Gases
Chapter 5
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Characteristics of Gases
• Gases expand to fill any container.
– random motion, no attraction
• Gases are fluids (like liquids).
– no attraction
• Gases have very low densities.
– no volume = lots of empty space
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Characteristics of Gases
• Gases can be compressed.
– no volume = lots of empty space
• Gases undergo diffusion & effusion.
– random motion
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11 of the periodical table elements are in the
gas form.
Pressure = Force
Area
Torrcelli
(force = mass x acceleration)
Units of Pressure
1 torr = 1 mmHg
1 atm = 760 mmHg = 760 torr
1 atm =
1.01325 x 105 Pa = 101,325 kPa
5
10 miles
4 miles
Sea level
0.2 atm
0.5 atm
1 atm
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• The atmospheric
pressure at the summit
of Mt. McKinley
(Denali) is 606 mm
Hg on a certain day.
What is the pressure in
atmospheres?
Boyle’s Law
Volume is inversely proportional to pressure
P a 1/V
P x V = constant
P1 x V1 = P2 x V2
Constant temperature
Constant amount of gas
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A sample of chlorine gas occupies a volume of 946 mL at a
pressure of 726 mmHg. What is the pressure of the gas (in
mmHg) if the volume is reduced at constant temperature to 154
mL?
P x V = constant
P1 x V1 = P2 x V2
P2 =
P1 = 726 mmHg
P2 = ?
V1 = 946 mL
V2 = 154 mL
P1 x V1
V2
726 mmHg x 946 mL
=
= 4460 mmHg
154 mL
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Charles’ Law
Volume is proportional to temperature
Variation in Gas Volume with Temperature at Constant Pressure
As T increases
V increases
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Gay-Lussac’s Law
Temperature is proportional to pressure
Variation of Gas Volume with Temperature
at Constant Pressure
VaT
V = constant x T
V1/T1 = V2 /T2
Charles’ &
Gay-Lussac’s
Law
Temperature must be
in Kelvin
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A sample of carbon monoxide gas occupies 3.20 L at 125 0C.
At what temperature will the gas occupy a volume of 1.54 L if
the pressure remains constant?
V1 /T1 = V2 /T2
V1 = 3.20 L
V2 = 1.54 L
T1 = 398.15 K
T2 = ?
T1 = 125 (0C) + 273.15 (K) = 398.15 K
T2 =
V2 x T1
V1
=
1.54 L x 398.15 K
3.20 L
= 192 K
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Avogadro’s Law
V a number of moles (n)
Constant temperature
Constant pressure
V = constant x n
V1 / n1 = V2 / n2
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The Gas Laws
• Boyles Law
pressure  -- volume 
– P  1/V
• Charles Law
temperature  -- volume 
– VT
• Avogadros Law
moles  -- volume 
– Vn
• Gay Lussac Law
– PT
temperature  -- pressure 
Ammonia burns in oxygen to form nitric oxide (NO) and water
vapor. How many volumes of NO are obtained from one volume
of ammonia at the same temperature and pressure?
4NH3 + 5O2
1 mole NH3
4NO + 6H2O
1 mole NO
At constant T and P
1 volume NH3
1 volume NO
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Ideal Gas Equation
Boyle’s law: P a 1 (at constant n and T)
V
Charles’ law: V a T (at constant n and P)
Avogadro’s law: V a n (at constant P and T)
Va
nT
P
V = constant x
nT
P
=R
nT
P
R is the gas constant
PV = nRT
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The conditions 0 0C and 1 atm are called standard
temperature and pressure (STP).
For any Gas Experiments show that at STP, 1
mole of an ideal gas occupies 22.414 L.
PV = nRT
(1 atm)(22.414L)
PV
R=
=
nT
(1 mol)(273.15 K)
R = 0.082057 L • atm / (mol • K)
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What is the volume (in milliliters) occupied by 63.7 g of HCl at
STP?
T = 0 0C = 273.15 K
P = 1 atm
PV = nRT
nRT
V=
P
1 mol HCl
n = 63.7 g x
= 1.75 mol
36.45 g HCl
1.75 mol x 0.0821
V=
L•atm
mol•K
x 273.15 K
1 atm
V = 39.1 L
= 391 ml
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What is the volume (in liters) occupied by 49.8 g of HCl at STP?
T = 0 0C = 273.15 K
P = 1 atm
PV = nRT
nRT
V=
P
1 mol HCl
n = 49.8 g x
= 1.37 mol
36.45 g HCl
1.37 mol x 0.0821
V=
L•atm
mol•K
x 273.15 K
1 atm
V = 30.7 L
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