Linear Time Invariant System [LTIS]: x1(t) y1(t) x2(t) y2(t) superposition is valid ax1(t)+ bx2(t) ay1(t) + by2(t) ax1(t) x1(t) x2(t) y1(t) T ax1(t) ∑ y2(t) ay2(t) T + bx2(t) + by2(t) bx2(t) If x1(t) is applied, it gives y1(t) for x2(t)=0 If x2(t) is applied, it gives y2(t) for x1(t)=0 And, If x1(t) and x2(t) both are applied, that results in y1(t) and y2(t) In case of AM; M(t)* C(t)= y(t) If C(t)=0, then for M(t) only, y(t)=0 If M(t)=0, then for C(t) only, y(t)=0 But for both M(t) and C(t), output is y(t)=M(t)*C(t) Considering C(t) be constant, |M1(t)|----M1(t)*C(t) and |M2(t)|----M2(t)*C(t) Then, M(t)= M1(t) + M2(t) Y(t) = { M1(t) + M2(t)}*C(t)=M1(t)*C(t) + M2(t)*C(t) Hence superposition principle is satisfied. Time Invariant: Behavior of the system does not change with time If system is time variant then the delayed input will produce delayed output for the same value and the delay is same. Most of the system are generally time invariant. Eg. If x(t)--------y(t) x(t-t0)--------y(t-t0) x(t) x(t-t0) Signal Property: 1. Continuous and Discrete Signals CT: x(t)---------analog t------------continuous/analog DT: x[n]---------continuous n-------------discrete Digital: x[n]----------discrete n--------------discrete 2. Power and Energy Signals: Power signal: Energy is infinite, power is finite P∞=finite, E∞=∞ Dealt with harmonics Energy signal: Power is infinite, energy is finite E∞=∞, P∞=0 3. Periodic and Non-periodic: Periodic: x(t)=x(t+T) ; T=1,2,3,…. Every signal may have zero period or infinite period Non-periodic: Above condition not satisfied ie, x(t)≠x(t+T) x[n]=x[n+kn] ejωt T=2П/ω ej ωn ej ωn ej ωn = * ωN=2Пk N=2Пk/ω ej(ω+2П)t , then T=2П/(ω+2П) 4. Deterministic or Random: Deterministic: At any value of time, value of the system can be known Random: Value is uncertain at any value of time t Speech is random signal Any system is whether or not: Causal Stable Linear Memory Invertible Time invariant Observable (internal description with view point of output) Controllable (internal description with view point of input) LTI System Analysis/Characteristics: Linear and time invariant property is satisfied CT ax1 (t) +bx2 (t) ----------ay1 (t) +by2 (t) x1(t-t0)---------y1(t-t0) x2(t-t0)----------y2(t-t0) DT ax1 [n] + bx2 [n] -------ay1 [n] +by2 [n] x1[n-n0]-------y1[n-n0] x2[n+n0]------y2[n+n0] Concept of linearity gives the decomposition of signals that allows to simplify the complexity of signals. In terms of Impulse: (δ and shifted δ) DT system δ[n+5] δ[0] δ[n-5] -5 5 x[0] x[n] N 5 x[n]*δ[n-5]=x[5]*δ[n-5] In general, x[1] δ[n-1] x[2] δ[n-2] ….. …. ….. Hence, x[n] = ……….+ x[-2]δ[n+2]+x[-1] δ[n+1]+x[0] δ[n]+x[1] δ[n-1]+………. X[n]= ∑ x[k] δ[n-k] δ[n] system h[n] impulse response Time invariant system: δ[n-1]-------h[n-1] δ[n-k]-------h[n-k] y[n]= …….+ x[-2]h[n-2] + x[-1]h[n-1] + x[0]h[n] + x[1]h[n+1] + …………… y[n]= ∑ x[k]h[n-k] If system is LTI and its impulse response is known, we can obtain the output for any kind of inputs. Conversely, impulse response completely characterizes the LTI system. y[n]= ∑ x[k]h[n-k] but how to compute???? We know, y(t)=∫ x(*)ﺡh(t-(ﺡdﺡ tietulor onilnrgetni x[n]=x[k] n h[n] h[-k] k k h[n-k] k x[k]h[n-k] Steps: Write the system representation Flip h[k] Shift (delay) by ‘n’ Multiply x[k]h[n-k] Add Get y[n]