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Algebra chains (Level 5) (a) This algebra chain begins and ends with 2x + 1 Show what to do to move along each step in the chain. The first step is done for you. 2x + 1 add 3 2x + 4 add . . . . . . . 3x + 4 add . . . . . . . 10x + 5 divide by . . . . . . . 2x + 1 3 marks (b) Multiply (2x + 1) by 6 Write your answer without any brackets. 1 mark Simplify (Level 5) Write each expression in its simplest form. 7 + 2t + 3t ………………… 1 mark b + 7 + 2b + 10 ………………… 1 mark 5k + 7 + 3k = ............................................................................................... 1 mark k+1+k+4= ............................................................................................. 1 mark Simplify (Level 6) Write each expression in its simplest form. (3d + 5) + (d – 2) ………………… 1 mark 3m – (–m) ………………… 1 mark Total 2 marks Expressions Write these expressions as simply as possible (Level 6) 9 – 3k + 5k = ............................ 1 mark k2 + 2k + 4k = ............................ 1 mark (Level 7) 3k + 2k = ............................ 1 mark 9k 2 = ............................ 3k 1 mark Algebra (a) (Level 7) Simplify this expression as fully as possible: 3 cd 2 5 cd 1 mark (b) Multiply out and simplify these expressions: 3(x – 2) – 2 (4 – 3x) 1 mark (x + 2)(x +3) 1 mark (x + 4)(x – 1) 1 mark (x – 2)2 1 mark Expansion (a) (Level 8) Explain how you know that (y + 3)2 is not equal to y2 + 9 1 mark (b) Multiply out and simplify these expressions. (y + 2)(y + 5) 1 mark (y – 6)(y – 6) 2 marks (3y – 8)(2y + 5) 2 marks Total 6 marks