4 - Cabrillo College

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Problem Set 4
Chapter 5: Circuit Theorems
Due: see website for due dates
P 5.2-3
Find vo using source transformations if
i = 2.5 A in the circuit shown. Solution: 28V
P 5.2-7
Use source transformations to simplify the circuit to
determine the power supplied by the 8V-source. Is the
source active or passive? Solution: - 4.14 W
P 5.3-6
Use superposition to find i for the circuit.
Solution: 3.5 mA
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P 5.4-3
Find the Thévenin equivalent circuit for the circuit.
Solution: 4, 2V
P 5.4-5
Find the Thévenin equivalent circuit for the circuit shown.
Solution: -8/3, -2V
P 5.4-16
Replace the part of the circuit to the left of terminals a–b by its
Thévenin equivalent circuit. Now determine the value of the
current io. Solution: 12.5 mA
P 5.5-10
Find the Norton equivalent circuit.
Solution: -18, 0.5A
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P 5.6-6
Determine the maximum power that can be absorbed by a
resistor, R, connected to terminals a–b of the circuit shown.
Specify the required value of R. Solution: 50, 2W
DP 5-4
The circuit shown has four unspecified circuit
parameters: vs, R1, R2, and d, where d is the gain of the
CCCS. To design this circuit, we must specify the
values of these four parameters. The graph shown
describes a relationship between the current i and the
voltage v. Specify values of vs, R1, R2, and d that cause
the current i and the voltage v to satisfy the relationship described by the graph.
Solution: -3.08V, 1k, 1k, -3.6
First Hint: The equation representing the straight line in graph is “v RThi + vOC.” That
is, the slope of the line is equal to −1 times the Thévenin resistance and the “v-intercept”
is equal to the open-circuit voltage.
Second Hint: There is more than one correct answer to this problem. Try setting
R1 = R2.
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Challenge Problem 4A
Use Thévenin’s theorem to find i0 in the circuit.
Challenge Problem 4B
Use Thévenin’s theorem to find v0 in the circuit.
Challenge Problem 4C
Use Thévenin’s theorem to find the power of the 12V-source. Is it active or passive?
Challenge Problem 4D
Use PSpice to check your answers for P 5.4-5.
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