Lesson 8.1 Review of Lewis Structures Suggested Reading Zumdahl Chapter 8 Section 8.10 Essential Question How are Lewis structures used to show bonding in chemical compounds? Learning Objective Differentiate between lone pairs and bonding pairs. Deduce the Lewis structures of molecules and ions for up to four electron pairs on each atom. Draw Lewis structures for compounds whose central atom does not obey the octet rule. Lewis Dot Symbols Recall that a Lewis electron-dot symbol is a symbol in which the electrons in the valence shell of an atom or ion are represented by dots placed around the letter symbol of the element. The table below shows the Lewis symbols for several main-group elements. Note that the dots are placed one to each side of a letter symbol until all fours sides are occupied. Note how Boron shows that the pairing of dots does not necessarily correspond to the pairing of electrons in orbitals in the ground state. Watch the following tutorial to review Lewis dot symbols: YouTube Video https://www.youtube.com/watch?v=EOkzt42DvE4 Lewis Dot Symbols & Ionic Bonds In an ionic bond, one atom looses all its outer electrons (leaving behind a filled inner shell) while another atom gains electron(s) to fill its valence shell. The two ions attract each other according to Coulombic interactions. Lewis dot symbols can be used to illustrate what occurs during the formation of an ionic bond. Coulombic Interactions: Attractions between opposite charges or repulsions between like charges that grow stronger as the charges become closer to each other. For example, consider sodium chloride. The Lewis structure for the salt NaCl, shows two ions which have their (Now) outer shells of electrons filled with a complete octet. In the case of the sodium cation, the filled shell is the outermost of the 'core' electron shells. In the chloride ion, the outer shell of valence electrons is complete with 8 electrons. The two ions are bonded by an ionic bond. Consider the compound magnesium oxide: MgO. Note that in both cases, the positive ions are metals and the negative ions are non-metals. This is generally true for ionic compounds Recall that in general metals have lower ionization energies and form cations while non metals have high ionization energies (and high electron affinities) and form anions. 1 2 Li+ Ba2+ Na+ Mg2+ K+ Ca2+ Rb+ Sr2+ Cs+ Ba2+ 3 4 5 6 7 Al3+ Lewis Dot Symbols & Covalent Bonds Covalent bonds involve the sharing of electrons to form 'bonding pairs' of electrons between atoms. Usually, when this occurs each atom ends up having eight electrons around it. This is the so-called octet rule. Take Cl2. Each Cl atom has one unpaired electron . It's unlikely that an ionic type bond will form since the two atoms are identical and such a transfer would leave one chlorine with only 6 electrons. More likely, they will share a pair of electrons so that each can 'think' it has 8 electrons in its valence shell. The other electrons around the chlorine atoms are referred to as lone pairs. Thus, each chorine has one bonding pair of electrons and three lone pairs of electrons. Mostly, this type of bonding occurs between non-metal atoms. Consider PCl3: Note: the lone pairs on the chlorines are hidden to emphasize the electron configuration around the phosphorous. Phosphorous normally has five electrons in its valance shell. The P shares one of its unpaired electrons with each of the three Cl atoms to form three covalent bonds. All four atoms now have a completed octet. It is not always necessary to use two dots to represent the pair of electrons. A dash can also represent the pair of electrons, especially in bonds. Consider the following examples or using a — to represent a bonding pair Watch the video to review the procedure for drawing Lewis structures for covalent compounds. YouTube Video https://www.youtube.com/watch?v=nw3xVVmEAU8 Exceptions to the Octet Rule There are exceptions to the octet rule. For example, H has only a 1s orbital occupied. The other orbitals are all higher in energy and not involved in the chemistry of hydrogen. Consider water H2O. There are only two electrons in the valence shell of hydrogen but that's all it takes to fill the first shell. Hence, the octet rule doesn't apply. Other compounds where the octet rule is not obeyed include some boron compounds. Boron has only three unpaired electrons to share. Here, Boron has only 6 valence electrons. It cannot complete its octet and remain a neutral compound. BF3 can combine with an F- ion to complete its octet as follows. One of the lone pairs on the fluoride is shared with the boron and forms a bond. Expanded Octets (Hypervalence) Elements in row 3,4,... have access to d orbitals (unlike row 2 elements that have only s and p orbitals) and can therefore have more than 8 electrons around them in certain compounds. Recall that P has a normal valence that includes 3 unpaired electrons and one lone pair. If that lone pair is divided into two extra unpaired electrons to be used in creating bonds, we then have a hypervalence of 5. By expanding the valence of P, we change it from Valence=3 with one lone pair to Valence=5 with no lone pairs. PCl5 is one such compound that has P with a hypervalence of 5 and no lone pairs. Other elements, like S can have more than one hypervalence. S has a normal valence of 2 unpaired electrons with two lone pairs. If we split the lone pairs one at a time to create extra unpaired electrons for bonding, we can create hypervalences of 4 with one lone pair and 6 with no lone pairs. The compounds are SF2, SF4, and SF6. Try drawing these Lewis structures out. Note that the number of lone pairs on the S decreases by one as the number of unpaired electrons goes up by 2. At one time, it was believed that the octet rule was the overriding factor in determining bonding. Using this logic, it was once thought that the Noble gases (He, Ne, ...) were totally unreactive since they already have a filled octet. Using the concept of hypervalences, we see that we can expect some compounds of noble-gases. We have in recent years produced compounds of Xe as follows: XeF2, XeF4, and XeF6, XeO4. All four of these compounds are using a hypervalent state of the Xenon. HOMEWORK: Book questions pg. 385 questions 67 & 68 Practice exercises 8.6-8.9, 8.11