Chemistry: Spring Semester Lecture Notes

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HC Unit 11: Equilibrium / Acids and Bases
reversible reaction:
Name: _______________________
AND
Acid dissociation is a reversible reaction.
H+ + NO2–
HNO2
equilibrium:
-- looks like nothing is happening; however…
--
Le Chatelier’s principle: When a system at equilibrium is disturbed, it shifts to a new
equilibrium that counteracts the disturbance.
EX.
N2(g) + 3 H2(g)
2 NH3(g)
Disturbance
Equilibrium Shift
Add more N2…………
Add more H2…………
Add more NH3……….
Remove NH3…………
Add a catalyst………..
Increase pressure……
EX.
Transition Lenses
AgCl + energy
(clear)
Go outside…
Then go inside…
1
Ago + Clo
(dark)
EX.
In a chicken… CaO + CO2
CaCO3
In summer, [CO2] in a chicken’s blood
due to panting.
-- shift…
How could we increase eggshell thickness in summer?
--
-Acids and Bases
pH
pH
taste ______
taste ______
react with ______
react with ______
proton (i.e., H+) donor
proton (i.e., H+) acceptor
turn litmus ______
turn litmus ______
lots of H+/H3O+
lots of OH–
react w/metals
don’t react w/metals
Both are electrolytes.
pH scale: measures acidity/basicity
ACID
D
0
1
2
3
4
BASE
5
6
7
8
9
10
11
NEUTRAL
Each step on pH scale represents a factor of ___.
pH 5
vs.
(___X more acidic)
EX.
pH 3 vs. pH 5
pH 8 vs. pH 13
2
pH 6
12
13
14
A Few Definitions
monoprotic acid:
polyprotic acid:
diprotic acid:
Common Acids
Strong Acids
hydrochloric acid:
H+ + Cl–
HCl
-nitric acid:
HNO3
H+ + NO3–
H2SO4
H+ + HSO4–
-sulfuric acid:
-**NOTE:
Weak Acids
acetic acid:
CH3COO– + H+
CH3COOH
-hydrofluoric acid:
H+ + F–
HF
-citric acid, H3C6H5O7
lactic acid, CH3CHOHCOOH
--
--
ascorbic acid, H2C6H6O6
carbonic acid, H2CO3
--
-- carbonated beverages
--
Dissociation and Ion Concentration
Strong acids or bases dissociate ~100%.
H+
NO3–
H+
+
HNO3
NO3–
1
2
100
1000/L
0.0058 M
3
H+
+
NO3–
HCl
4.0 M
**NOTE:
Ca(OH)2
0.025 M
pH Calculations
The hydronium ion (H3O+) is the species formed when hydrogen ion (H+) attaches to
water (H2O). OH– is the hydroxide ion.
For this class, in any aqueous sol’n,
EX.
If hydrogen ion concentration = 4.5 x 10–9 M, find hydroxide ion concentration.
EX.
Given:
Find:
A. [OH– ] = 5.2 x 10–6 M
[H+]
B. [OH–] = 3.8 x 10–11 M
[H+]
C. [H+] = 1.8 x 10–3 M
[OH–]
D. [H+] = 7.3 x 10–12 M
[H3O+]
EX.
Find the pH of each sol’n above.
A.
B.
C.
D.
4
A few last equations…
[H+] = 10–pH
pH
[H+]
pH = –log [H ]
+
[H+] [OH–] = 1 x 10–14
pH + pOH = 14
[OH–] = 10–pOH
pOH
EX.
pOH = –log [OH–]
If pH = 4.87, find [H+].
EX.
For the following problems, assume 100% dissociation.
EX.
Find pH of a 0.00057 M nitric acid sol’n.
5
[OH–]
If [OH–] = 5.6 x 10–11 M, find pH.
EX.
Find pH of 3.2 x 10–5 M barium hydroxide sol’n.
EX.
Find the concentration of an HClO4 sol’n w/pH 3.38.
EX.
Find pH of a sol’n with 3.65 g HCl in 2.00 dm3 of sol’n.
EX.
What mass of Al(OH)3 is req’d to make 15.6 L of a sol’n with a pH of 10.72?
Acid-Dissociation Constant, Ka
For the generic reaction in sol’n:
A + B
For strong acids, e.g., HCl…
Other Ka’s for weak acids:
C + D
For weak acids, e.g., HF…
CH3COOH
HC3H5O3
HNO2
6
CH3COO– + H+
Ka =
H+ + C3H5O3–
Ka =
H+ + NO2–
Ka =
EX.
Find the pH of a 0.85 M nitric acid solution.
EX.
Find the pH of a 0.85 M nitrous acid solution. Nitrous acid’s Ka is 4.5 x 10–4.
Indicators:
Two examples, out of many:
litmus…………………
phenolphthalein……..
Measuring pH
litmus paper
phenolphthalein
pH paper
-- contains a mixture of various indicators
---
universal indicator -- is a mixture of several indicators
--
pH meter
-- measures small voltages in solutions
-- calibrated to convert voltages into pH
--
Neutralization Reaction
HCl +
H3PO4 +
H2SO4 +
HClO3 +
NaOH  _________ + ________
KOH  _________ + ________
NaOH  _________ + ________
Al(OH)3  _________ + ________
________ + ________ 
AlCl3 + ________
________ + ________ 
Fe2(SO4)3 + ________
7
Titration
If an acid and a base are mixed together in the right amounts, the resulting
solution will be perfectly neutralized and have a pH of 7.
-- For pH = 7…………………………...
In a titration, the above equation helps us to use…
EX.
2.42 L of 0.32 M HCl are used to titrate 1.22 L of an unknown conc. of KOH. Find the
molarity of the KOH.
EX.
458 mL of HNO3 (w/pH = 2.87) are neutralized w/661 mL of Ba(OH)2. What is the pH
of the base?
EX.
How many L of 0.872 M sodium hydroxide will titrate 1.382 L of 0.315 M sulfuric
acid?
**NOTE:
8
Buffers:
Example:
The pH of blood is 7.4.
Many buffers are present to keep pH stable.
H+ + HCO3–
H2CO3
H2O + CO2
hyperventilating: CO2 leaves blood too quickly
alkalosis: blood pH is too high (too basic)
Remedy:
acidosis: blood pH is too low (too acidic)
More on buffers:
-- a combination of a weak acid and a “common-ion” salt
e.g.,
-- together, these substances resist changes in pH
(A) weak acid: CH3COOH
(lots)
CH3COO– + H+
(little)
(little)
(B) salt:
Na+ +
(lots)
NaCH3COO
(little)
If you add acid…
(i.e., H+)
1.
2. **Conclusion:
If you add base…
(i.e., OH–)
1.
2. **Conclusion:
9
CH3COO–
(lots)
Amphoteric Substances:
e.g., NH3
NH3
e.g., H2O
H2O
Partial Neutralization
EX.
Find pH.
2.15 L of
0.22 M HCl
1.55 L of
0.26 M KOH
pH = ?
Procedure:
1. Calc. mol of substance,
then mol H+ and mol OH–.
2. Subtract smaller from larger.
3. Find [ ] of what’s left over,
and calc. pH.
EX.
4.25 L of 0.35 M hydrochloric acid is mixed w/3.83 L of 0.39 M sodium hydroxide.
Find final pH.
10
EX.
A. 0.038 g HNO3 in 450 mL of sol’n. Find pH.
EX.
B. 0.044 g Ba(OH)2 in 560 mL of sol’n. Find pH.
EX.
C. Mix them. Find pH of resulting sol’n.
11
Example Titration with HNO3 and NaOH
From a known [HNO3], find the unknown [NaOH].
HNO3  H+ + NO3–
NaOH  Na+ + OH–
0.10 M 0.10 M
?
Buret Readings, in mL
Trial 1
Acid
Base
Initial Vol.
Final Vol.
Amt. Used
[H+] VA = [OH–] VB
[OH–] = [NaOH] =
Buret Readings, in mL
Trial 2
Acid
Initial Vol.
Final Vol.
Amt. Used
[H+] VA = [OH–] VB
[OH–] = [NaOH] =
12
Base
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