Concept Tests: Chapter 5

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Concept Tests: Chapter 5
Concept Tests:
What is the concentration, in moles per L of 45 grams of hydrobromic acid dissolved in 300 ml of water?
How many grams of solute are in 2.25 L of 0.456 M potassium chloride?
Concept Test:
You are given a 6.0 M stock solution of NaCl. You are asked to prepare 0.80 L of 0.15 M
sodium chloride solution instead. Describe how you would prepare this:
1
Concept Test (review!!):
How many ammonium ions are there in 5.0 moles of ammonium sulfate?
5.0 moles of (NH4)2SO4 x
How many sulfate ions are there in 5.0 moles of ammonium sulfate?
5.0 moles of (NH4)2SO4 x
Concept Test:
Write the potential products in this double replacement reaction. Do not forget to
balance the equation!

AgNO3 (aq) + Na2CrO4 (aq)
+
By the way, what are the names of these ionic compounds???
Concept Test:
Write the ionic equation for the reaction above
Concept Test:
Write the net-ionic equation for the above reaction:
2AgNO3 (aq) + Na2CrO4 (aq)  Ag2CrO4 (s) + 2NaNO3 (aq)
2
Concept Test:
Write the following equations. Determine if there is an insoluble product.
Write ionic and net-ionic equations where applicable:
Ba(NO3)2 + Na2CO3 
Na2S + NiSO4 

(NH4)2SO4 + BaCl2
BaSO4 + NH4Cl 
Na2SO4 + KNO3 
HNO3(aq) + KOH(aq)  H2O(l) + KNO3(aq)
Concept Test:
Write the ionic and net ionic equations for the above acid-base reaction:
Ionic:
Net-Ionic:
Concept Test:
What is the pH of a solution whose [H+1] = 1.12 x 10-2 M?
What is the [H+1] if the pH = 4.41?
3
Concept Test: Relationship of [H+1] to pH
Calculate the pH of the following 4 solutions:
Comment on [H+1] concentration and how it relates to pH
and whether or not the solution is acidic or basic . . .
If [H+1] = 1.523 x 10-3 M
pH =
If [H+1] = 1.523 x 10-6 M
pH =
If [H+1] = 1.523 x 10-9 M
pH =
If [H+1] = 1.523 x 10-12 M
pH =
Comments:
4
Concept Test:
You perform an acid-base titration to standardize and HCl solution by placing 50.00 mL of HCl in a flask. Using
0.1524 M NaOH in the buret, whose initial reading is 0.55 mL you dispense NaOH solution to reach the
equivalence point, at which the buret of NaOH now reads 33.87 mL. What is the concentration of HCl?
NaOH(aq) + HCl(aq)
→
5
NaCl (aq) + H2O(l)
Concept Test (for extra practice at home):
What volume of 0.1292 M Ba(OH)2 would neutralize 50.00 mL of the HCl solution standardized above? (19.66 mL)
Concept Test:
Determine the oxidation number of each atom in the following:
ZnCl2
:
Zn
Cl
SO3
:
S
O
HNO3 :
H
N
Sc2O3
Sc
O
:
O
6
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