CUSTOMER_CODE SMUDE DIVISION_CODE SMUDE EVENT_CODE SMUAPR15 ASSESSMENT_CODE BCA3010_SMUAPR15 QUESTION_TYPE DESCRIPTIVE_QUESTION QUESTION_ID 10677 QUESTION_TEXT Define curve fitting. What are the methods of curve fitting. SCHEME OF EVALUATION The process of finding the equation of the curve of best fit which may be suitable for predicting the unknown values in known is curve fitting. (2 Marks) Methods: i.Graphic method (1 Mark) ii.Method of group average (1 Mark) iii.Method of moments (1 Mark) iv.Method of least squares (1 Mark) Graphical method explanation (4 Marks) QUESTION_TYPE DESCRIPTIVE_QUESTION QUESTION_ID 10678 QUESTION_TEXT Define interpolation and extrapolation. When the following formulate are useful i. Newton’s forward difference interpolation formula ii. Newton’s backward difference interpolation formula iii. Central difference formula SCHEME OF EVALUATION For a given table of values (Xk, Yk), K=0, 1,2, 3…….n the process of estimating value for Y, for any intermediate value of X is called interpolation (2 Marks) Computing Y for X, lying outside the table of values of X extrapolation (2 Marks) i.Interpolation near the beginning of set of tabular values (2 Marks) ii.Near the end of the tabular values (2 Marks) iii.Near middle of the table (2 Marks) QUESTION_TYPE DESCRIPTIVE_QUESTION QUESTION_ID 10680 QUESTION_TEXT Define significant digits. State the rules and describe the notion of significant digits SCHEME OF EVALUATION The digits that are used to express a number (1 Mark) Rule 1: (Numbers without decimal point) (2 Marks) Rule 2: (Numbers with decimal point) (2 Marks) Note: 1.All non zero digits are significant (1 Mark) 2.All zeros occurring between non zero digits are significant digits (1 Mark) 3.Trailing zeros following a decimal point (1 Mark) 4.Zeros between decimal point and preceding a non zero digit are not significant (1 Mark) 5.When the decimal point is not written trailing zeros are not considered to be significant. (1 Mark) QUESTION_TYPE DESCRIPTIVE_QUESTION QUESTION_ID 10681 QUESTION_TEXT Explain Inherent errors and numerical errors with their component SCHEME OF EVALUATION Inherent errors (2 Marks) Data error (2 Marks) Conversion error (2 Marks) Numerical errors (2 Marks) Truncation numerical error (2 Marks) QUESTION_TYPE DESCRIPTIVE_QUESTION QUESTION_ID 73416 QUESTION_TEXT Explain six steps to apply Cramer’s Rule SCHEME OF EVALUATION Step i. Write the given equations in order so that constant terms all on the right side (1.5 Marks) Step ii. Take = the determinant formed by the coefficients of x, y, z (1.5 Marks) Step iii. Replace the first column of by constant terms of the equations and denote as x (1.5 Marks) Step iv. Replace the second column of by constant terms of the equations and denote as y (1.5 Marks) Step v. Replace the third column of by constant terms of the equations and denote as z (1.5 Marks) Step vi. Write the solution (3 marks) QUESTION_TYPE DESCRIPTIVE_QUESTION QUESTION_ID 125708 QUESTION_TEXT Explain the power method. In many engineering problems, it is required to compute the numerically largest eigen value and the corresponding eigen vector. In such cases, the following power method is quite convenient which is also well suited for solid machine computation. Method: (To find the largest eigen value and the corresponding eigen vector). Suppose A is the given square matrix. Step 1: Choose the initial vector such that the largest element is unity. (choose initially an eigen vector X(0) = (1, 0, 0)t or (0, 1, 0)t or (0, 0, 1)t etc) SCHEME OF EVALUATION Step 2: This normalized (taking the largest component out as a common factor) vector X(0) is pre-multiplied by the given matrix. (evaluate the matrix product AX(0) which is written as (1) X(1) after normalization). Step 3: This gives the first approximation (1) to the eigen value and X(1) to the eigen vector. Step 4: Compute AX(1) and again put in the form AX(1) = (2) X(2) by normalization which gives the second approximation. Similarly we evaluate AX(2) and put it in the form AX(2) = (3) X(3). Step 5: Repeat this process till the difference between two successive iterations is negligible. The values so obtained are respectively the largest eigen value and the corresponding eigen vector of the given square matrix A