Chemistry I-Honors
Scientific Conversions Worksheet #1
Answer Key
I. Convert the following:
a) 6.41 dkg. = 0.0641 kg. =
2.26 oz. =
7.06 x 10-5 tons
6.41 dkg. ( 10 g. / 1 dkg.)( 1 kg. / 103 g.) = 0.0641 kg.
6.41 dkg. ( 10 g. / 1 dkg.)( 1 lb. / 453.6 g.)( 16 oz. / 1 lb.) = 2.26 oz.
6.41 dkg. ( 10 g. / 1 dkg.)( 1 lb. / 453.6 g.)( 1 ton / 2000 lbs.) = 7.06 x 10-5 tons
b) 270 ft. = 0.051 mi. = 8.2 x 1013 pm. =
0.82 hm.
270 ft. ( 1 mi. / 5280 ft.) = 0.051 mi.
270 ft. ( 12 in. / 1 ft.)( 2.54 cm / 1 in.)( 10-2 m / 1 cm)( 10-12 pm / 1 m) = 8.2 x 1013 pm.
8.2 x 1013 pm.( 10-12 m / 1 pm)( 10-2 hm / 1 m) = 0.82 hm.
c) 144 lb / in2 = 1.01 x 108 g / m2 = 144 psi
2
144 lb
453.6 g.
1 in.
--------- x ---------- x ---------- x
1 in2
1 lb.
2.54 cm
2
102 cm
---------1m
d) 6050 cups = 1.43 x 103 dm3 = 378 gal. =
“psi” means lb / in2
1.43 x 103 liters
6050 cups ( 1 pt. / 2 cups)( 1 qt. / 2 pts.)( 0.946 L / 1 qt.)( 1 dm3 / 1 L ) = 1.43 x 103 dm3
6050 cups ( 1 pt. / 2 cups)( 1 qt. / 2 pts.)( 1 gal. / 4 qts. ) = 378 gal.
1 Liter = 1 dm3, so 1.43 x 103 dm3 = 1.43 x 103 liters
e) 2.945 x 104 dkm = 2.945 x 10-4 Gm = 183.0 mi. = 294.5 km
2.945 x 104 dkm. ( 101 m / 1 dkm)( 10-9 m / 1m) = 2.945 x 10-4 Gm
2.945 x 104 dkm. ( 101 m / 1 dkm)( 10-3 km / 1m)( 1 mi. / 1.609 km) = 183.0 mi
2.945 x 104 dkm. ( 101 m / 1 dkm)( 10-3 km / 1m) = 294.5 km
f) 2.335 tons = 2.118 x 109 mg. =
2.118 Mg. = 7.472 x 104 oz.
2.335 tons ( 2000 lbs. / 1 ton)( 453.6 g / 1 lb. )( 103 mg. / 1 g.) = 2.118 x 109 mg.
2.118 x 109 mg. )( 10-3 g. / 1mg. )( 10-6 Mg. / 1 g.) = 2.118 Mg.
2.335 tons ( 2000 lbs. / 1 ton)( 16 oz. / 1 lb. ) = 7.472 x 104 oz.
II. A certain box has a total volume of 2.02 yd3. If the measure of one side is 34.9 inches and the measure of
another side is 235 mm, what is the measure of the third dimension, in units of meters?
235 mm = 23.5 cm (1 in. / 2.54 cm)(1 yd / 36 in) = 0.257 yd.
34.9 in(1 yd / 36 in) = 0.969 yd.
V = 2.02 yd3 / [(0.257 yd.)(0.969 yd.)] = 8.11 yd
8.11 yd(36 in / 1 yd)(2.54 cm / 1 in)(1 m / 102 cm) = 7.42
m
III. Convert the following temperatures:
12.0oF = 471.6 R =
262.0 K =
12.0 oF + 459.6 = 471.6 R
212 K =
-11.1oC
471.6 R / 1.8 = 262.0 K
262.0 K - 273.15 = -11.1oC
382 R = -78 oF = -61oC
212 K x 1.8 = 382 R 382 R - 460. = -78oF (-78oF - 32) / 1.8 = -61oC
IV. The following volumes were removed from a 5.000-liter volumetric flask: 60.00 ml, 3.25 cups, 5.07 pts.
How many fluid ounces of liquid remain in the flask?
3.25 cups (1 pt / 2 cups)( 1 qt / 2 pts)( 946 ml / 1 qt) = 769 ml
5.07 pts ( 1 qt / 2 pts)( 946 ml / 1 qt) = 2.40 x 103 ml
5000 ml - 60.00 ml - 769 ml - 2.40 x 103 ml = 1770 ml remain
1770 ml ( 1 qt / 946 ml)(32 fl. oz. / 1 qt) = 59.9 fl. oz.
V. If a biologist told you that a cheetah is able to move across an open field at 2.0 x 10-2 microns per
nanosecond, would you consider this scientist to be sane, based on this statement?
2.0 x 10-2 m 1 nsec
10-6 m
10-3 km
1 mi
3600 sec
----------------- x --------- x --------- x ---------- x ------------ x ------------ =
1 nsec
10-9 sec
1 m
1m
1.609 km
1 hr.
45 mph
VI. If have some liquid mercury (quicksilver) that needs to be transported across town. It’s been contained in
a large metal container that has a diameter of 26 inches and a height of 1.14 yards, so that it can be
transported in a truck. Knowing that the density of mercury is 13.6 g/ml, would you be able to pick up this
container and put it in the back of a pick-up truck for me?
d = 26 in.; then r = 13 in.
13 in. (2.54 cm / 1 in. ) = 33 cm
h = 1.14 yds ( 36 in. / 1 yd)( 2.54 cm / 1 in.) = 104 cm
V = r2h = 3.14(33 cm)2(104 cm) = 355623.84 = 3.6 x 105 cm3
D= m/V
m = DV = (13.6 g/ml)( 3.6 x 105 cm3)
1 cm3 = 1 ml
= 4.9 x 106 grams
4.9 x 106 grams ( 1 lb. / 453.6 g.)( 1 ton / 2000 lbs.) = 5.4 tons! Are you Superman?