ECHE 311/SPRING 2015 Problem Set 2 1. What is the heat required when 12 mol of propane is heated from 250 to 1,200 oC at approximately atmospheric pressure in a steady state-flow heat exchanger? Use equation 4.7 which approximate the heat capacity and calculates ICPH. H R ICPH Q(n) nH ( n is number of moles) Answer : Q=1.942 x106 (J) 2. What is the final temperature when heat in the amount of 800 kJ is added to the 10 mol of ethylene initially at 200oC in a steady-flow heat exchanger at approximately atmospheric pressure? Hint : T Use 2 (guess) To in equation B C Q nR{[ ATo ( 1) To2 ( 2 1)] To3 ( 3 1)} (1) 2 3 to estimate the best value for and the final temperature Answer: T=1.374 x 103 K 3. Chlorine is produced by the reaction 4HCl(g) + O2(g) = 2H2O(g) +2Cl2(g) The feed stream to the reactor consists of 60% HCl, 36 mol% O2 and 4 mole % N2, and it enters the reactor at 550oC. If the conversion of HCl is 75% and if the process is isothermal, how much heat must be transferred from the reactor per mole of the entering gas mixture? Hint: Take a basis of 1 mole gas entering reactor, containing 0.6 M HCl, 0.36 M O2 and 0.04 M N2. Therefore the amount of HCl reacted (r) is equal to 0.6x0.7=0.45. Using H298 as the reference, we can calculate H823 by the equation H 823 H 298 MDCPH R (T T298 ) B C D MDCPH A ( ) T o( 1) ( ) To2 ( 2 1) 2 3 To2 1 (2) where To=298.15 K ; T To Answer: Q= -13,229 J 4. If the heat of the amount of 2,500 kJ is added to 15 mol of 1 butene initially at 260oC in a steady state-flow process at approximately atmospheric pressure, what is its entropy change? T Use 3 as a guess value in Eq 1 to calculate the final temperature. To The entropy for 15 moles is the found by using (ICPS integral) S nR ICPS Answer S=1.243x106 J/K NOT REQUIRED 5. Calculate the reversible work done on compressing 1 ft3 of mercury at a constant temperature of 32(oF) from 1 atm to 3,000 (atm). The isothermal compressibility of mercury at 32oF is =3.9x10-6-0.1x10-9P where P is in (atm) and is in (atm)-1. Answer: 16.65 atm ft3 6. Five kilograms of liquid carbon tetrachloride undergo a mechanically reversible, isobaric change of state at 1 bar during which the temperature changes from 0oC to 20. Determine Vt, W, Q, Ht, and Ut. The following parameters for liquid carbon tetrachloride at 1 bar and 0oC may be assumed independent of temperature: =1.2x10-3 K-1, CP =0.84 kJ kg-1K-1, and =1.590 kg m-3. Answer: V total = 7.638x10-5 m3 (Const P) W =-7.638 Joule Q= 84 kJ H= 84 KJ 4 2 -2 Utotal 8.399 10 kgm sec 2