# Algebra chains (Level 5)

```Algebra chains (Level 5)
(a)
This algebra chain begins and ends with 2x + 1
Show what to do to move along each step in the chain.
The first step is done for you.
2x + 1
2x + 4
add . . . . . . .
3x + 4
add . . . . . . .
10x + 5
divide by . . . . . . .
2x + 1
3 marks
(b)
Multiply (2x + 1) by 6
1 mark
Simplify (Level 5)
Write each expression in its simplest form.
7 + 2t + 3t
…………………
1 mark
b + 7 + 2b + 10
…………………
1 mark
5k + 7 + 3k =
...............................................................................................
1 mark
k+1+k+4=
.............................................................................................
1 mark
Simplify (Level 6)
Write each expression in its simplest form.
(3d + 5) + (d – 2)
…………………
1 mark
3m – (–m)
…………………
1 mark
Total 2 marks
Expressions
Write these expressions as simply as possible
(Level 6)
9 – 3k + 5k = ............................
1 mark
k2 + 2k + 4k = ............................
1 mark
(Level 7)
3k + 2k = ............................
1 mark
9k 2
= ............................
3k
1 mark
Algebra
(a)
(Level 7)
Simplify this expression as fully as possible:
3 cd 2
5 cd
1 mark
(b)
Multiply out and simplify these expressions:
3(x – 2) – 2 (4 – 3x)
1 mark
(x + 2)(x +3)
1 mark
(x + 4)(x – 1)
1 mark
(x – 2)2
1 mark
Expansion
(a)
(Level 8)
Explain how you know that (y + 3)2 is not equal to y2 + 9
1 mark
(b)
Multiply out and simplify these expressions.
(y + 2)(y + 5)
1 mark
(y – 6)(y – 6)
2 marks
(3y – 8)(2y + 5)
2 marks
Total 6 marks
```