Balancing Chemical Equations
Chemical Reactions
The following diagrams graphically illustrate two simple chemical reactions.
Notice the difference between the subscripts (ex. H2) and the coefficients (shown
in red) in these reactions. When balancing reactions, the coefficients can (and
usually need to be) changed, but the subscripts present in the molecular formula
can not be altered.
H2 + Cl2 --> 2 HCl
Reaction of H2 + Cl2
2 H2 + O2 --> 2 H2O
Definitions
In a chemical reaction, atoms are NOT created or destroyed. What changes in a
chemical reaction is the connections (bonds) between atoms. In the first reaction
shown above, two hydrogen atoms (H) start out bonded to each other. During the
course of the chemical reaction, this H-H bond breaks and a new H-Cl bond is
formed.
A balanced chemical equation is a 'description' that accounts for all of the atoms
in a chemical reaction. Every atom that appears in the reactant side (left side =
starting material) MUST be accounted for in the products (right side). If five
carbon atoms are present on the left side of a chemical equation, there must be
exactly five carbon atoms on the right side. This is accomplished by changing the
coefficients (the numbers in front of the formula). You are NOT allowed to
change to formula to balance a chemical equation.
Balancing Chemical Equations
While there is not set procedure for balancing equations that works every time,
the following steps will generally produce a balanced equation without requiring
excess steps.
1. Be sure that the formulas for each compound are written correctly. (Usually
this will be taken care of).
2. Select the 'simplest' element to begin balancing the equation. The 'simplest'
element is an element that only occurs in one compound in the reactants and in
one compound in the products.
3. Change the coefficients of the compounds containing the selected element
so that the same number of atoms of this element occur on both the reactant and
product sides of the equation.
4. Go back to Step #2, selecting the 'next simplest' element. Repeat steps 2-4
as until every element is 'balanced'.
5. After you are finished, check the final balanced equation to make sure every
element is still balanced.
In general, you only want to change any coefficient one time. If you change a
coefficient a second time, you will probably cause one of the 'earlier' elements to
become 'unbalanced'.
Example: Combustion of ethanol
Question: Balance the following equation for the combustion of ethanol.
CH3CH2OH + O2 ----> CO2 + H2O
In this reaction, all of the compounds have the correct formulas. The next step is
to select the 'simplest' element. Either carbon (C) or hydrogen (H) could be used.
For this example, we will select carbon. Following step #3, we change the
coefficients in front of ethanol (CH3CH2OH) and carbon dioxide (CO2). Since
there are two carbon atoms in ethanol and only one carbon atom in CO2, we add
a two in front of CO2.
1 CH3CH2OH + ____ O2 ----> 2 CO2 + ____ H2O
This equation now has two carbon atoms on the reactant side and two carbon
atoms on the product side, so the carbon atoms are balanced. The 'next simplest
element' is hydrogen (H). Like before, we change the coefficients in front of
ethanol and water (H2O) to balance this element. One ethanol molecule contains
six (6) hydrogen atoms, and one water molecule contains two (2) hydrogen
atoms. To balance this, we need three water molecules (3x2=6).
1 CH3CH2OH + ____ O2 ----> 2 CO2 + 3 H2O
Finally, we need to balance the oxygen atoms. On the reactants (left) side of this
equation we have three (3) oxygen atoms, while on the product (right) side we
have seven (7) oxygen atoms. (Two O atoms/CO2 times 2 = 4 oxygen atoms
PLUS one O atom/H2O times 3 = 3 oxygen atoms. 4+3=7).
Since the reactant side has fewer oxygen atoms, we need to change one or both
coefficients to increase the number of oxygen atoms. However, we do NOT want
to change the coefficient in front of ethanol because we have already used this to
balance carbon. (This is why I put a one in front of this molecule). Changing the
coefficient in front of oxygen (O2) will give the correct answer.
1 CH3CH2OH + 3 O2 ----> 2 CO2 + 3 H2O
Finally, it is a good idea to check to be sure the equation really is still balanced.
1 CH3CH2OH
+
3 O2 ---->
2 CO2
+
3 H2O
Carbon (C): 2
+
0
=
2
+
0
Hydrogen (H):
6
+
0
=
0
+
6
Oxygen (O): 1
+
6
=
4
+
3