Mia Gonzalez
Fundamentals of Math 2
Lower Extreme
Lower Quartile
Median
Project Part 3
Upper Quartile
Upper Extreme
In the table you will see a list of scores for a 7th grade English test in order going down each row and
continuing to the right.
45
46
49
49
62
65
66
72
73
73
73
75
76
77
78
82
82
85
86
86
89
92
93
94
94
To find the lower extreme, you must put the data in order, and then find the lowest number, which will
be your lower extreme: which in this case is 45.
To find the upper extreme, you must put the data in order, and then find the highest number, which will
be your upper extreme: which in this case is 94.
To find the median, we have to look for the number in the middle, so you can line up all the numbers in
order. After you have lined up all the numbers, you can take one off of each end at a time. For example,
the first two numbers we would take off are 45 and 94; then 46 and 94; and following that, 49, and 93,
and so on. Our median with this method will become 76.
To find the lower quartile, we have to find the middle number of the first half of the set, which is all the
numbers on the left side of the median which in this case is all the numbers from 45-75. As we did with
the median, we can line our numbers off and take off the end numbers until we get to the middle. The
only problem is that we have an even amount of numbers, so once we have two numbers left (which in
this case is 65 and 66), we can find the mean of the two numbers and that will mark the beginning of our
lower quartile, which is 65.5.
Mia Gonzalez
Fundamentals of Math 2
Project Part 3
To find the upper quartile, we have to find the middle number of the second half of the set, which is all
the numbers on the right side of the median which in this case is all the numbers from 77-94. As we did
the median, we can line our numbers off and take off the end numbers until we get to the middle. We
also have the same problem we did with the lower quartile of having an even amount of numbers, once
we get down to 2 numbers with our median (which are 86 and 86), we can find the mean of the two
numbers and that will mark the ending of the upper quartile, which is 86.