Single displacement reactions between
different metals and ions can be easily carried
out in labs.
The results of these experiments can be used to
create redox tables which allow for prediction
of spontaneous reactions.
For example when Sn2+ ions are reacted with
Fe a reaction occurs. This happens because
Sn2+ ions have a stronger pull on electrons than
Fe atoms.
This information can be built into a useful
table.
Redox Table
Ions
Metals
Cu
Sn2+
Fe
Zn2+
If an ion reacts with
a metal place the
ion higher. If it
doesn’t place it
lower.
Sn2+ reacts with Fe
Sn2+ doesn’t react
with Cu.
Zn2+ ion does not
react with Fe.
Decreasing
SOA
strength
Ions
Metals
Fill in the missing
ions and metals.
Cu2+
Cu
The strongest
oxidizing agents are
Sn2+
Sn
at the top of the
ions column and the
Fe2+
Fe
strongest reducing
Zn2+
Zn
agents are at the
bottom
of
the
SRA
Decreasing
metals column.
strength
Decreasing Any ion above any
SOA
strength metal will steal the
Ions
Metals
metals electrons and
the reaction will be
Cu2+
Cu
spontaneous.
2+ ions will steal
Cu
Sn2+
Sn
electrons from
Sn, Fe, and Zn.
2+
Fe
Fe
Sn2+ ions will steal
1- from
2+
e
Zn
Zn
Fe
and
Zn.
Decreasing SRA
Fe2+ will react with
strength
SOA
Ions
Decreasing
strength
Metals
Cu2++ 2e1-  Cu
Sn2+ + 2e1-  Sn
Fe2+ + 2e1-  Fe
Zn2++ 2e1- 
Decreasing
strength
Zn
SRA
These half reactions
can be written as
reductions by
adding the electrons
to the equations.
Try question 9 on
page 677
10-13 on page 678.
#9
Cl2 is the most reactive, I2 is the least reactive
SOA
Cl2(aq) + 2e1- ---> 2Cl1-(aq)
Br2(aq) + 2e1- ---> 2Br1-(aq)
I2(aq) + 2e1- ---> 2I1-(aq)
SRA
10.
SOA
Co2+
+ 2e1- ---> Co
Zn2+ + 2e1- ---> Zn
Mg2+ + 2e1- ---> Mg
SRA
11. SOA
Cu2+ + 2e1- --> Cu
2H1+ + 2e1- --> H2
Cd2+ + 2e1- --> Cd
Be2+ + 2e1- -->
Be
Ca2+ + 2e1- --> Ca
SRA
12. It is empirical since experimental
observations can be used to verify it.
13. Cl (aq) + 2e1- --> 2 Cl1-(aq)
2
Br2(l)
+ 2e1- --> 2Br1-(aq)
Ag1+(aq) + 1e1- --> Ag(s)
I2(s) + 2e1- --> 2I1-(aq)
Cu2+ (aq) + 2e1- --> Cu(s)
Use the Extended Redox Table on page 804
to answer questions 14-19 on page 679.