Time Resolved Pulsed Laser Photolysis Study of Pyrene Fluorescence Quenching by I- Anion Michael Buchanan Partners: Derek Rowe, Alex Schneider, and Justin Miller Chem 457 Sec. 006 February 27, 2015 Abstract This experiment focuses on fluorescence which is the process of exciting an electron by absorbing a high energy photon to an excited state and then emitting that photon to drop back down to ground state, this can then be seen in the visible light spectrum. The time it takes for an electron in an excited state to drop to ground state can be changed by altering the variables of the system. This experiment shows the rate of emission to the ground state of an electron from pyrene was changed by adding I- anions to the pyrene solution. The excited state of pyrene is able to accept electrons from I- causing it to form Py- and I. In this experiment the rate of emission to the ground state of pyrene and the change in rate emission to the ground state with the addition of I- were measured. These two measurements were then taken to find the rate constants of the quenching of pyrene and the pyrene fluorescence. Introduction Fluorescence spectroscopy is process used to analyze the fluorescence of a given sample using ultraviolet light. The laser is used to excite the electrons of the molecules to cause them to go into an excited state and then emit photons as they go back to their ground state. From the emitted photons, the excited state of a specific compound can be examined and determined. Using the properties of the compound, the concentration of the sample can then be determined if need be. Using Fluorescence spectroscopy is important to be careful because it uses an extremely sensitive detector as a way to determine different structures and solution states. Being able to determine the structure of a molecule is extremely important and useful in modern day application like determining the difference in malignant tumors from benign tumors.1 The laser has to give off a certain wavelength to excite the compound so then once the compound is excited, the compound goes to the excited state and then emits photons as it goes back to its ground state. The photons produce a charge on the photodiode in the laser and then the photodiode uses the charge to find the intensity of the fluorescence in the compound. The process of quenching is used to help the transition back to the ground state for the compound and it decreases the photon intensity given off during the process. Experimental Method Five mixtures were created for the experiment. These mixtures consisted of pyrene, potassium iodide, and 50/50 ethanol/water in a 10 mL flask. Each flask contained 10 μM of pyrene and some concentration of KI (0mM, 10mM, 20mM, 30mM, and 40mM). One by one, the flasks were put into a cuvette and were purged under pure nitrogen for five minutes to avoid quenching by oxygen from the air. The cuvettes were then placed in the photolysis apparatus (Figure 1). 2 Figure 1: Experimental Apparatus Three data points were taken for each of the flasks and then were saved onto an USB drive to later analyze and use for our data. Results The oscilloscope measures the fluorescence intensity over time. It then displayed a graph of Intensity vs time and using an exponential curve for the different graphs, we were about to find kobs. Figure 2: Fluorescence Intensity vs Time These data points are the average of the three runs for each flask to give an average kobs for each of the flasks. By taking the equations above for each flask and applying it to the equation below, kobs was able to be found for each of the flasks. Example, for the 10mM solution, the ππππ = 4 × 106 ππ π . πΌ = πΌπ π −ππππ π‘ Equation 1: Equation if Intensity I is treated as proportional to excited pyrene concentration. Once the kobs was found for each of the flasks, it was then plotted against the concentration of iodide anions to determine k0 and kq by using the graph below. 1.E+07 9.E+06 Kobs 8.E+06 7.E+06 y = 1.385E+8x + 3.484E+6 R² = 9.001E-1 6.E+06 5.E+06 4.E+06 3.E+06 0 0.005 0.01 0.015 0.02 0.025 0.03 0.035 0.04 [I-] Figure 3: kobs vs [I-] Plotting the kobs against the concentration of the iodide anion gave the values for the rate constants, k0 and kq. Both of these rate constants can be determined by the slope of the line (ππ = 1.385 × 108 ππ π ) and by the y-intercept (π0 = 3.484 × 106 ππ π ). Discussion The rate of emission to the ground state of pyrene with iodide both depends on the amount of pyrene and iodide anions within the solution. Using the graphs and equations for the data, we can see that as there are more iodide anions than pyrene the rate is a pseudo first order reaction. With this information, the rate of emission to the ground state is proportional to the amount of pyrene in the solution while the rate constant is proportional to the amount of iodide anions in the solution. If the equations are rearranged, then the rate constant for quenching can be found while changing the amount of iodide anions. This can be seen in the emission rate constants kobs that were calculated for each of the five flasks that contained pyrene and different concentrations of potassium iodide. The relative intensity of fluorescence vs. time was plotted to for kobs by using linear regression analysis. Then after calculating the kobs for each of the flask, kobs vs [I-] was plotted to find the emission rate of pyrene and the quenching rate (k0 and kq). In the graph of kobs and [I-], k0 is the y-intercept and kq is the slope of the line. As seen in the two graphs, the residual value for the Figure 3 is much smaller than those that are in Figure 2. This is likely due to the way the experiment way done. As the mixtures were made, the potassoium iodide had to measured out and put in the 40mM flask and was mixed with the 50/50 ethanol/water solution. Each of the other flasks would have some sort of amount put in them from this original flask. The amount take from the original flask and put into the pther flasks may not have been the exact concentration as need. Another aspect is the purging under pure oxygen to prevent quenching from oxygen in the air. As the purging concluded for each sample, the extraction point of the purging needle being taken out of the cuvette might have let air in causing the samples to quench a bit. Conclusion To calculate the emission rate constant, the reaction of adding photons to pyrene to an excited state had to be treated as a first order reaction. Using this knowledge, he fluorescence intensity of pyrene was plotted against time, which gave us the observed rate constants. Once we had kobs, it was plotted against the concentration of iodide anions to find k0, the emission rate with no quencher present, and kq, the quenching rate. Using these rate constants and assume it to be a pseudo-first order reaction, the rate constants for quenching of pyrene by iodide were calculated. This experiment demonstrated the importance of fluorescence spectroscopy in all types of chemical systems, making it a very useful analytical tool that can be used to determine unique properties of molecules. Acknowledgements Chemical and Mechanical support from Dr. Milosavljevic and the whole Department of Chemistry. Assistance with experiment and accurately assessing questions from Codey Henderson. Literature Cited 1. Choi, J; Gupta, S; Park, I; Lee, D; Ye, J.C. Breast cancer diagnosis from fluorescence spectroscopy using support vector machine. Optical Tomography and Spectroscopy of Tissue 2007, 6434. 2. Milosavljevic, B. Lab Packet for CHEM 457 Experimental Physical Chemistry. The Pennsylvania State University. Spring 2015 pp. 5-6. Appendix Sample Calculations Mass of KI = (M ∗ V) ∗ MW (0.1 M ∗ 0.01L) ∗ (166 g ) mol = 0.1676 g KI 6π‘ ππππ : πΌ = πΌπ π −ππππ π‘ For example, 10mM π¦ = 0.2901π −4×10 ππ = 1.385 × 108 ππ π & π0 = 3.484 × 106 ππ π → ππππ = 4 × 106 ππ π , both are taken from the equation of kobs vs [I-]. Uncertainty analysis/error propagation Uncertainty of the slope and y-intercept of the kobs versus [I-] (observed rate constant vs concentration of the iodide anions). Slope: β95% π = π π ×π‘95% √π Y-Intercept: β95% π = Other Data = (2.753×107 )×2.78 π π ×π‘95% √π √5 = = 3.423 × 107 ( (6.74×105 )×2.78 √5 ππ π = 8.38 × 105 ( ) ππ π ) SUMMARY OUTPUT Regression Statistics Multiple R 0.953462617 R Square 0.909090962 Adjusted R Square 0.878787949 Standard Error 870535.1601 Observations 5 ANOVA df Regression Residual Total Intercept X Variable 1 1 3 4 SS MS F Significance F 2.2735E+13 2.27E+13 30.00002 0.011967 2.27349E+12 7.58E+11 2.50085E+13 Coefficients Standard Error t Stat P-value Lower 95%Upper 95% Lower 95.0% Upper 95.0% 3115655.593 674313.6354 4.620484 0.019082 969688.7 5261623 969688.7 5261623 150781160.8 27528738.89 5.477227 0.011967 63172427 2.38E+08 63172427 2.38E+08 0mM KI K1 3,476,372.13 K2 3,485,766.36 K3 3,489,507.44 Average 3483881.979 30mM KI K1 8,219,674.26 K2 8,214,372.25 K3 8,103,426.32 Average 8179157.61 10mM KI K1 3,523,941.39 K2 3,511,544.31 K3 3,523,172.16 Average 3519552.622 40mM KI K1 8,671,045.79 K2 8,712,155.41 K3 8,696,211.37 Average 8693137.523 20mM KI K1 6,706,591.03 K2 6,760,705.24 K3 6,874,696.66 Average 6780664.31