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1.

 Phenotype distribution for ear II: 9:3:3:1;

 Ear II indicates dark and smooth is dominant;

 phenotype distribution for ear I: 1:1:1:1;

 Therefore:

 Ear I could result from a testcross: AaBb x aabb

 Kernel B is dominant for both traits: most abundant phenotype for ear II:

AaBb x AaBb

 Kernel C is dominant for color but recessive for shape: about 3/16 of kernels in ear II. D is rarest phenotype.

 ALL phenotypes should be in equal frequency in ear I.

Answer: (A)- all statements are correct

2. See discussion in Hartwell:

I. False; Frequency is 1/600 in U.S. populations;

II. True; educational follow up was lacking;

III. False; prenatal testing is available;

IV. True; information did get out to insurers and employers.

Answer: (D)- II and IV are correct.

3. See discussion in Hartwell:

I. False; HD is an autosomal dominant

II. True; this was one of the first human genes to be mapped to a chromo- some using molecular markers;

III. False; a cure is still unavailable.

IV. True; symptoms of HD start to appear over time.

Answer: (D)- II and IV are correct.

4. From the data, both dominant and recessive phenotypes are present in the offspring, so neither parent could be homozygous for the dominant alleles; a recessive allele would need to be passed by both parents;

 The ratio of red:sepia in the offspring is 1:1, indicating a testcross: a se + /se x

se/se cross.

 The ratio of normal to vestigial is 3:1, indicating a hybrid cross; vg + /vg x vg + /vg

Answer: (C)- se+/se; vg+/vg x se/se; vg+/vg.

5. Probability has no memory; what has already happened is not relevant to the problem. The two births are independent events:

P (two girls) = P(girl) x P(girl) =½ x ½ = ¼

Answer: (D)- ¼

6. P(A_B_C_D_E_ff) =

½ x ¾ x ½ x ¾ x 1 x ½ = 9/128

Answer (E): none of the above

7. P(AaBbCcDdEeff) =

½ x ½ x ½ x ½ x ½ x ½ = 1/64

Answer (B): 1/64

8. 2 x 2 x 2 x 2 x 2 x 1 = 32

Answer (C): 32

A a

A a

AA Aa

Aa aa

Aa Aa Aa AA

Aa Aa

½ Aa

AA AA

2/3 Aa aa aa

½ Aa ½ Aa

?

¼ Aa

9. P(III-2 is heterozygote) = ½ x ½ = ¼;

Answer (A):

10. P(IV-1 is affected) = ½ x ½ x 2/3 x ½ x ¼ = 1/48;

Answer (D).

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