirical Formula = XeF4
8. Caffeine is 49.5% C, 5.20% H, 28.9% N, and 16.5% O. The molecular mass is 194.0 g. Calculate the
empirical formula and the molecular formula.
49.5g C 1 mol C = 4.13 mol/1.03 = 4
Empirical Formula = C4H5N2O
12.0 g C
5.20 g H 1 mol H = 5.20 mol/1.03 = 5
Empirical Formula Mass = 97.0 g
1.0 g H
28.9 g N 1 mol N = 2.06 mol/1.03 = 2
gfm/efm = 194.0/97.0 = 2
14.0g N
16.5 g O 1 mol O = 1.03 mol/1.03 = 1
Molecular Formula = C8H10N4O2
Name: ______________________________
Period: ______
16.0g O
9. An 18.0 g sample of H2O contains ___one mole____ mole(s) of H2O,
H2O, and a total of ___1.81 x 1024______ atoms.
___6.02x1023__ molecules of
10. Determine the number of moles in 345 liters of dinitrogen pentoxide at STP.
345 L N2O5 1 mol N2O5 = 15.4 L N2O5
22.4 L N2O5
11. How many grams of calcium are in 240.0 g of CaCO3?
(Hint: find the percent composition first!)
1 Ca = 40.1 g
1 C = 12.0 g
3Ox = 48.0 g
Total = 100.1 g
% Ca = (40.1g/100.1g) x 100.1 = 40.1%
Grams Ca = 0.401 x 240.0 = 96.2 g Ca