Tritation lab
Analysis question #2:
What is the molarity of a nitric acid, HNO3, solution if 43.33 ml of 0.1000M KOH solution is needed to
neutralize 20.00 ml of the acid solution?
Step 1: write the neutralization equation
HNO3 + KOH
KNO3 + H2O
1 mole of KOH reacts with 1 mole of HNO3 (1:1 mole ratio)
Step 2: Use dimensional analysis to solve for moles of KOH:
Moles of KOH = 0.1000 mol KOH X .04333L
= 0.004333 moles of KOH
1L
1
Moles of HNO3 = 0.004333 moles KOH X 1 mole HNO3 = 0.004333 moles HNO3
1
1 mole KOH
Step 3: Use dimensional analysis to solve for moles/L of HNO3:
[HNO3] = 0.004333 moles HNO3 = 0.217 M
0.020L