Atomic Vibrations in Solids: phonons Goal: understanding the temperature dependence of the lattice contribution to the heat capacity CV concept of the harmonic solid Photons* and Planck’s black body radiation law vibrational modes quantized phonons with properties in close analogy to photons The harmonic approximation Consider the interaction potential (q1 , ..., q3 N ) Let’s perform a Taylor series expansion around the equilibrium positions: 1 2 1 st q j qk st Ajk q j qk 2 j ,k q j qk 2 j ,k when introducing q j q j m j Ajk force constant matrix A jk Since 2 2 q j qk qk q j Ajk Akj and Ajk Ajk m j mk real and symmetric We can find an orthogonal matrix T such that T 1 1 T T Akj mk m j A jk m j mk Akj which diagonalizes A A T T A T where T 12 0 2 0 2 0 ... 0 2 3 N T T AT T j j A j k Tk k j j ,k 2 jk j , k With normal coordinates q j qkTkj k we diagonalize the quadratic form From q j q jTjj j st st 1 Ajk q j qk 2 j ,k qk Tk k q k k 1 1 A q q Ajk T jj q j Tk k q k st j k j k 2 j , k 2 j , k j k st 1 2 st 1 2 2 q j j 2 j j , k , j , k Ajk T jj q jTk k q k st 1 2 j jk q j q k 2 j ,k Hamiltonian in harmonic approximation can always be transformed into diagonal structure 1 3N 2 2 2 H p j j q j 2 j 1 harmonic oscillator problem with energy eigenvalues E 3N j 1 problem in complete analogy to the photon gas in a cavity Z e E e E0 e jnj e E0 j e 1n1 2 n2 ... n1 , n2 ,.. E j n j E0 j 1 e E0 1 e 1 1 1 e 2 1 1 e 3 1 j nj 2 1 E0 ... e j 1 e j With U ln Z U E ln 1 e 0 j j j je E0 1 e j j E0 j j e j 1 up to this point no difference to the photon gas Difference appears when executing the j-sum over the phonon modes by taking into account phonon dispersion relation The Einstein model j E for all oscillators In the Einstein model 3NE 3NE U / k T B 2 e 1 zero point energy U Heat capacity: C v T v Cv 3 N k B Cv 3 N k B Classical limit E / kBT 2 eE / kBT e E / kBT 1 2 E / kBT 2 eE / kBT e E / kBT 1 for kBT E 1 2 E kBT 2 e E / kBT for kBT E •good news: Einstein model explains decrease of Cv for T->0 CV /3NkB 1.0 •bad news: Experiments show Cv T3 for T->0 0.5 0.0 0 1 2 3 T/TE Assumption that all modes have the same frequency E unrealistic refinement The Debye model Some facts about phonon dispersion relations: For details see solid state physics lecture 1) (k ) E const. 2) wave vector k labels particular phonon mode 3) total # of modes = # of translational degrees of freedom 3Nmodes in 3 dimensions N modes in 1 dimension Example: Phonon dispersion of GaAs k for selected high symmetry directions data from D. Strauch and B. Dorner, J. Phys.: Condens. Matter 2 ,1457,(1990) We evaluate the sum in the general result U j j e j 1 U0 via an integration using the concept of density of states: # of modes in U max D() , d n(, T ) d U0 0 Energy of a mode = phonon energy temperature independent zero point energy # of excited phonons n(, T) In contrast to photons here finite # of modes=3N max D()d max total # of phonon modes In a 3D crystal D ( )d 3 N 0 0 Let us consider dispersion of elastic isotropic medium Particular branch i: vik vL V 3 D() ( ) d k k 3 ( 2) here (k ) (k ) v ik vT,1=vT,2=vT d3 k 4k 2dk 1 dk dk 2 vi k k 2 vi 2 k 1 V D() 4 ( k ) dk 3 ( 2 ) vi vi V 2 2 3 2 v i k Taking into account all 3 acoustic branches U max D() n(, T ) d U0 V 2 1 2 D() 2 3 3 2 v T v L 0 max V 1 2 2 U 2 3 3 d U0 2 v L v T 0 e 1 How to determine the cutoff frequency max D(ω) Density of states of Cu determined from neutron scattering ? also called Debye frequency D D D() d 3N 0 choose D such that both curves enclose the same area D() 2 with U Cv T v Cv 9N D max 3 0 2e / kBT d 2 2 k BT e / kBT 1 Let’s define the Debye temperature D D max energy Substitution: kBT d kBT dx T Cv 9Nk B D 3 D / T x D / kB : D temperature x 4e x ex 12 dx 0 Discussion of: T Cv 9Nk B D D / T T0 x 4e x e 0 x 3 D / T x 4e x ex 12 dx 0 1 2 dx 0 x 4e x e x 1 2 T 12 Cv Nk B 5 D 4 dx 3 T D D / T 0 x 4e x e x 1 2 dx D / T 0 1 D 2 x dx 3 T 3 Cv 3NkB Application of Debye theory for various metals with single fit parameter D