By: Nafees Ahmed Asstt. Prof., EE Deptt, DIT, Dehradun By: Nafees Ahmed, EED, DIT, DDun Introduction The polar plot of sinusoidal transfer function G(jω) is a plot of the magnitude of G(jω) verses the phase angle of G(jω) on polar coordinates as ω is varied from zero to infinity. Therefore it is the locus of G ( j ) G ( j ) as ω is varied from zero to infinity. As G ( j ) G ( j ) Me j ( ) So it is the plot of vector Me j ( ) as ω is varied from zero to infinity By: Nafees Ahmed, EED, DIT, DDun Introduction conti… In the polar plot the magnitude of G(jω) is plotted as the distance from the origin while phase angle is measured from positive real axis. + angle is taken for anticlockwise direction. Polar plot is also known as Nyquist Plot. By: Nafees Ahmed, EED, DIT, DDun Steps to draw Polar Plot Step 1: Determine the T.F G(s) Step 2: Put s=jω in the G(s) & lim G ( j ) Step 4: At ω=0 & ω=∞ find G ( j ) by lim G ( j ) & lim G ( j ) Step 5: Rationalize the function G(jω) and separate the real and imaginary parts Step 6: Put Re [G(jω) ]=0, determine the frequency at which plot intersects the Im axis and calculate intersection value by putting the above calculated frequency in G(jω) Step 3: At ω=0 & ω=∞ find G ( j ) by By: Nafees Ahmed, EED, DIT, DDun lim G ( j ) 0 0 Steps to draw Polar Plot conti… Step 7: Put Im [G(jω) ]=0, determine the frequency at which plot intersects the real axis and calculate intersection value by putting the above calculated frequency in G(jω) Step 8: Sketch the Polar Plot with the help of above information By: Nafees Ahmed, EED, DIT, DDun Polar Plot for Type 0 System Let G (s) K (1 sT 1 )( 1 sT 2 ) Step 1: Put s=jω G ( j ) K (1 j T1 )( 1 j T 2 ) K 1 T1 2 1 T 2 tan 2 1 T1 tan 1 T2 Step 2: Taking the limit for magnitude of G(jω) By: Nafees Ahmed, EED, DIT, DDun Type 0 system conti… lim G ( j ) lim G ( j ) 0 K 1 T1 1 j T 2 2 K 2 K 1 T1 2 1 j T 2 0 2 Step 3: Taking the limit of the Phase Angle of G(jω) lim G ( j ) tan 1 T1 tan 1 T2 0 lim G ( j ) tan 1 T1 tan 1 T 2 180 0 By: Nafees Ahmed, EED, DIT, DDun Type 0 system conti… Step 4: Separate the real and Im part of G(jω) K (1 T1T 2 ) K (T1 T 2 ) 2 G ( j ) 1 T1 T T1T 2 2 2 2 2 2 4 j 1 T1 T 2 T1T 2 2 2 2 2 Step 5: Put Re [G(jω)]=0 K (1 T1T 2 ) 2 1 T1 T 2 2 2 2 2 T1 T 2 4 0 1 & T1 T 2 So When 1 G ( j ) T1 T 2 & K T1 T 2 90 T1 T 2 G ( j ) 0 180 By: Nafees Ahmed, EED, DIT, DDun 0 0 4 Type 0 system conti… Step 6: Put Im [G(jω)]=0 K (T1 T 2 ) 1 T1 T T1T 2 2 2 2 2 2 4 0 0 & So When 0 G ( j ) K 0 0 G ( j ) 0 180 0 By: Nafees Ahmed, EED, DIT, DDun Type 0 system conti… By: Nafees Ahmed, EED, DIT, DDun Polar Plot for Type 1 System Let G ( s ) s (1 sT K)(1 sT 1 2 ) Step 1: Put s=jω K G ( j ) j (1 j T 1 )( 1 j T 2 ) K 1 T 1 2 1 j T 2 90 2 0 tan 1 T 1 tan By: Nafees Ahmed, EED, DIT, DDun 1 T2 Type 1 system conti… Step 2: Taking the limit for magnitude of G(jω) lim G ( j ) lim G ( j ) 0 K 1 T1 2 1 j T 2 2 K 1 T1 2 1 j T 2 0 2 Step 3: Taking the limit of the Phase Angle of G(jω) lim G ( j ) 90 0 tan 1 T1 tan 1 T 2 90 lim G ( j ) 90 0 tan 1 T1 tan 1 T 2 270 0 0 By: Nafees Ahmed, EED, DIT, DDun 0 Type 1 system conti… Step 4: Separate the real and Im part of G(jω) G ( j ) K (T 1 T 2 ) 2 (T 1 T 2 T 1 T 2 ) 3 2 2 j ( K T1T 2 K ) 2 2 2 j (T 1 T 2 T 1 T 2 ) 3 2 Step 5: Put Re [G(jω)]=0 K (T1 T 2 ) (T1 T 3 2 2 2 T1 T ) 2 2 2 2 0 So at G ( j ) 0 270 By: Nafees Ahmed, EED, DIT, DDun 0 2 2 2 2 Type 1 system conti… Step 6: Put Im [G(jω)]=0 j ( K T1T 2 K ) 2 (T1 T 3 2 2 2 T1 T ) 2 2 2 2 1 0 T1T 2 So When 1 T1T 2 G ( j ) K T1T 2 T1 T 2 G ( j ) 0 0 0 0 By: Nafees Ahmed, EED, DIT, DDun & Type 1 system conti… By: Nafees Ahmed, EED, DIT, DDun Polar Plot for Type 2 System Let G (s) K s (1 sT 1 )( 1 sT 2 ) 2 Similar to above By: Nafees Ahmed, EED, DIT, DDun Type 2 system conti… By: Nafees Ahmed, EED, DIT, DDun Note: Introduction of additional pole in denominator contributes a constant -1800 to the angle of G(jω) for all frequencies. See the figure 1, 2 & 3 Figure 1+(-1800 Rotation)=figure 2 Figure 2+(-1800 Rotation)=figure 3 By: Nafees Ahmed, EED, DIT, DDun Ex: Sketch the polar plot for G(s)=20/s(s+1)(s+2) Solution: Step 1: Put s=jω G ( j ) 20 j ( j 1)( j 2 ) 20 1 4 2 90 0 tan 1 tan 2 By: Nafees Ahmed, EED, DIT, DDun 1 /2 Step 2: Taking the limit for magnitude of G(jω) lim G ( j ) lim G ( j ) 20 0 1 4 2 2 20 0 1 4 2 2 Step 3: Taking the limit of the Phase Angle of G(jω) lim G ( j ) 90 0 tan 1 tan 1 / 2 90 lim G ( j ) 90 0 tan 1 tan 1 / 2 270 0 0 By: Nafees Ahmed, EED, DIT, DDun 0 Step 4: Separate the real and Im part of G(jω) G ( j ) 60 ( 4 ( 4 2 j ( 4 )( 4 ) 2 2 )( 4 ) 2 3 )( 4 ) 2 60 j 20 ( 2 ) 2 2 0 So at G ( j ) 0 270 By: Nafees Ahmed, EED, DIT, DDun 0 2 Step 6: Put Im [G(jω)]=0 j 20 ( ( 4 3 2 ) )( 4 ) 2 2 0 2 & So for positive value of 2 G ( j ) 10 0 0 G ( j ) 0 0 0 3 By: Nafees Ahmed, EED, DIT, DDun By: Nafees Ahmed, EED, DIT, DDun Gain Margin, Phase Margin & Stability By: Nafees Ahmed, EED, DIT, DDun Phase Crossover Frequency (ωp) : The frequency where a polar plot intersects the –ve real axis is called phase crossover frequency Gain Crossover Frequency (ωg) : The frequency where a polar plot intersects the unit circle is called gain crossover frequency So at ωg G ( j ) Unity By: Nafees Ahmed, EED, DIT, DDun Phase Margin (PM): Phase margin is that amount of additional phase lag at the gain crossover frequency required to bring the system to the verge of instability (marginally stabile) Φm=1800+Φ Where Φ=∠G(jωg) if Φm>0 => +PM (Stable System) if Φm<0 => -PM (Unstable System) By: Nafees Ahmed, EED, DIT, DDun Gain Margin (GM): The gain margin is the reciprocal of magnitude G ( j ) at the frequency at which the phase angle is -1800. GM 1 | G ( jwc ) | 1 x In terms of dB GM in dB 20 log 1 10 20 log | G ( jwc ) | By: Nafees Ahmed, EED, DIT, DDun 10 | G ( jwc ) | 20 log 10 ( x) Stability Stable: If critical point (-1+j0) is within the plot as shown, Both GM & PM are +ve GM=20log10(1 /x) dB By: Nafees Ahmed, EED, DIT, DDun Unstable: If critical point (-1+j0) is outside the plot as shown, Both GM & PM are -ve GM=20log10(1 /x) dB By: Nafees Ahmed, EED, DIT, DDun Marginally Stable System: If critical point (-1+j0) is on the plot as shown, Both GM & PM are ZERO GM=20log10(1 /1)=0 dB By: Nafees Ahmed, EED, DIT, DDun MATLAB Margin By: Nafees Ahmed, EED, DIT, DDun Inverse Polar Plot The inverse polar plot of G(jω) is a graph of 1/G(jω) as a function of ω. Ex: if G(jω) =1/jω then 1/G(jω)=jω lim G ( j ) 1 0 lim G ( j ) 1 0 By: Nafees Ahmed, EED, DIT, DDun Books Automatic Control system By S. Hasan Saeed Katson publication By: Nafees Ahmed, EED, DIT, DDun