BI475: Molecular Biology Ch. 10: Review Questions & Answer Key Spring, 2003 1 Circle the letters corresponding to the appropriate terms/phrases that complete items 1–20. 1. Operator constitutive mutants of the lac operon would a. express the lac repressor constitutively b. block the binding of RNA polymerase to the promoter c. expr -galactosidase constitutively d. prevent the inducer from binding to the repressor - c + + + 2. An E coli cell that has the genotype I O Z /I O Z would a. -galactosidase synthesis upon the addition of lactose b. galactosidase c. -galactosidase d. -galactosidase synthesis upon the addition of lactose 3. Which of the following is not used in the electrophoretic mobility shift assay (EMSA)? a. a radiolabeled DNA fragment b. a polyacrylamide gel c. a DNA binding protein d. DNase I 4. Which of the following proteins does not "footprint" the lac operon control region? a. lac repressor b. -galactosidase c. RNA polymerase cAMP-CAP d. 5. How does binding of the lac repressor to the lac operator block transcription initiation? a. lac repressor binding blocks RNA polymerase from interacting with DNA at the start site b. lac repressor binding induces a DNase which cleaves the DNA at the transcription start site c. lac repressor binding causes a conformational change in RNA polymerase d. lac repressor binding induces a protease which degrades the sigma subunit of RNA polymerase 6. All of the following statements about the essential carboxy terminal domain (CTD) of RNA polymerase are true except a. The CTD is present in RNA polymerase I, II , and III b. The CTD can become phosphorylated c. The CTD is critical for viability d. The CTD of mammals contains more than 50 repeats of a heptapeptide 7. Most eukaryotic and prokaryotic genes are controlled at the level of a. transcription initiation b.transcription elongation c.transcription d.translation initiation 8. Which of the following is not a step in the nascent-chain (run on) assay? a. isolation of nuclei b. incubation ribonucleoside triphosphate c. exposure of cells to a labeled RNA precursor d. hybridization cloned cDNAs termination with of labeled 9. An enhancer a. is a DNA element that stimulates transcription of eukaryotic promoters b. binds to RNA polymerase and stimulates transcription S2003BI475CH10RevQs&Key 32P-labeled 2/6/16 RNA to BI475: Molecular Biology Ch. 10: Review Questions & Answer Key Spring, 2003 2 c. acts as a binding site for RNA polymerase d. interacts with repressor proteins to enhance transcriptional repression 10. The TATA box a. serves as a promoter sequence for genes transcribed by RNA polymerase III b. is located approximately 100 base pairs upstream of the start site for mRNAs c. is present in all eukaryotic genes d. acts to position RNA polymerase II for transcription initiation 11. All of the following elements can function as eukaryotic promoters except a. a TATA box b. an initiator element c. CpG islands d. an enhancer 12. All of the following statements about the Wilms’ tumor (WT1) gene or WT1 protein are true except: a. Loss of functional WT1 protein leads to the development of kidney tumors b. The WT1 protein has a zinc finger binding domain c. WT1 protein is a transcription activator d. WT1 binds to the control region of the EGR1 gene 13. A leucine zipper motif contains a. a stretch of five leucine residues in a row c. a leucine residue complexed with a zinc ion structure b. a leucine residue at every seventh position d. an alternating leucine-alanine-proline 14. Which of the following is not a structural motif found in a DNA binding domain? a. homeodomain b.zinc finger c.helix-loop-helix d.random domain coil acidic 15. Which of the following is the correct order of binding of general transcription factors to initiate transcription at RNA polymerase II promoters? a. TFIID, TFIIB, Pol II, TFIIH b. PolII, TFIID, TFIIB, TFIIH c. TFIIB, PolII, TFIIH, TFIID d. TFIID, TFIIH, TFIIB, PolII 16. What is the function of TFIIH in the transcription initiation complex? a. TFIIH binds to the TATA box b. TFIIH unwinds the DNA duplex c. TFIIH catalyzes the synthesis of RNA d. all of the above 17. All of the following statements about heterochromatin are true except a. Heterochromatin stains more darkly with DNA dyes than euchromatin b. Heterochromatin contains more highly condensed DNA than euchromatin c. Heterochromatin is associated with inactive genes d. Heterochromatin is more susceptible to DNaseI than euchromatin 18. All of the following events play a role in yeast mating type switching except S2003BI475CH10RevQs&Key 2/6/16 BI475: Molecular Biology Ch. 10: Review Questions & Answer Key a. methylation of the silent mating type locus the MAT locus c. chromatin condensation at the silent mating type locus d. conversion 19. Lipid soluble hormones activate transcription by a. binding to specific cell-surface receptors c. binding to a nuclear receptor d. b. Spring, 2003 3 transcription of the gene at a recombination event known as gene b. phosphorylating a protein kinase inhibiting a histone deacetylase 20. All of the following statements about transcription by archaebacteria are true except a. Archaens use a single RNA polymerase b. Archael RNA polymerase has a subunit structure similar in complexity to bacteria c. Archaens transcribe operons into polycistronic mRNAs d. Archael promoters have an A/T rich sequence upstream of the transcription start site 21. Define the terms cis-acting DNA sequences and trans-acting proteins. + 22. Describe the experimental evidence that the product of the lac I gene is trans-acting. 23. Describe how the electrophoretic mobility shift assay (EMSA) and the techniques are used to identify DNA-protein interactions. DNase I footprinting 70 24. The major form of bacterial RNA polymerase is com the role of each of these subunits in the initiation of transcription. ). Describe 25. Most bacterial repressors bind DNA as dimers. Describe how these repressors bind to the operator sequence. 26. Contrast the transcriptional regulatory elements in prokaryotes and eukaryotes. 27. Describe the similarities and differences between prokaryotic and eukaryotic RNA polymerases. 28. Describe the structure and function of the carboxy terminal domain (CTD) of RNA polymerase II. 29. What is the functional difference between enhancers and promoter proximal elements? 30. Compare the general pattern of cis-acting control elements in yeast and higher eukaryotes. 31. What is an enhancesome? 32. How can transcription factors be purified using sequence-specific DNA-affinity chromatography? 33. Describe the structure and function of a zinc finger motif. 34. Describe the structure of the RNA polymerase II transcription initiation complex. S2003BI475CH10RevQs&Key 2/6/16 BI475: Molecular Biology Ch. 10: Review Questions & Answer Key Spring, 2003 4 35. Describe the functional properties of TFIID and TFIIH. 36. Describe the role of histone deacetylation and hyperacetylation in yeast transcriptional control. 37. Signal transduction is one mechanism for regulating transcription. Describe the model for interferon gamma-mediated gene activation. 38. Describe how lipid soluble hormones, for example glucocorticoid, regulate gene transcription acting through nuclear hormone receptors. 39. Describe the structure and function of the yeast mitochondrial RNA polymerase. 40. Discuss three features that distinguish transcription initiation at Pol I and Pol III promoters from that at Pol II promoters. S2003BI475CH10RevQs&Key 2/6/16 BI475: Molecular Biology Ch. 10: Review Questions & Answer Key Spring, 2003 5 PART C: Answers 1. c; 2. b; 3. d; 4. b; 5. a; 6. a; 7. d; 8. c; 9. a; 10. d; 11. d; 12. c; 13. b; 14. d; 15. a; 16. b; 17. d; 18. a; 19. c; 20. b 21. Cis-acting DNA elements affect only the expression of genes on the same DNA molecule that are linked to the DNA element. In contrast, trans-acting proteins are free to diffuse through the cell and can bind to any target DNA sequence. - - + + 22. An E. coli cell containing a single lac gene (I O Z ) produces an inactive repressor and as a result constitutively + synthesizes -galactosidase. The introduction of a lac gene on a plasmid into these E. coli cells leads to loss of galactosidase expression. In this case, the lac repressor can bind to the operator on the chromosome and repress synthesis of -galactosidase. 23. In the electrophoretic mobility shift assay (EMSA), DNA-protein interactions are detected by changes in the mobility of a DNA fragment bound to a protein. A DNA fragment containing a putative protein binding site is first radiolabeled and then incubated in the presence of sequence-specific DNA binding proteins. The DNA fragment containing a bound protein migrates slower in a gel, causing a shift in the location of the radiolabeled DNA detected by autoradiography. In 32 the DNase I footprinting technique, a DNA fragment is first labeled at only one end with P. The radiolabeled DNA fragment is incubated with a DNA binding protein and then digested with a limiting concentration of DNaseI. The DNaseI concentration is set such that on average each DNA molecule is cut only once. The resulting cut DNA fragments are separated using denaturing gel electrophoresis and visualized using autoradiography. In the absence of a DNA binding protein, a ladder of DNA bands are detected on the autoradiogram. Binding of a protein to the DNA prevents DNase I from digesting the radiolabeled DNA at the site of the DNA-protein interaction, resulting in a blank area (or footprint) in the DNA ladder. 24. The subunit interacts with the promoter and signals the polymerase to initiate transcription at a specific DNA sequence. The and ' subunits polymerize the ribonucleoside triphosphates as directed by the template strand. The subunit interacts with regulatory proteins and sometimes with DNA to regulate the rate of transcription initiation. 25. Many bacterial repressors bind to DNA as homodimers, i.e., two copies of the same molecule. In dimeric repressors an alpha helix in each repressor monomer inserts into the major groove of the operator DNA. Most operator sequences are short inverted repeats. Each half of the inverted repeat sequence in the operator is called a half-site. Each half site binds to one monomer of a dimeric repressor. Binding of the repressor to DNA is stabilized by hydrogen bonds, ionic bonds, and van der Waals interactions. 26. Transcriptional control in eukaryotes is a much more complex process in eukaryotes than in prokaryotes. In prokaryotes the control elements generally lie close (within 60 base pairs) to the promoters they regulate. In contrast, cis-acting control elements in eukaryotes often are located many kilobases away from the promoters they regulate. In some cases these regulatory sites can be tens of thousands of base pairs either “upstream” or “downstream” from the promoter. 27. In prokaryotes there is only one RNA polymerase, which consists of five subunits. In eukaryotes there are three RNA polymerases. RNA polymerase I synthesizes ribosomal RNA; RNA polymerase II synthesizes messenger RNA; and RNA polymerase III synthesizes tRNA and other small RNAs. The eukaryotic RNA polymerases are more complex than the bacterial RNA polymerase. All three contain two large subunits and 12–15 smaller subunits. All three eukaryotic RNA polymerases contain subunits with some sequence homology to the E. coli RNA polymerase subunits (, , and '). S2003BI475CH10RevQs&Key 2/6/16 BI475: Molecular Biology Ch. 10: Review Questions & Answer Key Spring, 2003 6 28. The carboxy terminal domain (CTD) of RNA polymerase II consists of a heptapeptide repeat, with a consensus sequence of Tyr-Ser-Pro-Thr-Ser-Pro-Ser. Yeast RNA polymerase II contains 26 or more repeats, while the mammalian RNA polymerase II contains 52 repeats. The CTD is critical for viability and at least 10 copies of the repeat must be present for survival. During formation of the transcription initiation complex, the CTD is unphosphorylated. When the RNA polymerase transcribes away from the promoter, the CTD is phosphorylated at serine and threonine residues. One hypothesis is that phosphorylation of the CTD causes the release of RNA polymerase from the transcription initiation complex. 29. Enhancers can stimulate transcription from a promoter tens of thousands of base pairs away. In contrast, promoterproximal elements are located 100- to 200-base pairs upstream of the start site and usually lose the ability to stimulate transcription from a promoter when moved only several tens of base pairs away. 30. In higher eukaryotes, genes contain both enhancers and promoter proximal elements as well as a TATA box or other promoter elements such as an initiator element or CpG islands. The promoter proximal elements are usually located within 200 base pairs of the start site, whereas the enhancers can be located tens of thousands of base pairs either upstream or downstream of the start site. In contrast, yeast genes contain an upstream activating sequence (UAS) which functions similarly to enhancers and promoter proximal elements in higher eukaryotes. Most yeast genes contain only one UAS located a few hundred base pairs upstream of the start site and a TATA box present approximately 90 base pairs upstream of the start site. 31. An enhancesome is a large nucleoprotein complex bound to an enhancer element. This complex is formed by the cooperative assembly of transcription factors to their multiple binding sites in an enhancer. 32. Sequence specific DNA affinity chromatography is a technique that takes advantage of the binding specificity of a protein to a specific DNA sequence. Once the DNA sequence to which a transcription factor binds is identified, this DNA sequence can be coupled to a bead in a column. A protein mix containing the transcription factor is applied to this column. Proteins that do not bind to the DNA fragment are washed out of the column. The bound transcription factor can then be eluted from the column in the presence of high salt. 33. A zinc finger is a structural motif found in DNA binding domains, which consists of a short length of the polypeptide 2+ chain folded around a Zn ion. The two basic classes of zinc finger domains are the C 2H2 and C4 structures. The C2H2 2+ zinc finger domain consists of two cysteine (C) and two histidine (H) residues bound to one Zn ion. The C4 zinc finger 2+ contains four cysteines bound to one Zn ion. The three-dimensional structure of the zinc finger forms a compact domain, which can insert its helix into the major groove of DNA. 34. The RNA polymerase II transcription initiation complex is a multiprotein complex. This complex consists of a DNA promoter element to which general transcription factors (i.e., TFIIA, TFIIB, TFIID, TFIIE, TFIIH) bind along with RNA polymerase II. This multisubunit nucleoprotein complex consists of 60–70 polypeptides with a mass of approximately 3 Mda and is nearly as large as an eukaryotic ribosome. 35. TFIID is a large multisubunit complex of approximately 750 kDa. TFIID consists of a 38 kDa TATA box-binding protein (TBP) and 11 TBP-associated factors (TAFs). TBP is the first protein to bind to a TATA box-containing promoter. TFIIH is the last protein to bind to the initiation complex. TFIIH contains helicase activity which unwinds the DNA duplex at the start site. As the polymerase transcribes away from the promoter, a subunit of TFIIH phosphorylates the carboxy terminal domain (CTD) of RNA polymerase II. S2003BI475CH10RevQs&Key 2/6/16 BI475: Molecular Biology Ch. 10: Review Questions & Answer Key Spring, 2003 7 36. Histone deacetylation/hyperacetylation is one mechanism for regulating transcriptional control in yeast. Repressor proteins can cause deacetylation of histone N-termini in nucleosomes. Unacetylated histones contain positive charges due to N-terminal lysines and interact strongly with DNA phosphates. These strong interactions may restrict access of general transcription factors thus leading to transcriptional repression. In contrast, histones that have their N-termini hyperacetylated are neutralized, eliminating the strong electrostatic interactions with the DNA phosphates. This more open chromatin configuration facilitates access of general transcription factors and induces transcriptional activation. 37. Signal transduction “translates” a signal from the cell surface to the nucleus. Binding of various polypeptide hormones to their cell-surface receptors leads to stimulation of transcription of particular genes. For example, several changes in a transcription factor called Stat1, which is present as an inactive monomer in the cytoplasm, is induced by binding of interferon gamma. Upon binding interferon gamma, the interferon gamma receptor dimerizes and activates JAK kinase. The activated JAK kinase phosphorylates a specific tyrosine residue in inactive Stat1 monomers. The phosphorylated monomers then form a homodimer, which is translocated from the cytoplasm to the nucleus, where it is capable of activating transcription of interferon gamma regulated genes. 38. Glucocorticoid is a lipid soluble hormone that binds to a member of the nuclear hormone receptor family, the glucocorticoid receptor (GR), and regulates gene transcription. In the absence of glucocorticoid, the GR in the cytoplasm is bound to the protein HSP90. When glucocorticoid diffuses through the cell membrane, it binds to the GR ligand binding domain and causes a conformational change in the GR releasing HSP90. The GR bound to glucocorticoid is then translocated into the nucleus, where it interacts with glucocorticoid response elements (GRE) and regulates transcription of responsive genes. 39. A nuclear-encoded RNA polymerase transcribes the circular mitochondrial genome. In yeast the mitochondrial RNA polymerase consists of a 145 kDa subunit with ribonucleotide-polymerizing activity and a 43 kDa factor that is essential for initiation at the start site. The large subunit is related to the monomeric RNA polymerases of bacteriophage. The small subunit is related to factors in bacterial RNA polymerases. Thus the mitochondrial polymerase appears to be a hybrid of the simple bacteriophage and bacterial RNA polymerases. 40. Transcription initiation at Pol II promoters requires hydrolysis of ATP to initiate transcription; this is not required at Pol I or Pol III promoters. The TATA box at –30 is the only control element involved in Pol II complexes; in contrast, assembly of Pol I complexes involves one upstream element and one promoter control element, and assembly of Pol III complexes involves two or three internal control elements. Finally, Pol I and Pol III are the final components assembled into their initiation complexes, whereas several additional transcription factors must be bound after addition of the polymerase to complete assembly of Pol II complexes. S2003BI475CH10RevQs&Key 2/6/16