Collins auto believes the number of cars sold in a day (Q) depends on two factors: the # of hrs the dealership is open (H) and the # of salespersons working that day (S). After collecting two months data (53 days), the manager estimates the following log-linear model: Q= Q=aHbSc a. Explain how to transform this log-linear model into a linear form that can be estimated using multiple regression analysis. b. How do you interpret coefficients b and c? If the dealership increases the # of salespersons by 20%, what will be the % increase in daily sales? c. Test the overall model for statistical significance at 5% significance level. d. What % of the total variation in daily autosales is explained by this equation? what could you suggest to increase this percentage? e.Test intercept for statitical significance at the 5% level of significance. If H & S both = 0 are sales expected to be 0? Why/not? f.If hrs of operation decreases 10% -the impact on sales is Regression analysis chart follows: Dependent Variable: LNQ R-Square F-Ration P-Value on P Observations: 53 0.5452 29.97 0.0001 Variable Parameter Standard T-Ratio P-Valu Estimate Error Intercept 0.9162 0.2413 3.80 0.0004 LNH 0.3517 0.1021 3.44 0.0012 LNS 0.2550 0.0785 3.25 .0021 Part A π = π π»π π π Taking natural logarithms on both sides LN( π) = πΏπ( π) + π LN( π») + π LN( π) That is π ∗ = π∗ + ππ» ∗ + ππ ∗ where, π ∗ = πΏπ( π), π∗ = πΏπ( π) , π» ∗ = Ln(π») πππ π ∗ = LN( π) Now we have transformed the log linear model into a linear model. Part B ππΏπ( π) π = π πΏπ(π») is the rate of proportional change π with respect to proportional change in π». For every 1% increase in π», the sales π increases by b%. ππΏπ( π) π = π πΏπ( π) is the rate of proportional change π with respect to proportional change in S. For every 1% increase in S, the sales π increases by c%. If the number of sale persons increases by 20%, then the sales increases by 20 c%. Part C Testing for statistical significance of the model Null hypothesis π»0 : π‘βπ πππππ ππππ πππ‘ ππ₯πππππ π‘βπ π£πππππ‘πππ ππ π‘βπ πππππππππ‘ π£πππππππ. Alternative hypothesis: π»1 : the null hypothesis is false. πΉ = 29.97 and π − π£πππ’π = 0.0001 < 0.05 F is significant at the 5% level. So reject the null hypothesis. The model is statistically significant. Part D 54.52% of the total variation in auto sales is explained by this equation. If we include the other explanatory variables such as advertising expenditure, price of fuel etc in to the model the percentage of variation explained by the model can be increased. Part E To test the statistical significance of the intercept, the t-value is 3.80 with p-value = 0.0004 < 0.05. So t is significant. So the intercept is statistically significant. If both π» and π are equal to 0, then the estimated sales is π = π π» π π π = (0.9162) × (0)0.3517 × (0)0.2550 = 0 Part F If hours of operation decreases by 10%, then sales decreases by 10 π% = 10 × 0.3517% = 3.517%