Chapter 9, continued Hybrid orbitals & multiple bonding Consider the ethylene molecule H H C H C H the observed H-C-H and H-C-C bond angles are 1200 in ethylene ; what type of hybridization does this suggest for the C atoms? what happens to the unhybridized 2p orbital on each C? 207 Now consider the bonding in acetylene, C2H2: H C C H Experimental evidence indicates that the H-C-C bond angles are 180o in acetylene; what hybridization scheme does this suggest for the carbon atoms? Again, what happens to unhybridized 2p orbitals on the carbons? Bonds with e- density concentrated along the internuclear axis are called sigma () bonds e.g., overlap of 2 s-type AOs, 2 p-type AOs, or s - p overlap along the internuclear axis also, overlap of sp, sp2, or sp3 hybrid with an unhybridized AO along the internuclear axis 208 Bonds which result from overlap of p-type AOs oriented perpendicularly to the internuclear axis are called pi () bonds bonds result from sideways overlap of unhybridized ptype AOs e- density is above and below the internuclear axis e.g., how many and bonds in C2H4? C2H2? e.g., the Lewis structure for glycine is H O H2N C C O H H What are the bond angles and hybridizations of the C, O, and N atoms? How many and bonds are there in this structure? 209 Delocalized bonding Consider the ethylene molecule, C2H4:The bonding in C2H4 is said to be localized between the C atoms What about molecules with 3 or more atoms which can bond (i.e., have unhybridized p-orbitals)? e.g., NO3-, CO32-, C6H6 : all have resonance forms bonding in molecules with resonance forms can't be accurately described as localized 210 Why? e.g., C6H6 (benzene): what is the hybridization of the C atoms in C6H6? what are the bond angles? In C6H6, all C-C bonds are of equal length, and are intermediate between C-C (single) and C=C (double) bonds how to explain this? 211 Each C atom is using sp2 hybrid orbitals: the orbitals of C6H6 are formed by the overlap of the 'leftover' 2p orbitals of each C: We envision the 2p e- of the carbons as being shared among all 6 C atoms, i.e., the 3 bonds are 'smeared out' over all 6 C this is delocalized bonding 212 other representations of benzene: General conclusions about VB theory and orbital hybridization bonds are localized between the atoms which are sharing the ethe set of hybrid orbitals used to form bonds is determined by the observed geometry of the molecule when atoms share > 1 e- pair, the additional pairs are in bonds e- in bonds that extend over > 2 atoms are said to be delocalized The VB model is a model of a molecule as composed of individual atoms Overlap of AOs on each atom leads to bond formation 213 Molecular orbitals VB theory relates AOs and Lewis structures hybrid orbitals help explain observed geometries VB theory does not explain an extremely important feature of molecules, namely, the fact that they can absorb and emit radiation recall: the allowed energy states of e- in atoms (i.e., n, l, ml) are called atomic orbitals we combine AOs to form molecular orbitals (MOs), in which e- can exist in discrete energy states in molecules in this model, the atoms themselves are not important – only the properties of the molecule are relevant 214 MOs and AOs have many of the same properties, e.g., MOs can hold a maximum of 2 e- (with opposite spin) When 2 AOs are combined, 2 MOs result e.g., consider the H2 molecule: how many ways can combine 2 1s orbitals? 1s: lower E than separated 1s atomic orbitals; bonding MO (high e- density between nuclei) *1s: higher E than 1s AOs; antibonding MO (no e- density between nuclei) 215 draw as a MO diagram: follow Hund's rule in filling the MOs Notice that, when we combined 2-s type AOs we obtained 2 -type MOs the total number of orbitals is conserved, i.e., we combine n AOs and obtain n MOs 216 e.g., draw the MO diagram for the He2 molecule and the He2+ ion 217 Bond order Measure of stability of a covalent bond Bond Order = 1/2 (# of bonding e- # of antibonding e-) Bond order = 1 represents single bond Bond order =2 “ “ double bond, etc. e.g., find the bond orders of H2, He2, and He2+ 218 MOs for homonuclear 2nd period diatomics Rules to live by: # of MOs formed = # of AOs combined AOs combine with other AOs of similar energy (e.g. 2s with 2s, 2p with 2p etc) Each MO can hold 2 e- with spins paired Hund's rule is used in filling MOs We will be concerned with valence electrons only when constructing MO diagrams Consider the Li and Be atoms note that the 2s AO on one atom interacts only with the 2s AO on the other atom 219 Draw the MO diagrams and find the bond orders of Li2 and Be2 220 MOs from 2p AOs: B2 - F2 in the above cases: only -type MOs formed (why?) recall: 3 p-type AOs (px, py, pz) p-type AOs which overlap along the internuclear axis (usually 2pz) form and * MOs p-type AOs which overlap perpendicular to the internuclear axis (2px, 2py) form and* MOs General MO diagram for second-row diatomics 221 In constructing the above diagram we assume no interaction between the 2s AO on one atom and the 2p AO on the other These in fact do interact with one another The closer together the 2s and 2p energy levels in the atoms, the stronger the interaction The 2s-2p energy gap increases moving across the second period For oxygen - neon, the 2s-2p gap is large enough that there isn’t a strong 2s-2p interaction For O2 – Ne2: 2p MO > 2p MO For boron-nitrogen, the 2s-2p gap is small enough that there is a strong 2s-2p interaction For B2 – N2: 2p MO > 2p MO 222 Moral of the story: start with ordering 2s, 2s*, 2p, 2p, 2p*, 2p* for B2-N2 (strong interaction) For O2 – Ne2, switch 2p, 2p (weak interaction): 2s, 2s*, 2p, 2p, 2p*, 2p* E.g., write MO configurations for B2, C2, N2, O2, and F2 223 E.g., Find the bond orders for these molecules How can MO theory explain magnetism in molecules? How does the molecular orbital theory explain molecular spectra? Problems du Jour 224 List the members of the following series in order of increasing bond length: N2+, N2, N2- Give the molecular orbital configuration for the following cations: C2+ Ne22+ Indicate whether addition of an electron would increase or decrease the stability of these species. 225 226