1st Honors Review Answers True/False F T F F F F T T F F T T

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1st Honors Review
Answers
True/False
1.
2.
3.
4.
5.
6.
7.
8.
9.
10.
11.
12.
F
T
F
F
F
F
T
T
F
F
T
T
Modified True/False
13. F, Helium
14. F, Empty Space
Multiple Choice
15.
16.
17.
18.
19.
20.
21.
22.
23.
24.
25.
26.
27.
28.
29.
30.
31.
32.
33.
34.
35.
36.
37.
38.
A
A
D
C
D
A
C
C
B
C
A
B
D
A
C
A
B
C
B
D
B
D
B
B
39.
40.
41.
42.
43.
44.
45.
46.
B
C
A
A
C
A
C
B
Completion
47.
48.
49.
50.
51.
52.
53.
54.
55.
56.
Chemical
Hypothesis
Proton
Metalloid
Transition Elements
Neon Atom and Fluoride Ion (F-)
Scientific Law
Mass Number
Periodic Law
Metalloids
Matching
57. B
58. C
Short Answer
59. The white solid must be a compound since it broke down into two new substances. No decision
on the grayish powder can be made since it would have to be examined first.
60. In the modern periodic table, the elements are placed in the order of their increasing atomic
numbers. The atomic number of argon is 18 while the atomic number of potassium is 19.
Therefore, argon is placed before potassium in the modern periodic table.
61. 50 Protons, 69 Neutrons, 50 Electrons
62. 178.55
63. As the amount of energy carried by a wave increases, the individual waves get closer together,
increasing their frequency but decreasing their wavelength.
64. The 2p sublevel must have six electrons before the 3s begins to fill.
65. 1s22s22p63s23p2
66. Nf3, TeBr4, P4S3, ClF
67. Ionic, Covalent, Polar Covalent, Ionic
Problem
68. Chemical Change; Charcoal (carbon) reacts to form gases (carbon dioxide and water vapor).
69. 17, 6, nonmetal, 7, 6, poor conductor and nonlustruous
70. The ionization energies of the elements repeat in a regular pattern when the elements are
arranged in order of increasing atomic number. The pattern is repeated for each period of
elements.
71.
72.
73.
74.
75.
76.
9; (4 p+ + 5 n0) and 4e45; (21 p+ + 24 n0) and 21e55; (25 p+ + 30 n0) and 25eAl2(CO3)3; Aluminum Carbonate
Fe2(SO4)3; Iron (III) Sulfate
βˆ†EN=1.0; Polar Covalent
Essay
77. Neither student is completely correct, although both students express partial truths about light.
Light is thought to have a dual nature, meaning that it behaves like waves of energy in some
ways, but behaves like a stream of particles in other ways. Photons have no mass and so are
energy not matter, which supports light acting as a wave. However, some of the behavior of
light suggests that it is made of a stream of particles, such as its characteristic of reflecting off
objects.
78. 22g; Volume = 18.0 mL – 10.0 mL = 8.0 mL
Mass = Volume x Density = 1.50 mL x 10.5 g/mL = 15.75 g = 15.8 g
79. 10.3 g/mL; 15.8 g
Density =
π‘€π‘Žπ‘ π‘ 
π‘‰π‘œπ‘™π‘’π‘šπ‘’
= 28.95 g/1.50 mL = 19.3 g/mL
Mass = Volume x Density = 1.50 mL x 10.5 g/mL = 15.75 g = 15.8
80. 88 km/h; 0.024 km/s
(55 mi/h)x(1.6 km/1 mi) = 88 km/h
(88 km/h)x(1 h/60 min)x(1 min/60 s) = 0.024 km/s or 2.4x10 -2 km/s
81. A) The SI unit of temperature is kelvin
Temperature in degrees Celsius (β—¦C) + 273 = temperature in kelvins (K)
2467β—¦C + 273 = 2740 K
B) Temperature in degrees Celsius (β—¦C) + 273 = temperature in kelvins (K)
-7.2β—¦C + 273 = 265.8 K
C) Temperature in kelvins (K) – 273 = temperature in degrees Celsius (β—¦C)
172 K – 273 = -101 β—¦C
D) Temperature in kelvins (K) -273 = temperature in degrees Celsius (β—¦C)
273- 273 = 0 β—¦C
82. A) Trial 1: 0.95%; Trial 2: 2.86%; Trial 3: 8.6%
π΄π‘π‘‘π‘’π‘Žπ‘™ − 𝐸π‘₯π‘π‘’π‘Ÿπ‘–π‘šπ‘’π‘›π‘‘π‘Žπ‘™
π‘₯ 100
π΄π‘π‘‘π‘’π‘Žπ‘™
83. 1.6%
π΄π‘π‘‘π‘’π‘Žπ‘™ − 𝐸π‘₯π‘π‘’π‘Ÿπ‘–π‘šπ‘’π‘›π‘‘π‘Žπ‘™
π‘₯ 100
π΄π‘π‘‘π‘’π‘Žπ‘™
84. A) 4
B) 6
C) 4
D) 4
E) Infinite, or unlimited
F) 6
85. A) 31.25759
B) 31.258
C) 31.3
86. A) 4.6 m3
B) 3.3 m/s
C) 55 cm2
87. Ephoton = hv = (6.626 x 10-34 Jβˆ™s)(4.8x1014 s-1) = 3.18048x10-19 J = 3.2x10-19 J
88. Calculate the frequency: c=λν,
c
Therefore, ν = λ
v = (3.00x108 m/s)/(3.36x10-9m) = 8.93x1016 sCalculate the energy of one quantum:
Ephoton=hν
Ephoton = (6.626x10-34 Jβˆ™s)(8.93x1016 s-1) = 5.92x10-17 J
From #87, orange light has an energy of 3.2x10-19 J. Therefore, a quantum of radiation with a
wavelength of 3.36x10-9 m has more energy than orange light does.
89. C= λν, therefore ν =
V=
3.00π‘₯108 π‘š/𝑠
2.90 π‘š
c
λ
= 1.034 x 108 s-1
1.034x10-8 s-1 = 103.4x10-6 s-1 = 103 megahertz
You can tune in at 103 FM
90. “To be precise, measure thrice.”
91. Precision: How close data points are to each other. Accuracy: How close data points are to the
actual value.
92. Freezing: Liquid > Solid
Melting: Solid > Liquid
Evaporating: Liquid > Gas
Condensation: Gas > Liquid
Sublimation: Solid > Gas
Deformation: Gas > Solid
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