B. Intralocular Interactions

Modifications to Mendelian Inheritance

I. Allelic, Genic, and Environmental Interactions

Modifications to Mendelian Inheritance


A. Overview:

The effect of a gene is influenced at three levels:

- Intralocular (effects of other alleles at this locus)

- Interlocular (effects of other genes at other loci)

- Environmental (the effect of the environment on determining the effect of a gene on the phenotype)

Environment

A a

PHENOTYPE


A. Overview:

B. Intralocular Interactions A a


A. Overview:

B. Intralocular Interactions

1. Complete Dominance:

- The presence of one allele is enough to cause the complete expression of a given phenotype.


A. Overview:



2. Incomplete Dominance:

- The heterozygote expresses a phenotype

between or intermediate to the phenotypes of the homozygotes.


A. Overview:




3. Codominance:

- Both alleles are expressed completely; the heterozygote does not have an intermediate phenotype, it has BOTH phenotypes.

AB Phenotype

ABO Blood Type:

A = ‘A’ surface antigens

B = ‘B’ surface antigens

O = no surface antigen from this locus

Phenotype

A

Genotypes

AA, AO

B

O

AB codominance

BB, BO

OO

AB

I. Allelic, Genic, and Environmental

Interactions

A. Overview:




3. Codominance:

4. Overdominance :

– the heterozygote expresses a phenotype MORE EXTREME than either homozygote

TT = tall (grows best in warm conditions) tt = short (grows best in cool conditions)

Tt = Very Tall (has both alleles and so grows optimally in cool and warm conditions)

TEMP

“t”

TEMP

“T”


Interactions

A. Overview:




3. Codominance:


5. Lethal Alleles:

- Essential genes: many proteins are required for life. “Loss-of-function” alleles may not affect heterozygotes, but in homozygotes may result in the death of the zygote, embryo, or adult – depending on when they should be expressed during development.


Interactions

A. Overview:




3. Codominance:



- Essential genes: many proteins are required for life. “Loss-of-function” alleles may not affect heterozygotes, but in homozygotes may result in the death of the zygote, embryo, or adult – depending on when they should be expressed during development.

Recessive Lethals:

Aa x

- 25% reduction in

Aa number of offspring

A a

A

AA

Aa a

Aa aa

Self-crossing the survivors shows that 1/3 show no reduction in offspring number (AA), while 2/3 show the 25% reduction in number

(Aa)


Interactions

A. Overview:




3. Codominance:



Sometimes, the heterozygote has a different phenotype than the homozygote. The phenotypic effect can be ‘dominant’ while the lethal effect is recessive. A Y exerts a dominant effect on coat color

(expressed in the heterozygote), but is lethal ONLY in the homozygous condition (recessive lethality).

Also an example of pleiotropy – one gene affecting >1 trait.


Interactions

A. Overview:




3. Codominance:



Conditional Lethality:

In this case, the expression of lethality only occurs under specific conditions. Favism is caused by a mutation in the gene that codes for the enzyme glucose-6-phosphate dehydrogenase. When afflicted individuals eat fava beans, their red blood cells rupture and clog capillaries, resulting in anemia and death.


A. Overview:




3. Codominance:


5. Lethality:

6. Multiple Alleles:

- not really an interaction, but a departure from simple Mendelian postulates.

- and VERY important as a source of variation

4

5

# Alleles at the Locus

1 (A)

2 (A, a)

3 (A, a, A’)

# Genotypes Possible

1 (AA)

3 (AA, Aa, aa)

6 (AA, Aa, aa, A’A’, A’A, A’a)

10

15


A. Overview:




3. Codominance:


5. Lethality:

6. Multiple Alleles:

7. Penetrance and Expressivity:

- Penetrance: the percentage of individuals with a given genotype that actually EXPRESS the associated phenotype. (Because of environment or other genes)

- Expressivity: The degree to which an individual expresses its genetically determined trait. The degree of “eyeless” expression in Drosophila is affected by genetic background and environment.


Interactions

A. Overview:


- Summary and Implications: populations can harbor extraordinary genetic variation at each locus, and these alleles can interact in myriad ways to produce complex and variable phenotypes.

-Consider this cross: AaBbCcDd x AABbCcDD

Assume:

The genes assort independently

A and a are codominant

B is incompletely dominant to b

C is incompletely dominant to c

D is completely dominant to d

How many phenotypes are possible in the offspring?


Interactions

A. Overview:


- Summary and Implications: populations can harbor extraordinary genetic variation at each locus, and these alleles can interact in myriad ways to produce complex and variable phenotypes.

-Consider this cross: AaBbCcDd x AABbCcDD

Assume:

The genes assort independently

A and a are codominant

B is incompletely dominant to b

C is incompletely dominant to c

D is completely dominant to d

How many phenotypes are possible in the offspring?

A

2 x

B C D

3 x 3 x 1 = 18

If they had all exhibited complete dominance, there would have been only:

1 x 2 x 2 x 1 = 4

So the variety of allelic interactions that are possible increases phenotypic variation multiplicatively. In a population with many alleles at each locus, there is an nearly limitless amount of phenotypic variability.


Interactions

A. Overview:


C. Interlocular Interactions

The phenotype can be affected by more than one gene.

C. Interlocular Interactions:

1. Quantitative (Polygenic) Traits:

There may be several genes that produce the same protein product; and the phenotype is the ADDITIVE sum of these multiple genes.

Creates continuously variable traits.

So here, both genes A and B produce the same pigment. The double homozygote

AABB produces 4 ‘doses’ of pigment and is very dark. It also means that there are more ‘intermediate gradations’ that are possible.



2. Epistasis: one gene masks/modifies the expression at another locus; the phenotype in the A,B,O blood group system can be affected by the genotype at the fucosyl transferase locus.

This locus makes the ‘H substance’ to which the sugar groups are added to make the A and

B surface antigens.

A non-function ‘h’ gene makes a nonfunctional foundation and sugar groups can’t be added – resulting in O blood regardless of the genotype at the A,B,O locus. This ‘O’ is called the ‘Bombay Phenotype’ – after a moman from Bombay (Mumbai) in which it was first described.

H-

H-

Hhh hh hh

Genotype at H

H-

Genotype at A,B,O

A-

Phenotype

A

B-

OO

AB

A-

B-

OO

B

O

AB

O

O

O hh AB O



2. Epistasis:

So, what are the phenotypic ratios from this cross:

HhAO x HhBO?



2. Epistasis:

So, what are the phenotypic ratios from this cross:

HhAO x HhBO?

Well, assume they are inherited independently.

AT H: ¾ H: ¼ h

At A,B,O: ¼ A : ¼ O: ¼ B : ¼ AB

So, the ¼ that is h is O type blood, regardless.

Then, we have:

¾ H x ¼ A = 3/16 A

¾ H x ¼ O = 3/16 O (+ 4/16 above)

¾ H x ¼ B = 3/16 B

¾ H x ¼ AB = 3/16 AB

Phenotypic Ratios: 3/16 A : 3/16 B : 3/16 AB : 7/16 O = 16/16 (check!)



2. Epistasis:

-example #2: in a enzymatic process, all enzymes may be needed to produce a given phenotype. Absence of either may produce the same alternative ‘null’.

Process: enzyme 1 enzyme 2

Precursor 1 precursor2 product

(pigment)


Process: enzyme 1 enzyme 2


2. Epistasis:

-example #2: in a enzymatic process, all enzymes may be needed to produce a given phenotype. Absence of either may

Precursor 1 precursor2 product

(pigment)

Strain 1: enzyme 1 enzyme 2 produce the same alternative ‘null’.

For example, two strains of white flowers may be white for different reasons; each lacking a different necessary enzyme to make color.

Precursor 1 precursor2 no product

(white)

Strain 2: enzyme 1 enzyme 2

Precursor 1 precursor2 no product

(white)



2. Epistasis:



So there must be a dominant gene at both loci to produce color.

Genotype aaBaabb

A-bb

A-B-

So, what’s the phenotypic ratio from a cross:

AaBb x AaBb ?

Phenotype white white white pigment



2. Epistasis:




Genotype aaBaabb

A-bb

A-B-

Phenotype white white white pigment

So, what’s the phenotypic ratio from a cross:

AaBb x AaBb ?

9/16 pigment (A-B-), 7/16 white



2. Epistasis:




Indeed, by mating two strains together, we can determine whether the mutation is the result of different alleles at the same locus, or different GENES acting on one PATHWAY. This is called a complementation test.

Consider two strains that are wingless. Do these strains have different “loss of function” mutations in the same gene, or mutations in different genes involved in the same process (wing development)?



2. Epistasis:


-example #3: Novel Phenotypes.

Comb shape in chickens is governed by 2 interacting genes that independently produce “Rose” or “Pea” combs, but together produce something completely different (walnut).

Genotype rrpp

R-pp rrP-

R-P-

Phenotype single rose pea

Walnut



2. Epistasis:


-example #3: Novel Phenotypes.

Comb shape in chickens is governed by 2 interacting genes that independently produce “Rose” or “Pea” combs, but together produce something completely different (walnut).

Fruit shape in summer squash is influnced by two interacting loci, also.

Genotype aabb

A-bb aaB-

A-B-

Phenotype long sphere sphere disc



2. Epistasis:

In all of these cases, the observed ratios are modifications of the basic Mendelian

Ratios.

A-B-

B. Intralocular Interactions

Related documents

Products

Support

B. Intralocular Interactions

Related documents

Add this document to collection(s)

Add this document to saved

Suggest us how to improve StudyLib