Rate Laws and Order of Reaction Read 6.3 p 372-378 Q 1-6 p 377 Chemical Kinetics Concentration and Rate Each reaction has its own equation that gives its rate as a function of reactant concentrations. this is called its Rate Law • A rate law is an equation expressing the rate of a reaction in terms of the [molar] of the species involved in the reaction. Chemical Kinetics aA + bB cC + dD • The rate is expressible as rate = k[A]m[B]n • The powers m and n are kinetic orders, • A and B are the chemical substances • k is the rate constant, different values for each rxn Chemical Kinetics Order of a Reaction • The “order” of a chemical reaction is the number of chemical [] terms upon which the rate depends • Rate = k[A] - first order rate; the rate only depends on one [] term • Rate = k[A]2 - second order rate • Rate = k[A][B] - second order rate Chemical Kinetics Concentration and Rate Compare Experiments 1 and 2: when [NH4+] doubles, the initial rate doubles. Chemical Kinetics Concentration and Rate Likewise, compare Experiments 5 and 6: when [NO2-] doubles, the initial rate doubles. Chemical Kinetics Concentration and Rate This equation is called the rate law, and k is the rate constant. Chemical Kinetics Rate Laws • Exponents tell the order of the reaction with respect to each reactant. • This reaction is First-order to [NH4+] First-order to [NO2−] • The overall reaction order can be found by adding the exponents on the reactants in the rate law. • This reaction is second-order overall. Chemical Kinetics Recall……………………….. • A rate law shows the relationship between the reaction rate and the concentrations of reactants. For gas-phase reactants use Partial Pressure instead of [A]. • k is a constant that has a specific value for each reaction. • The value of k is determined experimentally. “Constant” is relative herek is unique for each rxn k changes with T Chemical Kinetics Temperature and Rate • Generally, as temperature increases, so does the reaction rate. • This is because k is temperature dependent. Chemical Kinetics Determining Rxn Order from Experimental Data – Ex.1 • Four experiments were conducted to discover how the initial rate of consumption of BrO3ions in the rxn varies as the concentrations of the reactants are changed. • Use the experimental data in the table below to determine the order of the reaction with respect to each reactant and the overall order. • Write the rate law for the rxn and determing the value of k. Chemical Kinetics Data – Ex. 1 Initial [ ] mol L-1 Initial Rate Experiment BrO3- Br- H+ mol L-1 s-1 1 0.10 0.10 0.10 1.2x10-3 2 0.20 0.10 0.10 2.4x10-3 3 0.10 0.30 0.10 3.5x10-3 4 0.20 0.10 0.15 5.4x10-3 Chemical Kinetics Homework • Pg. 377 # 1-6 • Lab Exercise 6.4.1 The Sulfur Clock “determine the order of the reaction” p.404-405 Chemical Kinetics Review of Chemical Kinetics First order Second order Second order Linear Exponential Exponential -dependent on one molecule -dependent on two molecules -dependent on two molecules Rate Laws Graph of rate vs concn Chemical Kinetics First-Order Processes Consider the process in which methyl isonitrile is converted to acetonitrile. CH3NC CH3CN How do we know this is a first order rxn? Chemical Kinetics Reaction Mechanisms Read 6.4 p 383-390 The sequence of events that describes the actual process by which reactants become products is called the reaction mechanism. Chemical Kinetics Reaction Mechanisms • Reactions may occur all at once or through several discrete steps. • Each of these processes is known as an elementary reaction or elementary process. Chemical Kinetics Reaction Mechanisms • The molecularity of a process tells how many molecules are involved in the process. • The rate law for an elementary step is written directly from that step. Chemical Kinetics Multistep Mechanisms • In a multistep process, one of the steps will be slower than all others. • The overall reaction cannot occur faster than this slowest, rate-determining step. Chemical Kinetics Slow Initial Step NO2 (g) + CO (g) NO (g) + CO2 (g) • The rate law for this reaction is found experimentally to be Rate = k [NO2]2 • CO is necessary for this reaction to occur, but the rate of the reaction does not depend on its concentration. • This suggests the reaction occurs in two steps. Chemical Kinetics Slow Initial Step • A proposed mechanism for this reaction is Step 1: NO2 + NO2 NO3 + NO (slow) Step 2: NO3 + CO NO2 + CO2 (fast) • The NO3 intermediate is consumed in the second step. • As CO is not involved in the slow, rate-determining step, it does not appear in the rate law. Chemical Kinetics Fast Initial Step • The rate law for this reaction is found (experimentally) to be • Because termolecular (= trimolecular) processes are rare, this rate law suggests a two-step mechanism. Chemical Kinetics Fast Initial Step • A proposed mechanism is {Step 1 is an equilibriumit includes the forward and reverse reactions.} Chemical Kinetics Fast Initial Step • [NO] [Br2] = [NOBr2] Chemical Kinetics Questions • Q 2 p 390 • Q 1-3 p 391 Chemical Kinetics Unit Review • Chapter 5: Self Quiz Q 1-18 p 355 Q 2,4,6,9,14,16 • Chapter 6: Self Quiz 1-18 p 407, Q 4,7,910,13-16 p 408-409 Chemical Kinetics